Question

16£®Ä³º£Ñ󻯹¤¼¯ÍÅÓð±¼î·¨Éú²úµÄ¼î²úÆ·Öк¬ÓÐÉÙÁ¿ÂÈ»¯ÄÆÔÓÖÊ£¬Æä²úÆ·°ü×°´üÉÏ×¢Ã÷£ºÌ¼ËáÄÆ¡Ý96%£®Îª²â¶¨¸Ã²úÆ·Öк¬Ì¼ËáÄƵÄÖÊÁ¿·ÖÊý£¬½øÐÐÁËÒÔÏÂʵÑ飻ȡ11.0g´¿¼îÑùÆ··ÅÈëÉÕ±­ÖУ¬³ÆµÃÉÕ±­¼°ËùÊ¢´¿¼îÑùÆ·µÄ×ÜÖÊÁ¿Îª158.0g£¬ÔÙ°Ñ100gÏ¡ÑÎËáƽ¾ù·Ö³ÉËÄ·ÝÒÀ´Î¼ÓÈëÑùÆ·ÖУ¬³ä·Ö·´Ó¦ºó£¬ÊµÑéÊý¾Ý¼Ç¼ÈçÏ£º

Ëù¼ÓÑÎËáµÄ´ÎÊý	µÚÒ»´Î	µÚ¶þ´Î	µÚÈý´Î	µÚËÄ´Î
ÉÕ±­¼°ËùÊ¢ÎïÖʵÄ×ÜÖÊÁ¿/g	181.2	204.4	228.6	253.6

ÇëÄã¾Ý´Ë·ÖÎö¼ÆË㣺
£¨1£©µÚÒ»´Î¼ÓÈëÏ¡ÑÎËá³ä·Ö·´Ó¦ºó£¬Éú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿ÊÇ1.8g£®
£¨2£©µÚÈý´Î¼ÓÈëÑÎËá·´Ó¦½áÊøºóµÄÈÜÒºÖУ¬º¬ÓеÄÈÜÖÊÊÇÂÈ»¯ÄÆ¡¢ÂÈ»¯Çâ
£¨3£©¸Ã²úÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÊÇ·ñºÏ¸ñ£¿
£¨4£©Ëù¼ÓÏ¡ÑÎËáµÄÖÊÁ¿·ÖÊý£¿

Answer 1

·ÖÎö ̼ËáÄƺÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯ÄÆ¡¢Ë®ºÍ¶þÑõ»¯Ì¼£¬¸ù¾Ý±íÖÐÌṩµÄÊý¾ÝºÍ·´Ó¦µÄ»¯Ñ§·½³Ìʽ¿ÉÒÔ½øÐÐÏà¹Ø·½ÃæµÄ¼ÆËãºÍÅжϣ®

½â´ð ½â£º£¨1£©µÚÒ»´Î¼ÓÈëÏ¡ÑÎËá³ä·Ö·´Ó¦ºó£¬Éú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿ÊÇ£º158.0g+25g-181.2g=1.8g£®
¹ÊÌ1.8£®
£¨2£©µÚÈý´Î¼ÓÈëÑÎËá·´Ó¦½áÊøºó£¬Éú³É¶þÑõ»¯Ì¼ÖÊÁ¿ÊÇ4.4g£¬ËµÃ÷Ï¡ÑÎËá¹ýÁ¿£¬ÈÜÒºÖк¬ÓеÄÈÜÖÊÊÇÂÈ»¯ÄƺÍÂÈ»¯Ç⣮
¹ÊÌÂÈ»¯ÄÆ¡¢ÂÈ»¯Ç⣮
£¨3£©Éè̼ËáÄÆÖÊÁ¿Îªx£¬
Na₂CO₃+2HCl¨T2NaCl+H₂O+CO₂¡ü£¬
106                                        44
x                                            4.4g
$\frac{106}{x}$=$\frac{44}{4.4g}$£¬
x=10.6g£¬
¸Ã²úÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýΪ£º$\frac{10.6g}{11.0g}$¡Á100%=96.4%£¬
´ð£º¸Ã²úÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýºÏ¸ñ£®
£¨4£©Éè25gÏ¡ÑÎËáÖÐÂÈ»¯ÇâÖÊÁ¿Îªy£¬
Na₂CO₃+2HCl¨T2NaCl+H₂O+CO₂¡ü£¬
                73                          44
                y                          1.8g
$\frac{73}{y}$=$\frac{44}{1.8g}$£¬
y=2.99g£¬
´ð£ºËù¼ÓÏ¡ÑÎËáµÄÖÊÁ¿·ÖÊýΪ£º$\frac{2.99g}{25g}$¡Á100%=11.9%£¬
´ð£ºËù¼ÓÏ¡ÑÎËáµÄÖÊÁ¿·ÖÊýΪ11.9%£®

µãÆÀ ²îÁ¿·¨ÔÚ¼ÆËãÖеÄÓ¦Óúܹ㷺£¬½â´ðµÄ¹Ø¼üÊÇÒª·ÖÎö³öÎïÖʵÄÖÊÁ¿²îÓëÒªÇóµÄδ֪ÊýÖ®¼äµÄ¹Øϵ£¬ÔÙ¸ù¾Ý¾ßÌåµÄÊý¾ÝÇó½â£®