£¨1£©Ç뽫ÏÂÁжÌÎÄÖмӵãµÄÎÄ×Öת»¯ÎªÇ¡µ±µÄ»¯Ñ§ÓÃÓÌîÔÚºóÃæµÄºáÏßÉÏ£º¸ÕÓñÊDZ¦Ê¯µÄÒ»ÖÖ£¬ËüµÄÖ÷Òª³É·ÖÊÇÑõ»¯ÂÁ£¬Ñõ»¯ÂÁÖÐÂÁÔªËصĻ¯ºÏ¼ÛΪ+3¼Û     £¬¶ø²»ÊÇÇâÑõ»¯ÂÁ     £¬ ÆäÓ²¶È½ö´ÎÓÚ½ð¸Õʯ     £¬Ò»Ð©¸ÕÓñÓÉÓÚ»ìÓÐÉÙÁ¿ÑÇÌúÀë×Ó     µÈÔÓÖʶøÏÔÀ¶É«£¬Ë׳ÆÀ¶±¦Ê¯¡£

£¨2£©Ëæ×ÅÉú»îˮƽµÄÌá¸ß£¬Éú»îÖеÄ˽¼Ò³µÔ½À´Ô½¶à¡£

¢ÙÖÆÔìÆû³µÂÖÌ¥µÄÏð½ºÊôÓÚ     ¡£

A£®ÓлúºÏ³É²ÄÁÏ      B£®½ðÊô²ÄÁÏ          C£®¸´ºÏ²ÄÁÏ         D£®ÎÞ»ú²ÄÁÏ

¢ÚÆû³µµç·µ¼Ïß´ó¶àÊÇÍ­ÖƵģ¬ÕâÊÇÀûÓýðÊôÍ­µÄÑÓÕ¹ÐԺ͠    ¡£

¢Û½ñÄêµÄ3.15¸øÕû¸öÆû³µÐÐÒµ´øÀ´Á˲»Ð¡µÄÕðµ´£¬ºÜ¶àÆû³µÊ¹ÓÃÁ¤Çà×èÄáƬ£¬µ¼Ö³µÄÚÓÐÒì棬Á¤ÇàÊÇÓɲ»Í¬Ïà¶Ô·Ö×ÓÖÊÁ¿µÄ̼Ç⻯ºÏÎï¼°Æä·Ç½ðÊôÑÜÉúÎï×é³ÉµÄ£¬ÓÉ´ËÍƶÏÁ¤ÇàÊôÓÚ     £¨¡°»ìºÏÎ»ò¡°´¿¾»Î£©¡£

¢ÜÔÚÆûÓÍÖмÓÈëÊÊÁ¿µÄÒÒ´¼¾ÍµÃµ½ÒÒ´¼ÆûÓÍ£¬Ê¹ÓÃÒÒ´¼ÆûÓ͵ÄÓŵ㠠   £¨´ðÒ»µã£©¡£

¢Ý³µÓÃǦËáµç³Ø³äµçµÄ·´Ó¦£¨Ìõ¼þÒÑÊ¡ÂÔ£©£º2PbSO4+2H2O =Pb+2H2SO4 +       ¡£

 

¡¾´ð°¸¡¿

£¨1£©           C    

£¨2£©¢ÙA            ¢Úµ¼µçÐÔ           ¢Û »ìºÏÎï  

¢Ü¼õÉÙÎÛȾ£¨½ÚԼʯÓÍ×ÊÔ´µÈ£©     ¢Ý

¡¾½âÎö¡¿

ÊÔÌâ·ÖÎö£º£¨1£©ÈýÑõ»¯¶þÂÁÖÐÂÁÔªËصĻ¯ºÏ¼ÛΪÕýÈý¼Û±íʾ·½·¨Îª£¬ÇâÑõ»¯ÂÁΪ£¬½ð¸ÕʯµÄ»¯Ñ§×é³ÉΪ̼£¬ÑÇÌúÀë×ÓΪ£»£¨2£©¢ÙÏð½ºÊôÓÚÓлúºÏ³É²ÄÁÏ£¬¢ÚÍ­¿ÉÒÔÓÃ×öµ¼ÏßÊÇÓÉÓÚÆäÁ¼ºÃµÄµ¼µçÐÔºÍÑÓÕ¹ÐÔ£¬¢ÛÓÉÌâ¿ÉÖªÁ¤ÇàÓɶàÖÖÓлúÎï×é³É£¬ÊôÓÚ»ìºÏÎ¢ÜÒÒ´¼ÆûÓÍ¿ÉÒÔÔö´óȼÉÕЧÂÊ£¬¼õÉÙÎÛȾ£¬½ÚÔ¼ÄÜÔ´£»¢Ý¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬»¯Ñ§·´Ó¦Ç°ºó¸÷ÎïÖÊÔ­×Ó×ÜÊý²»·¢Éú±ä»¯£¬ËùÒÔ¸ÃÎïÖÊΪ¡£

