32¡¢ÏÂÁпòͼÖеÄÎïÖʾùΪ³õÖл¯Ñ§³£¼ûµÄÎïÖÊ£¬ÆäÖÐAÊǽ¨Öþ²ÄÁϵÄÖ÷Òª³É·Ö£¬BÊôÓÚÑõ»¯ÎÏÂͼÊÇËüÃÇÖ®¼äµÄÏ໥ת»¯¹Øϵ£®Çë»Ø´ð£º

£¨1£©Ð´³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£ºA
CaCO3
C
CO2
£®
£¨2£©µÃµ½FÈÜÒºµÄ²Ù×÷¢ñµÄÃû³ÆΪ£º
¹ýÂË
£®
£¨3£©ÈôIÊǺìºÖÉ«³Áµí£¬Çëд³öG+F¡úIµÄ»¯Ñ§·½³Ìʽ£º
FeCl3+3NaOH¨TFe£¨OH£©3¡ý+3NaCl

£¨4£©Ð´³ö·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ
CaO+H2O¨TCa£¨OH£©2
£®
·ÖÎö£º±¾ÌâµÄ½âÌâÍ»ÆÆ¿ÚÔÚÓÚAÊǽ¨Öþ²ÄÁϵÄÖ÷Òª³É·Ö£¬ÇÒ¸ßÎÂʱÄÜ·Ö½âÉú³ÉÎÞÉ«ÆøÌåCºÍD£¬¸ù¾Ý³£¼ûÎïÖʵÄÐÔÖÊ¿ÉÖª´ËÎïÖÊΪ̼Ëá¸Æ£¬´Ó¶ø¿É˳ÍƳöC¡¢D¡¢E¡¢FÎïÖʵĻ¯Ñ§Ê½£¬ÁíһͻÆÆ¿ÚÔÚÓÚIÊǺìºÖÉ«³Áµí˵Ã÷IÊÇÇâÑõ»¯Ìú£¬´Ó¶ø¿ÉÄæÍƳöGºÍBµÄ»¯Ñ§Ê½£®
½â´ð£º½â£º£º£¨1£©AÊǽ¨Öþ²ÄÁϵÄÖ÷Òª³É·Ö£¬ÇÒ¸ßÎÂʱÄÜ·Ö½âÉú³ÉÎÞÉ«ÆøÌåCºÍD£¬¸ù¾Ý³£¼ûÎïÖʵÄÐÔÖÊ¿ÉÖª´ËÎïÖÊΪ̼Ëá¸Æ£¬ÔòCΪ¶þÑõ»¯Ì¼£¬DΪÑõ»¯¸Æ£¬ËùÒÔ±¾Ìâ´ð°¸Îª£ºA£ºCaCO3£¬C£ºCO2£»
£¨2£©Ñõ»¯¸ÆÓëË®·¢Éú»¯ºÏ·´Ó¦Éú³ÉÇâÑõ»¯¸Æ£¬ÇâÑõ»¯¸ÆÓë̼ËáÄÆ·´Ó¦Éú³ÉÇâÑõ»¯ÄƺÍ̼Ëá¸Æ³Áµí£¬Òª°Ñ̼Ëá¸Æ³Áµí·ÖÀë³öÈ¥£¬¿ÉÒÔ²ÉÓùýÂ˵ķ½·¨£¬ËùÒÔ±¾Ìâ´ð°¸Îª£º¹ýÂË£»
£¨3£©IÊǺìºÖÉ«³Áµí˵Ã÷IÊÇÇâÑõ»¯Ìú£¬ÔòGÖк¬ÓÐÌúÀë×Ó£¬¶øGÊÇÓÉÑõ»¯ÎïÓëÑÎËá·´Ó¦Éú³É£¬ËµÃ÷GÊÇÂÈ»¯Ìú£¬ËùÒÔG+F¡úIµÄ·´Ó¦ÎªÂÈ»¯ÌúÓëÇâÑõ»¯ÄƵķ´Ó¦£¬
¹Ê´ð°¸Îª£ºFeCl3+3NaOH=Fe£¨OH£©3¡ý+3NaCl£»
£¨4£©·´Ó¦¢ÙÊÇÑõ»¯¸ÆÓëË®·´Ó¦Éú³ÉÇâÑõ»¯¸Æ£¬¹Ê´ð°¸Îª£ºCaO+H2O¨TCa£¨OH£©2£®
µãÆÀ£º½â¾ö¿òͼʽÎïÖÊÍƶÏÌ⣬Ê×ÏÈÒª·ÖÎöÌâÖеÄÒþº¬Ìõ¼þºÍÃ÷ÏÔÌõ¼þ£¬×¥¹Ø¼ü£¬ÕÒ×¼½âÌâÍ»ÆÆ¿Ú£¬Ö±½ÓµÃ³ö½áÂÛ£¬È»ºóÀûÓÃ˳Ïò»òÄæÏò»òÁ½±ßÏòÖмäÍƶϣ¬ÖðÒ»ÍƵ¼³öÆäËû½áÂÛ£¬´Ó¶øµÃ³öÎïÖʵÄ×é³É£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

21¡¢ÏÂÁпòͼÖеÄÎïÖʾùΪ³õÖл¯Ñ§³£¼ûµÄÎïÖÊ£¬ÆäÖÐAÊǽ¨Öþ²ÄÁϵÄÖ÷Òª³É·Ö£¬BÊôÓÚ½ðÊôÑõ»¯ÎÏÂͼÊÇËüÃÇÖ®¼äµÄÏ໥ת»¯¹Øϵ£®Çë»Ø´ð£º

