±È½ÏÓë·ÖÎö¹éÄÉ»áʹÄãµÄÍ·ÄÔ±äµÃ¸ü´ÏÃ÷¡£Çë·ÖÎöϱíÖÐÐÅÏ¢£¬»Ø´ðÓйØÎÊÌ⣺

Ãû³Æ

·ûºÅ

Ô­×ӽṹʾÒâͼ

µ¥ÖÊ»¯Ñ§Ê½

³£Î³£Ñ¹ÏÂ״̬

µ¥ÖÊÓëÇâÆø·´Ó¦

·ú

F

F2

              

ºÚ°µ´¦±¬Õ¨

ÂÈ

Cl

             

Cl2

Æø̬

¹âÕÕ±¬Õ¨

äå

Br

Br2

Һ̬

¼ÓÈÈ·´Ó¦

µâ

I

          

¹Ì̬

³ÖÐø¼ÓÈÈ»ºÂý·´Ó¦

£¨1£©Çë°ÑÉÏÊö±íÖеĿոñ²¹³äÍêÕû¡£

£¨2£©¢ÙÊÔ¹éÄÉ·ú¡¢ÂÈ¡¢äå¡¢µâµÄÔ­×ӽṹ¹æÂÉ£¨´ðÒ»µã¼´¿É£©£º

                                                                           £»

¢ÚÊÔ¹éÄÉ·ú¡¢ÂÈ¡¢äå¡¢µâ¶ÔÓ¦µ¥ÖʵÄÐÔÖʱ仯¹æÂÉ£¨´ðÒ»µã¼´¿É£©£º

                                                                           £»

£¨3£©ÒÑÖª£ºCl2ºÍBr2µÄ»¯Ñ§ÐÔÖÊÏàËÆ£¬Cl2+H2O£½HCl+HClO,ÆäÖÐHClOÒ²ÊÇÒ»ÖÖËᣬËüÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄ·½³ÌʽΪ£ºHClO+NaOH£½NaClO+ H2O£¬ÊÔ·Ö±ðд³öBr2ÓëË®£¬Br2ÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º                                                     £»

                                                     ¡£

Ãû³Æ

·ûºÅ

Ô­×ӽṹʾÒâͼ

µ¥ÖÊ»¯Ñ§Ê½

³£Î³£Ñ¹ÏÂ״̬

µ¥ÖÊÓëÇâÆø·´Ó¦

·ú

F

F2

ÆøÌå

             

ºÚ°µ´¦±¬Õ¨

ÂÈ

Cl

             

Cl2

Æø̬

¹âÕÕ±¬Õ¨

äå

Br

 


Br2

Һ̬

¼ÓÈÈ·´Ó¦

µâ

I

   I2  

¹Ì̬

³ÖÐø¼ÓÈÈ»ºÂý·´Ó¦

£¨1£©Çë°ÑÉÏÊö±íÖеĿոñ²¹³äÍêÕû¡£

£¨2£©¢Ù·ú¡¢ÂÈ¡¢äå¡¢µâÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÏàͬ»ò·ú¡¢ÂÈ¡¢äå¡¢µâÔ­×ӵĵç×Ó²ãÊýÖð½¥µÝÔö¡£

¢Ú·ú¡¢ÂÈ¡¢äå¡¢µâµ¥ÖʵĻ¯Ñ§ÐÔÖÊÖð½¥¼õÈõ

£¨3£©Br2+2NaOH£½NaBrO+ NaBr + H2O

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2011?Ò˱ö£©±È½ÏÓë·ÖÎö¹éÄÉ»áʹÄãµÄÍ·ÄÔ±äµÃ¸ü´ÏÃ÷£®Çë·ÖÎöϱíÖÐÐÅÏ¢£¬»Ø´ðÓйØÎÊÌ⣺
Ãû³Æ·ûºÅÔ­×ӽṹʾÒâͼµ¥ÖÊ»¯Ñ§Ê½³£Î³£Ñ¹ÏÂ״̬µ¥ÖÊÓëÇâÆø·´Ó¦
·úF
 
F2
Æø̬
Æø̬
 
ºÚ°µ´¦±¬Õ¨
ÂÈCl
 
Cl2Æø̬¹âÕÕ±¬Õ¨
äåBr
 
Br2Һ̬¼ÓÈÈ·´Ó¦
µâI
 
 
 
