5£®ÊµÑéÊÒÓÐһƿŨÁòËá·ÏÒº£¬Ð¡ºìͬѧÓÃÈçÏ·½°¸²â¶¨¸Ã·ÏÒºÖÐÁòËáµÄÖÊÁ¿·ÖÊý£¬È¡Ò»¶¨ÖÊÁ¿µÄŨÁòËá·ÏÒºÓÚÉÕ±­ÖУ¬¼ÓÈëһö½à¾»µÄÌú¶¤£¬¹Û²ìÖÁÌú¶¤±íÃæ²»ÔÚÓÐÆøÅÝ£¬¸÷²½³ÆÁ¿Êý¾ÝÈç±í£º
ÉÕ±­µÄÖÊÁ¿/g18.2g
ÉÕ±­¼°Ï¡ÁòËáµÄÖÊÁ¿/g33.2g
Ìú¶¤£¨ÒÑÓÃÉ°Ö½´òĥȥµôÌúÐ⣩/g10.8g
·´Ó¦ºóÉÕ±­¼°ËùÊ¢ÎïÖʵÄ×ÜÖÊÁ¿/g43.9g
£¨1£©·´Ó¦ÖвúÉúµÄÆøÌåµÄÖÊÁ¿ÊÇ0.1g£®
£¨2£©¼ÆËã¸Ã·ÏÒºÖÐÁòËáµÄÖÊÁ¿·ÖÊý£¨Ð´³ö¼ÆËã¹ý³Ì£¬¼ÆËã½á¹û±£ÁôһλСÊý£©£®
£¨3£©Èç¹ûÌú¶¤µÄÌúÐâδ³ý¾»£¬¶Ô¼ÆËã½á¹ûµÄÓ°ÏìÊÇƫС£¨Ñ¡Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°ÎÞÓ°Ï족£©£®

·ÖÎö ÌúºÍÏ¡ÁòËá·´Ó¦Éú³ÉÁòËáÑÇÌúºÍÇâÆø£¬·´Ó¦Ç°ºóµÄÖÊÁ¿²î¼´Îª·´Ó¦Éú³ÉÇâÆøµÄÖÊÁ¿£¬¸ù¾ÝÌṩµÄÊý¾ÝºÍ·´Ó¦µÄ»¯Ñ§·½³Ìʽ¿ÉÒÔ½øÐÐÏà¹Ø·½ÃæµÄ¼ÆË㣮

½â´ð ½â£º£¨1£©·´Ó¦Éú³ÉÇâÆøÖÊÁ¿Îª£º33.2g+10.8g-43.9g=0.1g£¬
¹ÊÌ0.1£®
£¨2£©½â£ºÉèÓëÌú·´Ó¦µÄÁòËáµÄÖÊÁ¿Îªx£¬
ÉÕ±­ÖÐÏ¡ÁòËá·ÏÒºµÄÖÊÁ¿Îª33.2g-18.2g=15.0g£¬
Fe+H2SO4¨TFeSO4+H2¡ü£¬
    98          2
    x           0.1g
$\frac{98}{x}$=$\frac{2}{0.1g}$£¬
x=4.9g£¬
¸Ã·ÏÒºÖÐÁòËáµÄÖÊÁ¿·ÖÊýΪ£º$\frac{4.9g}{15.0g}$¡Á100%¨T32.7%£¬
´ð£º·ÏÒºÖÐÁòËáµÄÖÊÁ¿·ÖÊýÊÇ32.7%£®
£¨3£©Èç¹ûÌú¶¤µÄÌúÐâδ³ý¾»£¬ÌúÐâ»áÏûºÄÒ»²¿·ÖÁòËᣬ»áµ¼Ö¸ù¾Ý»¯Ñ§·½³Ìʽ¼ÆËãµÄÁòËáÖÊÁ¿Æ«Ð¡£¬´Ó¶øµ¼Ö¼ÆËã½á¹ûƫС£®
¹ÊÌƫС£®

µãÆÀ ±¾ÌâÖ÷Òª¿¼²éѧÉúÔËÓüÙÉè·¨ºÍ»¯Ñ§·½³Ìʽ½øÐмÆËãºÍÍƶϵÄÄÜÁ¦£¬¼ÆËãʱҪעÒâ¹æ·¶ÐÔºÍ׼ȷÐÔ£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

15£®°´ÒªÇóÓû¯Ñ§ÓïÑÔÌî¿Õ
£¨1£©µ¼µçÐÔÄÜ×îºÃµÄ½ðÊôAg£»
£¨2£©ÏõËáÖеªÔªËصĻ¯ºÏ¼ÛH$\stackrel{+5}{N}$O3£»
£¨3£©ÁòËáÄÆÈÜÒºÖдæÔÚµÄ΢Á£Na+¡¢SO42-¡¢H2O£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

