»¯Ñ§ÎªÈËÀàÉç»áµÄ¿É³ÖÐø·¢Õ¹×ö³öÁ˾޴ó¹±Ï×£®
£¨1£©Ä¿Ç°ÈËÀàͨ¹ý»¯Ñ§·´Ó¦»ñµÃµÄÄÜÁ¿´ó¶àÀ´×ÔÓÚ______¡¢Ê¯ÓÍ¡¢ÌìÈ»ÆøµÈ»¯Ê¯È¼ÁÏ£®
£¨2£©ÇâÆøÊÇδÀ´µÄÀíÏëÄÜÔ´£¬¿ÉÒÔ×÷Ϊ»¯¹¤Éú²úµÄÖØÒªÔ­ÁÏ£¬Ò²¿ÉÒÔ×÷º½Ì칤ҵµÄ¸ßÄÜȼÁÏ£¬ÆäȼÉյĻ¯Ñ§·½³ÌʽÊÇ______£®
£¨3£©¿ª·¢ºÍÀûÓÃÇå½à¶ø¸ßЧµÄÐÂÄÜÔ´Ìæ´ú´«Í³ÄÜÔ´£ºÇâÆøÊÇδÀ´×îÀíÏëµÄÄÜÔ´£¬ÄãÈÏΪ×îÀíÏëµÄÖÆÇâ·½·¨ÊÇ______£¨ÌîÐòºÅ£©£®
A£®µç½âË®£º2H2O¨T2H2¡ü+O2¡ü
B£®½¹Ì¿ÓëË®ÕôÆø·´Ó¦£ºC+H2O
 ¸ßΠ
.
 
H2+CO
C£®Ì«Ñô¹â·Ö½âË®£º2H2O
     Li2O     
.
Ì«Ñô¹â
2H2¡ü+O2¡ü
D£®ÌìÈ»ÆøÓëË®ÕôÆø·´Ó¦£ºCH4+H2O
 ¸ßΠ
.
 
CO+3H2£®
£¨1£©Ä¿Ç°ÈËÀàͨ¹ý»¯Ñ§·´Ó¦»ñµÃµÄÄÜÁ¿´ó¶àÀ´×ÔÓÚú¡¢Ê¯ÓÍ¡¢ÌìÈ»ÆøµÈ»¯Ê¯È¼ÁÏ£»
£¨2£©ÇâÆøȼÉÕÉú³ÉÁËË®£¬·´Ó¦µÄ·½³ÌʽÊÇ£º2H2+O2
 µãȼ 
.
 
2H2O£»
£¨3£©ÓÉÖÆÈ¡ÇâÆøµÄ¸÷»¯Ñ§·´Ó¦·½³Ìʽ¿ÉÖª£¬ACµÄÉú³ÉÎïÊÇÇâÆøºÍÑõÆø£»BDµÄÉú³ÉÎïÊÇÒ»Ñõ»¯Ì¼ºÍÇâÆø£®¿É¼ûÀíÏëµÄÖÆÈ¡ÇâÆøµÄ·½·¨ÊÇAC£¬´Ó·´Ó¦Ìõ¼þ¿ÉÖª£¬CÊÇÀûÓÃÌ«Ñô¹â£¬½ÚÔ¼ÄÜÔ´£®ËùÒÔ×îÀíÏëµÄÊÇC£®
¹Ê´ðΪ£º£¨1£©Ãº£»£¨2£©2H2+O2
 µãȼ 
.
 
2H2O£»£¨3£©C£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?ÄÏÄþ£©»¯Ñ§ÎªÈËÀàÉç»áµÄ¿É³ÖÐø·¢Õ¹×ö³öÁ˾޴ó¹±Ï×£®
£¨1£©¼ÒÓÃÌ«ÑôÄÜ·¢µçÉ豸ÓëÌ«ÑôÄÜÈÈË®Æ÷Ò»Ñù£¬Ö»Òª½«Ò»¸öÌ«ÑôÄÜ°å·ÅÔÚÂ¥¶¥£¬¾ÍÄÜͨ¹ýÌ«ÑôÄܸø¼ÒÀï·¢µç£®´Ó»¯Ñ§½Ç¶È¿´£¬Ì«ÑôÄÜ×÷ΪÐÂÄÜÔ´µÄÖ÷ÒªÓŵãÓУ¨´ðÁ½µã£©£º¢Ù
Ì«ÑôÄÜ·Ö²¼¹ãÀ«£¬»ñÈ¡·½±ã
Ì«ÑôÄÜ·Ö²¼¹ãÀ«£¬»ñÈ¡·½±ã
¢Ú
Çå½à²»»áÔì³É»·¾³ÎÛȾ
Çå½à²»»áÔì³É»·¾³ÎÛȾ
£®
£¨2£©ÇâÆøÊÇδÀ´µÄÀíÏëÄÜÔ´£¬¿ÉÒÔ×÷Ϊ»¯¹¤Éú²úµÄÖØÒªÔ­ÁÏ£¬Ò²¿ÉÒÔ×÷º½Ì칤ҵµÄ¸ßÄÜȼÁÏ£¬ÆäȼÉյĻ¯Ñ§·½³ÌʽÊÇ
2H2+O2
 µãȼ 
.
 
2H2O
2H2+O2
 µãȼ 
.
 
