½«Í­·Û¡¢Ìú·ÛºÍÁòËáÍ­·ÛÄ©×é³ÉÍêÈ«¾ùÔȵĻìºÏÎï22.4g£¬·Ö³ÉÖÊÁ¿ÏàµÈµÄÁ½·Ý£¬·Ö±ð·ÅÈë¼×¡¢ÒÒÁ½ÉÕ±­ÖУ®ÔÚ¼×ÉÕ±­ÖмÓÈë×ãÁ¿µÄÕôÁóË®£¬³ä·Ö·´Ó¦ºó£¬ÈÜÒº³ÊÏÖdzÂÌÉ«£¬»¹Ê£Ï¹ÌÌå8g£»ÔÚÒÒÉÕ±­ÖмÓÈë×ãÁ¿Ï¡ÁòËá91.4g£¬½Á°èʹ֮³ä·Ö·´Ó¦ºó£¬²âµÃÒÒÉÕ±­ÖÐÓÐ2.4g°µºìÉ«¹ÌÌåºÍ100gdzÂÌÉ«ÈÜÒº£¨´ËʱÈÜÒºÖÐÖ»ÓÐÁòËáÑÇÌúÒ»ÖÖÈÜÖÊ£©£®ÊÔ¼ÆË㣺
£¨1£©Ô­À´22.4g»ìºÏÎïÖÐÁòËáÍ­·ÛÄ©µÄÖÊÁ¿£»
£¨2£©ÒÒÉÕ±­Öз´Ó¦ËùÉú³ÉÇâÆøµÄÖÊÁ¿£»
£¨3£©ÒÒÉÕ±­ÖеÄÉú³ÉÎïÈÜÒºÖÐÁòËáÑÇÌúµÄÖÊÁ¿·ÖÊý£®
£¨1£©¸ù¾ÝÖÊÁ¿Êغ㣬¼×ÉÕ±­ÖУºÉú³ÉFeSO4µÄÖÊÁ¿=11.2g-8g=3.2g
Éè¼×ÉÕ±­ÖÐCuSO4µÄÖÊÁ¿Îªx         
Fe+CuSO4¨TFeSO4+Cu  
   160    152
    x     3.2g
160£º152=x£º3.2g
x=3.4g
ËùÒÔÔ­»ìºÏÎïÖÐCuSO4µÄÖÊÁ¿=3.4g¡Á2=6.8g
£¨2£©¸ù¾ÝÖÊÁ¿Êغ㣬ÒÒÉÕ±­ÖÐÉú³ÉÇâÆøµÄÖÊÁ¿£º11.2g+91.4g-100g-2.4g=0.2g
£¨3£©ÉèFeÓëH2SO4·´Ó¦Éú³ÉFeSO4µÄÖÊÁ¿Îªy
Fe+H2SO4¨TFeSO4+H2¡ü
          152   2
           y   0.2g
152£º2=y£º0.2g
y=15.2g
ËùÒÔÒÒÉÕ±­ÖÐFeSO4µÄ×ÜÖÊÁ¿Îª£º15.2g+3.2g=18.4g
ËùÒÔFeSO4ÖÊÁ¿·ÖÊýΪ£º
18.4g
100g
¡Á100%=18.4%
´ð£º£¨1£©Ô­À´22.4g»ìºÏÎïÖÐÁòËáÍ­·ÛÄ©µÄÖÊÁ¿6.8g£»
£¨2£©ÒÒÉÕ±­Öз´Ó¦ËùÉú³ÉÇâÆøµÄÖÊÁ¿0.2g£»
£¨3£©ÒÒÉÕ±­ÖеÄÉú³ÉÎïÈÜÒºÖÐÁòËáÑÇÌúµÄÖÊÁ¿·ÖÊý18.4%£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

½«Í­·Û¡¢Ìú·ÛºÍÁòËáÍ­·ÛÄ©×é³ÉÍêÈ«¾ùÔȵĻìºÏÎï22.4g£¬·Ö³ÉÖÊÁ¿ÏàµÈµÄÁ½·Ý£¬·Ö±ð·ÅÈë¼×¡¢ÒÒÁ½ÉÕ±­ÖУ®ÔÚ¼×ÉÕ±­ÖмÓÈë×ãÁ¿µÄÕôÁóË®£¬³ä·Ö·´Ó¦ºó£¬ÈÜÒº³ÊÏÖdzÂÌÉ«£¬»¹Ê£Ï¹ÌÌå8g£»ÔÚÒÒÉÕ±­ÖмÓÈë×ãÁ¿Ï¡ÁòËá91.4g£¬½Á°èʹ֮³ä·Ö·´Ó¦ºó£¬²âµÃÒÒÉÕ±­ÖÐÓÐ2.4g°µºìÉ«¹ÌÌåºÍ100gdzÂÌÉ«ÈÜÒº£¨´ËʱÈÜÒºÖÐÖ»ÓÐÁòËáÑÇÌúÒ»ÖÖÈÜÖÊ£©£®ÊÔ¼ÆË㣺
£¨1£©Ô­À´22.4g»ìºÏÎïÖÐÁòËáÍ­·ÛÄ©µÄÖÊÁ¿£»
£¨2£©ÒÒÉÕ±­Öз´Ó¦ËùÉú³ÉÇâÆøµÄÖÊÁ¿£»
£¨3£©ÒÒÉÕ±­ÖеÄÉú³ÉÎïÈÜÒºÖÐÁòËáÑÇÌúµÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

