СÁá¼Ò¹ºÂòÁËһƿ°×´×£¬±êÇ©ÉÏ×¢Ã÷´×ËáµÄÖÊÁ¿·ÖÊý¡Ý5%£®Ð¡ÁáÏ룺ÕâÆ¿°×´×Öд×ËáµÄº¬Á¿ÊÇ·ñÓë±ê×¢Ïà·û£¿ÇëÄãºÍСÁáÒ»ÆðÓÃËá¼îµÄ֪ʶÀ´²â¶¨°×´×Öд×ËáµÄº¬Á¿£®
[ʵÑéÔÀí]´×ËáÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£ºCH3COOH+NaOH¨TCH3COONa+H2O
[ʵÑé¹ý³Ì]½«40mLÈÜÖÊÖÊÁ¿·ÖÊýΪ1%µÄÇâÑõ»¯ÄÆÈÜÒº£¨ÃܶȽüËÆΪ1.0g/mL£©£¬ÖðµÎ¼Óµ½12mL°×´×£¨ÃܶȽüËÆΪ1.0g/mL£©ÖУ¬Ç¡ºÃÍêÈ«Öкͣ®
[½»Á÷·´Ë¼]ÔÚʵÑéÖÐÈç¹ûÊ¢°×´×µÄÉÕ±ÖÐÊÂÏȲÐÁôÓÐÕôÁóË®£¬¶ÔʵÑé½á¹ûÓÐÎÞÓ°Ï죿Ϊʲô£¿
[Êý¾Ý´¦Àí]¸ù¾ÝʵÑéÊý¾Ý£¬Í¨¹ý¼ÆËãÅжϰ״×Öд×ËáµÄº¬Á¿ÊÇ·ñÓë±êÇ©µÄ±ê×¢Ïà·û£¿
½â£º[½»Á÷Ó뷴˼]²â¶¨°×´×Öд×ËáµÄº¬Á¿ÊÇÀûÓô×ËáÓëÇâÑõ»¯ÄÆ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£¬ÓÉ·´Ó¦ÏûºÄÇâÑõ»¯ÄƵÄÖÊÁ¿¼ÆËã´×ËáµÄÖÊÁ¿£¬Óë´×ËáÈÜÒºµÄÖÊÁ¿·ÖÊýÎ޹أ»¶øÉÕ±ÖвÐÁôµÄÕôÁóˮֻ»áʹ´×ËáµÄÖÊÁ¿·ÖÊý¼õС£¬²»»áÓ°Ïì´×ËáµÄÖÊÁ¿£¬Òò´Ë£¬²ÐÁôµÄÕôÁóË®Óë²â¶¨°×´×Öд×ËáÖÊÁ¿Î޹أ»
¹Ê´ð°¸Îª£ºÎÞÓ°Ï죻ÉÕ±ÖÐÓÐˮֻÊǽ«ÈÜҺϡÊÍ£¬µ«ÈÜÖʵÄÖÊÁ¿²»»á¸Ä±ä£»
[Êý¾Ý´¦Àí]
40mLÈÜÖÊÖÊÁ¿·ÖÊýΪ1%µÄÇâÑõ»¯ÄÆÈÜÒºÖÐÇâÑõ»¯ÄƵÄÖÊÁ¿=40mL¡Á1.0g/mL¡Á1%=0.4g£»
Éè²Î¼Ó·´Ó¦µÄ´×ËáµÄÖÊÁ¿Îªx
CH
3COOH+NaOH¨TCH
3COONa+H
2O
60 40
x 0.4g
x=0.6g
°×´×Öд×ËáµÄº¬Á¿=
=5%£¬Óë±êÇ©µÄ±ê×¢Ïà·û£®
´ð£º°×´×Öд×ËáµÄº¬Á¿Óë±êÇ©µÄ±ê×¢Ïà·û£®
·ÖÎö£º[½»Á÷Ó뷴˼]ʵÑéÖÐÈç¹ûÊ¢°×´×µÄÉÕ±ÖÐÊÂÏȲÐÁôÓÐÕôÁóË®£¬»áʹ´×ËáÒò¼ÓË®¶øÏ¡ÊÍ£¬µ«Ï¡ÊÍÇ°ºóÈÜÖÊ´×ËáµÄÖÊÁ¿²»±ä£¬¶Ô·´Ó¦ÏûºÄÇâÑõ»¯ÄƵÄÖÊÁ¿Ã»ÓÐÓ°Ï죻
[Êý¾Ý´¦Àí]°×´×Öд×ËáµÄº¬Á¿=
£¬ÀûÓÃËùÇóµÃ´×ËáµÄº¬Á¿Óë±êÇ©ÖеÄ5%Ïà±È¶Ô£¬Òò´Ë£¬ÐèÒª¸ù¾Ý·´Ó¦µÄ»¯Ñ§·½³Ìʽ¼ÆËã³ö´×ËáµÄÖÊÁ¿£®
