8£®ÀûÓóÁµí·¨¿É²â¶¨Ä³´ÖÑÎÑùÆ·µÄ´¿¶È£¨¼Ù¶¨´ÖÑÎÖеÄÔÓÖÊÈ«²¿ÊÇMgCl2£©£®Ã¿´ÎÈ¡100gÑùÆ·ÅäÖƳÉÈÜÒº£¬ÏòÆäÖмÓÈë10%µÄÇâÑõ»¯ÄÆÈÜÒº£¬²âµÃÉú³É³ÁµíµÄÖÊÁ¿ÓëËù¼ÓÇâÑõ»¯ÄÆÈÜÒºµÄÖÊÁ¿¹ØϵÈçϱíËùʾ£º
²â¶¨´ÎÊýµÚÒ»´ÎµÚ¶þ´ÎµÚÈý´ÎµÚËÄ´Î
ÑùÆ·ÖÊÁ¿£¨g£©100100100100
ÇâÑõ»¯ÄÆÈÜÒºÖÊÁ¿£¨g£©4080120160
³ÁµíÖÊÁ¿£¨g£©2.95.88.78.7
£¨1£©µÚÈý´Î¼ÓÈëµÄÇâÑõ»¯ÄÆÈÜÒºÓë´ÖÑÎÖеÄMgCl2Ç¡ºÃÍêÈ«·´Ó¦£®
£¨2£©Çó´ÖÑεĴ¿¶È£¨Ð´³ö½âÌâ¹ý³Ì£©£®

·ÖÎö ÑùÆ·ÓëËù¼ÓÇâÑõ»¯ÄÆÈÜҺǡºÃÍêÈ«·´Ó¦Ê±ÈÜÒºÖÐÂÈ»¯ÄƵÄÖÊÁ¿°üÀ¨´ÖÑÎÖÐÂÈ»¯ÄƵÄÖÊÁ¿ºÍ·´Ó¦Éú³ÉµÄÂÈ»¯ÄƵÄÖÊÁ¿£»¸ù¾Ý²úÉú³ÁµíÇâÑõ»¯Ã¾µÄÖÊÁ¿¿ÉÒÔ¼ÆËãÂÈ»¯Ã¾µÄÖÊÁ¿£¬¸ù¾ÝÂÈ»¯Ã¾µÄÖÊÁ¿¿ÉÒÔ¼ÆËãÂÈ»¯ÄƵÄÖÊÁ¿£¬½øÒ»²½¿ÉÒÔ¼ÆËã´ÖÑεĴ¿¶È£®

½â´ð ½â£º£¨1£©ÓɱíÖÐÊý¾Ý¿ÉÖª£¬µ±ÇâÑõ»¯ÄÆÈÜÒºÖÊÁ¿¼Óµ½120gʱ£¬³ÁµíµÄÖÊÁ¿²»ÔÙÔö¼Ó£¬ËµÃ÷ÑùÆ·ÖÐÂÈ»¯Ã¾È«²¿·´Ó¦£¬²¢ÇÒÿÔö¼Ó40gÇâÑõ»¯ÄÆÈÜÒºÖÊÁ¿Éú³É³Áµí2.9g£»µ±ÇâÑõ»¯ÄÆÈÜÒºÖÊÁ¿Îª120gʱ£¬Éú³É³Áµí8.7g£¬ÇâÑõ»¯ÄÆÈÜҺǡºÃÍêÈ«·´Ó¦£»ËùÒÔµÚÈý´Î¼ÓÈëµÄÇâÑõ»¯ÄÆÈÜÒºÓë´ÖÑÎÖеÄMgCl2Ç¡ºÃÍêÈ«·´Ó¦£®
£¨2£©½â£ºÉèÑùÆ·ÖÐMgCl2µÄÖÊÁ¿Îªx
MgCl2+2NaOH¨T2NaCl+Mg£¨OH£©2¡ý
95                    58
x                    8.7g
$\frac{95}{58}$=$\frac{x}{8.7g}$
x=14.25g
´ÖÑδ¿¶ÈΪ£º$\frac{100g-14.25g}{100g}$¡Á100%¨T85.75%
¹Ê´ð°¸Îª£º
£¨1£©Èý
£¨2£©85.75%