¿¼µã£º³£¼û»¯Ñ§ÓÃÓï

µãÆÀ£º³£¼ûµÄ»¯Ñ§ÓÃÓïºÍËùÉæ¼°µÄ»¯Ñ§³£Ê¶ÊôÓÚÖп¼µÄÈȵ㣬¿ÉÒÔÔÚÑ¡ÔñÌâºÍ´óÌâÖгöÏÖ£¬×¢Òâ×ÐϸÉóÌâ¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

14¡¢Éú»îÖд¦´¦Óл¯Ñ§£®ÇëÄãÓû¯Ñ§ÖªÊ¶»Ø´ðÒÔÏÂÉú»îÖеÄÎÊÌ⣺
£¨1£©Ç뽫ÏÂÁжÌÎÄÖдøµãµÄ²¿·Ö£¬ÓÃÇ¡µ±µÄ»¯Ñ§ÓÃÓïÌîдÔÚºáÏßÉÏ£º
Ì«Ñô¾µ¾ßÓб£»¤ÑÛ¾¦µÄ¹¦ÄÜ£®ËüµÄ¾µ½ÅÒ»°ãÊÇÓÉËÜÁÏ£¨ÆäÖк¬ÓÐ̼ԪËصÄ
C
£©ÖƳɵģ¬²£Á§¾µÆ¬µÄÖ÷Òª³É·ÖÊǶþÑõ»¯¹è
SiO2
£¬ÇÒ±äÉ«²£Á§Öк¬ÓÐÒøÀë×Ó
Ag+
£®
£¨2£©¾»»¯Ë®µÄ֪ʶÔÚÈÕ³£Éú»îÓÐ׏㷺µÄÓ¦Óã®
£¨a£©×ÔÖƾ»Ë®Æ÷Öг£¼ÓÈë
»îÐÔÌ¿
£¬ÓÃÓÚ³ýȥˮÖеÄÒìζºÍÉ«ËØ£®
£¨b£©¾®Ë®Öк¬Óн϶àµÄ¸Æ¡¢Ã¾Àë×Ó£¬ÎªÁ˽µµÍÓ²¶È£¬¿É²ÉÓõķ½·¨ÊÇ
Öó·Ð
£®
£¨3£©ÐÂ×°Ð޵ķ¿ÎÝÄÚ¿ÕÆøÖÐͨ³£º¬Óн϶àµÄ¼×È©£¨CH2O£©¡¢±½£¨C6H6£©µÈÓж¾ÎïÖÊ£®ÕâÁ½ÖÖÎïÖʶ¼ÊôÓÚ
ÓлúÎï
£¨Ìî¡°ÎÞ»úÎ»ò¡°ÓлúÎ£©£¬ÔÚ°áÈëÐÂ×°Ð޵ķ¿ÎÝ֮ǰ£¬¿ÉÒÔ²ÉÈ¡µÄ¼õÇáÎÛȾµÄ´ëÊ©Ö®Ò»ÊÇ
´ò¿ªÃÅ´°Í¨·ç
£®ÈËÃÇ»¹¿ÉÀûÓ᰹ⴥý¡±¼¼ÊõÓÃTiO2ÔÚ¹â´ß»¯¼Á×÷ÓÃϽ«ÉÏÊöÓк¦ÎïÖÊÉú³É¶þÑõ»¯Ì¼ºÍË®£¬½µµÍÊÒÄÚ¿ÕÆøÎÛȾ£®TiO2ÖÐTiµÄ»¯ºÏ¼ÛΪ
+4
¼Û£®
£¨4£©½¼Íâͨ³£±È½ÏÄàÅ¢£¬Èç¹ûÄãµÄ½»Í¨¹¤¾ßÊÇ×ÔÐгµ£¬Äã»ØÀ´½øÐÐÇåÏ´ºóÊÇÈçºÎ·ÀÖ¹×ÔÐгµÉúÐâµÄ£º
²Á¸ÉºóÍ¿ÓÍ
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2009?½ÒÑô£©Éú»îÖд¦´¦Óл¯Ñ§£®ÇëÄãÓû¯Ñ§ÖªÊ¶»Ø´ðÒÔÏÂÉú»îÖеÄÎÊÌ⣻
£¨1£©Ç뽫ÏÂÁжÌÎÄÖдøµãµÄ²¿·Ö£¬ÓÃÇ¡µ±µÄ»¯Ñ§ÓÃÓïÌîдÔÚºáÏßÉÏ£º
Ì«Ñô¾µ¾ßÓб£»¤ÑÛ¾¦µÄ¹¦ÄÜ£®ËüµÄ¾µ½ÅÒ»°ãÊÇÓÉËÜÁÏ£¨ÆäÖк¬ÓÐ̼ԪËصÄ
C
C
£©ÖƳɵģ¬²£Á§¾µÆ¬µÄÖ÷Òª³É·ÖÊǶþÑõ»¯¹è
SiO2
SiO2
£¬ÇÒ±äÉ«²£Á§Öк¬ÓÐÀë×Ó
Ag+
Ag+
£®
£¨2£©¾»»¯Ë®µÄ֪ʶÔÚÈÕ³£Éú»îÓÐ׏㷺µÄÓ¦Óã®
£¨a£©×ÔÖƾ»Ë®Æ÷Öг£¼ÓÈë
»îÐÔÌ¿
»îÐÔÌ¿
£¬ÓÃÓÚ³ýȥˮÖеÄÒìζºÍÉ«ËØ£®
£¨b£©¾®Ë®Öк¬Óн϶àµÄ¸Æ¡¢Ã¾Àë×Ó£¬ÎªÁ˽µµÍÓ²¶È£¬¿É²ÉÓõķ½·¨ÊÇ
Öó·Ð
Öó·Ð
£®
£¨3£©½¼Íâͨ³£±È½ÏÄàÅ¢£¬Èç¹ûÄãµÄ½»Í¨¹¤¾ßÊÇ×ÔÐгµ£¬Äã»ØÀ´½øÐÐÇåÏ´ºóÊÇÈçºÎ·ÀÖ¹×ÔÐгµÉúÐâµÄ£º
²Á¸É¡¢Í¿ÓÍ
²Á¸É¡¢Í¿ÓÍ
