£¨2011?ºÓÎ÷Çøһģ£©ÏÖÓеªÆø¡¢ÑõÆø¡¢Ò»Ñõ»¯Ì¼¡¢¼×Íé¡¢ÏõËá¼Ø¡¢¾Æ¾«¡¢Ê³ÑΡ¢Êìʯ»Ò¡¢Ì¼Ëá¸ÆµÈ¾ÅÖÖÎïÖÊ£¬Çë°´ÒªÇóÌîдÏÂÁпհף¨Óû¯Ñ§Ê½Ìîд£©£®
£¨1£©Ô¼Õ¼¿ÕÆø×ÜÌå»ý4/5µÄÊÇ
N2
N2
£»
£¨2£©Óж¾ÐÔ£¬¿ÉȼÉÕµÄÆøÌåÊÇ
CO
CO
£»
£¨3£©Ë¾»ú¼Ý³µÇ°ÒûÓõÄÒûÁÏÖУ¬²»Äܺ¬ÓеÄÊÇ
C2H5OH
C2H5OH
£»
£¨4£©ÈÕ³£Éú»îÖÐÓÃÀ´µ÷ζºÍ·À¸¯µÄÊÇ
NaCl
NaCl
£»
£¨5£©Å©ÌïÊ©Óõĸ´ºÏ·ÊÁÏÊÇ
KNO3
KNO3
£»
£¨6£©ÄÜÓÃÓÚ¸ÄÁ¼ËáÐÔÍÁÈÀµÄÊÇ
Ca£¨OH£©2
Ca£¨OH£©2
£®
·ÖÎö£º¸ù¾Ý¸÷ÖÖÎïÖʵÄÐÔÖʺÍÓÃ;Ìî¿Õ£¬¸ù¾Ý»¯Ñ§Ê½µÄÊéд¹æÔòÕýÈ·Êéд»¯Ñ§Ê½£®
½â´ð£º½â£º£¨1£©¿ÕÆøÖи÷³É·Ö¼°Ìå»ý·ÖÊýΪ£ºµªÆø£º78%¡¢ÑõÆø£º21%¡¢Ï¡ÓÐÆøÌ壺0.94%¡¢¶þÑõ»¯Ì¼0.03%¡¢Ë®ÕôÆøºÍÔÓÖÊ£º0.03%£®ËùÒÔµªÆøÔ¼Õ¼
4
5
£®Æ仯ѧʽΪ£ºN2£»
£¨2£©Ò»Ñõ»¯Ì¼Óж¾£¬¿ÉÒÔȼÉÕ£¬×´Ì¬ÎªÆøÌ壬·ûºÏÌâÒ⣬Æ仯ѧʽΪ£ºCO£»
£¨3£©Ë¾»ú¼Ý³µÇ°ÒûÓõÄÒûÁÏÖУ¬²»Äܺ¬ÓеÄÊǾƾ«£®Æ仯ѧʽΪ£ºC2H5OH£»
£¨4£©ÈÕ³£Éú»îÖÐÓÃÀ´µ÷ζºÍ·À¸¯µÄÊÇʳÑÎÂÈ»¯ÄÆ£®Æ仯ѧʽΪ£ºNaCl£»
£¨5£©¸´ºÏ·ÊÊǺ¬ÓÐN¡¢P¡¢KÈýÖÖÔªËØÖÐÁ½ÖÖ»òÁ½ÖÖÒÔÉϵĻ¯·Ê£¬ÏõËá¼Ø³£Óõĸ´ºÏ·ÊÁÏ£¬Æ仯ѧʽΪ£ºKNO3£»
£¨6£©¸ù¾Ý³£ÓÃÓÚ¸ÄÁ¼ËáÐÔÍÁÈÀµÄÎïÖÊÊÇÇâÑõ»¯¸Æ£¬ÇâÑõ»¯¸ÆµÄ»¯Ñ§Ê½Îª£ºCa£¨OH£©2£»
¹Ê´ð°¸Îª£º£¨1£©N2£» £¨2£©CO£» £¨3£©C2H5OH£» £¨4£©NaCl£» £¨5£©KNO3£» £¨6£©Ca£¨OH£©2£»
µãÆÀ£º½â´ð±¾ÌâµÄ¹Ø¼üÊÇÒªÕÆÎÕ¸÷ÖÖÎïÖʵÄÐÔÖÊ£¬Ö»ÓÐÕÆÎÕÁËÎïÖʵÄÐÔÖʲÅÄÜÈ·¶¨ÎïÖʵÄÓÃ;£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2011?ºÓÎ÷Çøһģ£©ÏÂÁÐʵÑé²Ù×÷ÕýÈ·µÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2011?ºÓÎ÷Çøһģ£©ÊµÑé²âµÃijЩʳÎïµÄ½üËÆpHÈçÏ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
ʳÎï ÅÝ²Ë ÆÏÌÑ ·¬ÇÑ Æ»¹û Å£ÄÌ ÓñÃ×Öà
pH 3.4 4.2 4.4 3.1 6.5 7.8

