¿×ȸʯÖ÷Òªº¬Cu 2(OH)2CO3£¬»¹º¬ÉÙÁ¿Fe¡¢SiµÄ»¯ºÏÎʵÑéÊÒÒÔ¿×ȸʯΪԭÁÏÖƱ¸CuSO4¡¤5H2O¼°CaCO3µÄʵÑéÁ÷³ÌÈçÏ£º   (ÎüÊÕ¹ý³ÌÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCl2+2NH3+CO2+H2O¡úCaCO3¡ý+2NH4Cl) Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢Ù Èܽâʱ£¬¼ÓÏ¡H2SO4·¢ÉúµÄÖ÷Òª·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________¡£ÎüÊÕ¹ý³ÌÖвúÉúµÄ¿ÉÓÃ×÷»¯·ÊµÄ¸±²úÆ·Ãû³ÆÊÇ_____________¡£
¢Ú ÓÉÂËÒºA»ñµÃCuSO4¡¤5H2O£¬ÐèÒª¾­¹ý___________¡¢ÀäÈ´½á¾§¡¢¹ýÂ˵ȲÙ×÷¡£³ýÉÕ±­¡¢Â©¶·Í⣬¹ýÂ˲Ù×÷»¹Óõ½ÁíÒ»ÖÖ²£Á§ÒÇÆ÷£¬¸ÃÒÇÆ÷Ôڴ˲Ù×÷ÖеÄÖ÷Òª×÷ÓÃÊÇ___________¡£ 
¢Û ÂËÒºÖмÓÉÙÁ¿CuOµÄÄ¿µÄÊÇ______________¡£
¢ÙCuO+H2SO4==CuSO4+H2O    £»ÂÈ»¯ï§
¢Ú¼ÓÈÈÕô·¢   £»°ÑÉÕ±­ÖеÄÒºÌåÒýÈ멶·ÖÐ
¢Ûµ÷½ÚÈÜÒºµÄpH£¬³ýÈ¥ÌúµÄ»¯ºÏÎͬʱ²»ÒýÈëеÄÔÓÖÊ 
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2011?Õ¿½­£©¿×ȸʯÖ÷Òªº¬Cu2£¨OH£©2CO3¡²Ò²¿ÉÈÏΪÊÇCu£¨OH£©2?CuCO3¡³£¬»¹º¬ÉÙÁ¿Fe¡¢SiµÄ»¯ºÏÎʵÑéÊÒÒÔ¿×ȸʯΪԭÁÏÖƱ¸CuSO4?5H2O£¬²½ÖèÈçÏ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÆøÌåEµÄ»¯Ñ§Ê½ÊÇ
CO2
CO2
£®
£¨2£©ÓÉÈÜÒºC»ñµÃCuSO4?5H2O£¬ÐèÒª¾­¹ýÕô·¢Å¨Ëõ¡¢ÀäÈ´½á¾§¡¢
¹ýÂË
¹ýÂË
ºÍ¸ÉÔïµÈ²Ù×÷£®
£¨3£©Ð´³ö¿×ȸʯÖ÷Òª³É·ÖÓëÏ¡ÁòËá·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
Cu2£¨OH£©2CO3+2H2SO4=2CuSO4+3H2O+CO2¡ü
Cu2£¨OH£©2CO3+2H2SO4=2CuSO4+3H2O+CO2¡ü
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?Ðì»ãÇø¶þÄ££©¿×ȸʯÖ÷Òªº¬Cu 2£¨OH£©2CO3£¬»¹º¬ÉÙÁ¿Fe¡¢SiµÄ»¯ºÏÎʵÑéÊÒÒÔ¿×ȸʯΪԭÁÏÖƱ¸CuSO4?5H2O¼°CaCO3µÄʵÑéÁ÷³ÌÈçͼ£º

