£¨4·Ö£©Ë®ÊÇÉúÃüÖ®Ô´£¬Õþ¸®ÎªÁ˽â¾öÎÒÊÐÈËÃñÓÃË®ÄѵÄÎÊÌ⣬ÓÚ2010ÄêÄ©¾ÙÐÐÁËÅþºÓ¹©Ë®Ò»ÆÚ¹¤³Ì¿ª¹¤¶¯Ô±ÊÄʦ´ó»á¡£

£¨1£©ºÓË®Öк¬ÓÐÐí¶àÔÓÖÊ£¬¿ÉÀûÓÃÎü¸½¡¢³Áµí¡¢¹ýÂ˺ÍÕôÁóµÈ·½·¨¾»»¯£¬ÆäÖо»»¯³Ì¶È×î¸ßµÄ·½·¨ÊÇ___________£»

£¨2£©Ó²Ë®¸øÉú»îºÍÉú²ú´øÀ´ºÜ¶àÂé·³£¬Éú»îÖг£ÓÃ______________________À´Çø·ÖӲˮºÍÈíË®£¬²¢³£ÓÃÖó·ÐµÄ·½·¨À´½µµÍË®µÄÓ²¶È£»

£¨3£©³£ÓÃÏ´½à¾«Ï´µÓÓÍÎÛ£¬ÊÇÒòÏ´½à¾«¾ßÓÐ___________¹¦ÄÜ£»

£¨4£©¡°84Ïû¶¾Òº¡±¿ÉÓÃÓÚ¶ÔˮԴµÄÏû¶¾É±¾ú£¬ÆäÖƱ¸µÄÖ÷Òª·´Ó¦Îª£º

2NaOH + Cl2 = NaClO +NaCl+H2O¡£Ö¤Ã÷¡°84Ïû¶¾Òº¡±ÖÐÊÇ·ñº¬ÓÐNaClµÄ·½·¨ÊÇ£ºÈ¡ÉÙÁ¿¡°84Ïû¶¾Òº¡±£¬¼ÓÈëÉÙÁ¿______________________ÈÜÒº£¨ÌîÃû³Æ£©£¬¹Û²ìÊÇ·ñ²úÉú²»ÈÜÓÚÏ¡ÏõËáµÄ°×É«³Áµí¡£

 

£¨1£©ÕôÁó   £¨2£©·ÊÔíË® £¨3£©È黯 £¨4£©ÏõËáÒøÈÜÒººÍÏ¡ÏõËᣨ»òÏõËáËữµÄÏõËáÒøÈÜÒº»òÏõËáÒøÈÜÒº£©

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

9¡¢Ë®ÊÇÉúÃüÖ®Ô´£¬Õþ¸®ÎªÁ˽â¾öÎÒÊÐÈËÃñÓÃË®ÄѵÄÎÊÌ⣬ÓÚ2010ÄêÄ©¾ÙÐÐÁËÅþºÓ¹©Ë®Ò»ÆÚ¹¤³Ì¿ª¹¤¶¯Ô±ÊÄʦ´ó»á£®
£¨1£©ºÓË®Öк¬ÓÐÐí¶àÔÓÖÊ£¬¿ÉÀûÓÃÎü¸½¡¢³Áµí¡¢¹ýÂ˺ÍÕôÁóµÈ·½·¨¾»»¯£¬ÆäÖо»»¯³Ì¶È×î¸ßµÄ·½·¨ÊÇ
ÕôÁó
£»
£¨2£©Ó²Ë®¸øÉú»îºÍÉú²ú´øÀ´ºÜ¶àÂé·³£¬Éú»îÖг£ÓÃ
·ÊÔíË®
À´Çø·ÖӲˮºÍÈíË®£¬²¢³£ÓÃÖó·ÐµÄ·½·¨À´½µµÍË®µÄÓ²¶È£»
£¨3£©³£ÓÃÏ´½à¾«Ï´µÓÓÍÎÛ£¬ÊÇÒòÏ´½à¾«¾ßÓÐ
È黯
¹¦ÄÜ£»
£¨4£©¡°84Ïû¶¾Òº¡±¿ÉÓÃÓÚ¶ÔˮԴµÄÏû¶¾É±¾ú£¬ÆäÖƱ¸µÄÖ÷Òª·´Ó¦Îª£º2NaOH+Cl2=NaClO+NaCl+H2O£®Ö¤Ã÷¡°84Ïû¶¾Òº¡±ÖÐÊÇ·ñº¬ÓÐNaClµÄ·½·¨ÊÇ£ºÈ¡ÉÙÁ¿¡°84Ïû¶¾Òº¡±£¬¼ÓÈëÉÙÁ¿
ÏõËáÒøÈÜÒººÍÏ¡ÏõËᣨ»òÏõËáËữµÄÏõËáÒøÈÜÒº»òÏõËáÒøÈÜÒº£©
ÈÜÒº£¨ÌîÃû³Æ£©£¬¹Û²ìÊÇ·ñ²úÉú²»ÈÜÓÚÏ¡ÏõËáµÄ°×É«³Áµí£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2011Äê³õÖбÏÒµÉýѧ¿¼ÊÔ£¨ËÄ´¨×ÊÑô¾í£©»¯Ñ§ ÌâÐÍ£ºÌî¿ÕÌâ

