19£®ÐËȤС×éͬѧÔÚʵÑéÊÒ´¦Àí·ÏҺʱ£¬½«Ò»Æ¿ÒÑÓнá¿éµÄÊìʯ»ÒÈ¡Ñù£¬¼ÓÈ뺬ÓÐÑÎËáµÄ·ÏÒºÖУ¬·¢ÏÖ·ÏÒºÖвúÉú´óÁ¿µÄÆøÅÝ£®ËûÃǽøÒ»²½Á˽âÊìʯ»ÒÑùÆ·±äÖʵij̶ȽøÐÐÒÔÏÂ̽¾¿»î¶¯£®
¡¾Ì½¾¿»î¶¯Ò»¡¿¼ì²âÊìʯ»ÒÑùÆ·ÊÇ·ñÍêÈ«±äÖÊ
ʵÑé²Ù×÷ʵÑéÏÖÏóʵÑé½áÂÛ
È¡ÑùÓÚÊÔ¹ÜÖУ¬¼ÓË®Èܽ⣬ÍùÉϲãÈÜÒºÖеμÓÎÞÉ«·Ó̪ÈÜÒºÏÔºìÉ«±äÖʵÄÊìʯ»ÒÖÐÈÔº¬ÇâÑõ»¯¸Æ
¡¾Ì½¾¿»î¶¯¶þ¡¿²â¶¨±äÖʵÄÊìʯ»ÒÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýÀûÓÃÈçͼËùʾװÖúÍÊÔ¼Á½øÐÐʵÑ飨Ìú¼Ų̈ÂÔÈ¥£¬×°ÖÃÆøÃÜÐÔÁ¼ºÃ£¬ºöÂÔÑÎËáµÄ»Ó·¢ÐÔÇÒÿ²½·´Ó¦»ò×÷Óö¼ÊÇÍêÈ«µÄ£©£¬³ÆÈ¡5gµÄÑùÆ·£¬Í¨¹ý²â¶¨ÑùÆ·ºÍÏ¡ÑÎËá
·´Ó¦²úÉúµÄÆøÌåµÄÖÊÁ¿£¬¼ÆËã̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý£®

¡¾ÊµÑé²½Öè¡¿
¢Ù°´Í¼Á¬½Ó×°Ö㬲¢¼ì²é×°ÖõÄÆøÃÜÐÔ£»
¢ÚÈçͼÁ¬½Ó×°Ö㨳ýC¡¢DÍ⣩²¢¼ÓÈë5.00gµÄÑùÆ·£¨³ÆÁ¿Ê±Ê¹Óõç×ÓÌìƽ£©£»
¢Û³ÆÁ¿²¢¼Ç¼װÖÃCµÄ×ÜÖÊÁ¿Îª200.00g£¨³ÆÁ¿Ê±×¢Òâ·â±ÕCµÄÁ½¶Ë£©£»
¢Ü´ò¿ªµ¯»É¼ÐK£¬¹ÄÈëN2Ô¼1·ÖÖÓ£»
¢Ý½ÓÈë×°ÖÃC¡¢D£¬¹Ø±Õµ¯»É¼ÐK£¬×°ÖÃAÖмÓÈëÏ¡ÑÎËᣬÖÁ²»ÔÙ²úÉúÆøÅÝΪֹ£»
¢ÞÖظ´²½Öè¢Ü²Ù×÷£¬³ÆÁ¿£¬×°ÖÃCµÄÖÊÁ¿Îª200.88g£¨³ÆÁ¿Ê±×¢Òâ·â±ÕCµÄÁ½¶Ë£©£»
¢ß¼ÆË㣮
»Ø´ðÏÂÁÐÏà¹ØÎÊÌ⣺
£¨1£©Ð´³öAÖвúÉúÆøÌåµÄ·´Ó¦»¯Ñ§·½³ÌʽCaCO3+2HCl¨TCaCl2+H2O+CO2¡ü£®
£¨2£©×°ÖÃBÖÐŨÁòËáµÄ×÷ÓÃÊÇÎüÊÕË®·Ö£»ÒÑÖª¼îʯ»ÒµÄÖ÷Òª³É·ÖÊÇCaOºÍNaOH£¬Ôò×°ÖÃDµÄ×÷ÓÃÊÇ·ÀÖ¹¿ÕÆøÖеÄCO2½øÈëC×°ÖÃÖУ®
£¨3£©²½Öè¢ÝÖмÓÈëÏ¡ÑÎËᣬÖÁ²»ÔÙ²úÉúÆøÅÝΪֹ£¬ÆäÄ¿µÄÊÇʹµÃCaCO3ÍêÈ«·´Ó¦£»
£¨4£©²½Öè¢ÞÖÐ×°ÖÃCµÄÖÊÁ¿²»ÔÙÔö¼Ó£¬ËµÃ÷CO2±»NaOHÍêÈ«ÎüÊÕ£¬Ð´³ö×°ÖÃCÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ£ºCO2+2NaOH¨TNa2CO3+H2O£®
£¨5£©ÒÀÌâÒâ¿ÉµÃCO2ÆøÌåµÄÖÊÁ¿Îª0.88gg£¬ÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿Îª2gg£®²â¶¨±äÖʵÄÊìʯ»ÒÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý=40%£®
£¨6£©ÏÂÁвÙ×÷»áµ¼Ö²âÁ¿½á¹ûÆ«µÍµÄÊÇD£¨ÌîÐòºÅ£©£®
A£®Ê¡ÂÔ×°ÖÃB    B£®Ã»ÓнøÐв½Öè¢ÜµÄ²Ù×÷C£®¹ÄÈëN2ʱ¼ä½Ï³¤    D£®²½Öè¢ÞûÓÐÖظ´²½Öè¢ÜµÄ²Ù×÷£®

