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【题目】读“某地等高线图”,回答问题.

(1)写出图中序号所代表的地形部位名称:①____;②_____;③____;④_____。

(2)乙山顶与A地的相对高度是_______米.

(3)甲山顶在乙山顶的_________方向.

(4)从A地或B地出发,更容易攀登到乙山顶的是____地,原因是_____。

【答案】(1)山顶;鞍部;山谷;陡崖; (2)460 (3)西南 (4)A;因为此处等高线比较稀疏,坡度较缓

【解析】整体分析:该题以读“某地等高线图”为切入点,考查的是等高线地形图的判读,要求学生较强的读图分析问题的能力.

(1)读图可知,是等高线闭合且等高线数值中间高四周低则为山顶;是两山顶之间相对低洼的部位为鞍部;是等高线向海拔高处凸为山谷;等高线重合的地方为陡崖。

(2)读图可知,乙山顶的海拔为560米,A地的海拔为100米,乙山顶与A地的相对高度是两地的海拔之差,即560米-100米=460米。

(3)该图带有指向标,要根据指向标来判断,箭头指的方向为北方,平移指向标到乙山顶可以判断出甲山顶在乙山顶的西南方向。

(4)读图可知,从A地或B地出发,更容易攀登到乙山顶的是A地;原因是因为此处等高线比较稀疏,坡度较缓

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