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2011?ºÓÎ÷Çøһģ£©Ð¡Ã÷ͬѧ¶ÔËùѧ²¿·Ö»¯Ñ§ÖªÊ¶¹éÄÉÈçÏ£¬ÆäÖÐÍêÈ«ÕýÈ·µÄ×é±ðÊÇ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2011?ºÓÎ÷Çøһģ£©¶¹½¬ÒѳÉΪÖÚ¶à¼ÒÍ¥µÄÔç²ÍÒûÆ·£¬ÒÔÏÂÊǶ¹½¬ÖÐһЩӪÑø³É·ÖµÄƽ¾ùÖÊÁ¿·ÖÊý£®Çë¸ù¾Ýϱí»Ø´ð£º
³É·Ö Ë® µ°°×ÖÊ Ö¬·¾ ÌÇÀà ¸Æ Á× Ìú άÉúËØA
ÖÊÁ¿·ÖÊý/% 96.0 1.8 0.7 1.1 0.01 0.03 0.0005 0.015
£¨1£©¶¹½¬Öк¬ÓеÄ΢Á¿ÔªËØÊÇ
Ìú
Ìú
£®
£¨2£©ÇàÉÙÄêȱ·¦
¸Æ
¸Æ
ÔªËØÒ×»¼ÓÐØþÙͲ¡£¬È±·¦
άÉúËØA
άÉúËØA
Ò×ÒýÆðҹä֢£®
£¨3£©ÔÚ¶¹½¬Ëùº¬µÄÓªÑøËØÖÐÄܹ©¸øÈËÌåÄÜÁ¿µÄÓªÑøËØÓÐ
µ°°×ÖÊ¡¢Ö¬·¾¡¢ÌÇÀà
µ°°×ÖÊ¡¢Ö¬·¾¡¢ÌÇÀà
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2011?ºÓÎ÷Çøһģ£©Ã¾ÌõÔÚ¿ÕÆøÖÐȼÉÕÉú³ÉÑõ»¯Ã¾£¬Í¬Ê±»¹ÓÐÒ»ÖÖ¼«ÉÙÁ¿½Ðµª»¯Ã¾£¨Mg3N2£©µÄµ­»ÆÉ«¹ÌÌåÉú³É£®µª»¯Ã¾ÓöˮѸËÙ·´Ó¦Éú³É°±Æø£¨NH3£©ºÍÒ»Öּ°±ÆøÔÚ»¯Ñ§¹¤ÒµÖÐÓÃ;¹ã·º£®ÀýÈ磬ÔÚϸ¾ú×÷ÓÃÏ£¬Óð±Æø´¦Àíº¬¼×´¼£¨CH3OH£©µÄ¹¤Òµ·ÏË®£¬Ê¹Óж¾µÄ¼×´¼×ª»¯³ÉN2ºÍCO2£¬´Ó¶øÏû³ý¶Ô»·¾³µÄÎÛȾ£®¸ù¾ÝÒÔÉÏÐÅÏ¢»Ø´ð£®
£¨1£©Ð´³öµª»¯Ã¾µÄÒ»µãÎïÀíÐÔÖÊ
µ­»ÆÉ«¹ÌÌå
µ­»ÆÉ«¹ÌÌå
£®
£¨2£©×ÏɫʯÈïÊÔÒºÖÐͨÈë°±ÆøºóÈÜÒº±äÀ¶É«£¬¸ÃÈÜÒºÏÔ
¼îÐÔ
¼îÐÔ
£¨Ìî¡°ËáÐÔ¡±¡¢¡°ÖÐÐÔ¡±»ò¡°¼îÐÔ¡±£©£®
£¨3£©Mg3N2ÖУ¬NÔªËصĻ¯ºÏ¼ÛΪ
-3¼Û
-3¼Û
£®
£¨4£©µª»¯Ã¾£¨Mg3N2£©ÓëË®·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
Mg3N2+6H2O¨T3Mg£¨OH£©2+2NH3¡ü
Mg3N2+6H2O¨T3Mg£¨OH£©2+2NH3¡ü
£®
£¨5£©ÒÑÖªÔÚϸ¾ú×÷ÓÃÏ£¬Óð±Æø´¦Àíº¬¼×´¼µÄ¹¤Òµ·ÏˮʱËù·¢ÉúµÄ·´Ó¦Îª6NH3+5CH3OH+12X=3N2¡ü+5CO2¡ü+19H2O£¬ÆäÖÐXµÄ»¯Ñ§Ê½ÊÇ
O2
O2
£®
£¨6£©
100
100
gµª»¯Ã¾Óë120gÑõ»¯Ã¾º¬ÓеÄþԪËØÖÊÁ¿ÏàµÈ£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