Question

9£®Ä³»¯Ñ§ÐËȤС×éÉè¼ÆÁËÒ»×é¡°´µÆøÇò¡±ÊµÑ飬Á½Ì××°ÖÃÈçA¡¢Bͼ£º

£¨1£©Çë·ÖÎöA×°Öãº
¢ÙÒÇÆ÷aµÄÃû³ÆΪ·ÖҺ©¶·£®
¢ÚÈôÉú³ÉO₂ʹÆøÇòÕÍ´ó£¬ÔòAÖз´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2H₂O₂$\frac{\underline{\;MnO_2\;}}{\;}$2H₂O+O₂¡ü£®Èô½«AÖÐÉú³ÉµÄO₂¸ÉÔï²¢ÊÕ¼¯ÆðÀ´£¬»¹ÐèҪѡÔñµÄ×°ÖÃÊÇCD£¨ÌîÐòºÅ£©£®
¢ÛÈôÉú³ÉCO₂ʹÆøÇòÕÍ´ó£¬Ôò׶ÐÎÆ¿ÖÐËù×°µÄ¹ÌÌåÎïÖÊ¿ÉÄÜÊÇʯ»Òʯ£¨»ò̼ËáÄƵȣ©£®£¨Ð´³öÒ»ÖÖ¼´¿É£©
¢ÜÈôaÖеÄÒºÌåÎïÖÊÊÇË®£¬Ôò׶ÐÎÆ¿ÖÐ×°ÓеĹÌÌå¿ÉÄÜÊÇÇâÑõ»¯ÄÆ£¨»òÑõ»¯¸Æ£©£®£¨Ð´³öÒ»ÖÖ¼´¿É£©
£¨2£©Çë·ÖÎöB×°Öãº
Èô׶ÐÎÆ¿ÖÐÊ¢ÂúCO₂£¬ÓûʹÆøÇòÕÍ´ó£¬ÔòaÖеÄÒºÌå¿ÉÄÜÊÇÇâÑõ»¯ÄÆ£¨»òÇâÑõ»¯¸Æ£©ÈÜÒº£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2NaOH+CO₂=Na₂CO₃+H₂O£¨»òCa£¨OH£©₂+CO₂=CaCO₃¡ý+H₂O£©£¨ÈôûÓз¢Éú»¯Ñ§·´Ó¦£¬Ôò±¾¿Õ²»ÓÃÌîд£©£®

Answer 1

·ÖÎö £¨1£©
¢Ù¸ù¾ÝʵÑéÊÒ³£ÓÃÒÇÆ÷½â´ð£»
¢Ú¸ù¾ÝÑõÆøµÄʵÑéÊÒÖÆ·¨¡¢Å¨ÁòËáµÄÐÔÖÊ¡¢ÑõÆøµÄÐÔÖʽøÐзÖÎö£»
¢Û¸ù¾ÝÖÆÈ¡¶þÑõ»¯Ì¼ËùÐèÒªµÄÒ©Æ·½â´ð£»
¢Ü¸ù¾ÝÓÐЩÎïÖÊÈÜÓÚË®·ÅÈÈ£¬Ê¹ÆøÌåÅòÕͽâ´ð£»
£¨2£©BÖÐCO₂ÆøÌå±»ÎüÊÕʱ£¬×°ÖÃÄÚѹǿ¼õС£¬ÄÚ²¿µÄÆøÇò¾Í»áÕʹ󣬾ݴ˷ÖÎö£®

½â´ð ½â£º£¨1£©¢Ù¸ù¾ÝʵÑéÊÒ³£ÓÃÒÇÆ÷¿ÉÖª£º¢Ù·ÖҺ©¶·£»
¢Ú¸Ã×°ÖÃÊǹÌÒºÔÚ³£ÎÂÏÂÖÆÈ¡ÆøÌåµÄ×°Öã¬ÈôÉú³ÉO₂ʹÆøÇòÕÍ´ó£¬Ôò׶ÐÎÆ¿ÖÐËù×°µÄ¹ÌÌåÎïÖÊ¿ÉÒÔÊÇ´ß»¯¼Á¶þÑõ»¯ÃÌ£¬µ¹ÈëµÄÒºÌåÊǹýÑõ»¯ÇâÈÜÒº£»·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2H₂O₂$\frac{\underline{\;MnO_2\;}}{\;}$2H₂O+O₂¡ü£»Å¨ÁòËá¾ßÓÐÎüË®ÐÔ£¬¿ÉÒÔ×ö¸ÉÔï¼Á£¬ÑõÆøµÄÃܶȱȿÕÆøµÄ´ó£¬¿ÉÒÔÓÃÏòÉÏÅÅ¿Õ·¨ÊÕ¼¯£»
¢ÛÖÆÈ¡¶þÑõ»¯Ì¼ËùÐèÒªµÄҩƷʯ»Òʯ£¨»ò̼ËáÄƵȣ©ºÍÏ¡ÑÎËᣬÔò׶ÐÎÆ¿ÖÐ×°ÓеĹÌÌå¿ÉÄÜÊÇʯ»Òʯ£¨»ò̼ËáÄƵȣ©£»
¢ÜÓÐЩÎïÖÊÈÜÓÚË®·ÅÈÈ£¬Ê¹ÆøÌåÅòÕÍ£¬ÈôaÖеÄÒºÌåÎïÖÊÊÇË®£¬Ôò׶ÐÎÆ¿ÖÐ×°ÓеĹÌÌå¿ÉÄÜÊÇÇâÑõ»¯ÄÆ£¨»òÑõ»¯¸Æ £©£»
£¨2£©BÖÐCO₂ÆøÌå±»ÎüÊÕʱ£¬×°ÖÃÄÚѹǿ¼õС£¬ÄÚ²¿µÄÆøÇò¾Í»áÕÍ´ó£¬ÇâÑõ»¯ÄÆÈÜÒº£¨»òÇâÑõ»¯¸ÆÈÜÒº£©¿ÉÎüÊÕ¶þÑõ»¯Ì¼ÆøÌ壮Æä·´Ó¦·½³ÌʽΪ£º
CO₂+2NaOH¨TNa₂CO₃+H₂O»òCO₂+Ca£¨OH£©₂=CaCO₃¡ý+H₂O£®
´ð°¸£º
£¨1£©¢Ù·ÖҺ©¶·  
¢Ú2H₂O₂$\frac{\underline{\;MnO_2\;}}{\;}$2H₂O+O₂¡ü   CD
¢Ûʯ»Òʯ£¨»ò̼ËáÄƵȣ©
 ¢ÜÇâÑõ»¯ÄÆ£¨»òÑõ»¯¸Æ £©
£¨2£©ÇâÑõ»¯ÄÆ£¨»òÇâÑõ»¯¸Æ£© 2NaOH+CO₂=Na₂CO₃+H₂O£¨»ò Ca£¨OH£©₂+CO₂=CaCO₃¡ý+H₂O£©

µãÆÀ ´ËÌâµÄÄѶȲ»´ó£¬ÕÆÎÕ¶þÑõ»¯Ì¼µÄ»¯Ñ§ÐÔÖÊ¡¢Éúʯ»ÒµÄÐÔÖÊÓëÓÃ;ÒÔ¼°ÇâÑõ»¯ÄƵÄÐÔÖʵȼ´¿É˳Àû½â´ð´ËÌ⣮