·ÖÎö ¡¾Ì½¾¿»î¶¯Ò»¡¿¿ÉÒÔÓ÷Ó̪ÊÔÒº¼ìÑéÊÇ·ñÓÐÇâÑõ»¯¸Æ£»ÓÃÏ¡ÑÎËá¼ìÑéÊÇ·ñÓÐ̼Ëá¸Æ£¬È»ºó¸ù¾ÝÏÖÏ󣬵óöÕýÈ·µÄ½áÂÛ£®
¡¾Ì½¾¿»î¶¯¶þ¡¿£¨1£©¸ù¾ÝÏ¡ÑÎËáÓë̼Ëá¸ÆµÄ·´Ó¦Ð´³ö·´Ó¦µÄ·½³Ìʽ£»
£¨2£©¸ù¾ÝŨÁòËáÓÐÎüË®ÐÔ£¬ÇâÑõ»¯ÄÆÄÜÎüÊÕ¶þÑõ»¯Ì¼·ÖÎö»Ø´ð£»
£¨3£©¸ù¾ÝÏ¡ÑÎËáÓë̼Ëá¸ÆµÄ·´Ó¦À´·ÖÎö£»
£¨4£©ÇâÑõ»¯ÄÆÈÜÒºÄÜÎüÊÕ¶þÑõ»¯Ì¼£¬Éú³É̼ËáÄƺÍË®£»
£¨5£©ÇâÑõ»¯ÄÆÈÜÒºÄÜÎüÊÕ¶þÑõ»¯Ì¼£¬×°ÖÃCµÄÖÊÁ¿±ä»¯¼´Îª¶þÑõ»¯Ì¼µÄÖÊÁ¿£¬¸ù¾Ý¶þÑõ»¯Ì¼µÄÖÊÁ¿½áºÏ·½³Ìʽ¼ÆË㣮
£¨6£©A¡¢×°ÖÃB»áʹAÖлӷ¢³öµÄË®ÕôÆøһͬ½øÈëC£»
B¡¢Ã»ÓнøÐв½Öè¢ÜµÄ²Ù×÷£¬»áʹװÖÃÖÐÔ­ÓеĶþÑõ»¯Ì¼±»CÎüÊÕ£»
C¡¢¹ÄÈëN2ʱ¼ä½Ï³¤£¬¶Ô½á¹ûÎÞÓ°Ï죻
D¡¢²½Öè¢ÞûÓÐÖظ´²½Öè¢ÜµÄ²Ù×÷£¬Éú³ÉµÄ¶þÑõ»¯Ì¼²¿·ÖÍ£ÁôÔÚABÖУ®

