Ϊ²â¶¨Ä³Ì¼ËáÇâ炙¯·ÊÖе嬵ªÁ¿£¬Ð¡±õÔÚʵÑéÊÒÀïÈ¡ÓÃ8.5 g¸Ã»¯·ÊÑùÆ·Óë20 g¡¡NaOHÈÜÒº¹²ÈÈ£¬Ç¡ºÃÍêÈ«·´Ó¦£¬²âµÃ²ÐÁôÎïΪ26.8 g(Ìáʾ£º·´Ó¦µÄ»¯Ñ§·½³ÌʽΪNH4HCO3£«2NaOHNa2CO3£«2H2O£«NH3¡ü£¬Éú³ÉµÄ°±ÆøÈ«²¿Òݳö£¬ÆäËû³É·Ö²»º¬µª£¬Ò²²»²Î¼Ó·´Ó¦)£®ÊÔÇó£º

(1)Éú³É°±ÆøµÄÖÊÁ¿£®

(2)¸Ã»¯·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊý(¼ÆËã½á¹û¾«È·µ½0.1£¥)£®

(3)ËùÓÃÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ϊ²â¶¨Ä³Ì¼ËáÇâ炙¯·ÊÖе嬵ªÁ¿£¬Ð¡±õÔÚʵÑéÊÒÀïÈ¡ÓÃ8.5g¸Ã»¯·ÊÑùÆ·Óë20gNaOHÈÜÒº¹²ÈÈ£¬Ç¡ºÃÍêÈ«·´Ó¦£¬²âµÃ²ÐÁôÎïΪ26.8g £¨Ìáʾ£º·´Ó¦µÄ»¯Ñ§·½³ÌʽΪNH4HCO3+2NaOH¨TNa2CO3+2H2O+NH3¡ü£¬Éú³ÉµÄ°±ÆøÈ«²¿Òݳö£¬ÆäËû³É·Ö²»º¬µª£¬Ò²²»²Î¼Ó·´Ó¦£©£®ÊÔÇó£º
£¨1£©Éú³É°±ÆøµÄÖÊÁ¿£®
£¨2£©¸Ã»¯·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊý£¨¼ÆËã½á¹û¾«È·µ½0.1%£©£®
£¨3£©ËùÓÃÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ϊ²â¶¨Ä³Ì¼ËáÇâ炙¯·ÊÖе嬵ªÁ¿£¬Ä³Í¬Ñ§ÔÚʵÑéÊÒÀïÈ¡ÓÃ8.5g¸Ã»¯·ÊÑùÆ·Óë20gNaOHÈÜÒº·ÅÈëÉÕ±­Öй²ÈÈ£¬Ç¡ºÃÍêÈ«·´Ó¦£¬Éú³ÉµÄ°±ÆøÈ«²¿Òݳöºó£¬²âµÃÉÕ±­ÖвÐÁôÎïΪ26.8g £¨·´Ó¦µÄ»¯Ñ§·½³ÌʽΪNH4HCO3+2NaOH
  ¡÷  
.
 
Na2CO3+2H2O+NH3¡ü£©£®ÊÔÇó£º
£¨1£©Éú³É°±ÆøµÄÖÊÁ¿£®
£¨2£©¸Ã»¯·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊý£¨¼ÆËã½á¹û¾«È·µ½0.1%£©£®
£¨3£©ËùÓÃNaOHÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

Ϊ²â¶¨Ä³Ì¼ËáÇâ炙¯·ÊÖе嬵ªÁ¿£¬Ð¡±õÔÚʵÑéÊÒÀïÈ¡ÓÃ8.5g¸Ã»¯·ÊÑùÆ·Óë20gNaOHÈÜÒº¹²ÈÈ£¬Ç¡ºÃÍêÈ«·´Ó¦£¬²âµÃ²ÐÁôÎïΪ26.8g £¨Ìáʾ£º·´Ó¦µÄ»¯Ñ§·½³ÌʽΪNH4HCO3+2NaOH¨TNa2CO3+2H2O+NH3¡ü£¬Éú³ÉµÄ°±ÆøÈ«²¿Òݳö£¬ÆäËû³É·Ö²»º¬µª£¬Ò²²»²Î¼Ó·´Ó¦£©£®ÊÔÇó£º
£¨1£©Éú³É°±ÆøµÄÖÊÁ¿£®
£¨2£©¸Ã»¯·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊý£¨¼ÆËã½á¹û¾«È·µ½0.1%£©£®
£¨3£©ËùÓÃÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ϊ²â¶¨Ä³Ì¼ËáÇâ炙¯·ÊÖе嬵ªÁ¿£¬Ð¡±õÔÚʵÑéÊÒÀïÈ¡ÓÃ8.5 g¸Ã»¯·ÊÑùÆ·Óë20 g NaOHÈÜÒº¹²ÈÈ£¬Ç¡ºÃÍêÈ«·´Ó¦£¬²âµÃ²ÐÁôÎïΪ26.8 g(Ìáʾ£º·´Ó¦µÄ»¯Ñ§·½³ÌʽΪNH4HCO3+2NaOH====Na2CO3+2H2O+NH3¡ü£¬Éú³ÉµÄ°±ÆøÈ«²¿Òݳö£¬ÆäËû³É·Ö²»º¬µª£¬Ò²²»²Î¼Ó·´Ó¦)¡£ÊÔÇó£º

(1)Éú³É°±ÆøµÄÖÊÁ¿¡£

(2)¸Ã»¯·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊý(¼ÆËã½á¹û¾«È·µ½0.1%)¡£

(3)ËùÓÃÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2011Äêɽ¶«Ê¡±õÖÝÊÐÖп¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

Ϊ²â¶¨Ä³Ì¼ËáÇâ炙¯·ÊÖе嬵ªÁ¿£¬Ð¡±õÔÚʵÑéÊÒÀïÈ¡ÓÃ8.5g¸Ã»¯·ÊÑùÆ·Óë20gNaOHÈÜÒº¹²ÈÈ£¬Ç¡ºÃÍêÈ«·´Ó¦£¬²âµÃ²ÐÁôÎïΪ26.8g £¨Ìáʾ£º·´Ó¦µÄ»¯Ñ§·½³ÌʽΪNH4HCO3+2NaOH¨TNa2CO3+2H2O+NH3¡ü£¬Éú³ÉµÄ°±ÆøÈ«²¿Òݳö£¬ÆäËû³É·Ö²»º¬µª£¬Ò²²»²Î¼Ó·´Ó¦£©£®ÊÔÇó£º
£¨1£©Éú³É°±ÆøµÄÖÊÁ¿£®
£¨2£©¸Ã»¯·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊý£¨¼ÆËã½á¹û¾«È·µ½0.1%£©£®
£¨3£©ËùÓÃÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