Ëæ×ÅÊÀ½çÈË¿ÚµÄÔö³¤£¬ÈËÀà¶ÔÁ¸Ê³µÄÐèÇóÁ¿²»¶ÏÔö´ó£®Ë×»°Ëµ£¬¡°×¯¼ÚÒ»Ö¦»¨£¬È«¿¿·Êµ±¼Ò£®¡±Çë¸ù¾ÝËùѧµÄ֪ʶ£¬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Å©×÷ÎïÉú³¤¹ý³ÌÖУ¬ÐèÇóÁ¿×î´óµÄÈýÖÖÓªÑøÔªËØÊÇ¡¡          ¡¡£¨ÌîÔªËØÃû³Æ£©

£¨2£©Ä³Å©Ãñ×¼±¸ÅäÖÆÒ»ÖÖ¸´ºÏ·Ê50kg£¬¸Ã¸´ºÏ·ÊÖк¬NH4Cl¡¢NH4H2PO4ºÍK2SO4µÄÖÊÁ¿±ÈΪ1£º2£º2£¬ÔòÐèÒªNH4H2PO4µÄÖÊÁ¿Îª¡¡        ¡¡kg£¬¸Ã¸´ºÏ·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊýΪ¡¡               ¡¡£»

£¨3£©Çëд³ö¼ø±ðNH4ClºÍK2SO4ÕâÁ½ÖÖ»¯Ñ§·ÊÁϵIJÙ×÷·½·¨¼°ÊµÑéÏÖÏ󣺡¡                  £»

·½·¨¶þ£º                                                                 £»

·½·¨Èý£º                                                                     £®

 

¡¾´ð°¸¡¿

£¨1£©µª¡¢Áס¢¼Ø£»£¨2£©20£»10.1%£¨3£©·½·¨Ò»£º·Ö±ðÈ¡ÉÙÁ¿Á½ÖÖ»¯·Ê£¬·ÅÔÚÌúƬÉÏ×ÆÉÕ£¬ÈôðÑ̵ÄÊÇNH4Cl£¬ÎÞ´ËÏÖÏóµÄÊÇK2SO4£®·½·¨¶þ£º·Ö±ðÈ¡ÉÙÁ¿Á½ÖÖ»¯·ÊÓÚÁ½Ö§ÊÔ¹ÜÖУ¬È»ºóÔÙ¼ÓÈëÕôÁóË®£¬Åä³ÉÈÜÒº£¬²¢·Ö±ðµÎ¼ÓBaCl2ÈÜÒº£¬Óа×É«³Áµí²úÉúµÄÊÇK2SO4£¬ÎÞ´ËÏÖÏóµÄÊÇNH4Cl£®·½·¨Èý£º·Ö±ðÈ¡ÉÙÁ¿Á½ÖÖ»¯·ÊÓÚÁ½Ö§ÊÔ¹ÜÖУ¬È»ºóÔÙ¼ÓÈëÊìʯ»Ò£¬¼ÓÈÈ£¬Óд̼¤ÐÔÆøζÆøÌå·Å³öµÄÊÇNH4Cl£¬ÎÞ´ËÏÖÏóµÄÊÇK2SO4£®

¡¾½âÎö¡¿

ÊÔÌâ·ÖÎö£º£¨1£©Ö²ÎïÉú³¤¹ý³ÌÖÐÐèÒªµÄÓªÑøÔªËرȽ϶࣬ÆäÖÐÐèÒªÁ¿×î´óµÄÈýÖÖÔªËØÊǵª¡¢Áס¢¼Ø£®£¨2£©ÐèÒªÂÈ»¯ï§µÄÖÊÁ¿Îª50kg¡Á=10kgÂÈ»¯ï§ÖеªÔªËصÄÖÊÁ¿Îª10kg¡Á¡Ö2.62kg Á×Ëá¶þÇâ淋ÄÖÊÁ¿Îª50kg¡Á=20kgÁ×Ëá¶þÇâï§ÖеªÔªËصÄÖÊÁ¿Îª20kg¡Á¡Á100%¡Ö2.43kg¸´ºÏ·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊý¡Á100%=10.1%

£¨3£©¼ø±ðÂÈ»¯ï§ºÍÁòËá¼ØµÄ·½·¨±È½Ï¶à£¬È磺·½·¨Ò»£º·Ö±ðÈ¡ÉÙÁ¿Á½ÖÖ»¯·Ê£¬·ÅÔÚÌúƬÉÏ×ÆÉÕ£¬ÈôðÑ̵ÄÊÇNH4Cl£¬ÎÞ´ËÏÖÏóµÄÊÇK2SO4£®·½·¨¶þ£º·Ö±ðÈ¡ÉÙÁ¿Á½ÖÖ»¯·ÊÓÚÁ½Ö§ÊÔ¹ÜÖУ¬È»ºóÔÙ¼ÓÈëÕôÁóË®£¬Åä³ÉÈÜÒº£¬²¢·Ö±ðµÎ¼ÓBaCl2ÈÜÒº£¬Óа×É«³Áµí²úÉúµÄÊÇK2SO4£¬ÎÞ´ËÏÖÏóµÄÊÇNH4Cl£®·½·¨Èý£º·Ö±ðÈ¡ÉÙÁ¿Á½ÖÖ»¯·ÊÓÚÁ½Ö§ÊÔ¹ÜÖУ¬È»ºóÔÙ¼ÓÈëÊìʯ»Ò£¬¼ÓÈÈ£¬Óд̼¤ÐÔÆøζÆøÌå·Å³öµÄÊÇNH4Cl£¬ÎÞ´ËÏÖÏóµÄÊÇK2SO4£®