½â´ð ½â£º¡¾Ì½¾¿»î¶¯Ò»¡¿ÓÉÓÚÇâÑõ»¯¸ÆÄܹ»ºÍ¿ÕÆøÖеĶþÑõ»¯Ì¼·¢Éú·´Ó¦Éú³É̼Ëá¸Æ¶øµ¼Ö±äÖÊ£¬ÈôÍêÈ«±äÖÊÔòÖ»ÓÐ̼Ëá¸Æ£¬ÈôûÓбäÖÊÔòÖ»ÓÐÇâÑõ»¯¸Æ£¬Èô²¿·Ö±äÖÊÔòÓÐ̼Ëá¸ÆºÍÇâÑõ»¯¸Æ£¬ÓÉÓÚÇâÑõ»¯¸ÆÊǼî¶ø̼Ëá¸ÆÊÇ̼ËáÑΣ¬ÇâÑõ»¯¸ÆÈÜÒºÄÜʹ·Ó̪ÊÔÒº±äºì£¬
¡¾Ì½¾¿»î¶¯¶þ¡¿£¨1£©ÔÚ×°ÖÃAÖУ¬¼ÓÈëµÄÏ¡ÑÎËáÄÜÓë̼Ëá¸Æ·´Ó¦£¬·´Ó¦µÄ·½³ÌʽÊÇ£ºCaCO3+2HCl=CaCl2+H2O+CO2¡ü£»
£¨2£©ÓÉÓÚŨÁòËáÓÐÎüË®ÐÔ£¬ËùÒÔ×°ÖÃDµÄ¼îʯ»Ò¿ÉÒÔÎüÊÕ¿ÕÆøÖжþÑõ»¯Ì¼ÆøÌ壬·ÀÖ¹¿ÕÆøÖеÄCO2½øÈëC×°ÖÃÖжԲⶨ²úÉúÓ°Ï죻
£¨3£©¼ÓÈëÏ¡ÑÎËᣬÖÁ²»ÔÙ²úÉúÆøÅÝ£¬ËµÃ÷CaCO3ÍêÈ«·´Ó¦£»
£¨4£©ÇâÑõ»¯ÄÆÈÜÒºÄÜÎüÊÕ¶þÑõ»¯Ì¼£¬Éú³É̼ËáÄƺÍË®£¬×°ÖÃCµÄÖÊÁ¿²»ÔÙÔö¼Ó£¬ËµÃ÷CO2±»NaOHÍêÈ«ÎüÊÕ£¬»¯Ñ§·½³ÌʽΪ£ºCO2+2NaOH¨TNa2CO3+H2O£»
£¨5£©×°ÖÃCµÄÖÊÁ¿±ä»¯¼´Îª¶þÑõ»¯Ì¼µÄÖÊÁ¿£¬200.88g-200.00g=0.88g£¬
ÉèÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿Îªx
CaCO3+2HCl¨TCaCl2+H2O+CO2¡ü
100                  44
x                   0.88g
$\frac{100}{x}$=$\frac{44}{0.88g}$
x=2.00g
±äÖʵÄÊìʯ»ÒÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý$\frac{2.00g}{5.00g}$¡Á100%=40%
£¨6£©A¡¢×°ÖÃB»áʹAÖлӷ¢³öµÄË®ÕôÆøһͬ½øÈëC£¬Ê¹½á¹ûÆ«´ó£»
B¡¢Ã»ÓнøÐв½Öè¢ÜµÄ²Ù×÷£¬»áʹװÖÃÖÐÔ­ÓеĶþÑõ»¯Ì¼±»CÎüÊÕ£¬Ê¹½á¹ûÆ«´ó£»
C¡¢¹ÄÈëN2ʱ¼ä½Ï³¤£¬¶Ô½á¹ûÎÞÓ°Ï죻
D¡¢²½Öè¢ÞûÓÐÖظ´²½Öè¢ÜµÄ²Ù×÷£¬Éú³ÉµÄ¶þÑõ»¯Ì¼²¿·ÖÍ£ÁôÔÚABÖУ¬Ã»Óб»CÎüÊÕ£¬Ê¹½á¹ûƫС£®
¹Ê´ð°¸Îª£º¡¾Ì½¾¿»î¶¯Ò»¡¿