16£®ÏÂÁÐÊÂÀýÊôÓÚ»¯Ñ§±ä»¯µÄÊÇ£¨¡¡¡¡£©
A£®¾Æ¾«»Ó·¢B£®Ê¯À¯ÈÛ»¯C£®ÌúÉúÐâD£®º£Ë®É¹ÑÎ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

13£®·ÇÎïÖÊÎÄ»¯ÒŲú¡°ÎߺþÌú»­¡±£¨¶Æ½ð£©º¬Óнð¡¢Ìú£¨ÆäËû³É·ÖºöÂÔ²»¼Æ£©£¬Ä³Í¬Ñ§Ïë²âÁ¿Æ京½ðÁ¿£¬ÓÚÊÇÈ¡Ò»¶¨ÖÊÁ¿µÄÌú»­±ß½ÇÁÏ£¬¼ÓÈë×ãÁ¿Ï¡ÁòËᣬʹËüÃdzä·Ö·´Ó¦£¬¾ßÌåÊý¾ÝÈçϱíËùʾ£¬Çë¼ÆË㣺
·´Ó¦Ç°ÎïÖʵÄÖÊÁ¿/g³ä·Ö·´Ó¦ºóÎïÖʵÄÖÊÁ¿/g
Ìú»­±ß½ÇÁÏÏ¡ÁòËáÊ£Óà¹ÌÌåºÍÒºÌåµÄ×ÜÖÊÁ¿
8.5170178.2
£¨1£©²úÉúÆøÌåµÄÖÊÁ¿Îª0.3g£»
£¨2£©ÑùÆ·ÖÐÌúµÄÖÊÁ¿ÊǶàÉÙ£¿
£¨3£©ÑùÆ·ÖнðµÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿£¨½á¹û±£ÁôһλСÊý£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

20£®ÏÂÁÐʵÑé·½°¸ÄܴﵽʵÑéÄ¿µÄÊÇ£¨¡¡¡¡£©
Ñ¡ÏîʵÑéÄ¿µÄʵÑé·½°¸
A³ýÈ¥Ñõ»¯¸ÆÖеÄ̼Ëá¸Æ¼ÓÈë×ãÁ¿µÄË®Èܽ⣬¹ýÂË
B³ýÈ¥ÂÈ»¯ÄƹÌÌåÖеÄÉÙÁ¿Ì¼ËáÄƼÓÈëÊÊÁ¿Ï¡ÑÎËᣬ³ä·Ö·´Ó¦£¬Õô·¢
CÖ¤Ã÷ËáºÍ¼îÇ¡ºÃÖкÍÏòº¬ÓзÓ̪µÄÇâÑõ»¯ÄÆÈÜÒºÖмÓÈëÑÎËᣬÈÜÒº×îÖÕ³ÊÎÞÉ«
D²â¶¨¾ÃÖÃÓÚ¿ÕÆøÖеÄNaOH¹ÌÌåÖÐ̼ËáÄƵĺ¬Á¿È¡ag¹ÌÌ壬¼ÓÈë×ãÁ¿Ï¡ÑÎËᣬÓÃÅÅË®·¨ÊÕ¼¯µ½VmolÆøÌå
A£®AB£®BC£®CD£®D

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

10£®ÔÚʵÑéÊÒÀ½«31.6g¸ßÃÌËá¼Ø·ÅÔÚ´óÊÔ¹ÜÖмÓÈÈ£¬¹ýÒ»¶Îʱ¼äºóÍ£Ö¹¼ÓÈÈ£¬ÀäÈ´ºó³ÆµÃÊ£Óà¹ÌÌåµÄÖÊÁ¿Îª30g£¬È»ºó¼ÌÐø¼ÓÈÈ£¬µ½²»ÔÙÓÐÆøÌå·Å³öΪֹ£¬µÚ¶þ´ÎÊÕ¼¯µ½µÄÑõÆøΪ1.6g£¬Çó£º
£¨1£©µÚÒ»´Î·´Ó¦Éú³ÉÑõÆø¶àÉÙ¿Ë£¿Á½´Î·´Ó¦¹²Éú³ÉÑõÆø¶àÉÙ¿Ë£¿
£¨2£©µÚÒ»´Î·´Ó¦ºóÊ£Óà¸ßÃÌËá¼Ø¶àÉÙ¿Ë£¿
£¨3£©ÊµÑé½áÊøºó£¬¿É»ØÊÕ¶þÑõ»¯Ã̵ÄÖÊÁ¿Îª¶àÉÙ¿Ë£¿

