Question

4£®°´ÒªÇóд³ö»¯Ñ§·½³Ìʽ£®
£¨1£©Ò»Ð©¹ÅÊ«´ÊÖг£Òþº¬¿Æѧ֪ʶ£¬ÈçÓÚÇ«µÄ¡¶Ê¯»ÒÒ÷¡·ÖоÍÉæ¼°µ½Ò»Ð©»¯Ñ§·´Ó¦£®¡°Ç§´¸ÍòÔä³öÉîɽ£¬ÁÒ»ð·ÙÉÕÈôµÈÏУ® ·ÛÉíËé¹ÇÈ«²»Å£¬ÒªÁôÇå°×ÔÚÈ˼䣮¡±Ð´³öÊ«¾äÖÐËùÉæ¼°µÄ»¯Ñ§·½³Ìʽ£º
¢ÙÁÒ»ð·ÙÉÕÈôµÈÏÐCaCO₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$CaO+CO₂¡ü£®
¢Ú·ÛÉíËé¹ÇÈ«²»ÅÂCaO+H₂O=Ca£¨OH£©₂£®
¢ÛÒªÁôÇå°×ÔÚÈ˼äCa£¨OH£©₂+CO₂=CaCO₃¡ý+H₂O£®
£¨2£©»ðÁ¦·¢µç³§ÅŷŵķÏÆøÖꬶþÑõ»¯ÁòÆøÌ壬Òò´ËÐèÒª¶Ô·ÏÆø½øÐд¦Àí£®
¢Ù¶þÑõ»¯ÁòÆøÌåÅŷŵ½¿ÕÆøÖлáÐγÉÁòËáÐÍËáÓ꣬д³öÐγÉÁòËáµÄ»¯Ñ§·½³Ìʽ2SO₂+2H₂O+O₂=2H₂SO₄£®
¢ÚÔÚ·ÏÆøÅÅ·ÅÑ̵ÀÖÐÅçÈ÷ÇâÑõ»¯ÄÆÈÜÒºÄÜÓÐЧÎüÊÕ¶þÑõ»¯ÁòÆøÌ壬д¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ2NaOH+SO₂=Na₂SO₃+H₂O£®
¢Ûʵ¼ÊÉÏ»ðÁ¦·¢µç³§²ÉÓõÄÎüÒý¼ÁÊÇÁ®¼ÛµÄʯ»Òʯ·Û½¬£¬Í¬Ê±ÔÚ·´Ó¦ÈÝÆ÷ÖйÄÈë¿ÕÆø£¬Õâ¸ö·´Ó¦¶Ô¶þÑõ»¯ÁòµÄÎüÊÕÂÊ´ï95%£¬Í¬Ê±»¹Äܵõ½Ê¯¸àÕâÖÖ¸±²úÆ·£¬²¢²úÉúÒ»ÖÖÎÞÉ«ÎÞζµÄÆøÌ壮д³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ2CaCO₃+2SO₂+O₂=2CaSO₄+2CO₂£®
£¨3£©ÒÑ֪ͭ²»ÄܺÍÏ¡ÁòËá·´Ó¦£¬µ«Í­ÄÜÓëŨÁòËá·´Ó¦£¬ÕâÖ÷ÒªÀûÓÃÁËŨÁòËáµÄÇ¿Ñõ»¯ÐÔ£®
¢ÙŨÏõËáÒ²¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬ÊµÑéÊÒ³£ÓÃÍ­ÓëŨÏõËá·´Ó¦À´ÖÆÈ¡ºì×ØÉ«µÄ¶þÑõ»¯µªÆøÌ壬д³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽCu+4HNO₃£¨Å¨£©=Cu£¨NO₃£©₂+2H₂O+2NO₂¡ü£®
¢ÚÏ¡ÏõËáÒ²¾ßÓнÏÇ¿µÄÑõ»¯ÐÔ£¬µ«ÆäÑõ»¯ÐÔÒªÈõÓÚŨÏõËᣬÇëÍƲâÍ­ÓëÏ¡ÏõËá·´Ó¦µÄ»¯Ñ§·½³Ìʽ3Cu+8HNO₃=3Cu£¨NO₃£©₂+4H₂O+2NO¡ü£®

