¸ÖÌúÊÇÖØÒªµÄ½ðÊô²ÄÁÏ£¬ÔÚ¹¤Å©ÒµÉú²úºÍÉú»îÖÐÓ¦Ó÷dz£¹ã·º£®
¢ñ£®ÌúµÄÒ±Á¶
¹¤ÒµÁ¶ÌúµÄÔÀíÊǸßÎÂÏÂÓÃCO×÷»¹Ô¼Á£¬½«Ìú´ÓÑõ»¯ÎïÖл¹Ô³öÀ´£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¸ß¯Á¶ÌúÖУ¬½¹Ì¿µÄ×÷ÓóýÁË¿ÉÒÔÉú³ÉÒ»Ñõ»¯Ì¼Í⣬»¹ÄÜ
£»
£¨2£©Ä³¸ÖÌú³§Ã¿ÌìÏûºÄ5000tº¬Ñõ»¯Ìú80%µÄ³àÌú¿óʯ£¬¸Ã³§ÀíÂÛÉÏ¿ÉÈÕ²úº¬Ìú98%µÄÉúÌúµÄÖÊÁ¿ÊǶàÉÙ£¿
¢ò£®ÊµÑé̽¾¿Á¶ÌúÔÀí
ij»¯Ñ§ÐËȤС×éÔÚʵÑéÊÒÖÐÄ£Ä⹤ҵÁ¶ÌúµÄÔÀí£¬²¢Ì½¾¿COÓëFe
2O
3·´Ó¦ºóµÄ²úÎ
ͨ¹ý²éÔÄ×ÊÁÏÖªµÀ£º¢Ù²ÝËᣨH
2C
2O
4£©¹ÌÌåÓëŨÁòËá»ìºÏ¼ÓÈÈ»á²úÉúÒ»Ñõ»¯Ì¼£¬·´Ó¦·½³ÌʽΪ£ºH
2C
2O
4CO¡ü+CO
2¡ü+H
2O£®
¢ÚNaOHÈÜÒº¿ÉÒÔÎüÊÕ¶þÑõ»¯Ì¼£¬·´Ó¦·½³ÌʽΪ£º2NaOH+CO
2=Na
2CO
3+H
2O
¢Û³£ÎÂÏ£¬Ca£¨OH£©
2΢ÈÜÓÚË®£»
ÓÚÊÇËûÉè¼ÆÁËÈçͼ1µÄʵÑé×°Ö㬽áºÏ×°ÖûشðÏÂÁÐÎÊÌâ
£¨1£©Í¼1AÊÇÓùÌÌå²ÝËáºÍŨÁòËáÖÆÈ¡COµÄ·´Ó¦×°Öã¬ÄãÈÏΪӦѡÔñͼ2ÖеÄ
£¨Ìî×°ÖñàºÅ£©£»
£¨2£©Í¼1ÖÐ×°ÖÃC¡¢DµÄ×÷Ó÷ֱðÊÇ
¡¢
£»
£¨3£©ÎªÁËÖ¤Ã÷²úÎïÖÐÓжþÑõ»¯Ì¼£¬×°ÖÃFÖеÄÊÔ¼ÁÓ¦¸ÃÊÇÉÙÁ¿µÄ³ÎÇåʯ»ÒË®£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
£»
£¨4£©¸Ã×°ÖÃÉè¼ÆÓÐÒ»¸öÃ÷ÏÔȱÏÝ£¬ÄãÈÏΪÊÇ
£®
£¨5£©ÊµÑéʱ׼ȷ³ÆÈ¡Ò»¶¨ÖÊÁ¿´¿¾»µÄFe
2O
3¹ÌÌ尴ͼ1½øÐÐʵÑ飬µ±EÖйÌÌåÈ«²¿±äºÚºó£¬¼ÌÐøͨÈëCOÖ±µ½²£Á§¹ÜÀäÈ´£®½«µÃµ½ºÚÉ«µÄ¹ÌÌå¼ÓÈëµ½×ãÁ¿µÄÏ¡ÑÎËᣬ·¢ÏÖ¹ÌÌåÈ«²¿Èܽ⣬µ«ÎÞÆøÅݲúÉú£®
²éÔÄ×ÊÁÏ£ºa£®ÌúµÄÑõ»¯ÎïÔÚ×ãÁ¿µÄÏ¡ÑÎËáÖоùÄÜÈ«²¿Èܽ⣮
b£®Fe
2O
3ÓëCO·´Ó¦µÄ¹ÌÌåÉú³ÉÎï¿ÉÄÜÇé¿öÈçÏ£º
Fe
2O
3Fe
3O
4FeO
Fe
¸ù¾Ý¡°ÎÞÆøÅÝ¡±²ÂÏ룬ºÚÉ«·ÛÄ©¿ÉÄÜÊÇ£º¢ÙFe
3O
4£»¢Ú
¢Û
£®
£¨6£©¶¨Á¿·ÖÎöÓõç×ÓÌìƽ³ÆÁ¿µÃ²¿·ÖÊý¾ÝÈçÏ£º
| ²£Á§¹ÜÖÊÁ¿ | ²£Á§¹Ü¼°ÆäÖйÌÌåµÄÖÊÁ¿ | ×°ÖÃF¼°ÆäÖÐÎïÖʵÄ×ÜÖÊÁ¿ |
·´Ó¦Ç° | 28.20g | 33.00g | 300.0g |
·´Ó¦ºó | 32.84g | 300.4g |
¸ù¾ÝÉÏÊöÊý¾Ý£¬ÇëÑ¡ÔñÓÐЧµÄÊý¾Ý£¬Íƶϳö·´Ó¦ºóºÚÉ«¹ÌÌåµÄ³É·Ö£®£¨Ð´³ö¼ÆËã¹ý³Ì£©