£¨1£©Ð´³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£ºA£®
CaCO3
C£®
CO2
£®
£¨2£©µÃµ½FÈÜÒºµÄ²Ù×÷¢ñµÄÃû³ÆΪ£º
¹ýÂË
£®
£¨3£©ÈôHÊǺìºÖÉ«³Áµí£¬Çëд³öG+F¡úHµÄ»¯Ñ§·½³Ìʽ£º
3NaOH+FeCl3¨TFe£¨OH£©3¡ý+3NaCl

£¨4£©Ö¸³ö·´Ó¦¢ÙµÄ»ù±¾ÀàÐÍÊÇ
»¯ºÏ·´Ó¦
·´Ó¦£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂÁпòͼÖеÄÎïÖʾùΪ³õÖл¯Ñ§³£¼ûÎïÖÊ£¬ÆäÖÐAÊǽ¨Öþ²ÄÁϵÄÖ÷Òª³É·Ö£¬BÊôÓÚÑõ»¯ÎHÊǽðÊôµ¥ÖÊ£¬ÏÂͼÊÇËüÃÇÖ®¼äµÄÏ໥ת»¯¹Øϵ£®Çë»Ø´ð£º
¾«Ó¢¼Ò½ÌÍø
£¨1£©Ð´³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£ºA
 
¡¢C
 
¡¢F
 
£®
£¨2£©µÃµ½FÈÜÒºµÄ²Ù×÷·½·¨Îª£º
 
£®
£¨3£©ÈôÓÐÆøÌåXÉú³É£¬ÔòIΪ
 
£»Bת»¯ÎªHµÄ»¯Ñ§·½³ÌʽΪ
 
£»ÈôûÓÐÆøÌåXÉú³É£¬Ôò GÓëFÈÜÒº·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
 
£¬¸Ã·´Ó¦µÄ»ù±¾·´Ó¦ÀàÐÍÊôÓÚ
 
·´Ó¦£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

17¡¢ÏÂÁпòͼÖеÄÎïÖʾùΪ³õÖл¯Ñ§³£¼ûµÄÎïÖÊ£¬ÆäÖÐAÊǽ¨Öþ²ÄÁϵÄÖ÷Òª³É·Ö£¬BÊôÓÚÑõ»¯ÎÏÂͼÊÇËüÃÇÖ®¼äµÄÏ໥ת»¯¹Øϵ£®Çë»Ø´ð£º¢ÙE×ãÁ¿Ë®D²Ù×÷¢ñÊÊÁ¿Na2CO3ÈÜÒºG£¨ÓÐÉ«ÈÜÒº£©Òº£©¸ßÎÂÏ¡ÑÎËáABFÈÜÒºÎÞÉ«ÆøÌåCI£¨ÓÐÉ«³Áµí£©

£¨1£©Ð´³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£ºA£®
CaCO3
 C£®
CO2
£®
£¨2£©µÃµ½FÈÜÒºµÄ²Ù×÷¢ñµÄÃû³ÆΪ£º
¹ýÂË
£®
£¨3£©ÈôIÊÇÀ¶É«³Áµí£¬Çëд³öG+F¡úIµÄ»¯Ñ§·½³Ìʽ£º
2NaOH+CuCl2¨TCu£¨OH£©2¡ý+2NaCl

£¨4£©Ö¸³ö·´Ó¦¢ÙµÄ»ù±¾ÀàÐÍÊÇ
»¯ºÏ·´Ó¦
·´Ó¦£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2013?Ë«ÂÐÇøÄ£Ä⣩ÏÂÁпòͼÖеÄÎïÖʾùΪ³õÖл¯Ñ§³£¼ûµÄÎïÖÊ£¬ÆäÖÐAÊǽ¨Öþ²ÄÁϵÄÖ÷Òª³É·Ö£¬BÊôÓÚÑõ»¯ÎÈçͼÊÇËüÃÇÖ®¼äµÄÏ໥ת»¯¹Øϵ£®Çë»Ø´ð£º

£¨1£©Ð´³öAÎïÖʵĻ¯Ñ§Ê½£º
CaCO3
CaCO3
£»
£¨2£©µÃµ½FÈÜÒºµÄ²Ù×÷¢ñµÄÃû³ÆΪ£º
¹ýÂË
¹ýÂË
£»
£¨3£©ÈôIÊǺìºÖÉ«³Áµí£¬Çëд³öG+F¡úIµÄ»¯Ñ§·½³Ìʽ£º
FeCl3+3NaOH¨T¨TFe£¨OH£©3¡ý+3NaCl
FeCl3+3NaOH¨T¨TFe£¨OH£©3¡ý+3NaCl
£»
£¨4£©Ð´³ö·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ£º
CaO+H2O¨T¨TCa£¨OH£©2
CaO+H2O¨T¨TCa£¨OH£©2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂÁпòͼÖеÄÎïÖʾùΪ³õÖл¯Ñ§³£¼ûµÄÎïÖÊ£¬ÆäÖÐAÊǽ¨Öþ²ÄÁϵÄÖ÷Òª³É·Ö£¬BÊôÓÚÑõ»¯ÎÈçͼÊÇËüÃÇÖ®¼äµÄÏ໥ת»¯¹Øϵ£®Çë»Ø´ð£º
¾«Ó¢¼Ò½ÌÍø
£¨1£©Ð´³öAÎïÖʵĻ¯Ñ§Ê½£º
 
£®
£¨2£©µÃµ½FÈÜÒºµÄ²Ù×÷¢ñµÄÃû³ÆΪ£º
 
£®
£¨3£©Çëд³öG+F¡úIµÄ»¯Ñ§·½³Ìʽ£º
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