ʵÑé²Ù×÷ʵÑéÏÖÏóʵÑé½áÂÛ
È¡ÑùÓÚÊÔ¹ÜÖУ¬¼ÓË®Èܽ⣬ÍùÉϲãÈÜÒºÖеμÓÎÞÉ«·Ó̪ÈÜÒºÏÔºìÉ«±äÖʵÄÊìʯ»ÒÖÐÈÔº¬ÇâÑõ»¯¸Æ
¡¾Ì½¾¿»î¶¯¶þ¡¿
£¨1£©CaCO3+2HCl¨TCaCl2+H2O+CO2¡ü
£¨2£©ÎüÊÕË®·Ö£»·ÀÖ¹¿ÕÆøÖеÄCO2½øÈëC×°ÖÃÖÐ
£¨3£©Ê¹µÃCaCO3ÍêÈ«·´Ó¦
£¨4£©CO2±»NaOHÍêÈ«ÎüÊÕ
CO2+2NaOH¨TNa2CO3+H2O
£¨5£©0.88g   2g   40%
£¨6£©D

µãÆÀ ±¾Ìâ×ۺϿ¼²éÁËÇâÑõ»¯¸ÆºÍ̼Ëá¸ÆµÄÐÔÖÊ¡¢Êéд·½³ÌʽµÄÄÜÁ¦£¬ÊìÁ·ÕÆÎÕÓйØÇâÑõ»¯¸ÆºÍ̼Ëá¸ÆµÄ֪ʶÊǽâ´ð±¾ÌâµÄ¹Ø¼ü£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

9£®Éռ¸É±ù¡¢Êìʯ»ÒºÍСËÕ´òËÄÖÖÎïÖÊ·Ö±ðÓëÏÂÁеÄÈËÀà»î¶¯Óйأ¬Ç뽫ËüÃǵĻ¯Ñ§Ê½ÌîÔÚÏàÓ¦µÄÀ¨ºÅÄÚ£º
£¨1£©¸ÄÁ¼ËáÐÔÍÁÈÀCa£¨OH£©2£»   
£¨2£©ÓÃÓÚÈ˹¤½µÓêCO2£»
£¨3£©ÓÃÓÚ±ºÖƵ°¸âNaHCO3£»   
£¨4£©ÓÃÀ´ÖÆ×÷·ÊÔíNaOH£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

10£®ºÏÀíʹÓÃ×ÊÔ´£¬¶Ô»·¾³±£»¤Æð×ÅÖØÒª×÷Óã®
£¨1£©ÎªÁ˼õÇá¶Ô»·¾³µÄÎÛȾ£¬ÈËÀàÕýÔÚ¿ª·¢³±Ï«ÄÜ¡¢ºËÄÜ¡¢ÉúÎïÖÊÄÜ¡¢Ì«ÑôÄÜ£¨»òµØÈÈÄÜ¡¢·çÄܵȣ©µÈÐÂÄÜÔ´£®
£¨2£©À¬»øµÄ»ØÊÕÀûÓúʹ¦ÀíÓÐÀûÓÚ½ÚÔ¼×ÊÔ´ºÍ¼õÇá»·¾³µÄÎÛȾ£®ÏÂÁÐÊôÓÚ¿É»ØÊÕÀ¬»øµÄÊÇ¢Ù¢Ú£¨ÌîÐòºÅ£©£®
¢ÙÒ×À­¹Þ      ¢Ú·Ï±¨Ö½      ¢ÛÊ£²Ë¡¢¹ûƤ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

