Ñо¿ÐÔѧϰ¿ÎÌ⣺ʵÑéÊÒÖоÃÖõÄNaOHµÄ±äÖʳ̶È
£¨1£©ÏȳÆÈ¡7.3gµÄNaOHÑùÆ·£¨ÔÓÖÊΪNa2CO3£©£¬Åä³ÉÈÜÒº£¬È»ºóÏòÈÜÒºÖÐÖðµÎ¼ÓÈëÖÊÁ¿·ÖÊýΪ7.3%µÄÏ¡ÑÎËᣬ¸ù¾ÝÑÎËáµÄÁ¿£¬£¨ÔÚNa2CO3ÖеÎÈëHClµÄ·´Ó¦Ô­ÀíΪ£ºHCl+Na2CO3=NaHCO3+NaCl£¬NaHCO3+HCl=NaCl+H2O+CO2¡ü£©´Ó¶ø½øÒ»²½È·¶¨ÑùÆ·ÖÐNaOHµÄ±äÖʳ̶ȣ®
£¨2£©ÊµÑé¹ý³ÌÖмÓÈëÏ¡ÑÎËáµÄÖÊÁ¿Óë²úÉúCO2ÆøÌåµÄÖÊÁ¿¹ØϵÈçͼËùʾ£®
£¨3£©ÇëÌîдÏÂ±í£º£¨¼ÆËã½á¹û±£ÁôСÊýµãºóÃæһ룩
Na2CO3µÄÖÊÁ¿/g______
±äÖÊNaOHµÄÖÊÁ¿/g______
NaOHµÄ±äÖʳ̶ȣ¨ÓÃÖÊÁ¿·ÖÊý±íʾ£©______


¡¾´ð°¸¡¿·ÖÎö£ºÔÚ±äÖʵÄÇâÑõ»¯ÄÆÖеμÓÑÎËᣬÑÎËáÓë̼ËáÇâÄƲúÉú¶þÑõ»¯Ì¼ÆøÌ壬¸ù¾ÝÓë̼ËáÇâÄÆ·´Ó¦µÄÑÎËáµÄÖÊÁ¿¿ÉÈ·¶¨Ì¼ËáÄƵÄÖÊÁ¿£®
¸ù¾ÝÇâÑõ»¯ÄÆÓë¶þÑõ»¯Ì¼·´Ó¦µÄ»¯Ñ§·½³ÌʽºÍ̼ËáÄƵÄÖÊÁ¿¿ÉÇóµÃ±äÖʵÄNaOHµÄÖÊÁ¿£»
¸ù¾Ý±äÖʵÄNaOHµÄÖÊÁ¿ºÍ±äÖÊÇ°ÇâÑõ»¯ÄƵÄ×ÜÁ¿¿ÉÇóµÃNaOHµÄ±äÖʳ̶È
½â´ð£º½â£º¸ù¾Ý»¯Ñ§·½³Ìʽ£ºHCl+Na2CO3=NaHCO3+NaCl
NaHCO3+HCl=NaCl+H2O+CO2¡ü
¿É֪̼ËáÄÆÓëÂÈ»¯ÇâÖ®¼äµÄÖÊÁ¿¹Øϵ£»Éè̼ËáÄƵÄÖÊÁ¿Îªx
Na2CO3¡«NaHCO3¡«HCl
106             36.5
 x             £¨75g-50g£©×7.3%

x=5.3g
Éè±äÖʵÄÇâÑõ»¯ÄÆÖÊÁ¿Îªy
2NaOH+CO2¨TNa2CO3+H2O
80          106
 y           5.3g

y=4g
NaOHµÄ±äÖʳ̶ÈΪ×100%¨T66.7%
¹Ê´ð°¸Îª£º
Na2CO3µÄÖÊÁ¿/g5.3g
±äÖÊNaOHµÄÖÊÁ¿/g4.0 g
NaOHµÄ±äÖʳ̶ȣ¨ÓÃÖÊÁ¿·ÖÊý±íʾ£©66.7%

