ÈçͼËùʾ£¬ºÓ°¶±ß·Ö²¼¼×¡¢ÒÒ¡¢±û¡¢¶¡ËÄ×ù»¯¹¤³§£¬»·±£ÈËԱΪ¼à²âË®ÖÊÀ´µ½ºÓ±ß£¬¹Û²ìµ½ÈçÏÂÏÖÏó£ºb´¦³öÏÖºìºÖÉ«»ë×Ç£¬c´¦ºÓË®ÓÉ»ë×DZä³ÎÇ壬d´¦ºÓˮðÆøÅÝ£®²âµÃa´¦Ë®ÑùpH=12£¬M´¦Ë®ÑùpH=5£®ÒÑÖªÁ½¸ö»¯¹¤³§ÅŷŵķÏÒºÖк¬ÏÂÁÐÎïÖÊÖеĸ÷Ò»ÖÖ£ºNa2CO3¡¢FeCl3¡¢HClºÍBa£¨OH£©2£®ÇëÄã°ïÖú»·±£ÈËÔ±Íƶϣ¬±û³§ÅŷŵÄÊÇ________£¬¶¡³§ÅŷŵÄÊÇ________£¬M´¦Ò»¶¨²»º¬ÓеÄÒõÀë×ÓÊÇ________£®

Çëд³ö£º
b´¦Éú³É³ÁµíµÄ»¯Ñ§·½³Ìʽ________
c´¦ºÓË®ÓÉ»ë×DZä³ÎÇåµÄ»¯Ñ§·½³Ìʽ________£®

HCl    Na2CO3    OH-ºÍCO3 2-    3Ba£¨OH£©2+2FeCl3=2Fe£¨OH£©3¡ý+3BaCl2    Fe£¨OH£©3+3HCl=FeCl3+3H2O
·ÖÎö£º¸ù¾Ýa´¦Ë®ÑùpH=12£¬ËµÃ÷a´¦´æÔÚ´óÁ¿µÄÇâÑõ¸ùÀë×Ó£¬¼×³§µÄ·ÏË®Öк¬ÓÐÇâÑõ»¯±µ£»ÔÚÒÒ´¦»á³öÏÖ³öÏÖºìºÖÉ«»ë×Ç£¬ËµÃ÷Éú³ÉÁËÇâÑõ»¯Ìú³Áµí£¬ÒÒ³§µÄ·ÏË®Öк¬ÓÐÂÈ»¯Ìú£¬c´¦ºÓË®ÓÉ»ë×DZä³ÎÇ壬˵Ã÷±û³§µÄ·ÏË®Öк¬ÓÐÑÎËᣬd´¦ºÓˮðÆøÅÝ£¬ËµÃ÷¶¡³§µÄ·ÏË®Öк¬ÓÐ̼ËáÄÆ£¬M´¦Ë®ÑùpH=5£¬´æÔÚ´óÁ¿µÄÇâÀë×Ó£¬¾Í²»»á´æÔÚÇâÑõ¸ùÀë×ÓºÍ̼Ëá¸ùÀë×Ó£»
¸ù¾ÝÍƵ¼³öµÄÎïÖÊÊéд·½³Ìʽ£®
½â´ð£º
a´¦Ë®ÑùpH=12£¬ËµÃ÷a´¦´æÔÚ´óÁ¿µÄÇâÑõ¸ùÀë×Ó£¬¼×³§µÄ·ÏË®Öк¬ÓÐÇâÑõ»¯±µ£»ÔÚÒÒ´¦»á³öÏÖ³öÏÖºìºÖÉ«»ë×Ç£¬ËµÃ÷Éú³ÉÁËÇâÑõ»¯Ìú³Áµí£¬ÒÒ³§µÄ·ÏË®Öк¬ÓÐÂÈ»¯Ìú£¬c´¦ºÓË®ÓÉ»ë×DZä³ÎÇ壬˵Ã÷±û³§µÄ·ÏË®Öк¬ÓÐÑÎËᣬd´¦ºÓˮðÆøÅÝ£¬ËµÃ÷¶¡³§µÄ·ÏË®Öк¬ÓÐ̼ËáÄÆ£¬M´¦Ë®ÑùpH=5£¬´æÔÚ´óÁ¿µÄÇâÀë×Ó£¬¾Í²»»á´æÔÚÇâÑõ¸ùÀë×ÓºÍ̼Ëá¸ùÀë×Ó£»
ÇâÑõ»¯±µºÍÂÈ»¯ÌúÉú³ÉÇâÑõ»¯Ìú³ÁµíºÍÂÈ»¯±µ£»
ÇâÑõ»¯ÌúºÍÑÎËá·´Ó¦Éú³ÉÂÈ»¯ÌúºÍË®£»
¹Ê´ð°¸Îª£ºHCl£¬Na2CO3£¬OH-ºÍCO3 2-
3Ba£¨OH£©2+2FeCl3=2Fe£¨OH£©3¡ý+3BaCl2
Fe£¨OH£©3+3HCl=FeCl3+3H2O
µãÆÀ£ºÔÚ½â´ËÀàÌâʱ£¬Ê×ÏÈ·ÖÎö¸÷´¦µÄÏÖÏó£¬È»ºó½áºÏÀë×ÓÖ®¼äµÄ¹²´æÎÊÌâ½øÐзÖÎö£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

