13£®ÔĶÁÏÂÃæ¿ÆÆÕ¶ÌÎÄ£¨±¾ÎÄÓÉÍøÂçÎÄÕ¸Äд£©£®
ËÉ»¨µ°ÓÖ³ÆƤµ°¡¢±äµ°¡¢»Ò°üµ°µÈ£¬Òò°þ¿ªµ°¿Çºó½º¶³×´µÄµ°ÇåÖг£ÓÐËÉÕë×´µÄ½á¾§»ò»¨ÎƶøµÃÃû£¬ÊÇÒ»ÖÖÎÒ¹ú´«Í³·çζʳƷ£¬¿Ú¸ÐÏÊ»¬Ë¬¿Ú£¬É«Ïãζ¾ùÓжÀµ½Ö®´¦£®ÖÐÒ½ÈÏΪ£¬ËÉ»¨µ°ÐÔÁ¹£¬¶ÔÑÀÍ´¡¢ÑÛÍ´µÈ¼²²¡ÓÐÒ»¶¨ÁÆЧ£®ÓÉÓÚËÉ»¨µ°»áÓÐÒ»¹É¼îɬ棬ÔÚ³ÔËÉ»¨µ°µÄʱºò¿ÉÒÔ¼ÓÈëÉÙÁ¿µÄ½ª´×Ö­£®
ËÉ»¨µ°ÊÇÓÃÁÏÄà°ü¹üѼµ°¡¢¼¦µ°µÈ¼Ó¹¤¶ø³É£®ÁÏÄàÊÇÓÉÉúʯ»Ò¡¢´¿¼î¡¢Ê³ÑΡ¢ºì²è¡¢²Ýľ»Ò£¨Ö÷Òª³É·ÖK2CO3£©µÈÔ­ÁÏÓëË®°´±ÈÀý»ìºÏ¾ùÔÈÖƵã®ÁÏÄàÖÆ×÷¹ý³ÌÖУ¬Í¨¹ýһϵÁз´Ó¦£¬²úÉúµÄÇ¿¼î£¨NaOH¡¢KOH£©¾­µ°¿ÇÉøÈëµ½µ°ÇåºÍµ°»ÆÖУ¬ÓëÆäÖеĵ°°×ÖÊ×÷Óã¬ÖÂʹµ°°×Öʷֽ⡢Äý¹Ì²¢·Å³öÉÙÁ¿Áò»¯ÇâÆøÌåºÍ°±Æø£®Í¬Ê±ÉøÈëµÄ¼î»¹»áÓëµ°°×ÖÊ·Ö½â³öµÄ°±»ùËá½øÒ»²½·¢ÉúÖкͷ´Ó¦£¬Éú³ÉµÄÑεľ§Ìå³Á»ýÔÚÄý½ºÌ¬µÄµ°ÇåÖУ¬±ã³öÏÖÁ˶ä¶ä¡°ËÉ»¨¡±£®¶øÁò»¯ÇâÆøÌåÔòÓëµ°ÇåºÍµ°»ÆÖеĿóÎïÖÊ×÷ÓÃÉú³É¸÷ÖÖÁò»¯Îʹµ°ÇåºÍµ°»ÆµÄÑÕÉ«·¢Éú¸Ä±ä£¬µ°Çå³ÊÌØÊâµÄ²èºÖÉ«¡¢µ°»ÆÔò³ÊÄ«ÂÌÉ«£®ÏÂͼ±íʾËÉ»¨µ°ëçÖÆʱ¼äÓëÆäÖе°ÇåºÍµ°»ÆµÄpHµÄ±ä»¯¹Øϵ£®