µãÆÀ£º¸ù¾Ý»¯Ñ§·½³ÌʽµÄ¼ÆËãʱ£¬´úÈ뻯ѧ·½³ÌʽµÄÖÊÁ¿Ó¦Îª´¿¾»ÎïµÄÖÊÁ¿£¬¶ø²»ÄÜ°ÑÈÜÒºµÄÖÊÁ¿Ö±½Ó´úÈë·´Ó¦½øÐмÆË㣮
¿ÆÄ¿£º³õÖл¯Ñ§
À´Ô´£º2009Äê½ËÕÊ¡ÑγÇÊÐÑζ¼ÇøÖп¼»¯Ñ§¶þÄ£ÊÔ¾í£¨½âÎö°æ£©
ÌâÐÍ£º½â´ðÌâ
СÁá¼Ò¹ºÂòÁËһƿ°×´×£¬±êÇ©ÉÏ×¢Ã÷´×ËáµÄÖÊÁ¿·ÖÊý¡Ý5%£®Ð¡ÁáÏ룺ÕâÆ¿°×´×Öд×ËáµÄº¬Á¿ÊÇ·ñÓë±ê×¢Ïà·û£¿ÇëÄãºÍСÁáÒ»ÆðÓÃËá¼îµÄ֪ʶÀ´²â¶¨°×´×Öд×ËáµÄº¬Á¿£®
[ʵÑéÔÀí]´×ËáÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£ºCH3COOH+NaOH¨TCH3COONa+H2O
[ʵÑé¹ý³Ì]½«40mLÈÜÖÊÖÊÁ¿·ÖÊýΪ1%µÄÇâÑõ»¯ÄÆÈÜÒº£¨ÃܶȽüËÆΪ1.0g/mL£©£¬ÖðµÎ¼Óµ½12mL°×´×£¨ÃܶȽüËÆΪ1.0g/mL£©ÖУ¬Ç¡ºÃÍêÈ«Öкͣ®
[½»Á÷·´Ë¼]ÔÚʵÑéÖÐÈç¹ûÊ¢°×´×µÄÉÕ±ÖÐÊÂÏȲÐÁôÓÐÕôÁóË®£¬¶ÔʵÑé½á¹ûÓÐÎÞÓ°Ï죿Ϊʲô£¿
[Êý¾Ý´¦Àí]¸ù¾ÝʵÑéÊý¾Ý£¬Í¨¹ý¼ÆËãÅжϰ״×Öд×ËáµÄº¬Á¿ÊÇ·ñÓë±êÇ©µÄ±ê×¢Ïà·û£¿
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§
À´Ô´£º2010-2011ѧÄê¸ßÒ»ÐÂÉú·Ö°à¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨8Ô·ݣ©£¨½âÎö°æ£©
ÌâÐÍ£º½â´ðÌâ
£¨2007?ÉÛÑô£©Ð¡Áá¼Ò¹ºÂòÁËһƿ°×´×£¬±êÇ©ÉÏ×¢Ã÷´×ËáµÄÖÊÁ¿·ÖÊý¡Ý5%£®Ð¡ÁáÏ룺ÕâÆ¿°×´×Öд×ËáµÄº¬Á¿ÊÇ·ñÓë±ê×¢Ïà·û£¿ÇëÄãºÍСÁáÒ»ÆðÓÃËá¼îµÄ֪ʶÀ´²â¶¨°×´×Öд×ËáµÄº¬Á¿£®
[ʵÑéÔÀí]´×ËáÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£ºCH3COOH+NaOH¨TCH3COONa+H2O
[ʵÑé¹ý³Ì]½«40mLÈÜÖÊÖÊÁ¿·ÖÊýΪ1%µÄÇâÑõ»¯ÄÆÈÜÒº£¨ÃܶȽüËÆΪ1.0g/mL£©£¬ÖðµÎ¼Óµ½12mL°×´×£¨ÃܶȽüËÆΪ1.0g/mL£©ÖУ¬Ç¡ºÃÍêÈ«Öкͣ®
[½»Á÷·´Ë¼]ÔÚʵÑéÖÐÈç¹ûÊ¢°×´×µÄÉÕ±ÖÐÊÂÏȲÐÁôÓÐÕôÁóË®£¬¶ÔʵÑé½á¹ûÓÐÎÞÓ°Ï죿Ϊʲô£¿
[Êý¾Ý´¦Àí]¸ù¾ÝʵÑéÊý¾Ý£¬Í¨¹ý¼ÆËãÅжϰ״×Öд×ËáµÄº¬Á¿ÊÇ·ñÓë±êÇ©µÄ±ê×¢Ïà·û£¿
²é¿´´ð°¸ºÍ½âÎö>>