2H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

»¯Ñ§ÎªÈËÀàÉç»áµÄ¿É³ÖÐø·¢Õ¹×ö³öÁ˾޴ó¹±Ï×£®
£¨1£©Ä¿Ç°ÈËÀàͨ¹ý»¯Ñ§·´Ó¦»ñµÃµÄÄÜÁ¿´ó¶àÀ´×ÔÓÚ
ú
ú
¡¢Ê¯ÓÍ¡¢ÌìÈ»ÆøµÈ»¯Ê¯È¼ÁÏ£®
£¨2£©ÇâÆøÊÇδÀ´µÄÀíÏëÄÜÔ´£¬¿ÉÒÔ×÷Ϊ»¯¹¤Éú²úµÄÖØÒªÔ­ÁÏ£¬Ò²¿ÉÒÔ×÷º½Ì칤ҵµÄ¸ßÄÜȼÁÏ£¬ÆäȼÉյĻ¯Ñ§·½³ÌʽÊÇ
2H2+O2
 µãȼ 
.
 
2H2O
2H2+O2
 µãȼ 
.
 
2H2O
£®
£¨3£©¿ª·¢ºÍÀûÓÃÇå½à¶ø¸ßЧµÄÐÂÄÜÔ´Ìæ´ú´«Í³ÄÜÔ´£ºÇâÆøÊÇδÀ´×îÀíÏëµÄÄÜÔ´£¬ÄãÈÏΪ×îÀíÏëµÄÖÆÇâ·½·¨ÊÇ
C
C
£¨ÌîÐòºÅ£©£®
A£®µç½âË®£º2H2O¨T2H2¡ü+O2¡ü
B£®½¹Ì¿ÓëË®ÕôÆø·´Ó¦£ºC+H2O
 ¸ßΠ
.
 
H2+CO
C£®Ì«Ñô¹â·Ö½âË®£º2H2O
     Li2O     
.
Ì«Ñô¹â
2H2¡ü+O2¡ü
D£®ÌìÈ»ÆøÓëË®ÕôÆø·´Ó¦£ºCH4+H2O
 ¸ßΠ
.
 
CO+3H2£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

»¯Ñ§ÎªÈËÀàÉç»áµÄ¿É³ÖÐø·¢Õ¹×ö³öÁ˾޴ó¹±Ï×£®
£¨1£©Ä¿Ç°ÈËÀàͨ¹ý»¯Ñ§·´Ó¦»ñµÃµÄÄÜÁ¿´ó¶àÀ´×ÔÓÚ________¡¢Ê¯ÓÍ¡¢ÌìÈ»ÆøµÈ»¯Ê¯È¼ÁÏ£®
£¨2£©ÇâÆøÊÇδÀ´µÄÀíÏëÄÜÔ´£¬¿ÉÒÔ×÷Ϊ»¯¹¤Éú²úµÄÖØÒªÔ­ÁÏ£¬Ò²¿ÉÒÔ×÷º½Ì칤ҵµÄ¸ßÄÜȼÁÏ£¬ÆäȼÉյĻ¯Ñ§·½³ÌʽÊÇ________£®
£¨3£©¿ª·¢ºÍÀûÓÃÇå½à¶ø¸ßЧµÄÐÂÄÜÔ´Ìæ´ú´«Í³ÄÜÔ´£ºÇâÆøÊÇδÀ´×îÀíÏëµÄÄÜÔ´£¬ÄãÈÏΪ×îÀíÏëµÄÖÆÇâ·½·¨ÊÇ________£¨ÌîÐòºÅ£©£®
A£®µç½âË®£º2H2O¨T2H2¡ü+O2¡ü
B£®½¹Ì¿ÓëË®ÕôÆø·´Ó¦£ºC+H2OÊýѧ¹«Ê½H2+CO
C£®Ì«Ñô¹â·Ö½âË®£º2H2OÊýѧ¹«Ê½2H2¡ü+O2¡ü
D£®ÌìÈ»ÆøÓëË®ÕôÆø·´Ó¦£ºCH4+H2OÊýѧ¹«Ê½CO+3H2£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

»¯Ñ§ÎªÈËÀàÉç»áµÄ¿É³ÖÐø·¢Õ¹×ö³öÁ˾޴ó¹±Ïס£
£¨1£©¼ÒÓÃÌ«ÑôÄÜ·¢µçÉè¸÷ÓëÌ«ÑôÄÜÈÈË®Æ÷Ò»Ñù£¬Ö»Òª½«Ò»¸öÌ«ÑôÄÜ°å·ÅÔÚÂ¥¶¥£¬¾ÍÄÜͨ¹ýÌ«ÑôÄܸø¼ÒÀï·¢µç¡£´Ó»¯Ñ§½Ç¶È¿´£¬Ì«ÑôÄÜ×÷ΪÐÂÄÜÔ´µÄÖ÷ÒªÓŵãÓУ¨´ðÁ½µã£©£º¢Ù       £»¢Ú        ¡£
£¨2£©ÇâÆøÊÇδÀ´µÄÀíÏëÄÜÔ´£¬¿ÉÒÔ×÷Ϊ»¯¹¤Éú²úµÄÖØÒªÔ­ÁÏ£¬Ò²¿ÉÒÔ×÷º½Ì칤ҵµÄ¸ßÄÜȼÁÏ£¬ÆäȼÉյĻ¯Ñ§·½³ÌʽÊÇ                     ¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