µãÆÀ ±¾ÌâÖ÷Òª¿¼²éѧÉúÔËÓüÙÉè·¨ºÍ»¯Ñ§·½³Ìʽ½øÐмÆËãºÍÍƶϵÄÄÜÁ¦£¬¼ÆËãʱҪעÒâ¹æ·¶ÐÔºÍ׼ȷÐÔ£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

18£®´¿¼îÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤»ù±¾Ô­ÁÏ£¬¹¤Òµ´¿¼îÖÐÍùÍù»áº¬ÓÐÉÙÁ¿ÂÈ»¯ÄÆÔÓÖÊ£®Îª²â¶¨¹¤Òµ´¿¼îÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊý£¬Ä³Ñ§ÉúÉè¼ÆÁËÈçͼËùʾµÄʵÑé×°Öãº
ʵÑé²½Ö裺
¢Ù׼ȷ³ÆÈ¡Ê¢Óмîʯ»ÒµÄ¸ÉÔï¹ÜµÄÖÊÁ¿Îª158.0g£¬ÔÙ׼ȷ³ÆÈ¡11.0g´¿¼îÑùÆ·²¢È«²¿·ÅÈëAÖУ»
¢Ú×é×°È«²¿·´Ó¦×°Öò¢¼ì²éÆøÃÜÐÔ£¬¹Ø±Õd£»ÓÉeÖðµÎ¼ÓÈëÏ¡ÁòËáÖÁ²»ÔÙ²úÉúÆøÅÝΪֹ£»    
¢Û´ò¿ªd£¬ÂýÂý¹ÄÈë¿ÕÆø10min£»
¢ÜÔٳƸÉÔï¹ÜµÄ×ÜÖÊÁ¿Îª162.4g£®
ÎÊÌâ·ÖÎö£º
£¨1£©Í¨¹ý×°ÖÃB¹ÄÈë¿ÕÆøµÄÄ¿µÄÊǽ«²ÐÁôÔÚAÆ¿¡¢CÊԹܺ͵¼¹ÜÖеĶþÑõ»¯Ì¼Åųö£¬Ê¹Ö®È«²¿±»¼îʯ»ÒÎüÊÕ£»
£¨2£©²»ÉèÖÃ×°ÖÃC½«Ê¹²â¶¨½á¹ûÆ«´ó£¨ÌîÆ«´ó¡¢Æ«Ð¡»ò²»±ä£©£»
£¨3£©¸Ã²úÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýΪ$\frac{£¨{m}_{2}-{m}_{1}£©¡Á53}{22m}$¡Á100%£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

19£®Ä³Í¬Ñ§×öÁËÈçͼËùʾʵÑ飺

 µÚÒ»´ÎµÚ¶þ´Î
¼ÓÈëÏ¡ÁòËáµÄÖÊÁ¿mgmg
µÎ¼ÓÇâÑõ»¯ÄÆÈÜÒºµÄÖÊÁ¿60g100g
µÎ¼ÓÁòËáÍ­ÈÜÒºµÄÖÊÁ¿40g40g
ʵÑéÏÖÏóÎÞÃ÷ÏÔÏÖÏó²úÉúÀ¶É«³Áµí
ÒÑÖªµÚ¶þ´ÎʵÑéÖмÓÈëµÄÎïÖʾùºÄ¾¡£¬ÇÒ¼ÓÈëµÄÈýÖÖÈÜÒºÖÐÈÜÖÊÖÊÁ¿·ÖÊý¾ùΪ10%£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ð´³öµÚ¶þ´ÎʵÑéÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ2NaOH+H2SO4¨TNa2SO4+2H2O£¬CuSO4+2NaOH¨TNa2SO4+Cu£¨OH£©2¡ý£»
£¨2£©µÚÒ»´ÎʵÑéºóÈÜÒºÖÐÈÜÖʵÄ×é³ÉÊÇH2SO4¡¢CuSO4¡¢Na2SO4£»
£¨3£©¸ù¾ÝÒÑÖªÌõ¼þÇó½âµÚ¶þ´ÎʵÑéÖÐÉú³É³ÁµíµÄÖÊÁ¿£¨x£©µÄ±ÈÀýʽ$\frac{160}{40g¡Á10%}$=$\frac{98}{x}$£»
£¨4£©ÊµÑéÖÐÿ´Î¼ÓÈëÏ¡ÁòËáµÄÖÊÁ¿£¨m£©Îª98g£»
£¨5£©Èô½«µÚ¶þ´Î·´Ó¦ºóµÄ¹ÌÒº»ìºÏÎïÕô·¢µô135.55gË®ºó£¬ÔÙ¹ýÂË£¬ÔòËùµÃÂËÒº£¨²»±¥ºÍÈÜÒº£©ÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýΪ17.75%£»
£¨6£©ÈôÓÃ98%µÄŨÁòËáÅäÖÆÉÏÊöʵÑéËùÐèµÄÏ¡ÁòËᣬÔòÐèҪŨÁòËáºÍ¼ÓÈëË®µÄÖÊÁ¿±ÈΪ5£º44£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

