15¡¢Ò»Ì죬С¾êºÍÀÏʦһÆð×ß½øʵÑéÊÒ£¬¼ì²éÿ¸öʵÑé×ÀÉϵÄÒ©Æ·¡¢ÒÇÆ÷ÊÇ·ñÆ뱸£¬µ±Ëý×ß½øij×éµÄʱºò£¬¿´µ½ÁËÒ»¸ö²»ºÍгµÄ¡°Òô·û¡±£¨ÈçͼËùʾ£©
£¨1£©Äã¼ûµ½´ËÇé¾°£¬Ê×ÏÈÏëµ½µÄÊÇÇâÑõ»¯ÄÆÈÜÒº¿ÉÄܱäÖÊÁË£¬¸Ã±äÖÊ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
2NaOH+CO2¨TNa2CO3+H2O
£®
£¨2£©Î§ÈÆ´ËÆ¿NaOHÈÜÒºÊÇ·ñ±äÖʵÄÎÊÌ⣬С¾êÀûÓÃʵÑéÊÒµÄÈýÖÖÊÔ¼Á£¨ÂÈ»¯¸ÆÈÜÒº¡¢Ï¡ÁòËá¡¢·Ó̪ÊÔÒº£©Õ¹¿ªÁËÈçÏÂ̽¾¿»î¶¯£®
¢ñ£®È¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬µÎ¼ÓijÖÖÊÔ¼Á£¬ÓÐÆøÅݲúÉú£¬ÓÉ´ËÖ¤Ã÷NaOHÈÜÒºÒѾ­±äÖÊ£¬ÄãÈÏΪС¾êËù¼ÓµÄÊÔ¼ÁÊÇ
Ï¡ÁòËá
£»Ö¤Ã÷NaOHÈÜÒºÒѾ­±äÖʵķ´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
H2SO4+Na2CO3=Na2SO4+CO2¡ü+H2O
£®
¢ò£®ÓûÖ¤Ã÷±äÖʵÄÈÜÒºÖÐÉдæNaOH£¬ÇëÄãÌîдÏÂÃæÓйؿոñ£¬°ïÖúС¾êÍê³É̽¾¿·½°¸£º
̽¾¿Ä¿µÄ ̽¾¿²½Öè Ô¤¼ÆÏÖÏó
1£®³ý¾¡ÈÜÒºÖеÄCO32- A£ºÈ¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬
µÎ¼Ó×ãÁ¿µÄ
ÂÈ»¯¸ÆÈÜÒº
£®
B£ºÓÐ
°×É«³Áµí
²úÉú
2£®Ö¤Ã÷ÈÜÒºÖÐÉдæNaOH ÏòʵÑéAËùµÃÈÜÒºÖеÎ
¼Ó
·Ó̪ÊÔÒº
£®
C£º
ÈÜÒº±äºì
£®
·ÖÎö£º£¨1£©NaOHÈÜÒºÎüÊÕ¿ÕÆøÖеĶþÑõ»¯Ì¼Éú³ÉNa2CO3£»
£¨2£©¢ñ¡¢H2SO4+Na2CO3=Na2SO4+CO2¡ü+H2O£»
¢ò¡¢Na2CO3+CaCl2=CaCO3¡ý+2NaCl£¬·Ó̪Óö¼î±äºìÉ«£¬Èç¹ûÈÜÒºÖÐÉдæNaOH£¬ÄÇôÔÚÉÙÁ¿NaOHÈÜÒºÖмÓÈë×ãÁ¿CaCl2ÈÜÒººóÔÙ¼Ó·Ó̪ÊÔÒºÔò¼È²úÉú°×É«³ÁµíÓÖ±äºìÉ«£¬Èç¹ûÈÜÒºÖв»´æÔÚNaOH£¬¼ÓÈë×ãÁ¿CaCl2ÈÜÒººó¾Í³ý¾¡ÁËCO32-¼ÈûÓÐÁËÇâÑõ»¯ÄÆҲûÓÐÁË̼ËáÄÆÖ»²úÉú°×É«³ÁµíÔÙ¼Ó·Ó̪ÊÔÒº²»±äÉ«£®
½â´ð£º½â£º£¨1£©NaOHÈÜÒºÒ×ÎüÊÕ¿ÕÆøÖеĶþÑõ»¯Ì¼Éú³ÉNa2CO3 
¹Ê¸Ã±äÖÊ·´Ó¦µÄ·½³ÌʽΪ£º2NaOH+CO2¨TNa2CO3+H2O
£¨2£©¢ñ¡¢Ï¡ÁòËá¿ÉÓë̼ËáÄÆ·´Ó¦Éú³É¶þÑõ»¯Ì¼ÆøÌ壬H2SO4+Na2CO3=Na2SO4+CO2¡ü+H2O£»
¢ò¡¢Na2CO3+CaCl2=CaCO3¡ý+2NaCl£¬·Ó̪Óö¼î±äºìÉ«£¬Èç¹ûÈÜÒºÖÐÉдæNaOH£¬ÄÇôÔÚÉÙÁ¿NaOHÈÜÒºÖмÓÈë×ãÁ¿CaCl2ÈÜÒººóÔÙ¼Ó·Ó̪ÊÔÒºÔò¼È²úÉú°×É«³ÁµíÓÖ±äºìÉ«£¬Èç¹ûÈÜÒºÖв»´æÔÚNaOH£¬¼ÓÈë×ãÁ¿CaCl2ÈÜÒººó¾Í³ý¾¡ÁËCO32-¼ÈûÓÐÁËÇâÑõ»¯ÄÆҲûÓÐÁË̼ËáÄÆÔÙ¼Ó·Ó̪ÊÔÒºÖ»²úÉú°×É«³Áµí¶ø²»±äÉ«£»
¹Ê´ð°¸Îª£º£¨1£©2NaOH+CO2¨TNa2CO3+H2O£»
£¨2£©¢ñ¡¢Ï¡ÁòËᣬH2SO4+Na2CO3=Na2SO4+CO2¡ü+H2O£»
¢ò¡¢
     