ºÜ¶àÈËÔÚƽʱÉú»îÖж¼·Ç³£Ï²»¶³ÔƤµ°ÊÝÈâÖà¡¢Á¹°èËÉ»¨µ°£¬×¨¼ÒÌáÐÑÕâÖÖʳÎïÉÙ³ÔÎÞ·Á£¬È´²»Äܹý¶àʳÓã®ÆäÒ»£¬ËÉ»¨µ°ëçÖƹý³ÌÖе°°×Öʷֽ⡢±äÖÊ£¬µ¼ÖÂÓªÑø¼ÛÖµÔâµ½ÁËÒ»¶¨µÄÆÆ»µ£®Æä¶þ£¬ÊÐÊÛËÉ»¨µ°»¹¿ÉÄܺ¬Ç¦£¨¹ú¼Ò¹æ¶¨ËÉ»¨µ°ÖÐǦº¬Á¿ÐèСÓÚ0.5mg/kg£©£®Î¢Á¿Ç¦ºÜÈÝÒ×±»¶ùͯÎüÊÕ£¬µ¼ÖÂǦÖж¾£®ÆäÈý£¬°þ¿ªÆ¤µÄËÉ»¨µ°1ÖÁ2СʱÄÚÒ»¶¨Òª³ÔÍ꣬Èô³¤Ê±¼ä±©Â¶ÔÚ¿ÕÆøÖУ¬·Ç³£ÈÝÒ׸ÐȾɳÃÅÊϸ˾ú£¬É³ÃÅÊϸ˾ú»á¿ìËÙ·±Ö³£¬´ËʱʳÓÃËÉ»¨µ°ºÜÈÝÒ×ÒýÆðÖж¾ÏÖÏó£®                                                    
ÒÀ¾ÝÎÄÕÂÄÚÈÝ£¬»Ø´ðÏÂÁÐÎÊÌ⣮
£¨1£©Ê³ÓÃËÉ»¨µ°Ê±¼ÓÈëÉÙÁ¿½ª´×Ö­¿ÉÒÔ³ýÈ¥ËÉ»¨µ°Öмîɬζ£®
£¨2£©ÁÏÄàÖÆ×÷¹ý³ÌÖлáÉú³ÉÇ¿¼îNaOHºÍKOH£¬¼ØÔªËØÀ´×ÔÓÚÔ­ÁÏÖеIJÝľ»Ò£¨»òK2CO3£©£®
Éú³ÉNaOHµÄ¹ý³ÌÖУ¬ÊôÓÚ¸´·Ö½â·´Ó¦µÄ»¯Ñ§·½³ÌʽΪCa£¨OH£©2+Na2CO3¨TCaCO3¡ý+2NaOH£®
£¨3£©ÒÀ¾ÝËÉ»¨µ°ëçÖÆʱ¼äÓëÆäÖе°ÇåºÍµ°»ÆpHµÄ±ä»¯¹ØϵÅжϣ¬µ±µ°ÇåºÍµ°»ÆpH¾ù
´ïµ½9ÒÔÉÏʱ£¬ËÉ»¨µ°ÖÁÉÙëçÖƵÄÌìÊýΪB£¨Ìî×ÖĸÐòºÅ£¬ÏÂͬ£©£®
A£®2Ìì        B£®6Ìì       C£®12Ìì       D£®32Ìì
£¨4£©ÏÂÁйØÓÚËÉ»¨µ°µÄ˵·¨ÕýÈ·µÄÊÇAC£®
A£®ËÉ»¨µ°ÌØÊâÑÕÉ«µÄÐγÉÓëÁò»¯ÇâÆøÌåÓйØ
B£®ËÉ»¨µ°¾ßÓкܸߵÄÓªÑø¼ÛÖµ£¬³ÉÈË¿ÉÒÔ¶à³Ô
C£®ÊÐÊÛËÉ»¨µ°¿ÉÄܺ¬ÓÐÉÙÁ¿µÄǦ£¬¶ùͯ²»ÒËʳÓÃ
D£®°þ¿ªÆ¤µÄËÉ»¨µ°¸ôÒ¹·ÅÖúóÒÀÈ»¿ÉÒÔ·ÅÐÄʳÓã®