29¡¢ÈçͼËùʾ£¬ºÓ°¶±ß·Ö²¼¼×¡¢ÒÒ¡¢±û¡¢¶¡ËÄ×ù»¯¹¤³§£¬»·±£ÈËԱΪ¼à²âË®ÖÊÀ´µ½ºÓ±ß£¬¹Û²ìµ½ÈçÏÂÏÖÏó£ºb´¦³öÏÖºìºÖÉ«»ë×Ç£¬c´¦ºÓË®ÓÉ»ë×DZä³ÎÇ壬d´¦ºÓˮðÆøÅÝ£®²âµÃa´¦Ë®ÑùpH=12£¬M´¦Ë®ÑùpH=5£®ÒÑÖªÁ½¸ö»¯¹¤³§ÅŷŵķÏÒºÖк¬ÏÂÁÐÎïÖÊÖеĸ÷Ò»ÖÖ£ºNa2CO3¡¢FeCl3¡¢HClºÍBa£¨OH£©2£®ÇëÄã°ïÖú»·±£ÈËÔ±Íƶϣ¬±û³§ÅŷŵÄÊÇ
HCl
£¬¶¡³§ÅŷŵÄÊÇ
Na2CO3
£¬M´¦Ò»¶¨²»º¬ÓеÄÒõÀë×ÓÊÇ
OH-ºÍCO3 2-

Çëд³ö£º
b´¦Éú³É³ÁµíµÄ»¯Ñ§·½³Ìʽ
3Ba£¨OH£©2+FeCl3=Fe£¨OH£©3¡ý+BaCl2

c´¦ºÓË®ÓÉ»ë×DZä³ÎÇåµÄ»¯Ñ§·½³Ìʽ
Fe£¨OH£©3+3HCl=FeCl3+2H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£ºÐ½̲ÄÍêÈ«½â¶Á¡¡¾ÅÄ꼶»¯Ñ§¡¡(ϲá)¡¡(È˽̰æ) È˽̰æ ÌâÐÍ£º022

ÈçͼËùʾ£¬ºÓ°¶±ß·Ö²¼ËÄ×ù»¯¹¤³§£¬»·±£ÈËԱΪ¼à²âË®ÖÊÀ´µ½ºÓ±ß£¬¹Û²ìµ½ÈçÏÂÏÖÏó£ºb´¦³öÏÖºìºÖÉ«»ë×Ç£¬c´¦ºÓË®ÓÉ»ë×DZä³ÎÇ壬d´¦ºÓˮðÆøÅÝ£®²âµÃa´¦Ë®ÑùµÄpH£½12£¬m´¦Ë®ÑùµÄpH£½5£®ÒÑ֪ÿ¸ö¹¤³§ÅŷŵķÏÒºÖÐÖ»º¬ÓÐÏÂÁÐÎïÖÊÖеÄÒ»ÖÖ£ºNa2CO3¡¢FeCl3¡¢HClºÍBa(OH)2£®

(1)ÇëÄã°ïÖú»·±£ÈËÔ±ÍƲⶡ³§ÅŷŵÄÊÇ________£¬m´¦Ò»¶¨²»º¬ÓеÄÒõÀë×ÓÊÇ________£®

(2)Çëд³öb´¦Éú³É³ÁµíµÄ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º________£®

(3)Çëд³öc´¦ºÓË®ÓÉ»ë×DZä³ÎÇåµÄ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º________£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2002ÄêºÚÁú½­Ê¡Öп¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

ÈçͼËùʾ£¬ºÓ°¶±ß·Ö²¼¼×¡¢ÒÒ¡¢±û¡¢¶¡ËÄ×ù»¯¹¤³§£¬»·±£ÈËԱΪ¼à²âË®ÖÊÀ´µ½ºÓ±ß£¬¹Û²ìµ½ÈçÏÂÏÖÏó£ºb´¦³öÏÖºìºÖÉ«»ë×Ç£¬c´¦ºÓË®ÓÉ»ë×DZä³ÎÇ壬d´¦ºÓˮðÆøÅÝ£®²âµÃa´¦Ë®ÑùpH=12£¬M´¦Ë®ÑùpH=5£®ÒÑÖªÁ½¸ö»¯¹¤³§ÅŷŵķÏÒºÖк¬ÏÂÁÐÎïÖÊÖеĸ÷Ò»ÖÖ£ºNa2CO3¡¢FeCl3¡¢HClºÍBa£¨OH£©2£®ÇëÄã°ïÖú»·±£ÈËÔ±Íƶϣ¬±û³§ÅŷŵÄÊÇ    £¬¶¡³§ÅŷŵÄÊÇ    £¬M´¦Ò»¶¨²»º¬ÓеÄÒõÀë×ÓÊÇ    £®

Çëд³ö£º
b´¦Éú³É³ÁµíµÄ»¯Ñ§·½³Ìʽ   
c´¦ºÓË®ÓÉ»ë×DZä³ÎÇåµÄ»¯Ñ§·½³Ìʽ    £®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