Æû³µ¹¤ÒµµÄѸËÙ·¢Õ¹£¬¸øÈËÃǵÄÉú»î´øÀ´Á˺ܴóµÄ·½±ã¡£Òò´Ë£¬Æû³µµÄ°²È«ÐÔºÍÆû³µÎ²ÆøµÄÅŷųÉΪÈËÃǹØ×¢µÄÎÊÌ⣬¸ù¾ÝÒÔÏÂÄÚÈݻشð£º

£¨1£©Ñо¿Ö¤Ã÷£¬Æû³µÎ²ÆøϵͳÖУ¬¿ÉÒÔ°²×°´ß»¯×ª»¯Æ÷£¬½«Î²ÆøÖеÄCO¡¢NOÔÚ´ß»¯¼ÁµÄ×÷ÓÃÏ£¬×ª»¯³ÉCO2ºÍN2£¬ÒÔ¼õÉÙβÆø¶Ô´óÆøµÄÎÛȾ£¬Çëд³öCOºÍNOÔÚ´ß»¯¼ÁµÄ×÷ÓÃÏÂÉú³ÉCO2ºÍN2µÄ»¯Ñ§·½³Ìʽ________________________________£¬ÊÔ¼ÆËãNOÖи÷ÔªËصÄÖÊÁ¿±È______________£»NOÖеªÔªËصÄÖÊÁ¿·ÖÊýΪ_________________¡£

£¨2£©ÎªÔö¼Ó¼Ý³ËÈËÔ±µÄ°²È«£¬¼ÝÊ»ÊÒÖÐÉè¼ÆÁË°²È«ÆøÄÒ¡£µ±°²È«ÆøÄÒÊܵ½Ç¿ÁÒÕð¶¯Ê±£¬ÆøÄÒÖеĵþµª»¯ÄÆ£¨NaN3£©»á·¢Éú·Ö½â£¬Ñ¸ËÙ²úÉúµªÆøºÍ¹ÌÌå½ðÊôÄÆ£¬´Ëʱ£¬ÆøÄÒµÄÌå»ýѸËÙÅòÕÍ£¬ÒÔ´ïµ½±£»¤¼Ý³ËÈËÔ±°²È«µÄÄ¿µÄ¡£ÊÔ¼ÆË㣬ÔÚͨ³£×´¿öÏ£¬Òª²úÉú60LµªÆø£¬ÐèÒª·Ö½â¶àÉٿ˵þµª»¯ÄÆ£¿£¨ÒÑÖª£ºÔÚͨ³£×´¿öÏ£¬µªÆøµÄÃܶÈԼΪ1.25g/L£©

£¨1£©2CO + 2 NO          2CO2 + N2  

7£º8       46.7%

£¨2£©½â£ºÉèÐèÒª·Ö½âµþµª»¯ÄƵÄÖÊÁ¿ÎªX

2NaN=  2Na  +  3N2 ¡ü                               

130                84

X              60L¡Á1.25g/L                             

130£º84 = X£º60L¡Á1.25g/L

X  = 60L¡Á1.25g/L¡Á130¡Â84                                

= 116 g

´ð£ºÒª²úÉú60LµªÆø£¬ÐèÒª·Ö½â116 gµþµª»¯ÄÆ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2006?×Ͳ©£©Æû³µ¹¤ÒµµÄѸËÙ·¢Õ¹£¬¸øÈËÃǵÄÉú»î´øÀ´Á˺ܴóµÄ·½±ã£®Í¬Ê±£¬Æû³µµÄ°²È«ÐÔºÍÆû³µÎ²ÆøµÄÅŷųÉΪÈËÃǹØ×¢µÄÎÊÌ⣬¸ù¾ÝÒÔÏÂÄÚÈݻشð£º
£¨1£©Ñо¿Ö¤Ã÷£¬Æû³µÎ²ÆøϵͳÖУ¬¿ÉÒÔ°²×°´ß»¯×ª»¯Æ÷£¬½«Î²ÆøÖеÄCO¡¢NOÔÚ´ß»¯¼ÁµÄ×÷ÓÃÏ£¬×ª»¯³ÉCO2ºÍN2£¬ÒÔ¼õÉÙβÆø¶Ô´óÆøµÄÎÛȾ£®Çëд³öÉÏÊöת»¯µÄ»¯Ñ§·½³Ìʽ
2CO+2NO
 ´ß»¯¼Á 
.
 
2CO2+N2
2CO+2NO
 ´ß»¯¼Á 
.
 
