ÇëÓÃËùѧ»¯Ñ§ÖªÊ¶½âÊÍÏÂÁÐÔ­Àí£®
£¨1£©±»ÓêË®ÁÜʪµÄ×ÔÐгµ£¬ÎªÊ²Ã´ÐëÏÈÓøÉĨ²¼²Á¾»ºó²ÅÄÜÓôøÓ͵ÄĨ²¼²Á£¿
ÒòΪ×ÔÐгµÓëË®ºÍÑõÆøͬʱ½Ó´¥Ê±ÈÝÒ×ÉúÐâ
ÒòΪ×ÔÐгµÓëË®ºÍÑõÆøͬʱ½Ó´¥Ê±ÈÝÒ×ÉúÐâ
£®
£¨2£©Éú»îÖÐΪ½µµÍË®µÄÓ²¶È²¢É±ÃðË®Öв¡Ô­ÉúÎ¿É²ÉÓõķ½·¨ÊÇ
¼ÓÈÈÖó·Ð
¼ÓÈÈÖó·Ð
£®
£¨3£©ÎÒ¹úÄϺ£º£µ×Âñ²Ø×ŷḻµÄ¡°¿Éȼ±ù¡±£¬¡°¿Éȼ±ù¡±Ö÷ҪΪ¼×ÍéµÄË®ºÏÎÊÇδÀ´ÖØÒªµÄÄÜÔ´¼×ÍéȼÉÕʱ£¬·Å³ö´óÁ¿µÄÈÈ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
CH4+2O2
 µãȼ 
.
 
CO2+2H2O
CH4+2O2
 µãȼ 
.
 
CO2+2H2O
£®
£¨4£©Ó²Ë®Öк¬ÓпÉÈÜÐÔµÄCa£¨HCO3£©2ÔÚ¼ÓÈÈ»ò¾ÃÖÃʱ£¬»á²úÉúË®¹¸[Ö÷Òª³É·ÖÊÇCaCO3 ºÍMg£¨OH£©2]£¬Éú»îÖпÉÓÃÊÊÁ¿Ï¡ÑÎËá³ýÈ¥ÈÈˮƿ±ÚÉϵÄË®¹¸£¬Ð´³öÓйط´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
CaCO3+2HCl¨TCaCl2+H2O+CO2¡ü
CaCO3+2HCl¨TCaCl2+H2O+CO2¡ü
¡¢
Mg£¨OH£©2+2HCl¨TMgCl2+2H2O
Mg£¨OH£©2+2HCl¨TMgCl2+2H2O
£®
·ÖÎö£º£¨1£©ÌúÓëË®ºÍÑõÆøͬʱ½Ó´¥Ê±ÈÝÒ×ÉúÐ⣬ÓÍ¿ÉÒÔÔÚÌúÖÆÆ·ÉÏÐγɱ£»¤Ä¤£»
£¨2£©º¬Óн϶à¸ÆÀë×Ó¡¢Ã¾Àë×ÓµÄË®ÊôÓÚӲˮ£¬¼ÓÈÈʱ¸ÆÀë×Ó¡¢Ã¾Àë×ÓÄܹ»ÒÔ̼Ëá¸Æ¡¢ÇâÑõ»¯Ã¾µÄÐÎʽ´ÓË®ÖÐÎö³ö£¬´Ó¶ø½µµÍË®µÄÓ²¶È£»
£¨3£©¼×ÍéȼÉÕÄÜÉú³ÉË®ºÍ¶þÑõ»¯Ì¼£¬Êéд»¯Ñ§·½³ÌʽʱҪ×ñÑ­ÖÊÁ¿Êغ㶨ÂÉ£»
£¨4£©Ì¼Ëá¸ÆÊôÓÚ̼ËáÑΣ¬ÄܺÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯¸Æ¡¢Ë®ºÍ¶þÑõ»¯Ì¼£»ÇâÑõ»¯Ã¾ÊôÓڼÄܺÍÏ¡ÑÎËá·¢ÉúÖкͷ´Ó¦£¬Éú³ÉÂÈ»¯Ã¾ºÍË®£®
½â´ð£º½â£º£¨1£©±»ÓêË®ÁÜʪµÄ×ÔÐгµ£¬Èç¹ûÖ±½ÓÓÃÓôøÓ͵ÄĨ²¼²Á£¬ÐγɵÄÓÍĤ°ÑË®°üΧÔÚÀïÃ棬ˮ²»ÈÝÒ×»Ó·¢£¬×ÔÐгµÈÝÒ×ÉúÐ⣬Èç¹ûÏÈÓøÉĨ²¼²Á¾»ºóÔÙÓôøÓ͵ÄĨ²¼²Á£¬ÐγɵÄÓÍĤÄÜʹ×ÔÐгµºÍË®¡¢ÑõÆø¸ô¾ø£¬×ÔÐгµ²»ÈÝÒ×ÉúÐ⣮
¹ÊÌÒòΪ×ÔÐгµÓëË®ºÍÑõÆøͬʱ½Ó´¥Ê±ÈÝÒ×ÉúÐ⣮
£¨2£©¼ÓÈÈÖó·Ðʱ£¬»á¼õÉÙË®ÖеĸÆÀë×Ó¡¢Ã¾Àë×Ó£¬Äܹ»½µµÍË®µÄÓ²¶È£¬Í¬Ê±ÔÚ¸ßÎÂÌõ¼þÏ£¬Ë®ÖеIJ¡Ô­ÉúÎï²»ÈÝÒ×´æ»î£¬ËùÒÔ¼ÓÈÈÖó·Ð¼È¿ÉÒÔ½µµÍË®µÄÓ²¶È£¬ÓÖ¿ÉÒÔɱÃðË®Öв¡Ô­ÉúÎ
¹ÊÌ¼ÓÈÈÖó·Ð£®
£¨3£©¼×ÍéÊÇ̼Ç⻯ºÏÎÍêȫȼÉÕÄÜÉú³ÉË®ºÍ¶þÑõ»¯Ì¼£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽµÄΪ£ºCH4+2O2
 µãȼ 
.
 
