ÒÑÖª£ºNa2CO3ÊÜÈȲ»Ò׷ֽ⣬2NaHCO3Na2CO3+CO2¡ü+H2O¡£Ä³´¿¼îÑùÆ·ÖлìÓÐÉÙÁ¿µÄ̼ËáÇâÄÆ£¬ÎªÁ˲ⶨÑùÆ·µÄ´¿¶È£¬»ªÑ©Í¬Ñ§×öÁËÈçÏÂʵÑ飺׼ȷ³ÆÈ¡ÑùÆ·10.0g·ÅÈëÊÔ¹ÜÖУ¬¼ÓÈȳä·Ö·´Ó¦ÖÁÎÞÆøÌå·Å³ö£¬¹²²úÉúCO2ÆøÌå224 mL(¸ÃÌõ¼þÏÂÆøÌåµÄÃܶÈΪ1.964 g/L)¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)Éú³ÉCO2µÄÖÊÁ¿Îª________g(¾«È·µ½0.01g)¡£

(2)´¿¼îÑùÆ·ÖÐNa2CO3µÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿(ÒªÇóд³ö¼ÆËã¹ý³Ì£¬½á¹û¾«È·µ½0.1%)

(3)Èô½«a g¸Ã´¿¼îÑùÆ·³ä·Ö¼ÓÈÈÖÁÎÞÆøÌå·Å³ö£¬ÀäÈ´ºó³ÆµÃÊ£Óà¸ÉÔï¹ÌÌåµÄÖÊÁ¿Îªb g(b£¼a)¡£Ôò¸Ã´¿¼îÑùÆ·ÖÐNa2CO3µÄÖÊÁ¿·ÖÊýµÄ±í´ïʽΪ_______________¡£(ÒªÇóд³ö¼ÆËã¹ý³Ì)


(1)0.44 £¨2£©Éè´¿¼îÑùÆ·ÖÐNa2CO3µÄÖÊÁ¿Îªx¡£

2NaHCO3Na2CO3+CO2¡ü+H2O

168               44

10.0 g-x          0.44 g

=     x=8.32 g

´¿¼îÑùÆ·ÖÐNa2CO3µÄÖÊÁ¿·ÖÊýΪ¡Á100%=83.2%

´ð£º´¿¼îÑùÆ·ÖÐNa2CO3µÄÖÊÁ¿·ÖÊýΪ83.2%¡£

(3)ÓÉÌâÒâÖª£¬·´Ó¦ºó¹ÌÌå¼õÉÙµÄÖÊÁ¿(a-b)gΪÉú³ÉµÄË®ºÍ¶þÑõ»¯Ì¼µÄÖÊÁ¿¡£ÉèÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýΪy¡£

2NaHCO3Na2CO3+CO2¡ü+H2O

168                 44+18

a¡Á(1-y)           (a-b)g

=    ½âµÃ:y=


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÂÈ»¯ï§ºÍÁòËáÄƵÄÈܽâ¶ÈÇúÏßÈçͼËùʾ£¬ÏÂÁдÓͼÖлñÈ¡µÄÐÅÏ¢ÖÐÕýÈ·µÄÊÇ £¨      £©

A£®Á½ÖÖÎïÖÊÈܽâ¶È¶¼ËæζÈÉý¸ß¶øÔö´ó

B£®45¡æʱÁ½ÖÖÎïÖÊÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýÏàµÈ

C£®½«50¡æµÄÁòËáÄƱ¥ºÍÈÜÒº½µÖÁ20¡æ£¬Ê¼ÖÕûÓо§ÌåÎö³ö

D£®20¡æÅäÖÆ100g5%ÁòËáÄÆÈÜÒº£¬ÈôÁ¿Ë®Ê±¸©ÊÓ¶ÁÊý£¬ÔòËùµÃÈÜÒºÖÊÁ¿·ÖÊýÆ«´ó

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


¡°ËÜ»¯¼Á¡±ÊÇÒ»ÖÖ¹¤ÒµÔ­ÁÏ£¬µ«²»·¨ÉÌÈË°ÑËüÌí¼Óµ½ÒûÓÃÆ·µ±ÖУ¬È˺ÈÁËÕâÑùµÄÒûÓÃÆ·£¬»á¶ÔÉíÌåÔì³ÉÑÏÖصÄΣº¦¡£ÒÑÖª¡°ËÜ»¯¼Á¡±µÄÖ÷Òª³É·ÖÊÇÁÚ±½¶þ¼×Ëá¶þÐÁõ¥£¬»¯Ñ§Ê½ÎªC24H38O4£¬Íê³ÉÏÂÁÐÎÊÌ⣺