¿¼µã£º³£¼û»¯·ÊµÄÖÖÀàºÍ×÷Óã»»¯·ÊµÄ¼òÒ×¼ø±ð£»ÔªËصÄÖÊÁ¿·ÖÊý¼ÆË㣻ÎïÖÊ×é³ÉµÄ×ۺϼÆË㣮

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ëæ×ÅÊÀ½çÈË¿ÚµÄÔö³¤£¬ÈËÀà¶ÔÁ¸Ê³µÄÐèÇóÁ¿²»¶ÏÔö´ó£®Ë×»°Ëµ£¬¡°×¯¼ÚÒ»Ö¦»¨£¬È«¿¿·Êµ±¼Ò£®¡±
Å©×÷ÎïÉú³¤¹ý³ÌÖУ¬ÐèÇóÁ¿×î´óµÄÈýÖÖÓªÑøÔªËØÊÇ
 
£¨ÌîÔªËØÃû³Æ£©£®Ä³Å©Ãñ¸ù¾ÝÖÖÖ²µÄÅ©×÷ÎïÉú³¤µÄÇé¿ö£¬×¼±¸ÅäÖÆÒ»ÖÖ¸´ºÏ·Ê60kg£¬¸Ã¸´ºÏ·ÊÖк¬KCl¡¢NH4H2PO4ºÍ£¨NH4£©2SO4µÄÖÊÁ¿±ÈΪ1£º2£º1£¬ÔòÐèÒª£¨NH4£©2SO4µÄÖÊÁ¿Îª
 
kg£¬¸Ã¸´ºÏ·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊýΪ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ëæ×ÅÊÀ½çÈË¿ÚµÄÔö³¤£¬ÈËÀà¶ÔÁ¸Ê³µÄÐèÇóÁ¿²»¶ÏÔö´ó£®Ë×»°Ëµ£¬¡°×¯¼ÚÒ»Ö¦»¨£¬È«¿¿·Êµ±¼Ò£®¡±Çë¸ù¾ÝËùѧµÄ֪ʶ£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Å©×÷ÎïÉú³¤¹ý³ÌÖУ¬ÐèÇóÁ¿×î´óµÄÈýÖÖÓªÑøÔªËØÊÇ
 
£¨ÌîÔªËØÃû³Æ£©
£¨2£©Ä³Å©Ãñ×¼±¸ÅäÖÆÒ»ÖÖ¸´ºÏ·Ê50kg£¬¸Ã¸´ºÏ·ÊÖк¬NH4Cl¡¢NH4H2PO4ºÍK2SO4µÄÖÊÁ¿±ÈΪ1£º2£º2£¬ÔòÐèÒªNH4H2PO4µÄÖÊÁ¿Îª
 
kg£¬¸Ã¸´ºÏ·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊýΪ
 
£®
£¨3£©Çëд³ö¼ø±ðNH4ClºÍK2SO4ÕâÁ½ÖÖ»¯Ñ§·ÊÁϵIJÙ×÷·½·¨¼°ÊµÑéÏÖÏó£º
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ëæ×ÅÊÀ½çÈË¿ÚµÄÔö³¤£¬ÈËÀà¶ÔÁ¸Ê³µÄÐèÇóÁ¿²»¶ÏÔö´ó£®Ë×»°Ëµ£¬¡°×¯¼ÚÒ»Ö¦»¨£¬È«¿¿·Êµ±¼Ò£®¡±Çë¸ù¾ÝËùѧµÄ֪ʶ£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Å©×÷ÎïÉú³¤¹ý³ÌÖУ¬ÐèÇóÁ¿×î´óµÄÈýÖÖÓªÑøÔªËØÊÇ
µª¡¢Áס¢¼Ø
µª¡¢Áס¢¼Ø
£¨ÌîÔªËØÃû³Æ£©£®
£¨2£©Ä³Å©Ãñ×¼±¸ÅäÖÆÒ»ÖÖ¸´ºÏ·Ê50kg£¬¸Ã¸´ºÏ·ÊÖк¬NH4Cl¡¢NH4H2PO4ºÍK2SO4µÄÖÊÁ¿±ÈΪ1£º2£º2£¬ÔòÐèÒªNH4H2PO4µÄÖÊÁ¿Îª
20
20
kg£¬¸Ã¸´ºÏ·ÊÖеªÔªËصÄÖÊÁ¿·ÖÊýΪ
10.1%
10.1%
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