7£®Î¬ÉúËØC£¨»¯Ñ§Ê½ÎªC6H8O6£©ÊÇÈËÌå²»¿ÉȱÉÙµÄÓªÑøÎïÖÊ£®ÏÂÁйØÓÚάÉúËØCµÄÐðÊöÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®ÊÇÑõ»¯Îï
B£®ÑõÔªËصÄÖÊÁ¿·ÖÊý¼ÆËãʽΪ$\frac{6}{176}$¡Á100%
C£®Ã¿¸ö·Ö×ÓÖк¬ÓÐ20¸öÔ­×Ó
D£®Ì¼¡¢Çâ¡¢ÑõÈýÖÖÔªËصÄÖÊÁ¿±È3£º4£º3

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

14£®ÎªÁËÅäÖÆ100gÈÜÖÊÖÊÁ¿·ÖÊýΪ7.5%µÄÂÈ»¯ÄÆÈÜÒº£¬Ðè½øÐÐÈçϲÙ×÷£º
£¨1£©¢Ù¼ÆË㣻¢ÚÓÃÍÐÅÌÌìƽ³ÆÈ¡7.5g ÂÈ»¯ÄÆ£»¢ÛÓÃÁ¿Í²Á¿È¡92.5mLË®£»¢ÜÈܽ⣻¢Ý×°Æ¿£¬Ìù±êÇ©£®
£¨2£©½«ÉÏÊöÈÜҺϡÊͳÉÈÜÖÊÖÊÁ¿·ÖÊýΪ0.5%µÄÂÈ»¯ÄÆÈÜÒºÐè¼ÓÈë1400 mLË®£®£¨Ë®µÄÃܶÈΪ1g¨MmL£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

4£®ÈçͼÊÇa¡¢b¡¢cÈýÖÖÎïÖÊ£¨¾ù²»º¬½á¾§Ë®£©µÄÈܽâ¶ÈÇúÏߣ¬»Ø´ð£º£¨1£©PµãµÄº¬ÊÇÔÚt1¡æʱaºÍcµÄÈܽâ¶ÈÏàµÈ£®
£¨2£©t2¡æʱ½«30¿ËaÎïÖÊ·ÅÈë50¿ËË®Öгä·ÖÈܽ⣬ËùµÃaÈÜÒºÖÊÁ¿ÊÇ75¿Ë£®
£¨3£©ÒªÊ¹½Ó½ü±¥ºÍµÄaÈÜÒº±äΪ±¥ºÍÈÜÒº£¬¿É²ÉÓõķ½·¨ÊÇÔö¼ÓÈÜÖÊ£®£¨Ö»ÌîÒ»ÖÖ£©
£¨4£©Òª´Ó»ìÓÐÉÙÁ¿µÄbµÄaÎïÖʵÄÈÜÒºÖÐÌá´¿a£¬Ôò²ÉÓõķ½·¨ÊǽµÎ½ᾧ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

11£®Ä³¹ÌÌåÎï¿ÉÄÜÓÉNa2SO4¡¢NaCl¡¢Na2CO3¡¢KNO3ÖеÄÒ»ÖÖ»ò¼¸ÖÖ×é³É£¬ÏÖ½øÐÐÈçÏÂʵÑ飮
ÊÔÍê³ÉÏÂÁÐÎÊÌ⣺
£¨1£©°×É«³ÁµíAµÄ»¯Ñ§Ê½ÎªBaCO3£»
£¨2£©Ô­¹ÌÌåÖÐÒ»¶¨²»º¬ÓÐNa2SO4¡¢KNO3£®
£¨3£©Îª¼ìÑéÉÏÊö¿ÉÄܺ¬ÓеÄÎïÖÊÊÇ·ñÒ»¶¨´æÔÚ£¬Ä³Í¬Ñ§ÓÖÉè¼ÆÁËÈçÏÂʵÑé·½°¸£º
¢ÙÈ¡ÉÙÁ¿¹ÌÌåÈÜÓÚË®£¬¼ÓÈë×ãÁ¿µÄBa£¨NO3£©2ÈÜÒº£¬³ä·Ö·´Ó¦ºó£¬¹ýÂË£»
¢ÚÈ¡ÂËÒº¼ÓÈëAgNO3ÈÜÒº£¬¹Û²ìÓÐÎÞ°×É«³ÁµíÉú³É£¬Óɴ˵óö½áÂÛ£®
ÔÚÉÏÊöijͬѧµÄʵÑé·½°¸¢ÙÖУ¬¼ÓÈë×ãÁ¿µÄBa£¨NO3£©2ÈÜÒºµÄÄ¿µÄÊdzýÈ¥Na2CO3£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

