ijͬѧΪÁ˼ìÑé¼ÒÀﹺÂòµÄÁòËá炙¯·ÊÊÇ·ñºÏ¸ñ£¬Ëû³ÆÈ¡27.5g»¯·ÊÑùÆ·Óë×ãÁ¿Å¨ÉÕ¼îÈÜÒº¼ÓÈÈ£¬²úÉúµÄ°±ÆøÓÃ100.0g·ÏÁòËᣨ×ãÁ¿£©ÎüÊÕ£®²âµÃÎüÊÕ°±ÆøµÄÈÜÒº×ÜÖÊÁ¿mÓ뷴Ӧʱ¼äµÄ±ä»¯ÈçͼËùʾ£®£¨ËùÉæ¼°·´Ó¦£¨NH4£©SO4+2NaOH=Na2SO4+2H2O+NH3¡ü£»
2NH3+H2SO4=£¨NH4£©2SO4£©
Çë¼ÆË㣺
£¨1£©ÍêÈ«·´Ó¦ºó²úÉú°±ÆøÖÊÁ¿Îª
6.8g
6.8g
£®
£¨2£©¸Ã»¯·ÊµÄº¬µªÁ¿Îª¶àÉÙ£¿Ð´³ö½âÌâ¹ý³Ì£®Í¨¹ý¼ÆËãÅжÏÕâÖÖ»¯·ÊÊÇ·ñºÏ¸ñ£¿
·ÖÎö£º£¨1£©ÔËÓÃÖÊÁ¿Êغ㶨Âɽâ´ð£»
£¨2£©ÔËÓÃÖÊÁ¿Êغ㶨Âɺ͸ù¾Ý»¯Ñ§Ê½µÄ¼ÆËã½â´ð£®
½â´ð£º½â£º£¨1£©¸ù¾ÝÖÊÁ¿Êغ㶨ÂɽáºÏÌâÖÐͼʾ¿ÉÖªÉú³ÉµÄ°±ÆøÖÊÁ¿Îª106.8g-100g=6.8g£»¹Ê´ð°¸Îª£º6.8g£»
£¨2£©¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ°±ÆøÖеĵªÔªËØÖÊÁ¿¼´ÁòËá炙¯·ÊÖеªÔªËصÄÖÊÁ¿£¬°±ÆøÖеªÔªËصÄÖÊÁ¿Îª6.8g¡Á
14
17
¡Á100%=5.6g£¬¹Ê»¯·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊýΪ
5.6g
27.5g
¡Á100%=20.4%£¾20%£¬ËùÒÔΪºÏ¸ñ»¯·Ê£®¹Ê´ð°¸Îª£º20.4%£»ºÏ¸ñ£®
µãÆÀ£º±¾ÌâÊÇ×ÛºÏÐÔ¼ÆËãÌ⣬¿¼²éÖÊÁ¿Êغ㶨ÂɵļÆËã¡¢²àÖؼÆËãÄÜÁ¦µÄ¿¼²é£¬Æ½Ê±Ñ§Ï°Ê±Ò»¶¨×¢Òâ¶à×ö¶à×ܽá¹æÂÉ£¬Ñ°ÕÒ½âÌâ˼·£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøijͬѧΪÁ˼ìÑé¼ÒÀﹺÂòµÄÁòËá炙¯·ÊÊÇ·ñºÏ¸ñ£¬³ÆÈ¡ÁË27.5g»¯·ÊÑùÆ·Óë×ãÁ¿Å¨ÉÕ¼îÈÜÒºÒ»Æð¼ÓÈÈ£¬²úÉúµÄ°±ÆøÓÃ×ãÁ¿µÄ100.0g·ÏÁòËáÎüÊÕ£®²âµÃÎüÊÕ°±ÆøµÄÈÜÒº×ÜÖÊÁ¿mÓ뷴Ӧʱ¼ätµÄ±ä»¯ÈçÓÒͼËùʾ£®ÒÑÖªºÏ¸ñÁòËá炙¯·ÊÖꬵªÁ¿²»µÍ£®20%£®ËùÉæ¼°µÄ·´Ó¦Îª£¨NH4£©2SO4+2NaOH=Na2SO4+2H2O+2NH3¡ü£»2NH3+H2SO4=£¨NH4£©2SO4£®ÊÔ¼ÆË㣺
£¨1£©»¯·ÊÑùÆ·ÍêÈ«·´Ó¦ºó²úÉú°±Æø
 
g£®
£¨2£©¸Ã»¯·ÊµÄº¬µªÁ¿Îª
 
 £¨¾«È·µ½0.1%£©£¬ÊôÓÚ
 
 £¨Ñ¡Ìî¡°ºÏ¸ñ¡±»ò¡°²»ºÏ¸ñ¡±£©²úÆ·£®
£¨3£©·ÏÁòËá³ä·ÖÎüÊÕ°±ÆøºóÈÜÒºÖеÄÁòËáï§ÖÊÁ¿·ÖÊýÊǶàÉÙ£¨Ð´³ö¼ÆËã¹ý³Ì£¬¾«È·µ½0.1%£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijͬѧΪÁ˼ìÑé¼ÒÀﹺÂòµÄÁòËá炙¯·ÊÊÇ·ñºÏ¸ñ£¬Ëû³ÆÈ¡27.5g»¯·ÊÑùÆ·Óë×ãÁ¿Å¨ÉÕ¼îÈÜÒº¼ÓÈÈ£¬²úÉúµÄ°±ÆøÓÃ100.0g·ÏÁòËáÎüÊÕ£®²âµÃÎüÊÕ°±ÆøµÄÈÜÒº×ÜÖÊÁ¿mÓ뷴Ӧʱ¼ätµÄ±ä»¯ÈçÓÒÏÂͼËùʾ£®ËùÉæ¼°µÄ·´Ó¦Îª£º¾«Ó¢¼Ò½ÌÍø
£¨NH4£©2SO4+2NaOH¨TNa2SO4+2H2O+2NH3¡ü£»2NH3+H2SO4¨T£¨NH4£©2SO4£®
Çë¼ÆË㣺
£¨1£©ÍêÈ«·´Ó¦ºó²úÉú°±Æø
 
