ijÖÖÑõ»¯Í­ÑùÆ·ÖлìÓÐÉÙÁ¿Ä¾Ì¿·Û£¬Îª²â¶¨¸ÃÑùÆ·ÖÐÑõ»¯Í­µÄÖÊÁ¿·ÖÊý£¬Ä³Í¬Ñ§Éè¼ÆÁËÈçÏÂ×°ÖýøÐÐʵÑ飨N2²»²Î¼Ó·´Ó¦£¬²»¿¼ÂÇÍâ½ç¿ÕÆø¶ÔʵÑéµÄÓ°Ï죩¡£

¢Ù ¸ÃʵÑéÐèÒª²â¶¨µÄÁ¿£º·´Ó¦Ç°ºó×°ÖâòµÄÖÊÁ¿ºÍ £¨9£© µÄÖÊÁ¿

¢Ú ³ä·Ö·´Ó¦ºó£¬×°ÖâòµÄÖÊÁ¿Ôö¼ÓÁË0.44 g£¬ÔòÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÎïÖʵÄÁ¿ÊÇ £¨10£© mol¡£Çó²Î¼Ó·´Ó¦µÄÇâÑõ»¯ÄƵÄÎïÖʵÄÁ¿¡££¨Çë¸ù¾Ý»¯Ñ§·½³ÌʽÁÐʽ¼ÆË㣩  £¨11£©  

¢Û Ϊ´ïµ½ÊµÑéÄ¿µÄ£¬¶Ô·´Ó¦Ç°ÇâÑõ»¯ÄÆÈÜÒºÖÐÈÜÖÊÖÊÁ¿µÄÒªÇóÊÇ £¨12£© g¡£

¢Ü ¹ØÓÚ¸ÃʵÑéµÄÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨13£© ¡£
A£®µ±ºÚÉ«·ÛÄ©È«²¿±äΪ¹âÁÁºìɫʱ·½¿ÉÍ£Ö¹¼ÓÈÈ
B£®ÊµÑé½áÊøʱÏÈϨÃð¾Æ¾«ÅçµÆ»áµ¼Ö¢òÖÐÒºÌåµ¹Á÷Èë¢ñÖÐ
C£®Ö»³ÆÁ¿·´Ó¦Ç°ºó×°ÖâñÖйÌÌåÖÊÁ¿Ò²¿É´ïµ½ÊµÑéÄ¿µÄ
D£®ÓÃÑõÆø´úÌ浪ÆøÍê³ÉʵÑéÒ²¿É´ïµ½ÊµÑéÄ¿µÄ


£¨9£©·ÅÈë¢ñÖеÄÑùÆ·                      £¨10£©0.01
£¨11£©½â£ºÉè²Î¼Ó·´Ó¦µÄÇâÑõ»¯ÄƵÄΪx mol

                 CO2 + 2NaOHNa2CO3 + H2O     £¨1·Ö£©
1       2

0.01    x

                    £¨1·Ö£©

x=0.02£¨mol£©                  £¨1·Ö£©

£¨12£©¡Ý0.8g
£¨13£©CD£¨2·Ö£¬Â©Ñ¡µÃ1·Ö£¬¶àÑ¡»ò´íÑ¡µÃ0·Ö£©£»


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


СÃ÷ÊǸö°®Ñ§Ï°µÄѧÉú£¬Ñ§ÁË»¯Ñ§ºóËûÊáÀíÁËÒÔÏÂ֪ʶ£ºÆäÖÐÕýÈ·µÄÊÇ

¢Ù¼ÓÈÈÖó·Ð¿ÉÒÔ½µµÍ¾®Ë®µÄÓ²¶È£»

¢ÚijÁ£×ӵĽṹʾÒâͼΪ¸ÃÁ£×ÓÒ»¶¨ÊÇÄÊÔ­×Ó£»

¢ÛΪ̽¾¿Ì¼ËáÇâ淋ÄÈÈÎȶ¨ÐÔ£¬½«Ëü½øÐеãȼʵÑ飻

¢Ü½øÈëÈܶ´ÏÈÒª×öµÆ»ðÊÔÑ飬ÒòΪ¶þÑõ»¯Ì¼¾ßÓж¾ÐÔ£»

¢ÝΪ¹Û²ì½ðÊôþµÄÑÕÉ«£¬ÓÃÉ°Ö½´òĥþÌõ£»

¢ÞµÎÆ¿ÉϵĵιÜʹÓùýºó²»ÐèÇåÏ´£¬Ö±½Ó·Å»ØÔ­Æ¿¡£

A£®¢Ù¢Ú¢Ý     B£®¢Ù¢Ý¢Þ   C£®¢Ú¢Û¢Ý   D£®¢Ù¢Ü¢Ý

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


Å̽õÊÇÃÀÀöµÄÑغ£³ÇÊУ¬º£Ë®×ÊÔ´·á¸»¡£º£Ë®É¹ÑοÉÒԵõ½´ÖÑΣ¬´ÖÑÎÖк¬

ÓÐÄàɳµÈ²»ÈÜÐÔÔÓÖÊ£¬¿ÉÄܺ¬MgCl2¡¢CaCl2ºÍNa2SO4µÈ¿ÉÈÜÐÔÔÓÖÊ£¬Ä³Í¬Ñ§Éè¼Æ

ÈçÏÂʵÑé·½°¸Ìá´¿´ÖÑΣ¬Í¬Ê±ÑéÖ¤¿ÉÈÜÐÔÔÓÖÊÊÇ·ñ´æÔÚ¡£

                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                             

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©²Ù×÷¢òµÄÃû³ÆÊÇ             £¬²Ù×÷¢ñ~¢ôÖоùÓõ½Ò»ÖÖ²£Á§ÒÇÆ÷£¬¸ÃÒÇÆ÷

