Question

5£®Ä¿Ç°£¬ÈËÀàÒÔ»¯Ê¯È¼ÁÏΪÖ÷ÒªÄÜÔ´£®»¯Ê¯È¼ÁÏÓÐú¡¢Ê¯ÓͺÍÌìÈ»Æø£¬ËüÃǶ¼ÊôÓÚ²»¿ÉÔÙÉú×ÊÔ´£®ÀûÓù¤ÒµÃº¿ÉÒÔÖƱ¸Ò»ÖÖÖØÒªµÄ»¯¹¤Ô­ÁÏ--ÒÒ¶þ´¼£¬Òò¾ßÓеͳɱ¾¡¢µÍÄܺġ¢µÍÅŷŵÈÌصã¶ø¾ßÓзdz£¹ãÀ«µÄÇ°¾°£¬¸ÃÖƱ¸¹ý³ÌÈçͼËùʾ£®»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÈçͼÊÇ¡°ÔìÆø¡±¹ý³ÌµÄ΢¹ÛʾÒâͼ£¬ÔòÖƱ¸ºÏ³ÉÆøµÄ»¯Ñ§·½³ÌʽΪC+H₂O$\frac{\underline{\;¸ßÎÂ\;}}{\;}$CO+H₂£®

£¨2£©ºÏ³ÉÆøÓл¹Ô­ÐÔ£¬¿ÉÓÃÓÚÒ±Á¶¸ÖÌú£®Çëд³öºÏ³ÉÆøÓëFe₂O₃·´Ó¦µÄÒ»¸ö»¯Ñ§·½³Ìʽ£º3H₂+2Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3H₂O£¬»ò3CO+Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3CO₂£®
£¨3£©´Óúֱ½Ó×÷ȼÁϵ½ÓÃúÖÆÈ¡ÒÒ¶þ´¼£¬ÄãµÃµ½µÄÆôʾÊÇ»¯Ñ§ÄÜÖ¸µ¼ÈËÀàºÏÀíÀûÓÃ×ÊÔ´£®

Answer 1

·ÖÎö ú¡¢Ê¯ÓͺÍÌìÈ»ÆøÊôÓÚ»¯Ê¯È¼ÁÏ£¬ÊDz»¿ÉÔÙÉúÄÜÔ´£»
¸ù¾Ý΢¹ÛÁ£×ÓʾÒâͼ¿ÉÒÔÅжϷ´Ó¦¹ý³Ì£»
ÇâÆøºÍÒ»Ñõ»¯Ì¼¶¼ÊǾßÓл¹Ô­ÐÔµÄÆøÌ壬¸ßÎÂÌõ¼þÏ£¬ÇâÆøºÍÑõ»¯Ìú·´Ó¦Éú³ÉÌúºÍË®£¬Ò»Ñõ»¯Ì¼ºÍÑõ»¯Ìú·´Ó¦Éú³ÉÌúºÍ¶þÑõ»¯Ì¼£®

½â´ð ½â£ºÄ¿Ç°£¬»¯Ê¯È¼ÁÏÓÐú¡¢Ê¯ÓͺÍÌìÈ»Æø£¬ËüÃǶ¼ÊôÓÚ²»¿ÉÔÙÉú×ÊÔ´£®
¹ÊÌʯÓÍ£®
£¨1£©ÈçͼÊÇ¡°ÔìÆø¡±¹ý³ÌµÄ΢¹ÛʾÒâͼ£¬ÓÉ´Ë¿ÉÖª£¬¸ßÎÂÌõ¼þÏ£¬Ì¼ºÍË®ÕôÆø·´Ó¦Éú³ÉÁËÒ»Ñõ»¯Ì¼ºÍÇâÆø£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºC+H₂O$\frac{\underline{\;¸ßÎÂ\;}}{\;}$CO+H₂£®
¹ÊÌC+H₂O$\frac{\underline{\;¸ßÎÂ\;}}{\;}$CO+H₂£®
£¨2£©ÇâÆø¡¢Ò»Ñõ»¯Ì¼ÓëFe₂O₃·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º3H₂+2Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3H₂O£¬3CO+Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3CO₂£®
¹ÊÌ3H₂+2Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3H₂O£¬»ò3CO+Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3CO₂£®
£¨3£©´Óúֱ½Ó×÷ȼÁϵ½ÓÃúÖÆÈ¡ÒÒ¶þ´¼£¬ÄãµÃµ½µÄÆôʾÊÇ»¯Ñ§ÄÜÖ¸µ¼ÈËÀàºÏÀíÀûÓÃ×ÊÔ´£®
¹ÊÌ»¯Ñ§ÄÜÖ¸µ¼ÈËÀàºÏÀíÀûÓÃ×ÊÔ´£®

µãÆÀ »¯Ê¯È¼ÁϵÄȼÉÕÄܹ»²úÉú´óÁ¿µÄ¶þÑõ»¯Áò¡¢µªÑõ»¯ÎÕâЩÎïÖÊÊÇÐγÉËáÓêµÄÖØÒªÎïÖÊ£¬Òò´Ë¼õÉÙ»¯Ê¯È¼ÁϵÄʹÓã¬×ÛºÏÀûÓû¯Ê¯È¼ÁÏÓÐÀûÓÚ¼õÉÙËáÓêµÄ²úÉú£®