£®
£¨4£©»Æ¹Ï¸»º¬Î¬ÉúËØC£¬Î¬ÉúËØCÔÚpH£¼7ºÍµÍεĻ·¾³ÖнÏÎȶ¨£¬Îª¼õÉÙάÉúËØCµÄËðʧ£¬Ê³ÓûƹÏʱ±È½ÏÇ¡µ±µÄ·½·¨ÊÇ
¼Ó´×Á¹°è»òÉú³Ô
¼Ó´×Á¹°è»òÉú³Ô
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©Ç뽫ÏÂÁжÌÎÄÖмӵãµÄÎÄ×Öת»¯ÎªÇ¡µ±µÄ»¯Ñ§ÓÃÓÌîÔÚºóÃæµÄºáÏßÉÏ£º
¸ÕÓñÊDZ¦Ê¯µÄÒ»ÖÖ£¬ËüµÄÖ÷Òª³É·ÖÊÇ
Ñõ»¯ÂÁ
?  ?  ?
Al2O3
Al2O3
£¬Ñõ»¯ÂÁÖÐÂÁÔªËصĻ¯ºÏ¼ÛΪ+3¼Û
+3
Al
2O3
+3
Al
2O3
£¬¶ø²»ÊÇ
ÇâÑõ»¯ÂÁ
?  ?  ?  ?
Al£¨OH£©3
Al£¨OH£©3
£¬ÆäÓ²¶È½ö´ÎÓÚ½ð¸Õʯ
½ð¸Õʯ
?  ?  ?
C
C
£¬Ò»Ð©¸ÕÓñÓÉÓÚ»ìÓÐÉÙÁ¿
ÑÇÌúÀë×Ó
?  ?  ?  ?
Fe2+
Fe2+
µÈÔÓÖʶøÏÔÀ¶É«£¬Ë׳ÆÀ¶±¦Ê¯£®
£¨2£©Ëæ×ÅÉú»îˮƽµÄÌá¸ß£¬Éú»îÖеÄ˽¼Ò³µÔ½À´Ô½¶à£®
¢ÙÖÆÔìÆû³µÂÖÌ¥µÄÏð½ºÊôÓÚ
A
A
£®
A£®ÓлúºÏ³É²ÄÁÏ   B£®½ðÊô²ÄÁÏ    C£®¸´ºÏ²ÄÁÏ  D£®ÎÞ»ú²ÄÁÏ
¢ÚÆû³µµç·µ¼Ïß´ó¶àÊÇÍ­ÖƵģ¬ÕâÊÇÀûÓýðÊôÍ­µÄÑÓÕ¹ÐÔºÍ
µ¼µçÐÔ
µ¼µçÐÔ
£®
¢Û½ñÄêµÄ3.15¸øÕû¸öÆû³µÐÐÒµ´øÀ´Á˲»Ð¡µÄÕðµ´£¬ºÜ¶àÆû³µÊ¹ÓÃÁ¤Çà×èÄáƬ£¬µ¼Ö³µÄÚÓÐÒì棬Á¤ÇàÊÇÓɲ»Í¬Ïà¶Ô·Ö×ÓÖÊÁ¿µÄ̼Ç⻯ºÏÎï¼°Æä·Ç½ðÊôÑÜÉúÎï×é³ÉµÄ£¬ÓÉ´ËÍƶÏÁ¤ÇàÊôÓÚ
»ìºÏÎï
»ìºÏÎï
£¨¡°»ìºÏÎ»ò¡°´¿¾»Î£©£®
¢ÜÔÚÆûÓÍÖмÓÈëÊÊÁ¿µÄÒÒ´¼¾ÍµÃµ½ÒÒ´¼ÆûÓÍ£¬Ê¹ÓÃÒÒ´¼ÆûÓ͵ÄÓŵã
¼õÉÙ¿ÕÆøÎÛȾµÈ
¼õÉÙ¿ÕÆøÎÛȾµÈ
£¨´ðÒ»µã£©£®
¢Ý³µÓÃǦËáµç³Ø³äµçµÄ·´Ó¦£¨Ìõ¼þÒÑÊ¡ÂÔ£©£º2PbSO4+2H2O¨TPb+2H2SO4+
PbO2
PbO2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2013½ì½­ËÕÊ¡ÑγÇÊеÚÒ»³õ¼¶ÖÐѧ½ÌÓý¼¯ÍžÅÄ꼶ÏÂѧÆÚµ÷Ñп¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨1£©Ç뽫ÏÂÁжÌÎÄÖмӵãµÄÎÄ×Öת»¯ÎªÇ¡µ±µÄ»¯Ñ§ÓÃÓÌîÔÚºóÃæµÄºáÏßÉÏ£º¸ÕÓñÊDZ¦Ê¯µÄÒ»ÖÖ£¬ËüµÄÖ÷Òª³É·ÖÊÇÑõ»¯ÂÁ£¬Ñõ»¯ÂÁÖÐÂÁÔªËصĻ¯ºÏ¼ÛΪ+3¼Û     £¬¶ø²»ÊÇÇâÑõ»¯ÂÁ     £¬ ÆäÓ²¶È½ö´ÎÓÚ½ð¸Õʯ     £¬Ò»Ð©¸ÕÓñÓÉÓÚ»ìÓÐÉÙÁ¿ÑÇÌúÀë×Ó     µÈÔÓÖʶøÏÔÀ¶É«£¬Ë׳ÆÀ¶±¦Ê¯¡£
£¨2£©Ëæ×ÅÉú»îˮƽµÄÌá¸ß£¬Éú»îÖеÄ˽¼Ò³µÔ½À´Ô½¶à¡£
¢ÙÖÆÔìÆû³µÂÖÌ¥µÄÏð½ºÊôÓÚ     ¡£