CO2+2H2O£®
¹ÊÌCH4+2O2
 µãȼ 
.
 
CO2+2H2O£®
£¨4£©Ì¼Ëá¸ÆºÍÏ¡ÑÎËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCO3+2HCl¨TCaCl2+H2O+CO2¡ü£¬ÇâÑõ»¯Ã¾ºÍÏ¡ÑÎËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºMg£¨OH£©2+2HCl¨TMgCl2+2H2O£®
¹ÊÌCaCO3+2HCl¨TCaCl2+H2O+CO2¡ü£»Mg£¨OH£©2+2HCl¨TMgCl2+2H2O£®
µãÆÀ£ºÊéд»¯Ñ§·½³ÌʽҪעÒâËĸö²½Ö裺һ¡¢·´Ó¦ÎïºÍÉú³ÉÎïµÄ»¯Ñ§Ê½ÒªÕýÈ·£»¶þ¡¢Òª×ñÑ­ÖÊÁ¿Êغ㶨ÂÉ£¬¼´Åäƽ»¯Ñ§·½³Ìʽ£»Èý¡¢ÒªÓбØÒªµÄÌõ¼þ£»ËÄ¡¢Òª·ÖÎöÊÇ·ñÓС°¡ü¡±»ò¡°¡ý¡±£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2013?Ðí²ýһģ£©ÇëÓÃËùѧ»¯Ñ§ÖªÊ¶½âÊÍÏÂÁÐÔ­Àí£®
£¨1£©Ï´µÓ¼ÁÄܹ»³ýÈ¥ÓÍÎÛµÄÔ­ÒòÊÇʲô£¿
£¨2£©»ðÔÖÏÖ³¡£¬Ïû·ÀսʿʹÓøßѹˮǹÃð»ðµÄÔ­ÀíÊÇʲô£¿
£¨3£©Éúʯ»ÒΪʲô¿ÉÓÃ×÷ʳƷµÄ¸ÉÔï¼Á£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2013?¶õÖÝ£©ÇëÓÃËùѧ»¯Ñ§ÖªÊ¶½âÊÍÏÂÁÐÔ­Àí£®
£¨1£©ÓûîÐÔÌ¿³ýÈ¥±ùÏäÀïµÄÒì棬ÊÇÀûÓÃÆä
Îü¸½
Îü¸½
ÐÔ£®
£¨2£©ÊÔÓÃÎÄ×Ö½âÊÍΪʲôÂÁÖÆÆ·¾ßÓÐÁ¼ºÃµÄ¿¹¸¯Ê´ÐÔÄÜ£º
ÂÁÓë¿ÕÆøÖеÄÑõÆøÐγÉÖÂÃܵÄÑõ»¯ÂÁ±¡Ä¤£¬×èÖ¹ÂÁ½øÒ»²½±»Ñõ»¯
ÂÁÓë¿ÕÆøÖеÄÑõÆøÐγÉÖÂÃܵÄÑõ»¯ÂÁ±¡Ä¤£¬×èÖ¹ÂÁ½øÒ»²½±»Ñõ»¯
£®
£¨3£©¹¤ÒµÉÏ¿ÉÓÃCl2ÓëNAOHÈÜÒº×÷ÓÃÖÆƯ°×·Û£ºCl2+2NaOH¨TNaCl+NaClO+H2O£®Óë´ËÀàËÆ£¬¿ÉÓÃCl2Óëʯ»ÒÈ飨Ö÷Òª³É·ÖCa£¨OH£©2£©ÖÆƯ°×·Û£¬ÊÔд³ö´Ë·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
2Cl2+2Ca£¨OH£©2=CaCl2+Ca£¨ClO£©2+2H2O
2Cl2+2Ca£¨OH£©2=CaCl2+Ca£¨ClO£©2+2H2O
£®
£¨4£©¼Ù»Æ½ð£¨Cu£¬ZnºÏ½ð£©Íâ¹ÛÓë»Æ½ð£¨Au£©¼°ÆäÏàËÆ£®ÊÔ¸ù¾Ý½ðÊôµÄÐÔÖÊд³ö¼ø±ðʱÓëÈýÀ಻ͬÎïÖÊ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£¨Ã¿Àà¸÷дһ¸ö»¯Ñ§·½³Ìʽ£©£º
¢Ù
2Cu+O2
  ¡÷  
.
 