16£®Ä³»¯Ñ§ÐËȤС×éÀûÓÃÏÂͼËùʾװÖòâÁ¿¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý£®
¡¾²éÔÄ×ÊÁÏ]¡¿°×Á×µÄ×Å»ðµãΪ40¡æ£®
¡¾ÊµÑé̽¾¿¡¿
£¨1£©²âÁ¿×¶ÐÎÆ¿µÄÈÝ»ý£®²âÁ¿×¶ÐÎÆ¿ÈÝ»ýµÄ·½·¨Êǽ«×¶ÐÎƿװÂúË®£¬½«×¶ÐÎÆ¿ÖеÄË®µ¹ÈëÁ¿Í²ÖУ¬¶Á³öË®µÄÌå»ý£¬×¶ÐÎÆ¿µÄÈÝ»ý¾ÍµÈÓÚÁ¿Í²ÖÐË®µÄÌå»ý£®×îºó²âµÃ׶ÐÎÆ¿ÈÝ»ýΪ230ml£®
£¨2£©¼ì²é×°ÖõÄÆøÃÜÐÔ£®¼ì²éÓÒͼװÖÃÆøÃÜÐԵķ½·¨Êǽ«ÕëͲÄÚÁôÓеIJ¿·Ö¿ÕÆø£¬´ò¿ªµ¯»É¼Ð£¬Ö»Òª½«×¢ÉäÆ÷µÄ»îÈûÍùÏÂÍÆ£¬Ñ¹Ç¿±ä´ó£¬·¢ÏÖÆøÇò³¤´ó£¬¾ÍÄÜ˵Ã÷×°ÖÃÆøÃÜÐÔÁ¼ºÃ£®   
£¨3£©ÔÚ׶ÐÎÆ¿ÄÚ×°ÈëÒ©Æ·£¬×¢ÉäÆ÷ÄÚÎüÈë50mLË®£¬È»ºó°´ÈçͼÁ¬½ÓºÃÒÇÆ÷£¬¼Ó½ôµ¯»É¼Ð£¬Òýȼ°×Á×£®Òýȼ°×Á׿ɲÉÓõķ½·¨ÓÐBC£¨¶àÑ¡£©£®
A£®½«×¶ÐÎÆ¿·ÅÔھƾ«µÆ»ðÑæÉÏÖ±½Ó×ÆÉÕ
B£®½«×¶ÐÎÆ¿µ×²¿½þûÔÚ80¡æµÄÈÈË®ÖÐ
C£®Ó÷Ŵ󾵾۽¹Ì«Ñô¹âµ½°×Á×ÉÏ
¡¾ÏÖÏó·ÖÎö¡¿
£¨1£©ÓÃÉÏÊö·½·¨Òýȼ°×Á×£¬ËµÃ÷¿ÉȼÎïµÄȼÉÕ²»ÄÜȱÉÙµÄÒ»¸öÌõ¼þÊÇζȴﵽ×Å»ðµã£®×ãÁ¿µÄ°×Á×ÔÚ׶ÐÎÆ¿ÄÚδÄÜÈ«²¿È¼ÉÕ£¬ËµÃ÷Æ¿ÄÚÊ£ÓàÆøÌåµÄÐÔÖÊÊǵªÆø£®
£¨2£©ÔÚÕû¸öʵÑé¹ý³ÌÖУ¬¿É¹Û²ìµ½ÆøÇòµÄ±ä»¯ÊÇÏÈÅòÕÍ£¬ºóËõС£®
£¨3£©´ý°×Á×ϨÃð£¬×¶ÐÎÆ¿ÀäÈ´µ½ÊÒκ󣬴ò¿ªÖ¹Ë®¼Ð£¬»¹¿É¹Û²ìµ½µÄÏÖÏóÊÇ£º
¢Ù×¢ÉäÆ÷ÖеÄË®×Ô¶¯ÅçÉä³öÀ´£»
¢Ú×¢ÉäÆ÷ÖеÄË®»¹Ê£Ô¼4mLʱ£¬Í£Ö¹Á÷Ï£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

