ʵÑéÐòºÅ | a | b | c |
ºÏ½ðÖÊÁ¿/mg | 510 | 765 | 918 |
ÆøÌåÌå»ý/mL | 560 | 672 | 672 |
·ÖÎö £¨1£©¸ù¾Ý·¢ÉúµÄ»¯Ñ§·´Ó¦£¬2Al+2NaOH+2H2O¨T2NaAlO2+3H2¡ü£¬NaAlO2+CO2+2H2O=NaHCO3+Al£¨OH£©3¡ý£¬2Al£¨OH£©3$\frac{\underline{\;\;¡÷\;\;}}{\;}$Al2O3+3H2O£¬×îºóµÃµ½µÄ¹ÌÌåÊÇÑõ»¯ÂÁ£¬ÖÊÁ¿²»±ä£¬ËµÃ÷Ñõ»¯ÂÁÖÐÑõÔªËصÄÖÊÁ¿·ÖÊýµÈÓÚþԪËصÄÖÊÁ¿·ÖÊý£»
£¨2£©¸ù¾Ý±í¸ñÌṩµÄÊý¾ÝÅжÏÑÎËá·´Ó¦µÄÁ¿£¬ÔÙ½øÐмÆË㣮
½â´ð ½â£º£¨1£©2Al+2NaOH+2H2O¨T2NaAlO2+3H2¡ü£¬NaAlO2+CO2+2H2O=NaHCO3+Al£¨OH£©3¡ý£¬2Al£¨OH£©3$\frac{\underline{\;\;¡÷\;\;}}{\;}$Al2O3+3H2O£¬×îºóµÃµ½µÄ¹ÌÌåÊÇÑõ»¯ÂÁ£¬ÖÊÁ¿²»±ä£¬ËµÃ÷Ñõ»¯ÂÁÖÐÑõÔªËصÄÖÊÁ¿·ÖÊýµÈÓÚþԪËصÄÖÊÁ¿·ÖÊý£¬¼´ÂÁÔªËصÄÖÊÁ¿·ÖÊý¾ÍÊÇÑõ»¯ÂÁÖÐÂÁÔªËصÄÖÊÁ¿·ÖÊý£¬$\frac{27¡Á2}{27¡Á2+16¡Á3}¡Á100%$¡Ö52.9%£»
£¨2¸ù¾Ý±í¸ñ¿ÉÒÔ¿´³ö£¬µÚÒ»´ÎµÄºÏ½ðÈ«²¿²Î¼Ó·´Ó¦£¬Éú³ÉµÄÇâÆøµÄÖÊÁ¿Îª£º0.56L¡Á0.0893g/L¡Ö0.05g
ÉèþµÄÖÊÁ¿Îªx£¬Éú³ÉµÄÇâÆøµÄÖÊÁ¿Îªa£¬ÔòÂÁµÄÖÊÁ¿Îª0.51g-x£¬Éú³ÉµÄÇâÆøµÄÖÊÁ¿Îª0.05g-a
Mg+2HCl¨TMgCl2+H2¡ü
24 2
x a
$\frac{24}{x}=\frac{2}{a}$
2Al+6HCl¨T2AlCl3+3H2¡ü
54 6
0.51g-x 0.05g-a
$\frac{54}{0.51g-x}=\frac{6}{0.05g-a}$
½âµÃx=0.24g£¬
¹ÊÂÁµÄÖÊÁ¿Îª0.51g-0.24g=0.27g
¹ÊÂÁºÍþµÄÖÊÁ¿±ÈΪ£º0.27g£º0.24g=9£º8
´ð£ººÏ½ðÖÐÂÁþµÄÖÊÁ¿±ÈΪ9£º8£®
µãÆÀ ±¾ÌâÖ÷Òª¿¼²éѧÉúÔËÓû¯Ñ§·½³Ìʽ½øÐмÆËãºÍÍƶϵÄÄÜÁ¦£¬¼ÆËãʱҪעÒâ¹æ·¶ÐÔºÍ׼ȷÐÔ£®
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ÊÔ¹Ü | B£® | ÉÕ± | C£® | ÉÕÆ¿ | D£® | ׶ÐÎÆ¿ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
ÎïÖÊ | a | b | c | d |
·´Ó¦Ç°µÄÖÊÁ¿£¨g£© | 6.4 | 1.0 | 0.1 | 1.6 |
tʱ¿ÌµÄÖÊÁ¿£¨g£© | 3.2 | X | ||
·´Ó¦ºóµÄÖÊÁ¿£¨g£© | 0 | 5.4 | Y | 0 |
A£® | aºÍcÊÇ·´Ó¦Îï | |
B£® | X=2g | |
C£® | ¸Ã·´Ó¦ÊÇ»¯ºÏÎï | |
D£® | ¸Ã·´Ó¦»¯Ñ§·½³ÌʽÖÐaºÍdµÄ»¯Ñ§¼ÆÁ¿ÊýÖ®±ÈΪ2£º1 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | Á¬½ÓÒÇÆ÷ | B£® | ¼ì²éÆøÃÜÐÔ | C£® | È¡ÓÃʯ»Òʯ | D£® | CO2ÑéÂú |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ´øµçºÉµÄÁ£×ÓÒ»¶¨ÊÇÀë×Ó | |
B£® | ·Ö×Ó¿É·ÖÔ×ÓÒ»¶¨²»¿É·Ö | |
C£® | ·Ö×ÓÒ»¶¨Äܱ£³ÖÎïÖʵĻ¯Ñ§ÐÔÖÊ | |
D£® | ÔªËصÄÖÖÀàÒ»¶¨ÓÉÔ×ÓµÄ×îÍâ²ãµç×ÓÊý¾ö¶¨ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ľ̿ÔÚÑõÆøÖÐȼÉÕ£¬Éú³É´Ì¼¤ÐÔÆøζµÄÆøÌå | |
B£® | ºìÁ×ÔÚ¿ÕÆøÖÐȼÉÕ²úÉú´óÁ¿µÄ°×Îí | |
C£® | ÌúË¿ÔÚÑõÆøÖоçÁÒȼÉÕ£¬»ðÐÇËÄÉ䣬Éú³ÉºÚÉ«¹ÌÌå | |
D£® | Ò»Ñõ»¯Ì¼»¹ÔÑõ»¯Íʱ£¬¹ÌÌåÎïÖʵÄÑÕÉ«ÓɺìÉ«±äΪºÚÉ« |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com