É̵êÃÅÅÆÉÏ×°äêµÄö̽ð´ó×Ö£¬½ð¹â²ÓÀã¬Ëƽð·Ç½ð£¬²»ÉÙÊÇÓÉ»ÆÍ­ÖÊÁÏ×öµÄ£®ÎÒ¹ú¹Å´úÄϱ±³¯Ê±ÆÚ¾ÍÄÜÖýÔì»ÆÍ­£®»ÆÍ­ÊÇÍ­ºÍпµÄºÏ½ð£¬Ëü¿ÉÓÃÀ´ÖÆÔì»úÆ÷¡¢µç×ÓÁã¼þ¼°ÈÕ³£ÓÃÆ·£®ÎªÁ˲ⶨij»ÆÍ­ÑùÆ·ÖÐÍ­µÄÖÊÁ¿·ÖÊý£¬È¡20g¸Ã»ÆÍ­ÑùÆ·¼Óµ½50gÏ¡ÁòËáÖУ¬Ç¡ºÃÍêÈ«·´Ó¦£¬²úÉúÇâÆø0.2g£®ÆäÖÐÍ­ÊDz»ÓëÏ¡ÁòËá·¢Éú·´Ó¦µÄ£®ÊÔÇó£º
£¨1£©¸Ã»ÆÍ­ÑùÆ·ÖÐÍ­µÄÖÊÁ¿·ÖÊý£»
£¨2£©Ï¡ÁòËáÈÜÒºÖÐÁòËáµÄÖÊÁ¿·ÖÊý£®
¡¾´ð°¸¡¿·ÖÎö£º¸ù¾ÝÍ­²»ÓëÏ¡ÁòËá·¢Éú·´Ó¦£¬Ôò²úÉúÇâÆø0.2gÊÇ»ÆÍ­ÖÐпÓëÏ¡ÁòËá·´Ó¦Éú³ÉµÄ£¬½«ÇâÆøµÄÖÊÁ¿´úÈ뻯ѧ·´Ó¦·½³Ìʽ¿É¼ÆËãпºÍÁòËáµÄÖÊÁ¿£®
½â´ð£º½â£º£¨1£©ÉèÇ¡ºÃÍêÈ«·´Ó¦Ê±»ÆÍ­ÖÐпµÄÖÊÁ¿Îªxg£¬ÁòËáÖÊÁ¿Îªyg£¬
 ÔòZn+H2SO4=ZnSO4+H2¡ü
   65  98         2
    x   y         0.2g
£¬
½âµÃx=6.5g£¬y=9.8g
Ôò¦Ø£¨Cu£©%=£¬
´ð£º¸Ã»ÆÍ­ÑùÆ·ÖÐÍ­µÄÖÊÁ¿·ÖÊýΪ67.5%£»
£¨2£©ÓÉ50gÏ¡ÁòËáÖк¬ÓÐÁòËá9.8g£¬Ôò
¦Ø£¨H2SO4£©%=£¬
´ð£ºÏ¡ÁòËáÈÜÒºÖÐÁòËáµÄÖÊÁ¿·ÖÊýΪ19.6%£®
µãÆÀ£º±¾Ìâ½Ï¼òµ¥£¬¿¼²éѧÉúÀûÓû¯Ñ§·´Ó¦·½³ÌʽµÄ¼ÆË㣬½«ÇâÆøµÄÖÊÁ¿Ö±½Ó´úÈëпÓëÁòËá·´Ó¦µÄ·½³ÌʽÖм´¿ÉÒ»Ò»½â´ð£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

É̵êÃÅÅÆÉÏ×°äêµÄö̽ð´ó×Ö£¬½ð¹â²ÓÀã¬Ëƽð·Ç½ð£¬²»ÉÙÊÇÓÉ»ÆÍ­ÖÊÁÏ×öµÄ£®ÎÒ¹ú¹Å´úÄϱ±³¯Ê±ÆÚ¾ÍÄÜÖýÔì»ÆÍ­£®»ÆÍ­ÊÇÍ­ºÍпµÄºÏ½ð£¬Ëü¿ÉÓÃÀ´ÖÆÔì»úÆ÷¡¢µç×ÓÁã¼þ¼°ÈÕ³£ÓÃÆ·£®ÎªÁ˲ⶨij»ÆÍ­ÑùÆ·ÖÐÍ­µÄÖÊÁ¿·ÖÊý£¬È¡20g¸Ã»ÆÍ­ÑùÆ·¼Óµ½50gÏ¡ÁòËáÖУ¬Ç¡ºÃÍêÈ«·´Ó¦£¬²úÉúÇâÆø0.2g£®ÆäÖÐÍ­ÊDz»ÓëÏ¡ÁòËá·¢Éú·´Ó¦µÄ£®ÊÔÇó£º
£¨1£©¸Ã»ÆÍ­ÑùÆ·ÖÐÍ­µÄÖÊÁ¿·ÖÊý£»
£¨2£©Ï¡ÁòËáÈÜÒºÖÐÁòËáµÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

