Question

11£®½«×ãÁ¿µÄ̼Ëá¸Æ¼ÓÈ뵽ʢÓÐ50mLµÄÏ¡ÑÎËáÖУ¬Á¢¼´½«ÉÕ±­·Åµ½ÌìƽÉϳÆÁ¿£¬ÔÚÒÔºóµÄ8minÄÚ£¬Ã¿Ò»·ÖÖÓ¶ÁÒ»´ÎÊý£®½á¹ûÈç±í£º

ʱ¼ä/min	0	1	2	3	4	5	6	7	8
ÖÊÁ¿/g	92.0	91.0	90.5	90.1	89.8	90.0	89.8	89.8	89.8

£¨1£©Ê¢Óз´Ó¦ÎïµÄÉÕ±­ÖÊÁ¿¼õСµÄÔ­ÒòÊÇ£º·´Ó¦Éú³ÉµÄ¶þÑõ»¯Ì¼Òݳö£»
£¨2£©±íÖÐÓÐÒ»¸öÊý¾ÝÊDz»ºÏÀíµÄ£¬¸Ã½á¹ûµÄ²âµÃʱ¼äÊǵÚ5·ÖÖÓ£»
£¨3£©¼ÆËãËùÓÃÑÎËáµÄÖÊÁ¿·ÖÊý£¨Ð´³öÍêÕûµÄ¼ÆËã¹ý³Ì£¬ÑÎËáÃܶȰ´1g/mL¼ÆË㣩£®

Answer 1

·ÖÎö ̼Ëá¸ÆºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯¸Æ¡¢Ë®ºÍ¶þÑõ»¯Ì¼£¬¸ù¾Ý±íÖÐÌṩµÄÊý¾ÝºÍ·´Ó¦µÄ»¯Ñ§·½³Ìʽ¿ÉÒÔ½øÐÐÏà¹Ø·½ÃæµÄ¼ÆËãºÍÅжϣ®

½â´ð ½â£º£¨1£©Ê¢Óз´Ó¦ÎïµÄÉÕ±­ÖÊÁ¿¼õСµÄÔ­ÒòÊÇ£º·´Ó¦Éú³ÉµÄ¶þÑõ»¯Ì¼Òݳö£®
¹ÊÌ·´Ó¦Éú³ÉµÄ¶þÑõ»¯Ì¼Òݳö£®
£¨2£©±íÖÐÓÐÒ»¸öÊý¾ÝÊDz»ºÏÀíµÄ£¬¸Ã½á¹ûµÄ²âµÃʱ¼äÊǵÚ5·ÖÖÓ£¬µÚ5·ÖÖÓÓ¦¸ÃÊÇСÓÚ»òµÈÓÚ89.8£®
¹ÊÌ5£®
£¨3£©Éè50mLÏ¡ÑÎËáÖÐÂÈ»¯ÇâµÄÖÊÁ¿Îªx£¬
·´Ó¦Éú³É¶þÑõ»¯Ì¼ÖÊÁ¿Îª£º92.0g-89.8g=2.2g£¬
CaCO₃+2HCl¨TCaCl₂+H₂O+CO₂¡ü£¬
       73             44
       x             2.2g
$\frac{73}{x}$=$\frac{44}{2.2g}$£¬
x=3.65g£¬
50mLÏ¡ÑÎËáµÄÖÊÁ¿Îª£º50mL¡Á1g/mL=50g£¬
ËùÓÃÑÎËáµÄÖÊÁ¿·ÖÊýΪ£º$\frac{3.65g}{50g}$¡Á100%=7.3%£¬
´ð£ºËùÓÃÑÎËáµÄÖÊÁ¿·ÖÊýΪ7.3%£®

µãÆÀ ²îÁ¿·¨ÔÚ¼ÆËãÖеÄÓ¦Óúܹ㷺£¬½â´ðµÄ¹Ø¼üÊÇÒª·ÖÎö³öÎïÖʵÄÖÊÁ¿²îÓëÒªÇóµÄδ֪ÊýÖ®¼äµÄ¹Øϵ£¬ÔÙ¸ù¾Ý¾ßÌåµÄÊý¾ÝÇó½â£®