(1)ÁÚ±½¶þ¼×Ëá¶þÐÁõ¥ÊôÓÚ_______(Ìî¡°ÓлúÎ»ò¡°ÎÞ»úÎ)¡£

(2)ÁÚ±½¶þ¼×Ëá¶þÐÁõ¥µÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ_______¡£

(3)ÁÚ±½¶þ¼×Ëá¶þÐÁõ¥ÖÐ̼¡¢Çâ¡¢ÑõÈýÖÖÔªËصÄÖÊÁ¿±ÈÊÇ_______¡£

(4)ÁÚ±½¶þ¼×Ëá¶þÐÁõ¥ÖÐ̼ԪËصÄÖÊÁ¿·ÖÊýÊÇ___________(¾«È·µ½0.1%)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


½«13 gij½ðÊôR·ÅÈë×ãÁ¿µÄÑÎËáÖУ¬Ê¹Æä³ä·Ö·´Ó¦£¬Éú³ÉRCl2ÐÍ»¯ºÏÎ¹²·Å³öÇâÆø0.4 g£¬ÔòRµÄÏà¶ÔÔ­×ÓÖÊÁ¿ÊÇ(  )

A.23             B.24              C.56             D.65

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


½«Ã¾·ÛºÍÂÁ·ÛµÄ»ìºÏÎï7.2gÓë×ãÁ¿µÄÑõÆø³ä·Ö·´Ó¦£¬µÃµ½µÄÑõ»¯ÎïÖÊÁ¿¿ÉÄÜΪ(  )

A.10.6g          B.12.0g          C.13.0g           D.13.6g

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


½«50g 98%µÄŨÁòËáÈÜÓÚ450gË®ÖУ¬ËùµÃÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýΪ(  )

A.9.8%             B.10.2%           C.10.8%          D.19.6%

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÎÒ¹úÖƼҵµÄÏÈÇý¡ª¡ªºîµÂ°ñ̽Ë÷·¢Ã÷ÁË¡°ºîÊÏÖƼ¡±£¬ÆäÉú²ú¹ý³ÌÉæ¼°µÄÖ÷Òª»¯Ñ§·´Ó¦ÈçÏ£º

¢ÙNH3£«CO2£«XNH4HCO3

¢ÚNH4HCO3£«NaClNH4Cl£«NaHCO3¡ý

¢Û2NaHCO3Na2CO3£«H2O£«CO2¡ü

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)·´Ó¦¢ÙÖÐXµÄ»¯Ñ§Ê½Îª_________¡£

(2)³ýÈ¥»ìÔÚNa2CO3·ÛÄ©ÖÐÉÙÁ¿µÄNaHCO3µÄ·½·¨ÊÇ_____________________¡£

(3)¹¤Òµ´¿¼îÖк¬ÓÐÂÈ»¯ÄÆ£¬È¡55 g¹¤Òµ´¿¼î£¬ÏòÆäÖмÓÈë269.5 gÏ¡ÑÎËᣬǡºÃÍêÈ«·´Ó¦£¬Éú³É22 g¶þÑõ»¯Ì¼£¬Ç󣺢ٹ¤Òµ´¿¼îÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊý¡£(¼ÆËã½á¹û±£Áôµ½0.1%)

¢Ú·´Ó¦ºóÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ijͬѧ×öºìÁ×ÔÚÑõÆøÖÐȼÉÕʵÑéʱ£¬½«µãȼµÄºìÁ×ÉìÈëÊ¢ÓÐÑõÆøµÄ¼¯ÆøÆ¿ÖУ¬ºìÁ×¾çÁÒȼÉÕ£¬¹ýÒ»»á¶ù£¬È¼ÉÕ³×ÄÚ»ðÑæϨÃð¡£½Ó×ÅÁ¢¼´´Ó¼¯ÆøÆ¿ÖÐÈ¡³öȼÉÕ³×£¬Ï¨ÃðµÄºìÁ×ÓÖ¸´È¼ÁË¡£

£¨1£©ÇëÄã·ÖÎöºìÁ׸´È¼µÄÔ­Òò___________________________________________________________________£º

£¨2£©Ïû·À¶ÓÔ±ÔÚ»ðÔÖÏÖ³¡ÆËÃðÃ÷»ðºó£¬»¹Òª¼ÌÐøÈ÷Ë®µÄÔ­ÒòÊÇ____________________________________________¡£3.(2014¡¤¼ÃÄþ)ÓÃÂËÖ½Õ۳ɺûµû²¢ÅçÈ÷

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÀûÓÃÄÉÃ׶þÑõ»¯îÑ£¨TiO2£©¿É¾»»¯ÊÒÄÚ¿ÕÆø¡£TiO2ÖÐTiµÄ»¯ºÏ¼ÛΪ

A.£«4           B. £«2            C.£«1            D.£­4

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