Question

1£®»¯Ñ§ÊµÑéÊǽøÐпÆѧ̽¾¿µÄÖØÒª·½Ê½£®
£¨1£©¸ù¾Ýͼ»Ø´ðÎÊÌ⣮

¢Ù×°ÖÃÖбꡰa¡±µÄÒÇÆ÷Ãû³ÆÊÇÊԹܣ»
¢ÚʵÑéÊÒÖƱ¸¡¢ÊÕ¼¯¶þÑõ»¯Ì¼Ñ¡ÓõÄ×°ÖÃΪBE£¨ÌîÐòºÅ£©£»
¢ÛʵÑéÊÒÓøßÃÌËá¼ØÖÆÈ¡ÑõÆøµÄ»¯Ñ§·½³ÌʽΪ2KMnO₄$\frac{\underline{\;\;¡÷\;\;}}{\;}$K₂MnO₄+MnO₂+O₂¡ü£®
£¨2£©ÈçͼװÖÿÉ×öÒ»Ñõ»¯Ì¼»¹Ô­Ñõ»¯ÌúµÄʵÑ飬²¢¼ìÑéÉú³ÉµÄÆøÌå²úÎ

¢ÙB×°Öò£Á§¹ÜÀï¿É¹Û²ìµ½µÄÏÖÏóÊǺìÉ«¹ÌÌå±äºÚÉ«£»·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º3CO+Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3CO₂£®
¢ÚC×°ÖÃÖз´Ó¦µÄ»¯Ñ§·½³ÌʽΪCa£¨OH£©₂+CO₂=CaCO₃¡ý+H₂O£®
£¨3£©Ä³Í¬Ñ§ÔÚ̽¾¿Öкͷ´Ó¦ÊµÑéʱÉè¼ÆÈçÏ·½°¸£º½«ÊÊÁ¿Ï¡ÑÎËáµ¹Èë׶ÐÎÆ¿ÖУ¬µÎÈë·Ó̪ÈÜÒººó£¬ÂýÂýµÎ¼ÓÇâÑõ»¯ÄÆÈÜÒº²¢²»¶Ï½Á°è£¬Í¨¹ýÈÜÒº¸Õ¸Õ±äºìÀ´ÅжÏÖкͷ´Ó¦Ç¡ºÃÍê³É£®Çë·ÖÎöÉÏÊö·½°¸ÊÇ·ñºÏÀí²¢ËµÃ÷ÀíÓÉ£®
£¨4£©½«Ò»¶¨ÖÊÁ¿µÄNaHCO₃ÈÜÒºÓë100gÏ¡ÑÎËá»ìºÏ£¬¶þÕßÇ¡ºÃÍêÈ«·´Ó¦£¬ÈÜÒºµÄ×ÜÖÊÁ¿¼õÉÙ8.8g£®Çó£ºÏ¡ÑÎËáÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý£®

Answer 1

·ÖÎö £¨1£©Êì¼Ç³£¼ûÒÇÆ÷Ãû³ÆÓëÓÃ;£»ÊµÑéÊÒͨ³£ÓôóÀíʯ»òʯ»ÒʯºÍÏ¡ÑÎËá·´Ó¦ÖÆÈ¡¶þÑõ»¯Ì¼£¬·´Ó¦²»ÐèÒª¼ÓÈÈ£¬¶þÑõ»¯Ì¼Äܹ»ÈÜÓÚË®£¬ÃܶȱȿÕÆø´ó£®¸ßÃÌËá¼ØÊÜÈÈʱÄܹ»·Ö½âÉú³ÉÃÌËá¼Ø¡¢¶þÑõ»¯Ã̺ÍÑõÆø£®
£¨2£©¢Ù¸ù¾ÝÑõ»¯ÌúºÍÒ»Ñõ»¯Ì¼ÔÚ¸ßεÄÌõ¼þÏÂÉú³ÉÌúºÍ¶þÑõ»¯Ì¼½øÐзÖÎö£»
¢Ú¸ù¾Ý¶þÑõ»¯Ì¼ºÍÇâÑõ»¯¸Æ·´Ó¦Éú³É̼Ëá¸Æ³ÁµíºÍË®½øÐзÖÎö£»
£¨3£©¸ù¾Ý·Ó̪ÈÜÒºÓöÇâÑõ»¯ÄÆÈÜÒº±äºì½â´ð£®
£¨4£©¸ù¾Ý̼ËáÇâÄƺÍÑÎËá·´Ó¦Éú³ÉÂÈ»¯ÄÆ¡¢Ë®ºÍ¶þÑõ»¯Ì¼£¬ÒÀ¾Ý¶þÑõ»¯Ì¼µÄÖÊÁ¿½øÐмÆË㣮

