£¨2003?³£ÖÝ£©¡°ÎïÖʵÄ×é³ÉÓë½á¹¹¾ö¶¨ÎïÖʵÄÐÔÖÊ¡±ÊÇ»¯Ñ§Ñ§¿ÆÖеÄÖØÒª¹Ûµã£®°´ÕÕÕâÒ»¹ÛµãÌÖÂÛÏÂÃæµÄÎÊÌâ
£¨1£©ËáÈÜÒº¾ßÓÐһЩ¹²Í¬µÄ»¯Ñ§ÐÔÖÊ£¬ÊÇÒòΪËáÈÜÒºÖж¼º¬ÓУ»¼îÈÜÒºÒ²¾ßÓÐһЩ¹²Í¬µÄ»¯Ñ§ÐÔÖÊ£¬ÊÇÒòΪ¼îÈÜÒºÖж¼º¬ÔÚÒò´Ë£¬ËáÈÜÒºÓë¼îÈÜÒº·´Ó¦Ò»¶¨ÄÜÉú³ÉÀýÈ磮
£¨2£©¹ýÑõ»¯ÇâÊÇÒ»ÖÖ³£¼ûµÄɱ¾úÏû¶¾¼Á£¬ÆäÔ­ÒòÊǹýÑõ»¯Çâ·Ö×ÓÖк¬ÓÐÒ»ÖÖ½Ð×ö¡°¹ýÑõ»ù¡±£¨ÏÂͼÖÐÐéÏß¿ò±ê³öµÄ²¿·Ö£©µÄ½á¹¹£®¾Ý´ËÍƲâÏÂÁТÚ-¢ÜµÄÎïÖÊÖУ¬¿ÉÓÃ×÷ɱ¾úÏû¶¾¼ÁµÄÊÇ£¨ÌîÐòºÅ£©
¡¾´ð°¸¡¿·ÖÎö£º¸ù¾ÝËá¡¢¼îµÄ¶¨ÒåºÍÖкͷ´Ó¦µÄʵÖʽâ¾ö±¾Ì⣬ÐÅÏ¢ÌâҪץסÐÅÏ¢µÄʵÖÊ£®
½â´ð£º½â£º£¨1£©ËáÊÇÖ¸µçÀë³öÀ´µÄÑôÀë×ÓÈ«²¿ÊÇÇâÀë×ӵĻ¯ºÏÎËùÒÔËáÈÜÒºÖж¼º¬ÓÐÇâÀë×Ó£¬¼îÊÇÖ¸µçÀë³öÀ´µÄÒõÀë×ÓÈ«²¿ÊÇÇâÑõ¸ùÀë×ӵĻ¯ºÏÎËùÒÔ¼îÈÜÒºÖж¼º¬ÓÐÇâÑõ¸ùÀë×Ó£®Öкͷ´Ó¦µÄʵÖÊÊÇÇâÀë×ÓºÍÇâÑõ¸ùÀë×ÓÉú³ÉË®£»
£¨2£©ÓÉͼʾÐÅÏ¢¿ÉÖªÑõÑõµ¥¼üÏàÁ¬²Å¾ßÓÐɱ¾úÏû¶¾¼Á£¬ËùÒԵڢܸ÷ÎïÖÊÖк¬ÓÐÕâÒ»¼ü£®
¹Ê´ð°¸Îª£º£¨1£©ÇâÀë×Ó£»ÇâÑõ¸ùÀë×Ó£»Ë®£»Ca£¨OH£©2+2HCl¨TCaCl2+2H20£»
£¨2£©¢Ü
µãÆÀ£ºÊì¼ÇËáºÍ¼îµÄ¶¨Ò壬֪µÀÖкͷ´Ó¦µÄʵÖÊ£¬¶ÔÓÚ½â¾öÐÅÏ¢Ì⣬ҪץסÐÅÏ¢µÄÖصã½â¾öÎÊÌ⣮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2003?³£ÖÝ£©ÓÒͼÊdz£ÓõÄʵÑéÊÒÖÆÈ¡ÆøÌåµÄ·¢Éú×°Ö㮾Ýͼ»Ø´ðÏÂÁÐÏà¹ØÎÊÌ⣮
£¨1£©ÖÆÈ¡O2ʱ£¬AÖÐÓ¦·Å
¶þÑõ»¯ÃÌ
¶þÑõ»¯ÃÌ
£¬Æä×÷ÓÃÊÇ
¼Ó¿ìH2O2µÄ·Ö½âËÙÂÊ
¼Ó¿ìH2O2µÄ·Ö½âËÙÂÊ
£®
£¨2£©ÖÆÈ¡H2ʱ£¬BÖпɷÅ
Ï¡ÑÎËá»òÏ¡ÁòËá
Ï¡ÑÎËá»òÏ¡ÁòËá
£®
£¨3£©ÖÆÈ¡CO2ʱ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
CaCO3+2HCl=CaCl2+CO2¡ü+H2O
CaCO3+2HCl=CaCl2+CO2¡ü+H2O
£®
£¨4£©ÔÚÉÏÊöÈýÖÖÆøÌåÖУ¬ÄÜÓÃÏòÏÂÅÅ¿ÕÆø·¨ÊÕ¼¯µÄÊÇ
ÇâÆø
ÇâÆø
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2003?³£ÖÝ£©ÔÚÏ¡ÁòËᡢʳÑΡ¢Êìʯ»Ò¡¢¸É±ùËÄÖÖÎïÖÊÖУ¬Éú»îÖг£ÓÃ×÷µ÷ζ¼ÁµÄÊÇ
NaCl
NaCl
£»¿ÉÓÃÓÚÈ˹¤½µÓêµÄÊÇ
CO2
CO2
£»¿ÉÓÃÓÚÇåÏ´¸ÖÌú±íÃæÌúÐâµÄÊÇ
H2SO4
H2SO4
£»ÄÜÓÃÀ´¸ÄÁ¼ËáÐÔÍÁÈÀµÄÊÇ
Ca£¨OH£©2
Ca£¨OH£©2
£®£¨Óû¯Ñ§Ê½Ìî¿Õ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2003?³£ÖÝ£©ÏÂÁйØÓÚ¿ÕÆøµÄÐðÊö£¬´íÎóµÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2003?³£ÖÝ£©ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2003?³£ÖÝ£©È˺ô³öµÄÆøÌåͨÈë³ÎÇåʯ»ÒË®Öлá³öÏÖ»ë×Ç£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
Ca£¨OH£©2+CO2=CaCO3¡ý+H2O
Ca£¨OH£©2+CO2=CaCO3¡ý+H2O
£®£»½¨ÖþÉÏÓõÄÊìʯ»ÒÊÇÓÃÉúʯ»ÒºÍË®·´Ó¦ÖƵõģ¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
CaO+H2O=Ca£¨OH£©2
CaO+H2O=Ca£¨OH£©2
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