2CO2+N2
£¬ÊÔ¼ÆËãNOÖеª¡¢ÑõÁ½ÖÖÔªËصÄÖÊÁ¿±È
7£º8
7£º8
£»NOÖеªÔªËصÄÖÊÁ¿·ÖÊýΪ
46.7%
46.7%
£®
£¨2£©ÎªÔö¼Ó¼Ý³ËÈËÔ±µÄ°²È«£¬¼ÝÊ»ÊÒÖÐÉè¼ÆÁË°²È«ÆøÄÒ£¨ÓÉÅöײ´«¸ÐÆ÷¡¢ÆøÌå·¢ÉúÆ÷ºÍÆøÄÒ×é³É£©£®µ±ÐÐÊ»µÄÆû³µÊܵ½Ç¿ÁÒÕð¶¯Ê±£¬´«¸ÐÆ÷·¢³öÐźţ¬ÆøÄÒÖеĵþµª»¯ÄÆ£¨NaN3£©·¢Éú·Ö½â£¬Ñ¸ËÙ²úÉúµªÆøºÍ¹ÌÌå½ðÊôÄÆ£¬ÆøÄÒµÄÌå»ýѸËÙÅòÕÍ£¬ÒÔ´ïµ½±£»¤¼Ý³ËÈËÔ±°²È«µÄÄ¿µÄ£®ÊÔ¼ÆË㣬ÔÚͨ³£×´¿öÏ£¬Òª²úÉú60LµªÆø£¬ÐèÒª·Ö½â¶àÉٿ˵þµª»¯ÄÆ£¿£¨ÒÑÖª£ºÔÚͨ³£×´¿öÏ£¬µªÆøµÄÃܶÈԼΪ1.25g/L£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2013?»±ÒñÇøһģ£©µªÔªËغÍÈËÀàµÄÉú´æÓë·¢Õ¹ÁªÏµÃÜÇУ®ÈçͼËùʾÊÇÓйغ¬µªÔªËØÎïÖʵÄת»¯Á÷³Ì£º
£¨1£©ÔÚÉÏÊöÁ÷³ÌÖУ¬Éú³ÉÎïHNO3ÖеªÔªËصĻ¯ºÏ¼ÛÊÇ
+5
+5
¼Û£®
£¨2£©¹ý³Ì¢ÙÖз¢ÉúµÄ»¯Ñ§·´Ó¦Îª£º4NH3+5O2
 ´ß»¯¼Á 
.
¼ÓÈÈ
4NO+6X£¬ÔòÎïÖÊXµÄ»¯Ñ§Ê½Îª
H2O
H2O
£¬¸Ã·´Ó¦ÊôÓÚ
Ñõ»¯
Ñõ»¯
·´Ó¦£¨Ìî¡°·Ö½â¡±¡°»¯ºÏ¡±¡°Öû»¡±¡°¸´·Ö½â¡±¡°Ñõ»¯¡±Ö®Ò»£©£®
£¨3£©¹¤ÒµµÄѸËÙ·¢Õ¹¡¢»¯Ê¯È¼ÁϵĴóÁ¿Ê¹ÓÃÒÔ¼°Æû³µ·¢¶¯»ú¶¼ÄܲúÉúµªÑõ»¯ÎµªÑõ»¯ÎïÓëË®¼°ÑõÆø·´Ó¦»áµ¼ÖÂÏõËáÐÍËáÓêµÄÐγɣ¬Ôì³É»·¾³ÎÛȾ£®ÏÂÁи÷ÏîÖУ¬²»ÀûÓÚ¼õÉÙËáÓêΣº¦µÄÊÇ
¢Û
¢Û
£¨ÌîÐòºÅ£©£®
¢Ù¼õÉÙÆû³µÎ²ÆøÅÅ·Å           ¢Ú¿ª·¢ÀûÓ÷çÄܺÍÌ«ÑôÄÜ
¢ÛÔö¼ÓȼúµÄÓÃÁ¿             ¢Ü¹¤Òµ·ÏÆø´ï±êºóÅÅ·Å£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