I¡¢Ëæ×ÅÈËÃǶÔÉíÌ彡¿µ¡¢Éú»îÖÊÁ¿µÄ¹Ø×¢³Ì¶È²»¶ÏÌá¸ß£¬Ô½À´Ô½¶àµÄÈËϲ°®ÉÏÁ˼ȿÉÒÔ¶ÍÁ¶ÉíÌ壬ÓÖ¿ÉÒÔÐÀÉÍ×ÔÈ»ÃÀ¾°£¬»¹¿ÉÒÔÓäÔÃÉíÐĵÄÅÀɽ»î¶¯£¬³ÉΪÖڶࡰ¿ÓÑ¡±ÖеÄÒ»Ô±£®
£¨1£©¡°Â¿ÓÑ¡±ÃÇÔÚÅÀɽʱ¾­³£´øµÄʳƷ֮һÊÇÅ£È⣬ţÈâ¿ÉΪÈËÌåÌṩµÄÓªÑøËØÊÇ
µ°°×ÖÊ
µ°°×ÖÊ
£®
£¨2£©ÅÀɽʱ£¬ÈËÌå»á´óÁ¿³öº¹£®Ä㽨Òé¿ÓÑ»¹Ó¦´øÉÏÊÊÁ¿µÄ
A
A
£¨Ìî×Öĸ£©
A¡¢ÌÇÑÎË®    B¡¢¹ûÖ­     C¡¢ÇÉ¿ËÁ¦
£¨3£©Íí¼äҪʹóô»ðȼÉÕµÄÍúÊ¢£¬Æä·½·¨ÊÇ
°Ñľ²ñ¼Ü¿ÕһЩ²ÅÄÜȼÉÕ¸üÍú
°Ñľ²ñ¼Ü¿ÕһЩ²ÅÄÜȼÉÕ¸üÍú
£®
II¡¢Ëæ×ÅÊÀ½çÈË¿ÚµÄÔö³¤£¬ÈËÀà¶ÔÁ¸Ê³µÄÐèÇóÁ¿²»¶ÏÔö´ó£®Ë×»°Ëµ£¬¡°×¯¼ÚÒ»Ö¦»¨£¬È«¿¿·Êµ±¼Ò£®¡±Çë¸ù¾ÝËùѧµÄ֪ʶ£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Å©×÷ÎïÉú³¤¹ý³ÌÖУ¬ÐèÇóÁ¿×î´óµÄÈýÖÖÓªÑøÔªËØÊÇ
N¡¢P¡¢K
N¡¢P¡¢K
£¨ÌîÔªËØ·ûºÅ£©£®
£¨2£©Ä³Å©Ãñ·¢ÏÖ×Ô¼ºµØÀïµÄׯ¼ÚҶɫ¿Ý»Æ£¬²¢ÇÒÓв¿·Öµ¹·üÏÖÏó£¬Ä㽨ÒéËüÓ¦¸ÃÊ©ÓÃÏÂÁÐÄÄÒ»ÖÖ·ÊÁÏ×îºÃ
C
C
£®
A£® NH4Cl       B£®K2SO4      C£®KNO3       D¡¢Ca£¨H2PO4£©2
£¨3£©ÓÃÒ»ÖÖÊÔ¼Á¼´¿É¼ø±ðNH4ClºÍK2SO4ÕâÁ½ÖÖ»¯Ñ§·ÊÁÏ£¬ÕâÖÖÊÔ¼ÁÊÇ
NaOH
NaOH
£¨Ìѧʽ£©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Ëæ×ÅÊÀ½çÈË¿ÚµÄÔö³¤£¬ÈËÀà¶ÔÁ¸Ê³µÄÐèÇóÁ¿²»¶ÏÔö´ó£®Ë×»°Ëµ£º¡°×¯¼ÚÒ»Ö¦»¨£¬È«¿¿·Êµ±¼Ò£®¡±Çë¸ù¾ÝËùѧµÄ֪ʶ£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Å©×÷ÎïÉú³¤¹ý³ÌÖУ¬ÐèÇóÁ¿×î´óµÄÈýÖÖÓªÑøÔªËØÊÇ
 
£¨ÌîÔªËØÃû³Æ£©£®
£¨2£©Ä³Å©Ãñ×¼±¸ÅäÖÆÒ»ÖÖ¸´ºÏ·Ê50kg£¬¸Ã¸´ºÏ·ÊÖк¬NH4Cl¡¢NH4H2PO4ºÍK2SO4µÄÖÊÁ¿±ÈΪ1£º2£º2£¬ÔòÐèÒªNH4H2PO4µÄÖÊÁ¿Îª
 
kg£¬¸Ã¸´ºÏ·ÊÖмØÔªËصÄÖÊÁ¿·ÖÊýΪ
 
£®
£¨3£©Çëд³ö¼ø±ðNH4ClºÍK2SO4ÕâÁ½ÖÖ»¯Ñ§·ÊÁϵIJÙ×÷·½·¨¼°ÊµÑé½áÂÛ£ºÊµÑé·½·¨
 
£»ÊµÑé½áÂÛ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