·ÖÎö £¨1£©¸ù¾Ý»¨µ°ÔÚÖÆ×÷¹ý³ÌÖÐËù¼ÓÈë³Ê¼îÐÔÎïÖÊ£¬ÀûÓÃÖкͷ´Ó¦µÄÀíÂÛ£¬Ñ¡ÔñÎïÖʽøÐÐÖкͷ´Ó¦¸ÄÉÆ¿Úζ½â´ð£»
£¨2£©¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬»¯Ñ§·´Ó¦Ç°ºó£¬ÔªËصÄÖÖÀ಻±ä½â´ð£»¸ù¾Ý·´Ó¦Ô­Àí·ÖÎö½â´ð£»
£¨3£©¸ù¾ÝͼÖÐÐÅÏ¢·ÖÎö½â´ð£»
£¨4£©A¡¢¸ù¾ÝËÉ»¨µ°ÌØÊâÑÕÉ«µÄÐγÉÓëÁò»¯ÇâÆøÌåÓйؽâ´ð£»
B¡¢¸ù¾ÝËÉ»¨µ°¾ßÓкܸߵÄÓªÑø¼ÛÖµ£¬Ó¦ÊÊÁ¿Ê¹Óýâ´ð£»
C£®¸ù¾ÝÊÐÊÛËÉ»¨µ°¿ÉÄܺ¬ÓÐÉÙÁ¿µÄǦ£¬¶ùͯ²»ÒËʳÓýâ´ð£»
D£®¸ù¾Ý°þ¿ªÆ¤µÄËÉ»¨µ°¸ôÒ¹·ÅÖúó¿ÉÄܱäÖÊ£¬²»ÄÜʳÓýâ´ð£®

½â´ð ½â£º£¨1£©ËÉ»¨µ°ÔÚÖÆ×÷¹ý³ÌÖмÓÈëÁË¡°¼îË®¡±£¨³Ê¼îÐÔµÄÎïÖÊ£©¶øÂÔ´øɬζ£¬Îª¼õÉÙɬ棬ÔÚ³ÔËÉ»¨µ°Ê±£¬×îºÃÕºµãÏÔËáÐÔµÄÎïÖÊ£¬ÕâÑù¿ÉÒÔÖкͼîË®£¬¶øʳ´×ÏÔËáÐÔ£¬Òò¶øÔÚ³ÔµÄʱºòÕºµãʳ´×¸ÄÉÆ¿Úζ£»
£¨2£©ÁÏÄàÖÆ×÷¹ý³ÌÖлáÉú³ÉÇ¿¼îNaOHºÍKOH£¬¼ØÔªËØÀ´×ÔÓÚÔ­ÁÏÖеIJÝľ»Ò£¨»òK2CO3£©£»Éúʯ»ÒÄÜÓëË®·´Ó¦Éú³ÉÇâÑõ»¯¸Æ£¬´Ë·´Ó¦Îª»¯ºÏ·´Ó¦£¬Éú³ÉµÄÇâÑõ»¯¸ÆÄÜÓë̼ËáÄÆ·´Ó¦Éú³É²»ÈÜÓÚË®µÄ̼Ëá¸ÆºÍÇâÑõ»¯ÄÆ£¬ÊôÓÚ¸´·Ö½â·´Ó¦£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCa£¨OH£©2+Na2CO3¨TCaCO3¡ý+2NaOH£»
£¨3£©¸ù¾ÝͼÖÐÐÅÏ¢¿ÉÖª£ºÒÀ¾ÝËÉ»¨µ°ëçÖÆʱ¼äÓëÆäÖе°ÇåºÍµ°»ÆpHµÄ±ä»¯¹ØϵÅжϣ¬µ±µ°ÇåºÍµ°»ÆpH¾ù´ïµ½9ÒÔÉÏʱ£¬ËÉ»¨µ°ÖÁÉÙëçÖƵÄÌìÊýΪ12Ì죻
£¨4£©A¡¢ËÉ»¨µ°ÌØÊâÑÕÉ«µÄÐγÉÓëÁò»¯ÇâÆøÌåÓйأ¬¹ÊÕýÈ·£»
B¡¢ËÉ»¨µ°¾ßÓкܸߵÄÓªÑø¼ÛÖµ£¬Ó¦ÊÊÁ¿Ê¹Ó㬹ʴíÎó£»
C£®ÊÐÊÛËÉ»¨µ°¿ÉÄܺ¬ÓÐÉÙÁ¿µÄǦ£¬¶ùͯ²»ÒËʳÓ㬹ÊÕýÈ·£»
D£®°þ¿ªÆ¤µÄËÉ»¨µ°¸ôÒ¹·ÅÖúó¿ÉÄܱäÖÊ£¬²»ÄÜʳÓ㬹ʴíÎó£®
´ð°¸£º
£¨1£©¼îɬ£»  
£¨2£©²Ýľ»Ò£¨»òK2CO3£©£» Ca£¨OH£©2+Na2CO3¨TCaCO3¡ý+2NaOH
£¨3£©B£»      
£¨4£©AC£®