½â´ð ½â£º£¨1£©¢ÙaÊÇÊԹܣ»¢ÚÔÚʵÑéÊÒÖУ¬ÖÆÈ¡¶þÑõ»¯Ì¼²»ÐèÒª¼ÓÈÈ£¬Ó¦¸ÃÓÃB×°ÖÃ×÷Ϊ·¢Éú×°Ö㻶þÑõ»¯Ì¼Äܹ»ÈÜÓÚË®£¬²»ÄÜÓÃÅÅË®·¨ÊÕ¼¯£¬ÃܶȱȿÕÆø´ó£¬¿ÉÒÔÓÃÏòÉÏÅÅ¿ÕÆø·¨ÊÕ¼¯£¬¼´ÓÃE×°ÖÃÊÕ¼¯£»¹ÊÌB¡¢E£»
¢Û¸ßÃÌËá¼ØÊÜÈÈʱÄܹ»·Ö½âÉú³ÉÃÌËá¼Ø¡¢¶þÑõ»¯Ã̺ÍÑõÆø£¬·½³ÌʽΪ£º2KMnO₄$\frac{\underline{\;\;¡÷\;\;}}{\;}$K₂MnO₄+MnO₂+O₂¡ü£»
£¨3£©¢ÙÑõ»¯ÌúºÍÒ»Ñõ»¯Ì¼ÔÚ¸ßεÄÌõ¼þÏÂÉú³ÉÌúºÍ¶þÑõ»¯Ì¼£¬ËùÒÔB×°Öò£Á§¹ÜÀï¿É¹Û²ìµ½µÄÏÖÏóΪ£ººìÉ«¹ÌÌå±äºÚ£»»¯Ñ§·½³ÌʽΪ£º3CO+Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3CO₂£»
¢Ú¶þÑõ»¯Ì¼ºÍÇâÑõ»¯¸Æ·´Ó¦Éú³É̼Ëá¸Æ³ÁµíºÍË®£¬»¯Ñ§·½³ÌʽΪ£ºCO₂+Ca£¨OH£©₂=CaCO₃¡ý+H₂O£»
£¨3£©½«ÊÊÁ¿Ï¡ÑÎËáµ¹Èë׶ÐÎÆ¿ÖУ¬µÎÈë·Ó̪ÈÜÒººó£¬ÂýÂýµÎ¼ÓÇâÑõ»¯ÄÆÈÜÒº²¢²»¶Ï½Á°è£®Ç¡ºÃÍêÈ«ÖкÍʱÈÜÒº²»±äÉ«£»ÈÜÒº¸Õ¸Õ±äºì£¬ËµÃ÷ÇâÑõ»¯ÄÆÒѾ­¹ýÁ¿£®
£¨4£©Éè²Î¼Ó·´Ó¦µÄÑÎËáµÄÖÊÁ¿Îªx
NaHCO₃+HCl=NaCl+H₂O+CO₂¡ü
              36.5                    44
                 x                     8.8g
$\frac{36.5}{x}=\frac{44}{8.8g}$        
        x=7.3g
ËùÒÔÏ¡ÑÎËáÕâÈÜÖʵÄÖÊÁ¿·ÖÊýΪ£º$\frac{7.3g}{100g}$¡Á100%=7.3%£®
¹Ê´ð°¸Îª£º£¨1£©¢ÙÊԹܣ»¢ÚB E£» ¢Û2KMnO₄$\frac{\underline{\;\;¡÷\;\;}}{\;}$K₂MnO₄+MnO₂+O₂¡ü£»
£¨2£©¢ÙºìÉ«¹ÌÌå±äºÚÉ«£»3CO+Fe₂O₃$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3CO₂£»
¢ÚCa£¨OH£©₂+CO₂=CaCO₃¡ý+H₂O£»
£¨3£©²»ºÏÀí£¬Ç¡ºÃÍêÈ«ÖкÍʱÈÜÒº²»±äÉ«£®
£¨4£©7.3%£®

µãÆÀ ±¾Ìâ×ۺϿ¼²éÁËÆøÌåµÄÖƱ¸¡¢Ò»Ñõ»¯Ì¼»¹Ô­Ñõ»¯Ìú¡¢Öкͷ´Ó¦µÄÅж¨ÒÔ¼°»¯Ñ§·½³ÌʽµÄ¼ÆË㣬ÄѶȲ»´ó£¬¿¼²éÃæ¹ã£®