I2
I2
 
¹Ì̬³ÖÐø¼ÓÈÈ»ºÂý·´Ó¦
£¨1£©Çë°ÑÉÏÊö±íÖеĿոñ²¹³äÍêÕû£®
£¨2£©¢ÙÊÔ¹éÄÉ·ú¡¢ÂÈ¡¢äå¡¢µâµÄÔ­×ӽṹ¹æÂÉ£¨´ðÒ»µã¼´¿É£©£º
·ú¡¢ÂÈ¡¢äå¡¢µâÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÏàͬ»ò·ú¡¢ÂÈ¡¢äå¡¢µâÔ­×ӵĵç×Ó²ãÊýÖð½¥µÝÔö
·ú¡¢ÂÈ¡¢äå¡¢µâÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÏàͬ»ò·ú¡¢ÂÈ¡¢äå¡¢µâÔ­×ӵĵç×Ó²ãÊýÖð½¥µÝÔö
£»
¢ÚÊÔ¹éÄÉ·ú¡¢ÂÈ¡¢äå¡¢µâ¶ÔÓ¦µ¥ÖʵÄÐÔÖʱ仯¹æÂÉ£¨´ðÒ»µã¼´¿É£©£º
·ú¡¢ÂÈ¡¢äå¡¢µâµ¥ÖʵĻ¯Ñ§ÐÔÖÊÖð½¥¼õÈõ
·ú¡¢ÂÈ¡¢äå¡¢µâµ¥ÖʵĻ¯Ñ§ÐÔÖÊÖð½¥¼õÈõ
£»
£¨3£©ÒÑÖª£ºCl2ºÍBr2µÄ»¯Ñ§ÐÔÖÊÏàËÆ£¬Cl2+H2O=HCl+HClO£¬ÆäÖÐHClOÒ²ÊÇÒ»ÖÖËᣬËüÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄ·½³ÌʽΪ£ºHClO+NaOH=NaClO+H2O£¬ÊÔ·Ö±ðд³öBr2ÓëË®£¬Br2ÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
Br2+H2O=HBr+HBrO£¬Br2+2NaOH=NaBrO+NaBr+H2O
Br2+H2O=HBr+HBrO£¬Br2+2NaOH=NaBrO+NaBr+H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

±È½ÏÓë·ÖÎö¹éÄÉ»áʹÄãµÄÍ·ÄÔ±äµÃ¸ü´ÏÃ÷£®Çë·ÖÎöϱíÖÐÐÅÏ¢£¬»Ø´ðÓйØÎÊÌ⣺
ÔªËØÃû³Æ ÔªËØ·ûºÅ Ô­×ӽṹʾÒâͼ µ¥ÖÊ
»¯Ñ§Ê½
³£Î³£Ñ¹Ïµ¥ÖʵÄ״̬ µ¥ÖÊÓëÇâÆø
·´Ó¦µÄ×´¿ö
·ú F F2
Æø̬
Æø̬
ºÚ°µ´¦±¬Õ¨
ÂÈ Cl
y=
8
8
Cl2 Æø̬ ¹âÕÕ±¬Õ¨
äå Br Br2 Һ̬ ¼ÓÈÈ·´Ó¦
µâ I
x=
53
53