A£®ÓлúºÏ³É²ÄÁÏB£®½ðÊô²ÄÁÏC£®¸´ºÏ²ÄÁÏD£®ÎÞ»ú²ÄÁÏ
¢ÚÆû³µµç·µ¼Ïß´ó¶àÊÇÍ­ÖƵģ¬ÕâÊÇÀûÓýðÊôÍ­µÄÑÓÕ¹ÐԺ͠    ¡£
¢Û½ñÄêµÄ3.15¸øÕû¸öÆû³µÐÐÒµ´øÀ´Á˲»Ð¡µÄÕðµ´£¬ºÜ¶àÆû³µÊ¹ÓÃÁ¤Çà×èÄáƬ£¬µ¼Ö³µÄÚÓÐÒì棬Á¤ÇàÊÇÓɲ»Í¬Ïà¶Ô·Ö×ÓÖÊÁ¿µÄ̼Ç⻯ºÏÎï¼°Æä·Ç½ðÊôÑÜÉúÎï×é³ÉµÄ£¬ÓÉ´ËÍƶÏÁ¤ÇàÊôÓÚ     £¨¡°»ìºÏÎ»ò¡°´¿¾»Î£©¡£
¢ÜÔÚÆûÓÍÖмÓÈëÊÊÁ¿µÄÒÒ´¼¾ÍµÃµ½ÒÒ´¼ÆûÓÍ£¬Ê¹ÓÃÒÒ´¼ÆûÓ͵ÄÓŵ㠠   £¨´ðÒ»µã£©¡£
¢Ý³µÓÃǦËáµç³Ø³äµçµÄ·´Ó¦£¨Ìõ¼þÒÑÊ¡ÂÔ£©£º2PbSO4+2H2O =Pb+2H2SO4 +       ¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