3£®ÏÂÁÐ˵·¨»ò×ö·¨ÖкÏÀíµÄÊÇ£¨¡¡¡¡£©
A£®´óÁ¦ÌᳫÓÃÅÝÄ­¿ì²ÍºÐ
B£®ÎªÁË·ÀÖ¹µâ·øÉ䣬³Ô´óÁ¿µÄ¼ÓµâÑÎ
C£®½«º£ÏÊÕæ¿Õ°ü×°ºóËÙ¶³Àä²Ø·ÀÖ¹º£Ïʸ¯ÀñäÖÊ
D£®ÊÐÕþ¹¤ÈËδ½øÐеã»ðʵÑé½øÈëÉî¶ø³¤µÄµØÏÂÎÛË®¹ÜµÀ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

13£®ÈçͼËùʾʵÑé²Ù×÷²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®
     Õô·¢
B£®
      È¡ÓùÌÌå·ÛÄ©
C£®
    È¡ÓÃÒºÌå
D£®
ÌúË¿ÔÚO2ÖÐȼÉÕ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

20£®¹æ·¶µÄ²Ù×÷ÊÇ»¯Ñ§ÊµÑé³É¹¦µÄ±£ÕÏ£®ÏÂÁÐʵÑé²Ù×÷ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®ÖÆÈ¡ÆøÌåʱ£¬Á¬ºÃ·¢Éú×°Öúó¼ì²éÆäÆøÃÜÐÔ
B£®Ã»Óи¯Ê´ÐԵĹÌÌåÒ©Æ·Ö±½Ó·ÅÔÚÍÐÅÌÉϳÆÁ¿
C£®²â¶¨Ä³ÖÖÊÔ¼ÁµÄpHʱ£¬½«ÊÔÖ½ÉìÈë´ý²âÒºÖÐ
D£®×öʵÑéÓÃÊ£µÄÒ©Æ·£¬Òª¼°Ê±·Å»ØÔ­ÊÔ¼ÁÆ¿ÖÐ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