½«Í­·Û¡¢Ìú·ÛºÍÁòËáÍ­·ÛÄ©×é³ÉÍêÈ«¾ùÔȵĻìºÏÎï22.4g£¬·Ö³ÉÖÊÁ¿ÏàµÈµÄÁ½·Ý£¬·Ö±ð·ÅÈë¼×¡¢ÒÒÁ½ÉÕ±­ÖУ®ÔÚ¼×ÉÕ±­ÖмÓÈë×ãÁ¿µÄÕôÁóË®£¬³ä·Ö·´Ó¦ºó£¬ÈÜÒº³ÊÏÖdzÂÌÉ«£¬»¹Ê£Ï¹ÌÌå8g£»ÔÚÒÒÉÕ±­ÖмÓÈë×ãÁ¿Ï¡ÁòËá91.4g£¬½Á°èʹ֮³ä·Ö·´Ó¦ºó£¬²âµÃÒÒÉÕ±­ÖÐÓÐ2.4g°µºìÉ«¹ÌÌåºÍ100gdzÂÌÉ«ÈÜÒº£¨´ËʱÈÜÒºÖÐÖ»ÓÐÁòËáÑÇÌúÒ»ÖÖÈÜÖÊ£©£®ÊÔ¼ÆË㣺
£¨1£©Ô­À´22.4g»ìºÏÎïÖÐÁòËáÍ­·ÛÄ©µÄÖÊÁ¿£»
£¨2£©ÒÒÉÕ±­Öз´Ó¦ËùÉú³ÉÇâÆøµÄÖÊÁ¿£»
£¨3£©ÒÒÉÕ±­ÖеÄÉú³ÉÎïÈÜÒºÖÐÁòËáÑÇÌúµÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2010ÄêרÌâÍ»ÆÆѵÁ·£º¸ù¾Ý»¯Ñ§Ê½µÄ¼ÆËã2£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

½«Í­·Û¡¢Ìú·ÛºÍÁòËáÍ­·ÛÄ©×é³ÉÍêÈ«¾ùÔȵĻìºÏÎï22.4g£¬·Ö³ÉÖÊÁ¿ÏàµÈµÄÁ½·Ý£¬·Ö±ð·ÅÈë¼×¡¢ÒÒÁ½ÉÕ±­ÖУ®ÔÚ¼×ÉÕ±­ÖмÓÈë×ãÁ¿µÄÕôÁóË®£¬³ä·Ö·´Ó¦ºó£¬ÈÜÒº³ÊÏÖdzÂÌÉ«£¬»¹Ê£Ï¹ÌÌå8g£»ÔÚÒÒÉÕ±­ÖмÓÈë×ãÁ¿Ï¡ÁòËá91.4g£¬½Á°èʹ֮³ä·Ö·´Ó¦ºó£¬²âµÃÒÒÉÕ±­ÖÐÓÐ2.4g°µºìÉ«¹ÌÌåºÍ100gdzÂÌÉ«ÈÜÒº£¨´ËʱÈÜÒºÖÐÖ»ÓÐÁòËáÑÇÌúÒ»ÖÖÈÜÖÊ£©£®ÊÔ¼ÆË㣺
£¨1£©Ô­À´22.4g»ìºÏÎïÖÐÁòËáÍ­·ÛÄ©µÄÖÊÁ¿£»
£¨2£©ÒÒÉÕ±­Öз´Ó¦ËùÉú³ÉÇâÆøµÄÖÊÁ¿£»
£¨3£©ÒÒÉÕ±­ÖеÄÉú³ÉÎïÈÜÒºÖÐÁòËáÑÇÌúµÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2011Äê¾ÅÄ꼶ѧÉúÓż¸¨µ¼»¯Ñ§ÑµÁ·ÊÔ¾í£¨Èý£©£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

½«Í­·Û¡¢Ìú·ÛºÍÁòËáÍ­·ÛÄ©×é³ÉÍêÈ«¾ùÔȵĻìºÏÎï22.4g£¬·Ö³ÉÖÊÁ¿ÏàµÈµÄÁ½·Ý£¬·Ö±ð·ÅÈë¼×¡¢ÒÒÁ½ÉÕ±­ÖУ®ÔÚ¼×ÉÕ±­ÖмÓÈë×ãÁ¿µÄÕôÁóË®£¬³ä·Ö·´Ó¦ºó£¬ÈÜÒº³ÊÏÖdzÂÌÉ«£¬»¹Ê£Ï¹ÌÌå8g£»ÔÚÒÒÉÕ±­ÖмÓÈë×ãÁ¿Ï¡ÁòËá91.4g£¬½Á°èʹ֮³ä·Ö·´Ó¦ºó£¬²âµÃÒÒÉÕ±­ÖÐÓÐ2.4g°µºìÉ«¹ÌÌåºÍ100gdzÂÌÉ«ÈÜÒº£¨´ËʱÈÜÒºÖÐÖ»ÓÐÁòËáÑÇÌúÒ»ÖÖÈÜÖÊ£©£®ÊÔ¼ÆË㣺
£¨1£©Ô­À´22.4g»ìºÏÎïÖÐÁòËáÍ­·ÛÄ©µÄÖÊÁ¿£»
£¨2£©ÒÒÉÕ±­Öз´Ó¦ËùÉú³ÉÇâÆøµÄÖÊÁ¿£»
£¨3£©ÒÒÉÕ±­ÖеÄÉú³ÉÎïÈÜÒºÖÐÁòËáÑÇÌúµÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