Æû³µ¹¤ÒµµÄѸËÙ·¢Õ¹£¬¸øÈËÃǵÄÉú»î´øÀ´Á˺ܴóµÄ·½±ã£®Í¬Ê±£¬Æû³µµÄ°²È«ÐÔºÍÆû³µÎ²ÆøµÄÅŷųÉΪÈËÃǹØ×¢µÄÎÊÌ⣬¸ù¾ÝÒÔÏÂÄÚÈݻشð£º
£¨1£©Ñо¿Ö¤Ã÷£¬Æû³µÎ²ÆøϵͳÖУ¬¿ÉÒÔ°²×°´ß»¯×ª»¯Æ÷£¬½«Î²ÆøÖеÄCO¡¢NOÔÚ´ß»¯¼ÁµÄ×÷ÓÃÏ£¬×ª»¯³ÉCO2ºÍN2£¬ÒÔ¼õÉÙβÆø¶Ô´óÆøµÄÎÛȾ£®Çëд³öÉÏÊöת»¯µÄ»¯Ñ§·½³Ìʽ______£¬ÊÔ¼ÆËãNOÖеª¡¢ÑõÁ½ÖÖÔªËصÄÖÊÁ¿±È______£»NOÖеªÔªËصÄÖÊÁ¿·ÖÊýΪ______£®
£¨2£©ÎªÔö¼Ó¼Ý³ËÈËÔ±µÄ°²È«£¬¼ÝÊ»ÊÒÖÐÉè¼ÆÁË°²È«ÆøÄÒ£¨ÓÉÅöײ´«¸ÐÆ÷¡¢ÆøÌå·¢ÉúÆ÷ºÍÆøÄÒ×é³É£©£®µ±ÐÐÊ»µÄÆû³µÊܵ½Ç¿ÁÒÕð¶¯Ê±£¬´«¸ÐÆ÷·¢³öÐźţ¬ÆøÄÒÖеĵþµª»¯ÄÆ£¨NaN3£©·¢Éú·Ö½â£¬Ñ¸ËÙ²úÉúµªÆøºÍ¹ÌÌå½ðÊôÄÆ£¬ÆøÄÒµÄÌå»ýѸËÙÅòÕÍ£¬ÒÔ´ïµ½±£»¤¼Ý³ËÈËÔ±°²È«µÄÄ¿µÄ£®ÊÔ¼ÆË㣬ÔÚͨ³£×´¿öÏ£¬Òª²úÉú60LµªÆø£¬ÐèÒª·Ö½â¶àÉٿ˵þµª»¯ÄÆ£¿£¨ÒÑÖª£ºÔÚͨ³£×´¿öÏ£¬µªÆøµÄÃܶÈԼΪ1.25g/L£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

 (×Ͳ©ÊÐ)Æû³µ¹¤ÒµµÄѸËÙ·¢Õ¹£¬¸øÈËÃǵÄÉú»î´øÀ´Á˺ܴóµÄ·½±ã¡£Í¬Ê±£¬Æû³µµÄ°²È«ÐÔºÍÆû³µÎ²ÆøµÄÅŷųÉΪÈËÃǹØ×¢µÄÎÊÌ⣬¸ù¾ÝÒÔÏÂÄÚÈݻشð£º

£¨1£©Ñо¿Ö¤Ã÷£¬Æû³µÎ²ÆøϵͳÖУ¬¿ÉÒÔ°²×°´ß»¯×ª»¯Æ÷£¬½«Î²ÆøÖеÄCO¡¢NOÔÚ´ß»¯¼ÁµÄ×÷ÓÃÏ£¬×ª»¯³ÉCO2ºÍN2£¬ÒÔ¼õÉÙβÆø¶Ô´óÆøµÄÎÛȾ¡£Çëд³öÉÏÊöת»¯µÄ»¯Ñ§·½³Ìʽ                                £¬ÊÔ¼ÆËãNOÖеª¡¢ÑõÁ½ÖÖÔªËصÄÖÊÁ¿±È         £»NOÖеªÔªËصÄÖÊÁ¿·ÖÊýΪ         ¡£

£¨2£©ÎªÔö¼Ó¼Ý³ËÈËÔ±µÄ°²È«£¬¼ÝÊ»ÊÒÖÐÉè¼ÆÁË°²È«ÆøÄÒ£¨ÓÉÅöײ´«¸ÐÆ÷¡¢ÆøÌå·¢ÉúÆ÷ºÍÆøÄÒ×é³É£©¡£µ±ÐÐÊ»µÄÆû³µÊܵ½Ç¿ÁÒÕð¶¯Ê±£¬´«¸ÐÆ÷·¢³öÐźţ¬ÆøÄÒÖеĵþµª»¯ÄÆ£¨NaN3£©·¢Éú·Ö½â£¬Ñ¸ËÙ²úÉúµªÆøºÍ¹ÌÌå½ðÊôÄÆ£¬ÆøÄÒµÄÌå»ýѸËÙÅòÕÍ£¬ÒÔ´ïµ½±£»¤¼Ý³ËÈËÔ±°²È«µÄÄ¿µÄ¡£ÊÔ¼ÆË㣬ÔÚͨ³£×´¿öÏ£¬Òª²úÉú60LµªÆø£¬ÐèÒª·Ö½â¶àÉٿ˵þµª»¯ÄÆ£¿£¨ÒÑÖª£ºÔÚͨ³£×´¿öÏ£¬µªÆøµÄÃܶÈԼΪ1.25g/L£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