2CuO£¨»ò2Zn+O2
  ¡÷  
.
 
2ZnO£©
2Cu+O2
  ¡÷  
.
 
2CuO£¨»ò2Zn+O2
  ¡÷  
.
 
2ZnO£©
£»
¢Ú
Zn+2HCl=ZnCl2+H2¡ü
Zn+2HCl=ZnCl2+H2¡ü
£»
¢Û
Cu+2AgNO3=Cu£¨NO3£©2+2Ag
Cu+2AgNO3=Cu£¨NO3£©2+2Ag
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÇëÓÃËùѧ»¯Ñ§ÖªÊ¶½âÊÍÏÂÁÐÔ­Àí£®
£¨1£©6000LÑõÆøÔÚ¼ÓѹµÄÇé¿öÏ¿ÉÒÔ×°Èë40LµÄ¸ÖÆ¿ÖУ®
£¨2£©´Ó΢¹Û½Ç¶È½âÊÍCO2ºÍCOÔªËØ×é³ÉÏàͬ£¬µ«¶þÕßÐÔÖÊÈ´²îÒìºÜ´ó£®
£¨3£©Óû¯Ñ§·½³Ìʽ±íʾ¹¤ÒµÉÏÓý¹Ì¿ÓëÌú¿óʯ£¨Ö÷Òª³É·ÖFe2O3£©·´Ó¦Á¶Ìú£®
£¨4£©×öľ̿ÔÚÑõÆøÀïȼÉÕʵÑéʱ£¬ºìÈȵÄľ̿ΪʲôҪÓÉÆ¿¿ÚÏòÏ»ºÂý²åÈ룮

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÇëÓÃËùѧ»¯Ñ§ÖªÊ¶½âÊÍÏÂÁÐÔ­Àí£®
£¨1£©¸øú¯Éú»ðʱ£¬ÓÃÓÚÒý»ðµÄľ²ñÓ¦¼Ü¿Õ¶ø²»Ò˽ôÃܶÑÔÚÒ»Æð£¬ÆäÄ¿µÄÊÇʲô£¿
£¨2£©ÈÕ³£Éú»îÖÐʹÓÃӲˮ»á´øÀ´Ðí¶àÂé·³£¬¼ÒÍ¥Éú»îÖг£ÓÃÀ´½µµÍˮӲ¶ÈµÄ·½·¨ÊÇ
Öó·Ð
Öó·Ð
£®
£¨3£©Óû¯Ñ§·½³Ìʽ±íʾΪʲô²»ÄÜÓÃÌúÖÆÈÝÆ÷Ê¢·ÅÁòËáÍ­£®
CuSO4+Fe=FeSO4+Cu
CuSO4+Fe=FeSO4+Cu

£¨4£©ÍâÆÅÔÚ¸øСǿ¼åºÉ°üµ°Ê±£¬·¢ÏÖ·ÅÈë³ø¹ñÄڵļ¦µ°Óв¿·Ö±ä³ôÁË£®Ð¡Ç¿¸ù¾ÝËùѧ»¯Ñ§ÖªÊ¶½¨ÒéÍâÆÅ£º¡°¿É½«¼¦µ°½þÓÚʯ»ÒË®ºóÀ̳ö±£´æ£®¡±ÕâÑù¾Í²»Òױ仵£¬ÄãÄܽâÊÍΪʲôÂð£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÇëÓÃËùѧ»¯Ñ§ÖªÊ¶½âÊÍÏÂÁÐÊÂʵ£º
£¨1£©Ï´µÓ¼ÁÄܳýÈ¥ÓÍÎÛ£¬ÊÇÒòΪËü¾ßÓÐ
 
¹¦ÄÜ£®
£¨2£©½ðÇïʱ½Ú£¬¹Å³Ç¿ª·â´¦´¦¶¼ÄÜÎŵ½âùÈ˵ľջ¨ÏãÆø£®
£¨3£©Ã¾ÌõÔÚ¿ÕÆøÖÐȼÉÕºó£¬Éú³ÉÎïµÄÖÊÁ¿±ÈÔ­À´Ã¾ÌõµÄÖÊÁ¿Ôö´ó£®
£¨4£©Å£ÄÌÔÚÏÄÌì±È¶¬Ìì¸üÈÝÒ×±äËᣮ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