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    【题目】水中溶解碳酸钠粉末，溶液温度升高，下列解释正确的是（ ）

    A.溶解过程只放热不吸热

    B.溶解过程只吸热不放热

    C.溶解过程不吸热不放热

    D.溶解过程既吸收热量也放出热量，只是放出的热量大于吸收的热量

    【答案】D

    【解析】

    试题分析：任何物质的溶解都包含着吸热和放热两个过程，如果放出的热量大于吸收的热量，溶液温度升高；如果放出的热量小于吸收的热量，溶液温度降低；如果放出热量等于吸收的热量，溶液温度不变。碳酸钠溶于水，溶液温度升高，说明溶解过程中放出的热量大于吸收的热量，故D正确。

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