Ò»Ôò¡¶Ð¡ÓêÒý¡°È¼¡±Ò»³µµçʯ¡·±¨µÀ£º5ÔÂ9ÈÕ°øÍí£¬Ò»Á¾´¢Ô˵çʯµÄÆû³µÒòδ×öºÃ·ÀË®¹¤×÷£¬ÐÐÊ»¹ý³ÌÖÐÌ콵СÓ꣬Òý·¢³µÏáׯ𡭣¬ËµÃ÷Ë®ÓÐʱҲÄÜ¡°Òý»ð¡±£®ÒÑÖª£ºµçʯ£¨CaC2£©²»¿Éȼ£¬ÓëË®½Ó´¥¾çÁÒ·´Ó¦²úÉúÒÒȲ£¨C2H2£©£®
£¨1£©µçʯºÍË®·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaC2+2H2O¡úX+C2H2¡ü£¬ÆäÖÐXµÄ»¯Ñ§Ê½Îª________£®
£¨2£©1mol C2H2Öк¬ÓÐ________¸öÇâÔ­×Ó£®
£¨3£©ÈôÓÃ3.2kgµÄµçʯÓëË®ÍêÈ«·´Ó¦£¬ÄÜÉú³É¶àÉÙmolÒÒȲÆøÌå________£®

½â£º£¨1£©ÓÉÖÊÁ¿Êغ㶨ÂɿɵÃXµÄ»¯Ñ§Ê½ÎªCa£¨OH£©2£®
£¨2£©1mol C2H2Öк¬ÓеķÖ×Ó¸öÊýΪ6.02¡Á1023¸ö£¬ÓÖÖªÒ»¸ö·Ö×ÓÖк¬ÓÐ2¸öÇâÔ­×Ó£®ËùÒÔ1mol C2H2Öк¬ÓÐ1.204¡Á1024¸öÇâÔ­×Ó£®
£¨3£©ÉèÄÜÉú³ÉÒÒȲÆøÌåµÄÎïÖʵÄÁ¿ÎªX
CaC2+2H2O=Ca£¨OH£©2+C2H2¡ü
64g 1mol
3200g X
=
X=50mol
´ð£ºÄÜÉú³É50molµÄÒÒȲÆøÌ壮
¹Ê´ð°¸Îª£º£¨1£©Ca£¨OH£©2
£¨2£©1.204¡Á1024
£¨3£©50mol
·ÖÎö£ºÔÚ»¯Ñ§·´Ó¦Ç°ºó£¬Ô­×ÓµÄÖÖÀà¡¢¸öÊý¡¢ÖÊÁ¿±£³Ö²»±ä£¬ËùÒÔ»¯Ñ§·´Ó¦Ç°ºóÖÊÁ¿Êغ㣮ÀûÓÃÖÊÁ¿Êغ㶨ÂÉÎÒÃÇ¿ÉÒÔÀ´È·¶¨Î´ÖªÔªËصĻ¯Ñ§Ê½£®
µãÆÀ£º1molÈκÎÎïÖÊËùº¬ÓеÄ΢Á£¸öÊý¶¼Îª6.02¡Á1023¸ö£¬µ«ÊÇ·Ö×ÓÖк¬ÓеÄÔ­×ӵĸöÊý²»Ò»¶¨µÈÓÚ6.02¡Á1023¸ö£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

25¡¢Ò»Ôò¡¶Ð¡ÓêÒý¡°È¼¡±Ò»³µµçʯ¡·±¨µÀ£º5ÔÂ9ÈÕ°øÍí£¬Ò»Á¾´¢Ô˵çʯµÄÆû³µÒòδ×öºÃ·ÀË®¹¤×÷£¬ÐÐÊ»¹ý³ÌÖÐÌ콵СÓ꣬Òý·¢³µÏáׯ𡭣¬ËµÃ÷Ë®ÓÐʱҲÄÜ¡°Òý»ð¡±£®ÒÑÖª£ºµçʯ£¨CaC2£©²»¿Éȼ£¬ÓëË®½Ó´¥¾çÁÒ·´Ó¦²úÉúÒÒȲ£¨C2H2£©£®
£¨1£©µçʯºÍË®·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaC2+2H2O¡úX+C2H2¡ü£¬ÆäÖÐXµÄ»¯Ñ§Ê½Îª
Ca£¨OH£©2
£®
£¨2£©1mol C2H2Öк¬ÓÐ
1.204¡Á1024
¸öÇâÔ­×Ó£®
£¨3£©ÈôÓÃ3.2kgµÄµçʯÓëË®ÍêÈ«·´Ó¦£¬ÄÜÉú³É¶àÉÙmolÒÒȲÆøÌå
0.05mol
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º»ÆÆÖÇøһģ ÌâÐÍ£ºÌî¿ÕÌâ

Ò»Ôò¡¶Ð¡ÓêÒý¡°È¼¡±Ò»³µµçʯ¡·±¨µÀ£º5ÔÂ9ÈÕ°øÍí£¬Ò»Á¾´¢Ô˵çʯµÄÆû³µÒòδ×öºÃ·ÀË®¹¤×÷£¬ÐÐÊ»¹ý³ÌÖÐÌ콵СÓ꣬Òý·¢³µÏáׯ𡭣¬ËµÃ÷Ë®ÓÐʱҲÄÜ¡°Òý»ð¡±£®ÒÑÖª£ºµçʯ£¨CaC2£©²»¿Éȼ£¬ÓëË®½Ó´¥¾çÁÒ·´Ó¦²úÉúÒÒȲ£¨C2H2£©£®
£¨1£©µçʯºÍË®·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaC2+2H2O¡úX+C2H2¡ü£¬ÆäÖÐXµÄ»¯Ñ§Ê½Îª______£®
£¨2£©1mol C2H2Öк¬ÓÐ______¸öÇâÔ­×Ó£®
£¨3£©ÈôÓÃ3.2kgµÄµçʯÓëË®ÍêÈ«·´Ó¦£¬ÄÜÉú³É¶àÉÙmolÒÒȲÆøÌå______£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2010ÄêÉϺ£ÊлÆÆÖÇøÖп¼»¯Ñ§Ò»Ä£ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

Ò»Ôò¡¶Ð¡ÓêÒý¡°È¼¡±Ò»³µµçʯ¡·±¨µÀ£º5ÔÂ9ÈÕ°øÍí£¬Ò»Á¾´¢Ô˵çʯµÄÆû³µÒòδ×öºÃ·ÀË®¹¤×÷£¬ÐÐÊ»¹ý³ÌÖÐÌ콵СÓ꣬Òý·¢³µÏáׯ𡭣¬ËµÃ÷Ë®ÓÐʱҲÄÜ¡°Òý»ð¡±£®ÒÑÖª£ºµçʯ£¨CaC2£©²»¿Éȼ£¬ÓëË®½Ó´¥¾çÁÒ·´Ó¦²úÉúÒÒȲ£¨C2H2£©£®
£¨1£©µçʯºÍË®·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaC2+2H2O¡úX+C2H2¡ü£¬ÆäÖÐXµÄ»¯Ñ§Ê½Îª    £®
£¨2£©1mol C2H2Öк¬ÓР   ¸öÇâÔ­×Ó£®
£¨3£©ÈôÓÃ3.2kgµÄµçʯÓëË®ÍêÈ«·´Ó¦£¬ÄÜÉú³É¶àÉÙmolÒÒȲÆøÌå    £®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