µãÆÀ ±¾ÌâÖ÷Òª¿¼²éѧÉúÔËÓÃËùѧ»¯Ñ§ÖªÊ¶×ۺϷÖÎöºÍ½â¾öʵ¼ÊÎÊÌâµÄÄÜÁ¦£¬Ôö¼ÓÁËѧÉú·ÖÎöÎÊÌâµÄ˼ά¿ç¶È£¬Ç¿µ÷ÁËѧÉúÕûºÏ֪ʶµÄÄÜÁ¦£®½â´ðʱҪÇóѧÉúÊìÁ·ÕÆÎÕÎïÖÊÖ®¼äÏ໥×÷ÓÃʱµÄ·´Ó¦Çé¿ö£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

3£®Îç·¹µÄʳÆ×ÖÐÓТٳ´ÓͲˠ ¢ÚÆ»¹û ¢ÛÃ×·¹ ¢ÜºìÉÕÈâ ¢ÝÌÇ´×Ó㣬ÄãÈÏΪ±È½ÏºÏÀíµÄ´îÅäÊÇ£¨¡¡¡¡£©
A£®¢Ù¢Ú¢ÛB£®¢Ù¢Û¢ÝC£®¢Ù¢Ü¢ÝD£®¢Û¢Ü¢Ý

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

4£®Èç±íËùʾ¶Ô²¿·Ö»¯Ñ§ÖªÊ¶µÄ¹éÄÉÍêÈ«ÕýÈ·µÄÒ»×éÊÇ£¨¡¡¡¡£©
A£®»¯Ñ§ÓëÉú»îB£®»¯Ñ§Óë»·¾³
¢ÙÓÃ×ÆÉյķ½·¨Äܼø±ðÄáÁúÏߺÍÑòëÏß  
¢Ú»îÐÔÌ¿Äܾ»Ë®ÊÇÒòΪ»îÐÔÌ¿ÓÐÎü¸½ÐÔ
¢ÙËáÓêÖ÷ÒªÊÇÓÉCO2¡¢SO2ÆøÌåÒýÆðµÄ
¢ÚPM2.5ÊÇÔì³ÉÎíö²ÌìÆøµÄ¡°ÔªÐס±Ö®Ò»
C£®»¯Ñ§Ó뽡¿µD£®»¯Ñ§Ó밲ȫ
¢Ù·¢Ã¹µÄ¹ÈÎïÁÀɹºó¼´¿ÉʳÓÃ
¢ÚʹÓüÓÌú½´ÓÍ¿ÉÔ¤·ÀƶѪ
¢Ù¾Æ¾«È÷ÔÚ×ÀÉϲ»É÷ȼÉÕÆðÀ´£¬¿ÉÒÔÓÃË®½½Ãð
¢ÚÎó·þÖؽðÊôÑÎÈÜÒº£¬ºÈ¼¦µ°Çå»òÅ£ÄÌ
A£®AB£®BC£®CD£®D

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

1£®Æû³µÎ²ÆøÖеÄÖ÷ÒªÎÛȾÎïÓÐÒ»Ñõ»¯Ì¼¡¢µªµÄÑõ»¯Îï¡¢º¬Ç¦»¯ºÏÎïºÍÑ̳¾µÈ£®Ä³ÖÖ´ß»¯¼Á¿É½«Î²ÆøÖеÄÒ»Ñõ»¯Ì¼¡¢¶þÑõ»¯µª×ª»¯ÎªÁ½ÖÖ¿ÕÆøÖеÄÎÞ¶¾³É·Ö£®¸ù¾Ý¸Ã·´Ó¦µÄ΢¹ÛʾÒâͼ£¬·ÖÎöÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®ËÄÖÖÎïÖʾùÊôÓÚ»¯ºÏÎïB£®Éú³É±ûºÍ¶¡µÄÖÊÁ¿±ÈΪ11£º7
C£®¼×ºÍÒҵķÖ×Ó¸öÊý±ÈΪ1£º2D£®¶¡·Ö×ÓµÄ΢¹ÛʾÒâͼΪ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