£¨ÎüÊÕ¹ý³ÌÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCl2+2NH3+CO2+H2O¡úCaCO3¡ý+2NH4Cl£©
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙÈܽâʱ£¬¼ÓÏ¡H2SO4·¢ÉúµÄÖ÷Òª·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
CuO+H2SO4¨TCuSO4+H2O
CuO+H2SO4¨TCuSO4+H2O
£®ÎüÊÕ¹ý³ÌÖвúÉúµÄ¿ÉÓÃ×÷»¯·ÊµÄ¸±²úÆ·Ãû³ÆÊÇ
ÂÈ»¯ï§
ÂÈ»¯ï§
£®
¢ÚÓÉÂËÒºA»ñµÃCuSO4?5H2O£¬ÐèÒª¾­¹ý
¼ÓÈÈÕô·¢
¼ÓÈÈÕô·¢
¡¢ÀäÈ´½á¾§¡¢¹ýÂ˵ȲÙ×÷£®³ýÉÕ±­¡¢Â©¶·Í⣬¹ýÂ˲Ù×÷»¹Óõ½ÁíÒ»ÖÖ²£Á§ÒÇÆ÷£¬¸ÃÒÇÆ÷Ôڴ˲Ù×÷ÖеÄÖ÷Òª×÷ÓÃÊÇ
°ÑÉÕ±­ÖеÄÒºÌåÒýÈ멶·ÖÐ
°ÑÉÕ±­ÖеÄÒºÌåÒýÈ멶·ÖÐ
£®
¢ÛÂËÒºÖмÓÉÙÁ¿CuOµÄÄ¿µÄÊÇ
µ÷½ÚÈÜÒºµÄpH£¬³ýÈ¥ÌúµÄ»¯ºÏÎͬʱ²»ÒýÈëеÄÔÓÖÊ
µ÷½ÚÈÜÒºµÄpH£¬³ýÈ¥ÌúµÄ»¯ºÏÎͬʱ²»ÒýÈëеÄÔÓÖÊ
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¿×ȸʯÖ÷Òªº¬Cu 2(OH)2CO3£¬»¹º¬ÉÙÁ¿Fe¡¢SiµÄ»¯ºÏÎʵÑéÊÒÒÔ¿×ȸʯΪԭÁÏÖƱ¸CuSO4·5H2O¼°CaCO3µÄʵÑéÁ÷³ÌÈçÏ£º

(ÎüÊÕ¹ý³ÌÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCl2+2NH3+CO2+H2O¡úCaCO3¡ý+2NH4Cl)

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢Ù Èܽâʱ£¬¼ÓÏ¡H2SO4·¢ÉúµÄÖ÷Òª·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                        ¡£ÎüÊÕ¹ý³ÌÖвúÉúµÄ¿ÉÓÃ×÷»¯·ÊµÄ¸±²úÆ·Ãû³ÆÊÇ          ¡£

¢Ú ÓÉÂËÒºA»ñµÃCuSO4·5H2O£¬ÐèÒª¾­¹ý     ¡¢ÀäÈ´½á¾§¡¢¹ýÂ˵ȲÙ×÷¡£³ýÉÕ±­¡¢Â©¶·Í⣬¹ýÂ˲Ù×÷»¹Óõ½ÁíÒ»ÖÖ²£Á§ÒÇÆ÷£¬¸ÃÒÇÆ÷Ôڴ˲Ù×÷ÖеÄÖ÷Òª×÷ÓÃÊÇ          ¡£

¢Û ÂËÒºÖмÓÉÙÁ¿CuOµÄÄ¿µÄÊÇ        ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2012ÄêÉϺ£ÊÐÐì»ãÇøÖп¼»¯Ñ§¶þÄ£ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

¿×ȸʯÖ÷Òªº¬Cu 2£¨OH£©2CO3£¬»¹º¬ÉÙÁ¿Fe¡¢SiµÄ»¯ºÏÎʵÑéÊÒÒÔ¿×ȸʯΪԭÁÏÖƱ¸CuSO4?5H2O¼°CaCO3µÄʵÑéÁ÷³ÌÈçͼ£º

£¨ÎüÊÕ¹ý³ÌÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCl2+2NH3+CO2+H2O¡úCaCO3¡ý+2NH4Cl£©
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙÈܽâʱ£¬¼ÓÏ¡H2SO4·¢ÉúµÄÖ÷Òª·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£®ÎüÊÕ¹ý³ÌÖвúÉúµÄ¿ÉÓÃ×÷»¯·ÊµÄ¸±²úÆ·Ãû³ÆÊÇ______£®
¢ÚÓÉÂËÒºA»ñµÃCuSO4?5H2O£¬ÐèÒª¾­¹ý______¡¢ÀäÈ´½á¾§¡¢¹ýÂ˵ȲÙ×÷£®³ýÉÕ±­¡¢Â©¶·Í⣬¹ýÂ˲Ù×÷»¹Óõ½ÁíÒ»ÖÖ²£Á§ÒÇÆ÷£¬¸ÃÒÇÆ÷Ôڴ˲Ù×÷ÖеÄÖ÷Òª×÷ÓÃÊÇ______£®
¢ÛÂËÒºÖмÓÉÙÁ¿CuOµÄÄ¿µÄÊÇ______£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