Answer 1

·ÖÎö £¨1£©¢Ù¸ù¾Ý̼Ëá¸ÆÔÚ¸ßεÄÌõ¼þÏÂÉú³ÉÑõ»¯¸ÆºÍ¶þÑõ»¯Ì¼½øÐзÖÎö£»
¢Ú¸ù¾ÝÑõ»¯¸ÆºÍË®·´Ó¦Éú³ÉÇâÑõ»¯¸Æ½øÐзÖÎö£»
¢Û¸ù¾ÝÇâÑõ»¯¸ÆºÍ¶þÑõ»¯Ì¼·´Ó¦Éú³É̼Ëá¸Æ³ÁµíºÍË®½øÐзÖÎö£»
£¨2£©¢Ù¸ù¾Ý¶þÑõ»¯Áò¡¢Ë®ºÍÑõÆø·´Ó¦Éú³ÉÁòËá½øÐзÖÎö£»
¢Ú¸ù¾ÝÇâÑõ»¯ÄƺͶþÑõ»¯Áò·´Ó¦Éú³ÉÑÇÁòËáÄƺÍË®½øÐзÖÎö£»
¢Û¸ù¾Ý̼Ëá¸Æ¡¢¶þÑõ»¯ÁòºÍÑõÆø·´Ó¦Éú³ÉÁòËá¸ÆºÍ¶þÑõ»¯Ì¼½øÐзÖÎö£»
£¨3£©¢Ù¸ù¾ÝÍ­ºÍŨÏõËá·´Ó¦Éú³ÉÏõËáÍ­¡¢Ë®ºÍ¶þÑõ»¯µª½øÐзÖÎö£»
¢Ú¸ù¾ÝÍ­ºÍÏ¡ÏõËá·´Ó¦Éú³ÉÏõËáÍ­¡¢Ë®ºÍÒ»Ñõ»¯µª½øÐзÖÎö£®

½â´ð ½â£º£¨1£©¢Ù̼Ëá¸ÆÔÚ¸ßεÄÌõ¼þÏÂÉú³ÉÑõ»¯¸ÆºÍ¶þÑõ»¯Ì¼£¬»¯Ñ§·½³ÌʽΪ£ºCaCO₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$CaO+CO₂¡ü£»
¢ÚÑõ»¯¸ÆºÍË®·´Ó¦Éú³ÉÇâÑõ»¯¸Æ£¬»¯Ñ§·½³ÌʽΪ£ºCaO+H₂O=Ca£¨OH£©₂£»
¢ÛÇâÑõ»¯¸ÆºÍ¶þÑõ»¯Ì¼·´Ó¦Éú³É̼Ëá¸Æ³ÁµíºÍË®£¬»¯Ñ§·½³ÌʽΪ£ºCa£¨OH£©₂+CO₂=CaCO₃¡ý+H₂O£»
£¨2£©¢Ù¶þÑõ»¯Áò¡¢Ë®ºÍÑõÆø·´Ó¦Éú³ÉÁòËᣬ»¯Ñ§·½³ÌʽΪ£º2SO₂+2H₂O+O₂=2H₂SO₄£»
¢ÚÇâÑõ»¯ÄƺͶþÑõ»¯Áò·´Ó¦Éú³ÉÑÇÁòËáÄƺÍË®£¬»¯Ñ§·½³ÌʽΪ£º2NaOH+SO₂=Na₂SO₃+H₂O£»
¢Û̼Ëá¸Æ¡¢¶þÑõ»¯ÁòºÍÑõÆø·´Ó¦Éú³ÉÁòËá¸ÆºÍ¶þÑõ»¯Ì¼£¬»¯Ñ§·½³ÌʽΪ£º2CaCO₃+2SO₂+O₂=2CaSO₄+2CO₂£»
£¨3£©¢ÙÍ­ºÍŨÏõËá·´Ó¦Éú³ÉÏõËáÍ­¡¢Ë®ºÍ¶þÑõ»¯µª£¬»¯Ñ§·½³ÌʽΪ£ºCu+4HNO₃£¨Å¨£©=Cu£¨NO₃£©₂+2H₂O+2NO₂¡ü£»
¢ÚÍ­ºÍÏ¡ÏõËá·´Ó¦Éú³ÉÏõËáÍ­¡¢Ë®ºÍÒ»Ñõ»¯µª£¬»¯Ñ§·½³ÌʽΪ£º3Cu+8HNO₃=3Cu£¨NO₃£©₂+4H₂O+2NO¡ü£®
¹Ê´ð°¸Îª£º£¨1£©¢ÙCaCO₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$CaO+CO₂¡ü£»
¢ÚCaO+H₂O=Ca£¨OH£©₂£»
¢ÛCa£¨OH£©₂+CO₂=CaCO₃¡ý+H₂O£»
£¨2£©¢Ù2SO₂+2H₂O+O₂=2H₂SO₄£»
¢Ú2NaOH+SO₂=Na₂SO₃+H₂O£»
¢Û2CaCO₃+2SO₂+O₂=2CaSO₄+2CO₂£»
£¨3£©¢ÙCu+4HNO₃£¨Å¨£©=Cu£¨NO₃£©₂+2H₂O+2NO₂¡ü£»
¢Ú3Cu+8HNO₃=3Cu£¨NO₃£©₂+4H₂O+2NO¡ü£®

µãÆÀ ÔÚ½â´ËÀàÌâʱ£¬Ê×ÏÈ·ÖÎöÓ¦ÓõÄÔ­Àí£¬È»ºóÕÒ³ö·´Ó¦Îï¡¢Éú³ÉÎ×îºó½áºÏ·½³ÌʽµÄÊéд¹æÔòÊéд·½³Ìʽ£®