8£®ÎÒ¹úÑÐÖƵĺ½ÌìÔ±²ÕÍâ·þΪº½ÌìÔ±³É¹¦½øÐÐÌ«¿ÕÐÐ×ßÌṩÁË¿É¿¿µÄ±£Ö¤£®º½ÌìÔ±²ÕÍâ·þÄÚº¬ÓÐÓëÇâÑõ»¯ÄÆÐÔÖÊÏàËƵÄÇâÑõ»¯ï®£¨LiOH£©£¬Ëü²»¿ÉÄܾßÓеÄÐÔÖÊÊÇ£¨¡¡¡¡£©
A£®ÄÜÓë¶þÑõ»¯Ì¼·´Ó¦B£®ÄÜÓëÑÎËá·´Ó¦
C£®ÄÜÓëÑõ»¯Ìú·´Ó¦D£®ÄÜʹ·Ó̪±äºì

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÊµÑé̽¾¿Ìâ

18£®Öп¼Ç°£¬ÎÒÊи÷У½øÐÐÁË»¯Ñ§ÊµÑé²Ù×÷¿¼ÊÔ£¬ÔÚ¸´Ï°Ó­¿¼Ê±£¬Ð¡Ã÷½øÐÐÁ˲Ù×÷ѵÁ·£¬ËùÓÃÒÇÆ÷ÈçͼËùʾ£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ð´³öÒÇÆ÷¢ÙµÄÃû³Æ׶ÐÎÆ¿£»
£¨2£©Ä³Í¬Ñ§ÊµÑéʱ£¬ËùÓÃ×°ÖÃCÊÕ¼¯ÆøÌ壬ÓÉ´Ë¿ÉÍÆÖªËùÊÕ¼¯¾ßÌåµÄ¾ßÓеÄÁ½ÌõÐÔÖÊÊÇ£ºÃܶȱȿÕÆø´ó¡¢²»Óë¿ÕÆøÖеÄÎïÖÊ·´Ó¦£»
£¨3£©Ð¡Ã÷ÓÃͼB£¬CÖƱ¸Ò»ÖÖ³£¼ûÆøÌ壬ÖÆÈ¡·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2KClO3 $\frac{\underline{MnO_2}}{¡÷}$2KCl+3O2¡ü£»ÊµÑé½áÊøʱ£¬Ó¦ÈçºÎ¼ìÑéÆøÌåÊÇ·ñÊÕ¼¯Âú£¨ÒªÇóʵÑé²Ù×÷¡¢ÏÖÏóºÍ½áÂÛ£©½«´ø»ðÐǵÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú£¬ÈôľÌõ¸´È¼£¬ÔòÖ¤Ã÷ÒÑÂú£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

5£®A¡¢BΪ̼Ëá¸Æ¿é×´¹ÌÌåºÍ̼ËáÄÆ·ÛÄ©ÖеÄijһÖÖ£¬ÔÚÁ½ÉÕ±­Öзֱð·ÅÈëÖÊÁ¿Îª16gµÄA¡¢BÁ½ÖÖÎïÖÊ£¬¸÷¼ÓÈë109.5gÈÜÖÊÖÊÁ¿·ÖÊýÏàͬµÄÏ¡ÑÎËᣬ³ä·Ö·´Ó¦£¬·´Ó¦²úÉúÆøÌåµÄÖÊÁ¿Ó뷴Ӧʱ¼äµÄ¹ØϵÈçͼËùʾ£®
£¨1£©B·´Ó¦ÖÁaµãʱ£¬ËùµÃÈÜÒºµÄÈÜÖÊΪCaCl2¡¢HCl£¨Ð´»¯Ñ§Ê½£©£®
£¨2£©·´Ó¦½áÊøºó£¬½«Á½ÉÕ±­ÖеÄÎïÖÊ»ìºÏ£¬³ÆÁ¿µÃÉÕ±­ÄÚÊ£ÓàÎïÖʵÄÖÊÁ¿Îª237.8g£¬ÇóËù¼ÓÏ¡ÑÎËáÖÐÈÜÖÊÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