µãÆÀ£º±¾ÌâÄѶȽϴó£¬Ö÷Òª¿¼²éÁËͨ¹ýͼÏó·ÖÎöÓмÛÖµµÄÊý¾Ý£¬È»ºó¸ù¾Ý»¯Ñ§·½³Ìʽ½øÐÐÓйØÁ¿µÄ¼ÆË㣬ÅàÑøѧÉúµÄ·ÖÎöÄÜÁ¦ºÍ½â¾öÎÊÌâµÄÄÜÁ¦£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2005?ÑïÖÝ£©Ñо¿ÐÔѧϰ¿ÎÌ⣺ʵÑéÊÒÖоÃÖõÄNaOHµÄ±äÖʳ̶È
£¨1£©ÏȳÆÈ¡7.3gµÄNaOHÑùÆ·£¨ÔÓÖÊΪNa2CO3£©£¬Åä³ÉÈÜÒº£¬È»ºóÏòÈÜÒºÖÐÖðµÎ¼ÓÈëÖÊÁ¿·ÖÊýΪ7.3%µÄÏ¡ÑÎËᣬ¸ù¾ÝÑÎËáµÄÁ¿£¬£¨ÔÚNa2CO3ÖеÎÈëHClµÄ·´Ó¦Ô­ÀíΪ£ºHCl+Na2CO3=NaHCO3+NaCl£¬NaHCO3+HCl=NaCl+H2O+CO2¡ü£©´Ó¶ø½øÒ»²½È·¶¨ÑùÆ·ÖÐNaOHµÄ±äÖʳ̶ȣ®
£¨2£©ÊµÑé¹ý³ÌÖмÓÈëÏ¡ÑÎËáµÄÖÊÁ¿Óë²úÉúCO2ÆøÌåµÄÖÊÁ¿¹ØϵÈçͼËùʾ£®
£¨3£©ÇëÌîдÏÂ±í£º£¨¼ÆËã½á¹û±£ÁôСÊýµãºóÃæһ룩
Na2CO3µÄÖÊÁ¿/g
5.3g
5.3g
±äÖÊNaOHµÄÖÊÁ¿/g
4.0g
4.0g
NaOHµÄ±äÖʳ̶ȣ¨ÓÃÖÊÁ¿·ÖÊý±íʾ£©
66.7%
66.7%

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?ÒåÎÚÊУ©ÈçͼÊÇ°ËÄ꼶ϲáÑо¿ÐÔѧϰ¿ÎÌ⡶»¯Ñ§·´Ó¦ÖÐÖÊÁ¿ÊغãµÄÑо¿¡·µÄʵÑé×°Öã®±¾ÊµÑéͨ¹ý²â¶¨Ñõ»¯¹¯·Ö½âÇ°ºó·´Ó¦ÎïºÍÉú³ÉÎïµÄÖÊÁ¿ÊÇ·ñÏàµÈÀ´ÑéÖ¤ÖÊÁ¿Êغ㶨ÂÉ£®
ÒÑÖª£ºÑõ»¯¹¯·Ö½âµÄ·´Ó¦·½³Ìʽ£º2HgO
  ¡÷  
.
 
2Hg+O2¡ü
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÔÚ×éװʵÑé×°ÖÃʱ£¬Óûµ÷ÕûÊԹܵÄÇãб¶È£¬Ó¦µ÷½ÚͼÖРA¡¢B¡¢CÄĸöÐýÅ¥£¿
B
B

£¨2£©ÏÂÁÐÓйر¾ÊµÑéµÄÃèÊöÕýÈ·µÄÓÐÄÄЩ£¿
AC
AC

A£®ÔÚÁ¿Í²ÖмÓÈëһЩúÓÍ£¬¿ÉÒÔ¼õÉÙÑõÆøÔÚË®ÖеÄÈܽâ
B£®ËÜÁϹܿڷųöÁ¬Ðø¾ùÔȵÄÆøÅݺó²ÅÄÜÊÕ¼¯ÆøÌå
C£®Ñõ»¯¹¯Î´·Ö½âÍêÈ«¾ÍÍ£Ö¹¼ÓÈȶÔʵÑé½á¹ûûÓÐÓ°Ï죮

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

Ñо¿ÐÔѧϰ¿ÎÌ⣺ʵÑéÊÒÖоÃÖõÄNaOHµÄ±äÖʳ̶È
£¨1£©ÏȳÆÈ¡7.3gµÄNaOHÑùÆ·£¨ÔÓÖÊΪNa2CO3£©£¬Åä³ÉÈÜÒº£¬È»ºóÏòÈÜÒºÖÐÖðµÎ¼ÓÈëÖÊÁ¿·ÖÊýΪ7.3%µÄÏ¡ÑÎËᣬ¸ù¾ÝÑÎËáµÄÁ¿£¬£¨ÔÚNa2CO3ÖеÎÈëHClµÄ·´Ó¦Ô­ÀíΪ£ºHCl+Na2CO3=NaHCO3+NaCl£¬NaHCO3+HCl=NaCl+H2O+CO2¡ü£©´Ó¶ø½øÒ»²½È·¶¨ÑùÆ·ÖÐNaOHµÄ±äÖʳ̶ȣ®
£¨2£©ÊµÑé¹ý³ÌÖмÓÈëÏ¡ÑÎËáµÄÖÊÁ¿Óë²úÉúCO2ÆøÌåµÄÖÊÁ¿¹ØϵÈçͼËùʾ£®
£¨3£©ÇëÌîдÏÂ±í£º£¨¼ÆËã½á¹û±£ÁôСÊýµãºóÃæһ룩
Na2CO3µÄÖÊÁ¿/g________
±äÖÊNaOHµÄÖÊÁ¿/g________
NaOHµÄ±äÖʳ̶ȣ¨ÓÃÖÊÁ¿·ÖÊý±íʾ£©________