 ³ý¾¡ÈÜÒºÖеÄCO32-  ÂÈ»¯¸ÆÈÜÒº Óа×É«³Áµí²úÉú
  ·Ó̪ÊÔÒº   ÈÜÒº±äºì
µãÆÀ£º±¾Ìâ×ۺϿ¼²éÁËÇâÑõ»¯ÄƵÄÐÔÖÊÒÔ¼°Ì¼Ëá¸ùµÄ¼ìÑé·½·¨¼°³ýÔÓ·½·¨£¬×¢Òâ°ÑÎÕ¼ÓÈëÊÔ¼ÁµÄÁ¿£¬³ýÔÓ¹ý³ÌÖв»ÄܼÓÈëеÄÔÓÖÊÀë×Ó£¬ÕýÈ·Ñ¡ÔñÊÔ¼Á£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

26¡¢Ò»Ì죬ʵÑéÖúÊÖС¾ê×ß½øʵÑéÊÒ£¬ºÍÀÏʦһÆð¼ì²éÿ¸öʵÑé×ÀÉϵÄÒ©Æ·¡¢ÒÇÆ÷ÊÇ·ñÆ뱸£¬×ßµ½Ä³×éµÄʱºò£¬¿´µ½ÁËÒ»¸ö²»ºÍгµÄ¡°Òô·û¡±£¨ÈçÓÒͼ£©£®
£¨1£©´ËÇé´Ë¾°ÄãÊ×ÏÈÏëµ½µÄÊÇËü¿ÉÄܱäÖÊÁË£¬¸Ã±äÖÊ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
2NaOH+CO2¨TNa2CO3+H2O
£®
£¨2£©Î§ÈÆ´ËÆ¿NaOHÈÜÒºÊÇ·ñ±äÖʵÄÎÊÌ⣬С¾êÀûÓÃʵÑéÊÒµÄÈýÖÖÊÔ¼Á£¨ÂÈ»¯¸ÆÈÜÒº¡¢Ï¡ÑÎËá¡¢·Ó̪ÊÔÒº£©Õ¹¿ªÁË̽¾¿»î¶¯£®
¢ÙÈ¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬µÎ¼ÓijÖÖÊÔ¼Á£¬ÓÐÆøÅݲúÉú£¬ÓÉ´ËÖ¤Ã÷NaOHÈÜÒºÒѾ­±äÖÊ£®ÄãÈÏΪС¾êËù¼ÓµÄÊÔ¼ÁÊÇ
Ï¡ÑÎËá
£®
¢ÚÒ²ÓÐͬѧÈÏΪ£ºÖ»Òª´ÓÆ¿ÖÐÈ¡³öÉÙÁ¿ÈÜÒº£¬ÏòÆäÖеμӷÓ̪ÊÔÒº£¬ÈÜÒº±ä³ÉºìÉ«£¬¾Í¿ÉÄÜÈ·¶¨ÄÜʹÈÜÒº³Ê¼îÐԵľÍÊÇNaOH£¬ÄãÈÏΪÕâÖÖ¿´·¨ÊÇ·ñÕýÈ·
²»ÕýÈ·
ÀíÓÉÊÇ
̼ËáÄÆÈÜÒºÒ²ÏÔ¼îÐÔ