8£®ÎÒ¹úÖøÃû»¯Ñ§¼ÒºîµÂ°ñ·¢Ã÷µÄ¡°ºîÊÏÖƼ¡±£¬ÆäÔ­ÀíÊÇÏò±¥ºÍʳÑÎË®ÖÐͨÈë×ãÁ¿°±ÆøÖÁ±¥ºÍ£¬È»ºóÔÙ¼ÓѹÌõ¼þÏÂͨÈë¹ýÁ¿¶þÑõ»¯Ì¼£¬¼´¿ÉÎö³öNaHCO3¹ÌÌ壬ÔÙ½«Æä¼ÓÈȼ´µÃµ½´¿¼î£®·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
NaCl+H2O+CO2+NH3¨TNaHCO3+NH4Cl
2NaHCO3 $\frac{\underline{\;\;¡÷\;\;}}{\;}$Na2CO3+CO2¡ü+H2O
£¨1£©Ö»ÓÃNaClÓëCO2ÎÞ·¨ÖƵÃNaHCO3µÄÔ­ÒòÊÇNaClÓëCO2Öж¼²»º¬ÇâÔªËØ£»
£¨2£©¹¤ÒµÖÆÈ¡CO2µÄ»¯Ñ§·½³ÌʽÊÇCaCO3$\frac{\underline{\;¸ßÎÂ\;}}{\;}$CaO+CO2¡ü£»
£¨3£©ÓÉÉÏÊö¹ý³Ì¿ÉÖª£¬ÈôNa2HCO3¹ÌÌåÖлìÓÐÉÙÁ¿NaHCO3ÔÓÖÊ£¬¿ÉÓüÓÈÈ·½·¨½«NaHCO3³ýÈ¥£»
£¨4£©ÇâÆøÊÇÖÆÔ쵪ÆøµÄÔ­ÁÏÖ®Ò»£¬ÊµÑéÊÒÓÃпÓëÏ¡ÁòËá·´Ó¦ÖÆÈ¡ÇâÆøµÄ΢¹Û±¾ÖÊÊÇпԭ×ÓÓëÇâÀë×Ó·´Ó¦Éú³ÉпÀë×ÓºÍÇâ·Ö×Ó£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

9£®ÊµÑéÊÒÅäÖÆ500gÈÜÖʵÄÖÊÁ¿·ÖÊýΪ0£¬5%µÄKMnO4ÈÜÒº£¬ÓÃÓÚ¶ÔÖÖ×Ó½øÐÐÏû¶¾£¬ÏÖ×¼±¸ÈçÏÂʵÑéÓÃÆ·£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©³ÆÁ¿KMnO4¹ÌÌåʱ£¬Ò©Æ·Ó¦·ÅÔÚÍÐÅÌÌìƽ×ó£¨Ìî¡°×ó¡±»ò¡°ÓÒ¡±£©Å̵ÄֽƬÉÏ£¬ÌìƽÉϵÄÓÎÂëλÖÃÓ¦ÊÇͼÖеÄC£¨Ìî×Öĸ£©£®

£¨2£©Á¿È¡ËùÐèˮʱ£¬³ýÉÏÊö×¼±¸µÄʵÑéÓÃÆ·Í⣬»¹ÐèÒªµÄÒ»ÖÖÒÇÆ÷ÊǽºÍ·µÎ¹Ü£¨ÌîÃû³Æ£©£®ÈôÑöÊÓ¶ÁÊý£¬ÔòËùÅäÖƵÄÈÜÒº£¬ÆäÈÜÖʵÄÖÊÁ¿·ÖÊý»áƫС£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°²»±ä¡±£©£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