ÔÚ²Ù×÷¢ôÖÐ×÷ÓÃÊÇ                                                 ¡£

£¨2£©ÓÉʵÑé¿ÉÒԵóö£¬¸Ã´ÖÑÎÖÐÒ»¶¨²»º¬µÄ¿ÉÈÜÐÔÔÓÖÊÊÇ                   ¡£

£¨3£©¾­·ÖÎö£¬³ÁµíbÖÐÒ»¶¨º¬ÓеÄÎïÖÊÊÇ                                 ¡£

£¨4£©ÔÚÌá´¿¹ý³ÌÖУ¬¼ÓÊÊÁ¿Ï¡ÑÎËáµÄÄ¿µÄÊÇ                               ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁÐÎïÖʵÄË×ÃûÓ뻯ѧʽһÖµÄÊÇ
A£®´¿¼îNaOH     B£®Êìʯ»Ò CaO     C£®¸É±ùH2O         D£®Ê³ÑÎNaCl

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ijÎÞÉ«»ìºÏÆøÌå¿ÉÄÜÓÉCH4¡¢H2¡¢CO¡¢CO2ºÍH2OÖеÄij¼¸ÖÖÆøÌå×é³É¡£ÎªÈ·¶¨Æä³É·ÖÒÀ´Î½øÐÐÁËÈçÏÂʵÑ飨¼ÙÉèÿһ²½·´Ó¦¾ùÍêÈ«£©¡£¢Ùͨ¹ý³ÎÇåʯ»ÒË®£¬ÈÜÒº±ä»ë×Ç£»¢Úͨ¹ýÇâÑõ»¯ÄƹÌÌ壬ÖÊÁ¿Ôö¼Ó£»¢ÛÔÚO2Öеãȼ£¬È¼ÉÕ²úÎïÄÜʹ°×É«CuSO4·ÛÄ©±äΪÀ¶É«¡£ÔòÔ­»ìºÏÆøÌåµÄ³É·Ý²»¿ÉÄÜÊÇ
A£®CO2¡¢H2O¡¢CH4            B£®CO2¡¢H2O¡¢H2
C£®CO2¡¢H2O¡¢CO                      D£®CO2¡¢CO¡¢CH4

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔÚ1¸öH2SO4·Ö×ÓºÍ1¸öH3PO4·Ö×ÓÖУ¬²»ÕýÈ·µÄÊÇ(    )

A.ÑõµÄÖÊÁ¿·ÖÊýÒ»Ñù     B.ÑõÔ­×Ó¸öÊýÒ»Ñù¶à

C.ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Ò»Ñù   D.ÁòÔªËغÍÁ×ÔªËصĸöÊýÒ»Ñù¶à

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔÚ»¯Ñ§ÊÀ½çÀïûÓÐÉúÃüµÄ°¢À­²®Êý×ÖÒ²±äµÃÏÊ»îÆðÀ´£¬ËüÃÇÔÚ²»Í¬µÄλÖñíʾ×Ų»Í¬µÄº¬Òå¡£ÏÂÁл¯Ñ§·ûºÅÖÐÊý×Ö¡°2¡±±íʾµÄÒâÒåÕýÈ·µÄÊÇ£¨        £©

  A¡¢Mg2+£ºÒ»¸öþÀë×Ó´ø2¸öµ¥Î»ÕýµçºÉ    B¡¢CO2£º¶þÑõ»¯Ì¼·Ö×ÓÖк¬ÓÐÑõÔ­×Ó

  C¡¢2H£º2¸öÇâÔªËØ                      D¡¢£ºÑõ»¯¸ÆµÄ»¯ºÏ¼ÛΪ+2¼Û

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

¡¡  A.ȼÉÕÊÇÈËÀà×îÔçÀûÓõĻ¯Ñ§·´Ó¦Ö®Ò»

¡¡  B.¿ÉȼÎïζȴﵽ×Å»ðµã¼´¿ÉȼÉÕ

¡¡  C.ͼÊéµµ°¸Æð»ðÒËÓÃË®»ùÐÍÃð»ðÆ÷ÆËÃð

¡¡  D.²»É÷Åöµ¹Á˾ƾ«µÆ£¬¾Æ¾«ÔÚ×ÀÃæȼÉÕ£¬ÓÃË®À´Ãð»ð

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ʵÑéÊÒÓÃÏõËá¼Ø¹ÌÌåÅäÖÆ100.0 gÈÜÖÊÖÊÁ¿·ÖÊýΪ3.0%µÄÏõËá¼ØÈÜÒº£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨   £©

A£®ÓÃ50mLÁ¿Í²Á¿Ë®

B£®½«¹ÌÌå·ÅÓÚÍÐÅÌÌìƽµÄÓÒÅ̳ÆÈ¡

C£®½«¹ÌÌåÖ±½ÓͶÈËͯͲÖÐÈܽâ

D£®½«ÅäºÃµÄÈÜҺװÈËÌùÓбêÇ©£¨Èçͼ4£©µÄÊÔ¼ÁÆ¿ÖУ¬ÈûºÃÆ¿Èû

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