É̵êÃÅÅÆÉÏ×°äêµÄö̽ð´ó×Ö£¬½ð¹â²ÓÀã¬Ëƽð·Ç½ð£¬²»ÉÙÊÇÓÉ»ÆÍ­ÖÊÁÏ×öµÄ£®ÎÒ¹ú¹Å´úÄϱ±³¯Ê±ÆÚ¾ÍÄÜÖýÔì»ÆÍ­£®»ÆÍ­ÊÇÍ­ºÍпµÄºÏ½ð£¬Ëü¿ÉÓÃÀ´ÖÆÔì»úÆ÷¡¢µç×ÓÁã¼þ¼°ÈÕ³£ÓÃÆ·£®ÎªÁ˲ⶨij»ÆÍ­ÑùÆ·ÖÐÍ­µÄÖÊÁ¿·ÖÊý£¬È¡20g¸Ã»ÆÍ­ÑùÆ·¼Óµ½50gÏ¡ÁòËáÖУ¬Ç¡ºÃÍêÈ«·´Ó¦£¬²úÉúÇâÆø0.2g£®ÆäÖÐÍ­ÊDz»ÓëÏ¡ÁòËá·¢Éú·´Ó¦µÄ£®ÊÔÇó£º
£¨1£©¸Ã»ÆÍ­ÑùÆ·ÖÐÍ­µÄÖÊÁ¿·ÖÊý£»
£¨2£©Ï¡ÁòËáÈÜÒºÖÐÁòËáµÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÎÊ´ðÌâ

É̵êÃÅÅÆÉÏ×°äêµÄö̽ð´ó×Ö£¬½ð¹â²ÓÀã¬Ëƽð·Ç½ð£¬²»ÉÙÊÇÓÉ»ÆÍ­ÖÊÁÏ×öµÄ£®ÎÒ¹ú¹Å´úÄϱ±³¯Ê±ÆÚ¾ÍÄÜÖýÔì»ÆÍ­£®»ÆÍ­ÊÇÍ­ºÍпµÄºÏ½ð£¬Ëü¿ÉÓÃÀ´ÖÆÔì»úÆ÷¡¢µç×ÓÁã¼þ¼°ÈÕ³£ÓÃÆ·£®ÎªÁ˲ⶨij»ÆÍ­ÑùÆ·ÖÐÍ­µÄÖÊÁ¿·ÖÊý£¬È¡20g¸Ã»ÆÍ­ÑùÆ·¼Óµ½50gÏ¡ÁòËáÖУ¬Ç¡ºÃÍêÈ«·´Ó¦£¬²úÉúÇâÆø0.2g£®ÆäÖÐÍ­ÊDz»ÓëÏ¡ÁòËá·¢Éú·´Ó¦µÄ£®ÊÔÇó£º
£¨1£©¸Ã»ÆÍ­ÑùÆ·ÖÐÍ­µÄÖÊÁ¿·ÖÊý£»
£¨2£©Ï¡ÁòËáÈÜÒºÖÐÁòËáµÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2005ÄêÕã½­Ê¡º¼ÖÝÊÐʵÑéÍâ¹úÓïѧУÕÐÉú¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

É̵êÃÅÅÆÉÏ×°äêµÄö̽ð´ó×Ö£¬½ð¹â²ÓÀã¬Ëƽð·Ç½ð£¬²»ÉÙÊÇÓÉ»ÆÍ­ÖÊÁÏ×öµÄ£®ÎÒ¹ú¹Å´úÄϱ±³¯Ê±ÆÚ¾ÍÄÜÖýÔì»ÆÍ­£®»ÆÍ­ÊÇÍ­ºÍпµÄºÏ½ð£¬Ëü¿ÉÓÃÀ´ÖÆÔì»úÆ÷¡¢µç×ÓÁã¼þ¼°ÈÕ³£ÓÃÆ·£®ÎªÁ˲ⶨij»ÆÍ­ÑùÆ·ÖÐÍ­µÄÖÊÁ¿·ÖÊý£¬È¡20g¸Ã»ÆÍ­ÑùÆ·¼Óµ½50gÏ¡ÁòËáÖУ¬Ç¡ºÃÍêÈ«·´Ó¦£¬²úÉúÇâÆø0.2g£®ÆäÖÐÍ­ÊDz»ÓëÏ¡ÁòËá·¢Éú·´Ó¦µÄ£®ÊÔÇó£º
£¨1£©¸Ã»ÆÍ­ÑùÆ·ÖÐÍ­µÄÖÊÁ¿·ÖÊý£»
£¨2£©Ï¡ÁòËáÈÜÒºÖÐÁòËáµÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