£¨4·Ö£©Ë®ÊÇÉúÃüÖ®Ô´£¬Õþ¸®ÎªÁ˽â¾öÎÒÊÐÈËÃñÓÃË®ÄѵÄÎÊÌ⣬ÓÚ2010ÄêÄ©¾ÙÐÐÁËÅþºÓ¹©Ë®Ò»ÆÚ¹¤³Ì¿ª¹¤¶¯Ô±ÊÄʦ´ó»á¡£
£¨1£©ºÓË®Öк¬ÓÐÐí¶àÔÓÖÊ£¬¿ÉÀûÓÃÎü¸½¡¢³Áµí¡¢¹ýÂ˺ÍÕôÁóµÈ·½·¨¾»»¯£¬ÆäÖо»»¯³Ì¶È×î¸ßµÄ·½·¨ÊÇ___________£»
£¨2£©Ó²Ë®¸øÉú»îºÍÉú²ú´øÀ´ºÜ¶àÂé·³£¬Éú»îÖг£ÓÃ______________________À´Çø·ÖӲˮºÍÈíË®£¬²¢³£ÓÃÖó·ÐµÄ·½·¨À´½µµÍË®µÄÓ²¶È£»
£¨3£©³£ÓÃÏ´½à¾«Ï´µÓÓÍÎÛ£¬ÊÇÒòÏ´½à¾«¾ßÓÐ___________¹¦ÄÜ£»
£¨4£©¡°84Ïû¶¾Òº¡±¿ÉÓÃÓÚ¶ÔˮԴµÄÏû¶¾É±¾ú£¬ÆäÖƱ¸µÄÖ÷Òª·´Ó¦Îª£º
2NaOH + Cl2 =" NaClO" +NaCl+H2O¡£Ö¤Ã÷¡°84Ïû¶¾Òº¡±ÖÐÊÇ·ñº¬ÓÐNaClµÄ·½·¨ÊÇ£ºÈ¡ÉÙÁ¿¡°84Ïû¶¾Òº¡±£¬¼ÓÈëÉÙÁ¿______________________ÈÜÒº£¨ÌîÃû³Æ£©£¬¹Û²ìÊÇ·ñ²úÉú²»ÈÜÓÚÏ¡ÏõËáµÄ°×É«³Áµí¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

Ë®ÊÇÉúÃüÖ®Ô´£¬Õþ¸®ÎªÁ˽â¾öÎÒÊÐÈËÃñÓÃË®ÄѵÄÎÊÌ⣬ÓÚ2010ÄêÄ©¾ÙÐÐÁËÅþºÓ¹©Ë®Ò»ÆÚ¹¤³Ì¿ª¹¤¶¯Ô±ÊÄʦ´ó»á¡£
£¨1£©ºÓË®Öк¬ÓÐÐí¶àÔÓÖÊ£¬¿ÉÀûÓÃÎü¸½¡¢³Áµí¡¢¹ýÂ˺ÍÕôÁóµÈ·½·¨¾»»¯£¬ÆäÖо»»¯³Ì¶È×î¸ßµÄ·½·¨ÊÇ________£»
£¨2£©Ó²Ë®¸øÉú»îºÍÉú²ú´øÀ´ºÜ¶àÂé·³£¬Éú»îÖг£ÓÃ________À´Çø·ÖӲˮºÍÈíË®£¬²¢³£ÓÃÖó·ÐµÄ·½·¨À´½µµÍË®µÄÓ²¶È£»
£¨3£©³£ÓÃÏ´½à¾«Ï´µÓÓÍÎÛ£¬ÊÇÒòÏ´½à¾«¾ßÓÐ________¹¦ÄÜ£»
£¨4£©¡°84Ïû¶¾Òº¡±¿ÉÓÃÓÚ¶ÔˮԴµÄÏû¶¾É±¾ú£¬ÆäÖƱ¸µÄÖ÷Òª·´Ó¦Îª£º
2NaOH + Cl2 =" NaClO" +NaCl+H2O¡£Ö¤Ã÷¡°84Ïû¶¾Òº¡±ÖÐÊÇ·ñº¬ÓÐNaClµÄ·½·¨ÊÇ£ºÈ¡ÉÙÁ¿¡°84Ïû¶¾Òº¡±£¬¼ÓÈëÉÙÁ¿________ÈÜÒº£¨ÌîÃû³Æ£©£¬¹Û²ìÊÇ·ñ²úÉú²»ÈÜÓÚÏ¡ÏõËáµÄ°×É«³Áµí¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£ºËÄ´¨ ÌâÐÍ£ºÌî¿ÕÌâ