2£®ÖØÇìÒ»ÖÐij»¯Ñ§Ð¡×éΪ̽¾¿¶þÑõ»¯Ì¼µÄÖÆÈ¡¼°ÐÔÖÊ£¬Éè¼ÆÁËÈçÏÂʵÑé

£¨1£©AΪʵÑéÊÒÖÆÈ¡¶þÑõ»¯Ì¼µÄʵÑ飬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪCaCO3+2HCl=CaCl2+CO2¡ü+H2O
£¨2£©ÇëÓû¯Ñ§·½³Ìʽ½âÊÍDÖÐ×ÏɫʯÈï±äºìµÄÔ­Òò
ÈôÒªÖ¤Ã÷´óÀíʯÖк¬Ì¼Ëá¸ùÀë×Ó£¬Ö»Ð轫DÖÐÊÔ¼Á»»Îª³ÎÇåµÄʯ»ÒË®£¨ÌîÊÔ¼ÁÃû³Æ£©
£¨3£©ÓÃÁ½ÖÖ·½·¨ÊÕ¼¯ÆøÌåʱ£¬²âµÃB¡¢CÖÐÑõÆøÌå»ý·ÖÊýËæʱ¼äµÄ±ä»¯¹ØϵÈçͼ¼×Ëùʾ£¬ÄãÈÏΪÄÜ£¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©ÓÃÅÅË®·¨ÊÕ¼¯¶þÑõ»¯Ì¼£®ÏÂÁйØÓÚCµÄ´ëÊ©ÖÐÄܼõÉÙ¶þÑõ»¯Ì¼ÔÚË®ÖÐÈܽâÁ¿µÄÊÇ¢Ù¢Û£¨ÌîÐòºÅ£©

¢ÙÔÚË®ÃæÌí¼ÓÒ»²ãÖ²ÎïÓÍ
¢ÚÊÕ¼¯ÆøÌåʱ²»¶ÏÕñµ´C
¢ÛÓÃÈÈË®Ìæ»»ÀäË®
£¨4£©ÒÑÖª£º³£ÎÂÏÂ1Ìå»ýË®×î¶àÈܽâ1Ìå»ý¶þÑõ»¯Ì¼£¬µÃµ½pHֵԼΪ5.6µÄ±¥ºÍÈÜÒº£®Êµ¼ì½áÊøºó£¬Èô²âµÃDÖÐÈÜÒºpHֵСÓÚ5.6£¬ÔòÒÒ¡¢±û¡¢¶¡Í¼ÏóÓëEÖб仯Ïà·ûºÏµÄ ÊÇÒÒ¶¡£¨ÌîÐòºÅ£©
£¨5£©ÎªÅбðEÖÐNaOHÊÇ·ñ»¹ÓÐÊ£Ó࣬ӦÏòEÖмÓÈëµÄÊÔ¼ÁÓТܣ¨ÌîÐòºÅ£©£®
¢ÙÏ¡ÑÎËá
¢ÚÂÈ»¯±µÈÜÒº
¢ÛÇâÑõ»¯±µÈÜÒº
¢ÜÁòËáÍ­ÈÜÒº£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

3£®¶ÔÏÂÁÐËĸö»¯Ñ§·½³ÌʽµÄ·´Ó¦ÀàÐÍ£¬Åжϲ»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
¢Ù3Fe+2O2$\frac{\underline{\;¸ßÎÂ\;}}{\;}$Fe3O4              ¢ÚKMnO4$\frac{\underline{\;\;¡÷\;\;}}{\;}$K2MnO4+MnO2+O2¡ü
¢ÛH2+CuO$\frac{\underline{\;\;¡÷\;\;}}{\;}$Cu+H2O                ¢Ü2H2S+SO2¨T3S¡ý+2H2O£®
A£®¢ÙÊÇ»¯ºÏ·´Ó¦B£®¢ÚÊǷֽⷴӦC£®¢ÛÊÇÖû»·´Ó¦D£®¢ÜÊǸ´·Ö½â·´Ó¦

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