Question

15£®½ðÊô²ÄÁÏÊÇÎÒÃÇÉú»îÖбز»¿ÉȱÉÙµÄÎïÖÊ£®

£¨1£©¼×ͼÀûÓÃÁ˽ðÊôµÄÎïÀíÐÔÖÊÊǵ¼µçÐÔ£¬Í¼ÒÒÖеõ½µÄ½áÂÛÊǺϽðµÄÓ²¶È±È´¿½ðÊôµÄÓ²¶È´ó£»
£¨2£©¹¤ÒµÁ¶ÌúµÄÔ­ÀíÈçͼÒÒ£¬Ð´³öBÖÐÁ¶ÌúµÄ»¯Ñ§·´Ó¦·½³Ìʽ3CO+Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3CO₂£¬DÖÐÏÖÏóÊdzÎÇåµÄʯ»ÒË®±ä»ë×Ç£¬ÓйصĻ¯Ñ§·½³ÌʽΪCO₂+Ca£¨OH£©₂¨TCaCO₃¡ý+H₂O£®E×°ÖõÄ×÷ÓÃÊǵãȼβÆø£¬·ÀÖ¹ÎÛȾ¿ÕÆø£»
£¨3£©Ò»Ñõ»¯Ì¼¿ÉÓÃ̼»¹Ô­¶þÑõ»¯Ì¼µÃµ½£¬ÔÚʵÑéÊÒÖÐÓÃ12.5¿Ëʯ»Òʯ£¨Ö÷Òª³É·ÖÊÇCaCO₃£¬ÔÓÖʲ»ÓëËá·´Ó¦£©¼ÓÈë×ãÁ¿µÄÏ¡ÑÎËᣬ³ä·Ö·´Ó¦ºó£¬²úÉú4.4¿Ë¶þÑõ»¯Ì¼£¬Çóʯ»ÒʯÖÐCaCO₃µÄÖÊÁ¿·ÖÊý£®

Answer 1

·ÖÎö £¨1£©¼×ͼÊÇÀûÓýðÊôÖÆ×÷µçÏߣ¬Í¼ÒÒÊǺϽðÓë´¿½ðÊôÏ໥¿Ì»®£¬½øÐзÖÎö½â´ð£®
£¨2£©BÖÐÒ»Ñõ»¯Ì¼ÓëÑõ»¯Ìú·´Ó¦Éú³ÉÌúºÍ¶þÑõ»¯Ì¼£¬¶þÑõ»¯Ì¼ÄÜʹ³ÎÇåµÄʯ»ÒË®±ä»ë×Ç£¬Ò»Ñõ»¯Ì¼Óж¾£¬»áÎÛȾ¿ÕÆø£¬½øÐзÖÎö½â´ð£®
£¨3£©¸ù¾ÝÉú³É¶þÑõ»¯Ì¼ÆøÌåµÄÖÊÁ¿£¬ÓÉ·´Ó¦µÄ»¯Ñ§·½³ÌʽÁÐʽ¼ÆËã³ö²Î¼Ó·´Ó¦µÄ̼Ëá¸ÆµÄÖÊÁ¿£¬½ø¶ø¼ÆËã³öʯ»ÒʯÖÐCaCO₃µÄÖÊÁ¿·ÖÊý£®

½â´ð ½â£º£¨1£©¼×ͼÊÇÀûÓýðÊôÖÆ×÷µçÏߣ¬ÊÇÀûÓÃÁ˽ðÊôµÄµ¼µçÐÔ£»Í¼ÒÒÊǺϽðÓë´¿½ðÊôÏ໥¿Ì»®£¬Í¼ÒÒÖеõ½µÄ½áÂÛÊǺϽðµÄÓ²¶È±È´¿½ðÊôµÄÓ²¶È´ó£®
£¨2£©BÖÐÒ»Ñõ»¯Ì¼ÓëÑõ»¯Ìú·´Ó¦Éú³ÉÌúºÍ¶þÑõ»¯Ì¼£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ3CO+Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3CO₂£®
¶þÑõ»¯Ì¼ÄÜʹ³ÎÇåµÄʯ»ÒË®±ä»ë×Ç£¬¹Û²ìµ½DÖгÎÇåµÄʯ»ÒË®±ä»ë×Ç£»¸Ã·´Ó¦µÄ·´Ó¦·½³ÌʽΪCO₂+Ca£¨OH£©₂¨TCaCO₃¡ý+H₂O£®
Ò»Ñõ»¯Ì¼Óж¾£¬Ö±½ÓÅŷŵ½¿ÕÆøÖлáÔì³É¿ÕÆøÎÛȾ£¬E×°ÖõÄ×÷ÓÃÊǵãȼβÆø£¬·ÀÖ¹ÎÛȾ¿ÕÆø£®
£¨3£©Éè²Î¼Ó·´Ó¦µÄ̼Ëá¸ÆµÄÖÊÁ¿Îªx
CaCO₃+2HCl¨TCaCl₂+H₂O+CO₂¡ü
100                                    44
x                                       4.4g
$\frac{100}{44}=\frac{x}{4.4g}$       x=10g
ʯ»ÒʯÖÐCaCO₃µÄÖÊÁ¿·ÖÊýΪ$\frac{10g}{12.5g}$¡Á100%=80%£®
¹Ê´ð°¸Îª£º£¨1£©µ¼µçÐÔ£» ºÏ½ðµÄÓ²¶È±È´¿½ðÊôµÄÓ²¶È´ó£»
£¨2£©3CO+Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3CO₂£»³ÎÇåµÄʯ»ÒË®±ä»ë×Ç£»CO₂+Ca£¨OH£©₂¨TCaCO₃¡ý+H₂O£»µãȼβÆø£¬·ÀÖ¹ÎÛȾ¿ÕÆø£»
£¨3£©Ê¯»ÒʯÖÐCaCO₃µÄÖÊÁ¿·ÖÊýΪ80%£®

µãÆÀ ±¾ÌâÄѶȲ»´ó£¬ÕÆÎÕÀûÓû¯Ñ§·½³ÌʽµÄ¼ÆËã¡¢Ò»Ñõ»¯Ì¼»¹Ô­Ñõ»¯ÌúµÄʵÑéÔ­Àí¡¢½ðÊôÓëºÏ½ðµÄÐÔÖÊÓëÓÃ;µÈ²¢ÄÜÁé»îÔËÓÃÊÇÕýÈ·½â´ð±¾ÌâµÄ¹Ø¼ü£®