Ë®ÊÇÉúÃüÖ®Ô´£¬Õþ¸®ÎªÁ˽â¾öÎÒÊÐÈËÃñÓÃË®ÄѵÄÎÊÌ⣬ÓÚ2010ÄêÄ©¾ÙÐÐÁËÅþºÓ¹©Ë®Ò»ÆÚ¹¤³Ì¿ª¹¤¶¯Ô±ÊÄʦ´ó»á£®
£¨1£©ºÓË®Öк¬ÓÐÐí¶àÔÓÖÊ£¬¿ÉÀûÓÃÎü¸½¡¢³Áµí¡¢¹ýÂ˺ÍÕôÁóµÈ·½·¨¾»»¯£¬ÆäÖо»»¯³Ì¶È×î¸ßµÄ·½·¨ÊÇ______£»
£¨2£©Ó²Ë®¸øÉú»îºÍÉú²ú´øÀ´ºÜ¶àÂé·³£¬Éú»îÖг£ÓÃ______À´Çø·ÖӲˮºÍÈíË®£¬²¢³£ÓÃÖó·ÐµÄ·½·¨À´½µµÍË®µÄÓ²¶È£»
£¨3£©³£ÓÃÏ´½à¾«Ï´µÓÓÍÎÛ£¬ÊÇÒòÏ´½à¾«¾ßÓÐ______¹¦ÄÜ£»
£¨4£©¡°84Ïû¶¾Òº¡±¿ÉÓÃÓÚ¶ÔˮԴµÄÏû¶¾É±¾ú£¬ÆäÖƱ¸µÄÖ÷Òª·´Ó¦Îª£º2NaOH+Cl2=NaClO+NaCl+H2O£®Ö¤Ã÷¡°84Ïû¶¾Òº¡±ÖÐÊÇ·ñº¬ÓÐNaClµÄ·½·¨ÊÇ£ºÈ¡ÉÙÁ¿¡°84Ïû¶¾Òº¡±£¬¼ÓÈëÉÙÁ¿______ÈÜÒº£¨ÌîÃû³Æ£©£¬¹Û²ìÊÇ·ñ²úÉú²»ÈÜÓÚÏ¡ÏõËáµÄ°×É«³Áµí£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£ºËÄ´¨Ê¡Öп¼ÕæÌâ ÌâÐÍ£ºÌî¿ÕÌâ

Ë®ÊÇÉúÃüÖ®Ô´£¬Õþ¸®ÎªÁ˽â¾öÎÒÊÐÈËÃñÓÃË®ÄѵÄÎÊÌ⣬ÓÚ2010ÄêÄ©¾ÙÐÐÁËÅþºÓ¹©Ë®Ò»ÆÚ¹¤³Ì¿ª¹¤¶¯Ô±ÊÄʦ´ó»á¡£
£¨1£©ºÓË®Öк¬ÓÐÐí¶àÔÓÖÊ£¬¿ÉÀûÓÃÎü¸½¡¢³Áµí¡¢¹ýÂ˺ÍÕôÁóµÈ·½·¨¾»»¯£¬ÆäÖо»»¯³Ì¶È×î¸ßµÄ·½·¨ÊÇ___________£»
£¨2£©Ó²Ë®¸øÉú»îºÍÉú²ú´øÀ´ºÜ¶àÂé·³£¬Éú»îÖг£ÓÃ______________________À´Çø·ÖӲˮºÍÈíË®£¬²¢³£ÓÃÖó·ÐµÄ·½·¨À´½µµÍË®µÄÓ²¶È£»
£¨3£©³£ÓÃÏ´½à¾«Ï´µÓÓÍÎÛ£¬ÊÇÒòÏ´½à¾«¾ßÓÐ___________¹¦ÄÜ£»
£¨4£©¡°84Ïû¶¾Òº¡±¿ÉÓÃÓÚ¶ÔˮԴµÄÏû¶¾É±¾ú£¬ÆäÖƱ¸µÄÖ÷Òª·´Ó¦Îª£º2NaOH+Cl2==NaClO+NaCl+H2O¡£Ö¤Ã÷¡°84Ïû¶¾Òº¡±ÖÐÊÇ·ñº¬ÓÐNaClµÄ·½·¨ÊÇ£ºÈ¡ÉÙÁ¿¡°84Ïû¶¾Òº¡±£¬¼ÓÈëÉÙÁ¿_____________________ÈÜÒº£¨ÌîÃû³Æ£©£¬¹Û²ìÊÇ·ñ²úÉú²»ÈÜÓÚÏ¡ÏõËáµÄ°×É«³Áµí¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