Question

2£®Ä³Ìú¿ó·ÛÖ÷Òª³É·ÖΪÌúµÄÑõ»¯ÎFe_aO_b£©£¬Ò»Ñ§ÉúÀûÓÃʵÑé¶ÔÆä×÷½øÒ»²½·ÖÎö£¬¹ý³Ì¼°Êý¾ÝÈçÏ£®£¨×¢£ºÌú¿ó·ÛÖÐÔÓÖʲ»²ÎÓëÏÂÁйý³ÌÖеķ´Ó¦£©
²½Öè I£®È¡29g¸ÃÌú¿ó·ÛÔÚCOÆøÁ÷Öгä·Ö¼ÓÈÈ£¬½«·´Ó¦ºóµÄÆøÌåÓÃÉÕ¼îÈÜÒº³ä·ÖÎüÊÕ£¬ÉÕ¼îÈÜÒºÔöÖØ17.6g£®
²½Öè II£®½«ÉÏÊö¼ÓÈȺóµÄ¹ÌÌåÈ¡³öºó£¬ÔÙÏò¹ÌÌåÖðµÎ¼ÓÈëÏ¡ÁòËᣬ²âµÃ²úÉúÆøÌåÓëµÎÈëÏ¡ÁòËáµÄÖÊÁ¿¹ØϵÈçͼËùʾ£º

Çë¸ù¾ÝÒÔÉϹý³Ì¼°Êý¾Ý»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©²½Öè IÖÐÉú³ÉÆøÌåµÄÖÊÁ¿Îª17.6g£®
£¨2£©²½Öè IIËùÓÃÏ¡ÁòËáÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýΪ¶àÉÙ£¿£¨ÇëÁÐʽ¼ÆË㣩
£¨3£©¾­³ÆÁ¿£¬²½Öè I³ä·Ö¼ÓÈȺóÊ£Óà¹ÌÌåÖÊÁ¿Îª22.6g£®Ôò¸ÃÌúµÄÑõ»¯ÎﻯѧʽÖУ¬a¡¢bµÄ×î¼òÕûÊý±Èa£ºb=3£º4£®

Answer 1

·ÖÎö ʵÑéÉè¼ÆµÚÒ»²½ÊÇÈ·¶¨ÌúµÄÑõ»¯ÎïÖÐÑõÔªËصÄÖÊÁ¿£¬µÚ¶þ²½ÊÇÈ·¶¨ÌúÔªËصÄÖÊÁ¿£¬½ø¶ø¸ù¾Ý¸÷×ÔµÄÖÊÁ¿³ýÒÔ¸÷×ÔÏà¶ÔÔ­×ÓÖÊÁ¿ÇóË㻯ѧʽÖÐabµÄÊýֵȷ¶¨ÌúµÄ»¯ºÏÎïµÄ»¯Ñ§Ê½£®

½â´ð ½â£º£¨1£©ÈÜÒºÖÊÁ¿Ôö¼ÓÁ¿¾ÍÊÇÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿£¬ËùÒÔÉú³ÉµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª17.6g£¬ÆäÖÐËùº¬µÄÑõÔªËصÄÖÊÁ¿µÄÒ»°ëÀ´×ÔÓÚÌúµÄÑõ»¯ÎËùÒÔÌúµÄÑõ»¯ÎïÖеÄÑõÔªËصÄÖÊÁ¿Îª$\frac{16¡Á2}{12+16¡Á2}$¡Á$100%¡Á17.6g¡Á\frac{1}{2}$=6.4g£®
£¨2£©¸ù¾Ýͼ¿ÉÖª£¬Ìú¶ÔÓ¦µÄÇâÆøµÄÖÊÁ¿Îª0.6g£®
ÉèËùÓÃÏ¡ÁòËáÈÜÒºµÄÈÜÖÊÖÊÁ¿Îªx£¬ÌúµÄÖÊÁ¿Îªy
Fe+H₂SO₄=FeSO₄+H₂¡ü
56     98                 2
y        x            0.6g  
$\frac{56}{y}$=$\frac{98}{x}$=$\frac{2}{0.6g}$
x=29.4g    
y=16.8g
ËùÓÃÏ¡ÁòËáÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýΪ£º$\frac{29.4g}{60g}$¡Á100%=49%
£¨3£©ÌúÔ­×ӵĸöÊýºÍÑõÔ­×ӵĸöÊý±ÈΪa£ºb=$\frac{16.8g}{56}$£º$\frac{6.4g}{16}$=3£º4£®
´ð£º£¨1£©²½Öè IÖÐÉú³ÉÆøÌåµÄÖÊÁ¿Îª 17.6g£®
£¨2£©²½Öè IIËùÓÃÏ¡ÁòËáÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýΪ49%£®
£¨3£©¾­³ÆÁ¿£¬²½Öè I³ä·Ö¼ÓÈȺóÊ£Óà¹ÌÌåÖÊÁ¿Îª22.6g£®Ôò¸ÃÌúµÄÑõ»¯ÎﻯѧʽÖУ¬a¡¢bµÄ×î¼òÕûÊý±Èa£ºb=3£º4£®

µãÆÀ ¸ù¾Ý»¯Ñ§·½³Ìʽ¼ÆËãʱ£¬µÚÒ»ÒªÕýÈ·Êéд»¯Ñ§·½³Ìʽ£¬µÚ¶þҪʹÓÃÕýÈ·µÄÊý¾Ý£¬µÚÈý¼ÆËã¹ý³ÌÒªÍêÕû£®