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

6£®Ä³»¯Ñ§ÐËȤС×éµÄͬѧÔÚʵÑéÊÒÅäÖÆÖÊÁ¿·ÖÊýΪ8%µÄÇâÑõ»¯ÄÆÈÜÒº£¬²¢ÓÃÆä²â¶¨Ä³Ï¡ÑÎËáÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý£®
ÅäÖÆ200gÖÊÁ¿·ÖÊýΪ8%µÄÇâÑõ»¯ÄÆÈÜÒº£®
¢Ù¼ÆË㣺ÐèÒªÇâÑõ»¯ÄƹÌÌåµÄÖÊÁ¿Îª16g£¬Ë®µÄÌå»ýΪ184mL
£¨Ë®µÄÃܶȽüËÆ¿´×÷1g/cm3£©£®
¢Ú³ÆÁ¿£ºµ÷½ÚÍÐÅÌÌìƽƽºâ£¬½«Ò»¸öÉÕ±­·ÅÔÚÍÐÅÌÌìƽµÄ×óÅÌ£¬³ÆÁ¿ÆäÖÊÁ¿£®È»ºóBA£¨°´²Ù×÷µÄÏȺó˳ÐòÑ¡Ìî×Öĸ£©£¬Ö±ÖÁÌìƽƽºâ£®
A£®½«ÇâÑõ»¯ÄƹÌÌå¼ÓÈëÉÕ±­ÖР   B£®°´ÐèÒªÌí¼ÓíÀÂë¡¢Òƶ¯ÓÎÂë
¸Ã²½ÖèÖÐÓÃÉÕ±­¶ø²»ÓÃÖ½³ÆÁ¿ÇâÑõ»¯ÄƵÄÔ­ÒòÊÇÇâÑõ»¯ÄƾßÓÐÇ¿Áҵĸ¯Ê´ÐÔ£®
¢ÛÈܽ⣺ÓÃÁ¿Í²Á¿È¡ËùÐèµÄË®£¬µ¹ÈëÊ¢ÓÐÇâÑõ»¯ÄƹÌÌåµÄÉÕ±­À½Á°è£¬Ê¹ÆäÈܽ⣬²¢ÀäÈ´ÖÁÊÒΣ®
¢Ü°ÑÅäºÃµÄÈÜҺװÈëÊÔ¼ÁÆ¿£¬ÈûºÃÏðƤÈû²¢ÌùÉϱêÇ©£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

3£®°´ÒªÇóд³ö»¯Ñ§·½³Ìʽ£º
£¨1£©ÓÐÇâÆø·Å³öµÄ·Ö½â·´Ó¦2H2O$\frac{\underline{\;ͨµç\;}}{\;}$2H2¡ü+O2¡ü
£¨2£©¾çÁÒ·´Ó¦£¬»ðÐÇËÄÉ䣬Éú³ÉºÚÉ«¹ÌÌåµÄ»¯ºÏ·´Ó¦3Fe+2O2$\frac{\underline{\;µãȼ\;}}{\;}$Fe3O4
£¨3£©ÊµÑéÊÒÊÇÓüÓÈÈÂÈ»¯ï§£¨NH4Cl£©ºÍÊìʯ»Ò£¨Ca£¨OH£©2£©Á½ÖÖ·½¹ÌÌå»ìºÏÎïµÄ·½·¨ÖÆÈ¡°±ÆøµÄ£¬Í¬Éú³ÉÂÈ»¯¸ÆºÍË®£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ2NH4Cl+Ca£¨OH£©2$\frac{\underline{\;\;¡÷\;\;}}{\;}$CaCl2+2NH3¡ü+2H2O£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

4£®ÏÂÁÐʵÑéÏÖÏóÃèÊöÓëÊÂʵ·ûºÏµÄÊÇ£¨¡¡¡¡£©
A£®ºìÁ×ÔÚÑõÆøÖÐȼÉÕʱ£¬Éú³É´óÁ¿°×É«ÑÌÎí
B£®Ä¾Ì¿ÔÚÑõÆøÖÐȼÉÕ£¬·¢³ö°×¹â£¬ÓкÚÉ«¹ÌÌåÉú³É
C£®µç½âˮʱ£¬ÓëÕý¼«¡¢¸º¼«ÏàÁ¬µÄµç¼«ÖÜΧ²úÉúµÄÆøÌåÌå»ý±ÈԼΪ1£º2
D£®ÁòÔÚÑõÆøÖÐȼÉÕʱ£¬·¢³öÀ¶×ÏÉ«»ðÑ棬Éú³ÉÎÞÉ«ÎÞζµÄÆøÌå

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