¢ÛÓûÖ¤Ã÷±äÖʵÄÈÜÒºÖÐÉдæNaOH£¬ÇëÄã°ïÖúС¾êÍê³ÉÒÔÏÂ̽¾¿·½°¸£º

£¨3£©Í¨¹ýÉÏÊö̽¾¿£¬ËµÃ÷ÇâÑõ»¯ÄÆÈÜÒº±©Â¶ÔÚ¿ÕÆøÖÐÈÝÒ×±äÖÊ£¬¹ÊÓ¦
ÃÜ·â
±£´æ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¾«Ó¢¼Ò½ÌÍøÒ»Ì죬ʵÑéÖúÊÖС¾ê×ß½øʵÑéÊÒ£¬ºÍÀÏʦһÆð¼ì²éÿ¸öʵÑé×ÀÉϵÄÒ©Æ·¡¢ÒÇÆ÷ÊÇ·ñÆ뱸£¬×ßµ½Ä³×éµÄʱºò£¬¿´µ½ÁËÒ»¸ö²»ºÍгµÄ¡°Òô·û¡±£¬Èçͼ£º
£¨1£©´ËÇé´Ë¾°ÄãÊ×ÏÈÏëµ½µÄÊÇËü¿ÉÄܱäÖÊÁË£¬¸Ã±äÖÊ·´Ó¦µÄ»¯Ñ§·½³Ìʽ
 
£®
£¨2£©Î§ÈÆ´ËÆ¿NaOHÈÜÒºÊÇ·ñ±äÖʵÄÎÊÌ⣬С¾êÀûÓÃʵÑéÊÒµÄÈýÖÖÊÔ¼Á£¨ÂÈ»¯¸ÆÈÜÒº¡¢Ï¡ÑÎËá¡¢·Ó̪ÊÔÒº£©Õ¹¿ªÁË̽¾¿»î¶¯£®
¡¾²éÔÄ×ÊÁÏ¡¿£ºa£®ÂÈ»¯¸ÆÈÜÒº³ÊÖÐÐÔ£¬Ì¼ËáÄÆÈÜÒº³Ê¼îÐÔ
b£®ÂÈ»¯¸ÆÈÜÒºÓë̼ËáÄÆÈÜÒº·´Ó¦£ºCaCl2+Na2CO3
      
.
.
 CaCO3
¡ý+2NaCl
¢ÙÑéÖ¤¸ÃÈÜÒºÒѾ­±äÖÊ£®ÄãÈÏΪС¾êËù¼ÓµÄÊÔ¼ÁÊÇ
 
£®
¢ÚÓûÖ¤Ã÷±äÖʵÄÈÜÒºÖÐÉдæNaOH£¬ÇëÄã°ïÖúС¾êÍê³ÉÒÔÏÂ̽¾¿·½°¸£º
̽¾¿Ä¿µÄ ̽¾¿²½Öè Ô¤¼ÆÏÖÏó
³ý¾¡ÈÜÒºÖеÄCO32- aÈ¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬µÎ¼Ó×ãÁ¿µÄ
 
ÊÔ¼Á
 
Ö¤Ã÷ÈÜÒºÖÐÉдæNaOH bÏòʵÑéaËùµÃÈÜÒºÖеμӷÓ̪ÊÔÒº
 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