17£®Ä³»¯Ñ§ÐËȤС×é¶ÔijÔ±ý°ü×°ºÐÖеġ°ÍÑÑõ¼Á¡±ºÜºÃÆ棬ËûÃǹ۲쵽¡°ÍÑÑõ¼Á¡±Íâ°ü×°±ê×¢µÄ³É·ÖΪÌú·Û¡¢»îÐÔÌ¿ºÍÂÈ»¯ÄÆ£¬´ò¿ª·¢ÏÖ»ÒºÚÉ«µÄ¹ÌÌåÖл¹¼ÐÔÓ×ÅÉÙÁ¿ºì×ØÉ«·ÛÄ©£®
¡¾²éÔÄ×ÊÁÏ¡¿¢ÙÌúϵ¡°ÍÑÑõ¼Á¡±µÄ×÷ÓÃÔ­ÀíÊÇÀûÓÃÌúÄܱ»ÑõÆøÑõ»¯£¬´Ó¶ø´ïµ½³ýÑõ±£ÏʵÄÄ¿µÄ£®Ìú±»ÑõÆøÑõ»¯×îÖÕ²úÎïΪºì×ØÉ«µÄFe2O3£¨ÆäËû²úÎïºöÂÔ²»¼Æ£©£®
¢ÚFe2O3+3H2SO4¨TFe2£¨SO4£©3+3H2O£»Fe+Fe2£¨SO4£©3=3FeSO4£®
¡¾Ì½¾¿Ä¿µÄ¡¿Ð¡×éͬѧÓû̽¾¿¸Ã¡°ÍÑÑõ¼Á¡±ÊÇ·ñÒѾ­Ê§Ð§£¬²¢²â¶¨10gÑùÆ·¸÷³É·ÖµÄÖÊÁ¿£®
¡¾ÊµÑé̽¾¿¡¿£¨¼ÙÉèËùÓвÙ×÷¹ý³ÌÖÐÎïÖʵÄÖÊÁ¿Ã»ÓÐËðʧ£©
²½Öè1£ºÐ¡¿ÆÓôÅÌú½Ó½üÑùÆ·£¬·¢ÏÖ´ÅÌúÎüÒýÁ˲¿·ÖºÚÉ«¹ÌÌ壮
²½Öè2£º³ÆÈ¡10gÑùÆ·ÓÚÉÕ±­ÖУ¬¼Ó×ãÁ¿Ë®³ä·Ö½Á°èÈܽâºó£¬¹ýÂË£¬½«ÂËÔüÏ´µÓ¡¢¸ÉÔï¡¢³ÆµÃÆäÖÊÁ¿Îª7.32g£®
²½Öè3£º°´ÈçͼװÖã¬aµ¼¹Ü´¦ÔÙÁ¬½ÓÒ»¸öÊ¢Óмîʯ»ÒµÄ¸ÉÔï¹Ü£¬½«µÃµ½µÄ7.32g¹ÌÌåÓë×ãÁ¿Ï¡ÁòËá·´Ó¦£¬Óõç×ӳӳƵ÷´Ó¦Ç°ºó×ÜÖÊÁ¿²îΪ0.1g£®
²½Öè4£º½«×¶ÐÎÆ¿Öз´Ó¦ºóµÄÒºÌå¹ýÂË£¬·ÖÎö²âËãµÃÖª£ºÂËÒºÖÐÈÜÖÊÊÇÁòËáºÍÁòËáÑÇÌú£¬²¢½«ÂËÔüÏ´µÓ¡¢¸ÉÔïºó£¬³ÆµÃÆäÖÊÁ¿Îª1.82g£®
¡¾½»Á÷ÌÖÂÛ¡¿
£¨1£©²½Öè2Ä¿µÄÊÇÈܽâÑùÆ·ÖÐÂÈ»¯ÄÆ£®
£¨2£©Ð¡Ãô»¹ÈÏÕæ·ÖÎöÌâÖÐËù¸ø×ÊÁÏ£¬ËûÈÏΪÓòúÉúH2µÄÖÊÁ¿¼ÆËãÑùÆ·ÖÐÌúµÄÖÊÁ¿²»ºÏÀí£®ÆäÀíÓÉÊÇ£ºÑùÆ·ÖеÄÌú£¬³ýÁËÓëÏ¡ÁòËá·´Ó¦Éú³ÉH2Í⣬»¹ÓÐÒ»²¿·ÖÌúÓëÁòËáÌúÈÜÒº·´Ó¦£®
¡¾µÃ³ö½áÂÛ¡¿
£¨1£©Ð¡¿ÆÓɲ½Öè1µÃ³öµÄ½áÂÛÊÇ£ºÍÑÑõ¼Á»¹Ã»ÓÐʧЧ£®
£¨2£©Çë¸ù¾ÝÒÔÉÏÊý¾Ý£¬¼ÆËã10g¸ÃÑùÆ·ÖÐÌú·ÛµÄÖÊÁ¿£®£¨Ö»Ð´³ö½á¹û£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ

18£®ÏÂÁв»ÊôÓÚÁòȼÉÕʱËù²úÉúµÄÏÖÏóÊÇ£¨¡¡¡¡£©
A£®²úÉú´óÁ¿°×ÑÌB£®·Å³ö´óÁ¿µÄÈÈ
C£®·¢³öÀ¶É«»ðÑæD£®Éú³ÉÓÐØݼ¤ÐÔÆøζµÄÆøÌå

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