I2
I2
¹Ì̬ ³ÖÐø¼ÓÈÈ»ºÂý·´Ó¦
£¨1£©Çë°ÑÉÏÊö±íÖеĿոñ²¹³äÍêÕû£®
£¨2£©¢ÙÊÔ¹éÄÉ·ú¡¢ÂÈ¡¢äå¡¢µâµÄÔ­×ӽṹ¹æÂÉ£¨´ðÒ»µã¼´¿É£©£º
×îÍâ²ãµç×Ó¶¼Ïàͬ£¬µç×Ó²ãÊý´ÓÉϵ½ÏÂÒÀ´ÎµÝÔö
×îÍâ²ãµç×Ó¶¼Ïàͬ£¬µç×Ó²ãÊý´ÓÉϵ½ÏÂÒÀ´ÎµÝÔö
£»
¢ÚÊÔ¹éÄÉ·ú¡¢ÂÈ¡¢äå¡¢µâ¶ÔÓ¦µ¥ÖʵÄÐÔÖʱ仯¹æÂÉ£¨´ðÒ»µã¼´¿É£©£º
Ëæ×ÅÔ­×ӵĵç×Ó²ãÊýÒÀ´ÎµÝÔö»¯Ñ§ÐÔÖÊÔ½À´Ô½Îȶ¨ £¨ºÏÀí¼´¸ø·Ö£©
Ëæ×ÅÔ­×ӵĵç×Ó²ãÊýÒÀ´ÎµÝÔö»¯Ñ§ÐÔÖÊÔ½À´Ô½Îȶ¨ £¨ºÏÀí¼´¸ø·Ö£©
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2012?°°É½Ò»Ä££©±È½ÏÓë·ÖÎö¹éÄÉ»áʹÄã±äµÃ¸ü´ÏÃ÷£®Çë·ÖÎöϱíÖÐÐÅÏ¢£¬»Ø´ðÓйØÎÊÌ⣺
Ãû³Æ ·ûºÅ Ô­×ӽṹʾÒâͼ µ¥ÖʵÄ
»¯Ñ§Ê½
³£Î³£Ñ¹ÏÂ
״̬
µ¥ÖÊÓëÇâÆø·´Ó¦
·ú F F2 Æø̬ ºÚ°µ´¦±¬Õ¨
ÂÈ Cl Cl2 Æø̬ ¹âÕÕ±¬Õ¨
äå Br Br2 Һ̬ ¼ÓÈÈ·´Ó¦
µâ I I2 ¹Ì̬ ³ÖÐø¼ÓÈÈ»ºÂý·´Ó¦
£¨1£©ÉÏÊö±íÖÐX=
17
17
£»
£¨2£©¢ÙÊÔ¹éÄÉ·ú¡¢ÂÈ¡¢äå¡¢µâµÄÔ­×ӽṹ¹æÂÉ£¨´ðÒ»µã¼´¿É£©£º
Ëæ×ÅÔ­×Ӻ˵çºÉÊýµÄÔö¼Ó£¬µç×Ó²ãÊýÒ²Öð½¥Ôö¼Ó£¨×îÍâ²ãµç×ÓÊýÏàͬ£©
Ëæ×ÅÔ­×Ӻ˵çºÉÊýµÄÔö¼Ó£¬µç×Ó²ãÊýÒ²Öð½¥Ôö¼Ó£¨×îÍâ²ãµç×ÓÊýÏàͬ£©
£»
¢ÚÊÔ¹éÄÉ·ú¡¢ÂÈ¡¢äå¡¢µâ¶ÔÓ¦µ¥ÖʵÄÐÔÖʱ仯¹æÂÉ£¨´ðÒ»µã¼´¿É£©£º
Ëæ×ÅÔ­×Ӻ˵çºÉÊýµÄÔö¼Ó£¬ÆäÔÚ³£Î³£Ñ¹Ïµ¥ÖʵÄ״̬ÓÉÆø̬Öð½¥±äΪҺ̬¡¢¹Ì̬
£¨»òËæ×ÅÔ­×Ӻ˵çºÉÊýµÄÔö¼Ó£¬Æäµ¥ÖʵĻ¯Ñ§»îÆÃÐÔÖð½¥¼õÈõ£©
Ëæ×ÅÔ­×Ӻ˵çºÉÊýµÄÔö¼Ó£¬ÆäÔÚ³£Î³£Ñ¹Ïµ¥ÖʵÄ״̬ÓÉÆø̬Öð½¥±äΪҺ̬¡¢¹Ì̬
£¨»òËæ×ÅÔ­×Ӻ˵çºÉÊýµÄÔö¼Ó£¬Æäµ¥ÖʵĻ¯Ñ§»îÆÃÐÔÖð½¥¼õÈõ£©
£»
£¨3£©ÒÑÖª£ºCl2ºÍBr2µÄ»¯Ñ§ÐÔÖÊÏàËÆ£¬Cl2+H2O=HCl+HClO£¬ÆäÖÐHClOÒ²ÊÇÒ»ÖÖËᣬËüÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄ·´Ó¦·½³ÌʽΪ£ºHClO+NaOH=NaClO+H2O£¬ÊÔ·Ö±ðд³öBr2ÓëË®£¬Br2ÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
Br2+H2O=HBr+HBrO
Br2+H2O=HBr+HBrO
£»
Br2+2NaOH=NaBrO+NaBr+H2O
Br2+2NaOH=NaBrO+NaBr+H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

±È½ÏÓë·ÖÎö¹éÄÉ»áʹÄãµÄÍ·ÄÔ±äµÃ¸ü´ÏÃ÷£®Çë·ÖÎöϱíÖÐÐÅÏ¢£¬»Ø´ðÓйØÎÊÌ⣺
ÔªËØÃû³ÆÔªËØ·ûºÅÔ­×ӽṹʾÒâͼµ¥ÖÊ
»¯Ñ§Ê½
³£Î³£Ñ¹Ïµ¥ÖʵÄ״̬µ¥ÖÊÓëÇâÆø
·´Ó¦µÄ×´¿ö
·úFF2______ºÚ°µ´¦±¬Õ¨
ÂÈCl
y=______
Cl2Æø̬¹âÕÕ±¬Õ¨
äåBrBr2Һ̬¼ÓÈÈ·´Ó¦
µâI
x=______

______
¹Ì̬³ÖÐø¼ÓÈÈ»ºÂý·´Ó¦
£¨1£©Çë°ÑÉÏÊö±íÖеĿոñ²¹³äÍêÕû£®
£¨2£©¢ÙÊÔ¹éÄÉ·ú¡¢ÂÈ¡¢äå¡¢µâµÄÔ­×ӽṹ¹æÂÉ£¨´ðÒ»µã¼´¿É£©£º______£»
¢ÚÊÔ¹éÄÉ·ú¡¢ÂÈ¡¢äå¡¢µâ¶ÔÓ¦µ¥ÖʵÄÐÔÖʱ仯¹æÂÉ£¨´ðÒ»µã¼´¿É£©£º______£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