Ò»Ì죬С¾êºÍÀÏʦһÆð×ß½øʵÑéÊÒ£¬¼ì²éÿ¸öʵÑé×ÀÉϵÄÒ©Æ·¡¢ÒÇÆ÷ÊÇ·ñÆ뱸£¬µ±Ëý×ß½øij×éµÄʱºò£¬¿´µ½ÁËÒ»¸ö²»ºÍгµÄ¡°Òô·û¡±£¨ÈçͼËùʾ£©
£¨1£©Äã¼ûµ½´ËÇé¾°£¬Ê×ÏÈÏëµ½µÄÊÇÇâÑõ»¯ÄÆÈÜÒº¿ÉÄܱäÖÊÁË£¬¸Ã±äÖÊ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º______£®
£¨2£©Î§ÈÆ´ËÆ¿NaOHÈÜÒºÊÇ·ñ±äÖʵÄÎÊÌ⣬С¾êÀûÓÃʵÑéÊÒµÄÈýÖÖÊÔ¼Á£¨ÂÈ»¯¸ÆÈÜÒº¡¢Ï¡ÁòËá¡¢·Ó̪ÊÔÒº£©Õ¹¿ªÁËÈçÏÂ̽¾¿»î¶¯£®
¢ñ£®È¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬µÎ¼ÓijÖÖÊÔ¼Á£¬ÓÐÆøÅݲúÉú£¬ÓÉ´ËÖ¤Ã÷NaOHÈÜÒºÒѾ­±äÖÊ£¬ÄãÈÏΪС¾êËù¼ÓµÄÊÔ¼ÁÊÇ______£»Ö¤Ã÷NaOHÈÜÒºÒѾ­±äÖʵķ´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£®
¢ò£®ÓûÖ¤Ã÷±äÖʵÄÈÜÒºÖÐÉдæNaOH£¬ÇëÄãÌîдÏÂÃæÓйؿոñ£¬°ïÖúС¾êÍê³É̽¾¿·½°¸£º
̽¾¿Ä¿µÄ̽¾¿²½ÖèÔ¤¼ÆÏÖÏó
1£®³ý¾¡ÈÜÒºÖеÄCO32-A£ºÈ¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬
µÎ¼Ó×ãÁ¿µÄ______£®
B£ºÓÐ______²úÉú
2£®Ö¤Ã÷ÈÜÒºÖÐÉдæNaOHÏòʵÑéAËùµÃÈÜÒºÖеÎ
¼Ó______£®
C£º______£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2008-2009ѧÄê¹ã¶«Ê¡ÉîÛÚÊб¦°²Çø¾ÅÄ꼶£¨ÉÏ£©ÆÚÄ©µ÷ÑвâÊÔ¿ÆѧÊÔ¾í£¨»¯Ñ§²¿·Ö£©£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

Ò»Ì죬С¾êºÍÀÏʦһÆð×ß½øʵÑéÊÒ£¬¼ì²éÿ¸öʵÑé×ÀÉϵÄÒ©Æ·¡¢ÒÇÆ÷ÊÇ·ñÆ뱸£¬µ±Ëý×ß½øij×éµÄʱºò£¬¿´µ½ÁËÒ»¸ö²»ºÍгµÄ¡°Òô·û¡±£¨ÈçͼËùʾ£©
£¨1£©Äã¼ûµ½´ËÇé¾°£¬Ê×ÏÈÏëµ½µÄÊÇÇâÑõ»¯ÄÆÈÜÒº¿ÉÄܱäÖÊÁË£¬¸Ã±äÖÊ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º______£®
£¨2£©Î§ÈÆ´ËÆ¿NaOHÈÜÒºÊÇ·ñ±äÖʵÄÎÊÌ⣬С¾êÀûÓÃʵÑéÊÒµÄÈýÖÖÊÔ¼Á£¨ÂÈ»¯¸ÆÈÜÒº¡¢Ï¡ÁòËá¡¢·Ó̪ÊÔÒº£©Õ¹¿ªÁËÈçÏÂ̽¾¿»î¶¯£®
¢ñ£®È¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬µÎ¼ÓijÖÖÊÔ¼Á£¬ÓÐÆøÅݲúÉú£¬ÓÉ´ËÖ¤Ã÷NaOHÈÜÒºÒѾ­±äÖÊ£¬ÄãÈÏΪС¾êËù¼ÓµÄÊÔ¼ÁÊÇ______£»Ö¤Ã÷NaOHÈÜÒºÒѾ­±äÖʵķ´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£®
¢ò£®ÓûÖ¤Ã÷±äÖʵÄÈÜÒºÖÐÉдæNaOH£¬ÇëÄãÌîдÏÂÃæÓйؿոñ£¬°ïÖúС¾êÍê³É̽¾¿·½°¸£º
̽¾¿Ä¿µÄ̽¾¿²½ÖèÔ¤¼ÆÏÖÏó
1£®³ý¾¡ÈÜÒºÖеÄCO32-A£ºÈ¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬
µÎ¼Ó×ãÁ¿µÄ______£®
B£ºÓÐ______²úÉú
2£®Ö¤Ã÷ÈÜÒºÖÐÉдæNaOHÏòʵÑéAËùµÃÈÜÒºÖеÎ
¼Ó______£®
C£º______£®


²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