g£®
£¨2£©¸Ã»¯·ÊµÄº¬µªÁ¿Îª
 
£¨¾«È·µ½0.1%£©£¬ÔòÕâÖÖ»¯·ÊÊôÓÚ
 
£¨Ì¡°ºÏ¸ñ¡±»ò¡°²»ºÏ¸ñ¡±£®ºÏ¸ñÁòËá狀¬µªÁ¿Îª20%ÒÔÉÏ£©²úÆ·£®
£¨3£©Çë¼ÆËã·ÏÁòËáÖÐÁòËáµÄÖÊÁ¿·ÖÊý£¨Ð´³ö¼ÆËã¹ý³Ì£©£®
£¨4£©ÈôʵÑé¹ý³ÌÖа±Æø±»ÍêÈ«ÎüÊÕ£¬µ«¸ÃʵÑé²âµÃÁòËá炙¯·ÊµÄº¬µªÁ¿¸ßÓÚʵ¼ÊÖµ£¬ÆäÔ­ÒòÊÇ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2011?ºÍƽÇø¶þÄ££©Ä³Í¬Ñ§ÎªÁ˼ìÑé¼ÒÀﹺÂòµÄÁòËá炙¯·ÊÊÇ·ñºÏ¸ñ£¬Ëû³ÆÈ¡27.5g»¯·ÊÑùÆ·Óë×ãÁ¿Å¨ÉÕ¼îÈÜÒº¼ÓÈÈ£¬²úÉúµÄµªÆøÓÃ100.0g·ÏÁòËáÎüÊÕ£®²âµÃÎüÊÕ°±ÆøµÄÈÜÒº×ÜÖÊÁ¿mÓ뷴Ӧʱ¼ätµÄ±ä»¯ÈçͼËùʾ£¬ËùÉæ¼°µÄ·´Ó¦Îª£º£¨NH4£©SO4+2NaOH=Na2SO4+2NH3+2H2O¡ü£»2NH3+H2SO4=£¨NH4£©SO4£®Çë¼ÆË㣺£¨1£©ÍêÈ«·´Ó¦ºó²úÉú°±Æø
6.8
6.8
g
£¨2£©¸Ã»¯·ÊµÄº¬°±Á¿Îª
20.4%
20.4%
£¨¾«È·µ½0.1%£©£¬ÔòÕâÖÖ»¯·ÊÊôÓÚ
ºÏ¸ñ
ºÏ¸ñ
£¨Ìî¡°ºÏ¸ñ¡±»ò¡°²»ºÏ¸ñ¡±£¬ºÏ¸ñÁòËá狀¬µªÁ¿Îª20%ÒÔÉÏ£©²úÆ·£®
£¨3£©Çë¼ÆËã·ÏÁòËáÖÐÁòËáµÄÖÊÁ¿·ÖÊý£¨Ð´³ö¼ÆËã¹ý³Ì£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijͬѧΪÁ˼ìÑé¼ÒÀﹺÂòµÄÁòËá炙¯·ÊÊÇ·ñºÏ¸ñ£¬³ÆÈ¡ÁË27.5g»¯·ÊÑùÆ·Óë×ãÁ¿Å¨ÉÕ¼îÈÜÒºÒ»Æð¼ÓÈÈ£¬²úÉúµÄ°±ÆøÓÃ×ãÁ¿µÄ100.0g·ÏÁòËáÎüÊÕ£®²âµÃÎüÊÕ°±ÆøµÄÈÜÒº×ÜÖÊÁ¿mÓ뷴Ӧʱ¼ätµÄ±ä»¯ÈçÓÒͼËùʾ£®ÒÑÖªºÏ¸ñÁòËá炙¯·ÊÖꬵªÁ¿²»µÍÓÚ20%£®ËùÉæ¼°µÄ·´Ó¦Îª£¨NH4£©2SO4+2NaOH=Na2SO4+2H2O+2NH3¡ü£»2NH3+H2SO4=£¨NH4£©2SO4£®ÊÔ¼ÆË㣺
£¨1£©»¯·ÊÑùÆ·ÍêÈ«·´Ó¦ºó²úÉú°±Æø
6.8
6.8
g£®
£¨2£©¸Ã»¯·ÊµÄº¬µªÁ¿Îª
20.4%
20.4%
£¨¾«È·µ½0.1%£©£¬ÊôÓÚ
ºÏ¸ñ
ºÏ¸ñ
£¨Ñ¡Ìî¡°ºÏ¸ñ¡±»ò¡°²»ºÏ¸ñ¡±£©²úÆ·£®
£¨3£©·´Ó¦ÖÐËùÏûºÄµÄÁòËáµÄÖÊÁ¿ÊǶàÉÙ£¨Ð´³ö¼ÆËã¹ý³Ì£©£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