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£ºÆÚÄ©Ìâ ÌâÐÍ£ºÊµÑéÌâ

СÃ÷¶Ô¸¸Ç×ɱÓãʱȡ³öµÄÓã÷§²úÉúÁËÐËȤ£¬ËûÈ·¶¨ÁË¡°Ì½¾¿÷§ÄÚÆøÌåµÄÌå»ýºÍ³É·Ö¡±×÷ΪÑо¿ÐÔѧϰ¿ÎÌ⡣СÃ÷ͨ¹ýÉÏÍø»ñÖª¡°Óã÷§ÄÚÑõÆøÔ¼Õ¼£¬ÆäÓàÖ÷ÒªÊǶþÑõ»¯Ì¼ºÍµªÆø£¬·ÖÁ½²½½øÐÐ̽¾¿¡£
(1)²âÁ¿÷§ÄÚÆøÌåÌå»ý¡£Ð¡Ã÷Éè¼ÆÁËÁ½ÖÖ·½°¸£º
A. ÓÃÒ½ÓÃ×¢ÉäÆ÷³éÈ¡÷§ÄÚÆøÌ壬²âÁ¿ÆäÌå»ý¡£
B. ÔÚˮϴÌÆÆ÷§£¬ÓÃÅÅË®·¨ÊÕ¼¯÷§ÄÚÆøÌå²¢²âÆäÌå»ý¡£ÄãÈÏΪÕâÁ½ÖÖ·½·¨Öв»ºÏÀíµÄÊÇ                £¬ÀíÓÉ                             £¬Ð´³öÓëÀíÓÉÏà¹ØµÄ»¯Ñ§·½³Ìʽ                                       ¡£
(2)̽¾¿÷§ÄÚÆøÌåµÄ³É·Ö¡£¸øÄãÁ½¼¯ÆøÆ¿÷§ÄÚÆøÌ壬ÇëÉè¼ÆʵÑéÑéÖ¤¼ÙÉè¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2012ÄêÕã½­Ê¡ÒåÎÚÊÐÖп¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

ÈçͼÊÇ°ËÄ꼶ϲáÑо¿ÐÔѧϰ¿ÎÌ⡶»¯Ñ§·´Ó¦ÖÐÖÊÁ¿ÊغãµÄÑо¿¡·µÄʵÑé×°Öã®±¾ÊµÑéͨ¹ý²â¶¨Ñõ»¯¹¯·Ö½âÇ°ºó·´Ó¦ÎïºÍÉú³ÉÎïµÄÖÊÁ¿ÊÇ·ñÏàµÈÀ´ÑéÖ¤ÖÊÁ¿Êغ㶨ÂÉ£®
ÒÑÖª£ºÑõ»¯¹¯·Ö½âµÄ·´Ó¦·½³Ìʽ£º2HgO2Hg+O2¡ü
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÔÚ×éװʵÑé×°ÖÃʱ£¬Óûµ÷ÕûÊԹܵÄÇãб¶È£¬Ó¦µ÷½ÚͼÖРA¡¢B¡¢CÄĸöÐýÅ¥£¿______
£¨2£©ÏÂÁÐÓйر¾ÊµÑéµÄÃèÊöÕýÈ·µÄÓÐÄÄЩ£¿______
A£®ÔÚÁ¿Í²ÖмÓÈëһЩúÓÍ£¬¿ÉÒÔ¼õÉÙÑõÆøÔÚË®ÖеÄÈܽâ
B£®ËÜÁϹܿڷųöÁ¬Ðø¾ùÔȵÄÆøÅݺó²ÅÄÜÊÕ¼¯ÆøÌå
C£®Ñõ»¯¹¯Î´·Ö½âÍêÈ«¾ÍÍ£Ö¹¼ÓÈȶÔʵÑé½á¹ûûÓÐÓ°Ï죮

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