Question

17£®ÏÖÓÐÍ­ÓëÁíÒ»ÖÖ½ðÊôµÄ»ìºÏ·ÛÄ©£¬ÁíÒ»ÖÖ½ðÊô¿ÉÄÜÊÇþ¡¢Ìú¡¢Ð¿ÖеÄÒ»ÖÖ£¬ÏÖÓû²â¶¨Æä×é³É£®È¡¸Ã»ìºÏÎï·ÛÄ©8.0g·ÅÈëÉÕ±­ÖУ¬½«140.0g14.0%µÄÏ¡ÁòËá·ÖËĴμÓÈë¸ÃÉÕ±­ÖУ¬³ä·Ö·´Ó¦ºó£¬²âµÃÊ£Óà¹ÌÌåÊý¾Ý¼Ç¼ÈçÏ£º

´Î   Êý	1	2	3	4
¼ÓÈëÏ¡ÁòËáµÄÖÊÁ¿/g	35.0	35.0	35.0	35.0
Ê£Óà¹ÌÌåµÄÖÊÁ¿/g	6.8	5.6	4.4	4.2

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¸Ã»ìºÏÎïÖÐÍ­µÄÖÊÁ¿·ÖÊýΪ52.5%£»
£¨2£©Ð´³ö·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽMg+H₂SO₄=MgSO₄+H₂¡ü£»
£¨3£©¸ù¾Ý½ðÊôµÄÖÊÁ¿ÁгöµÚ¶þ´Î¼ÓÈëÁòËáºóÉú³ÉÆøÌå×ÜÖÊÁ¿£¨x£©µÄ±ÈÀýʽ$\frac{24}{2.4g}$=$\frac{2}{x}$£»
£¨4£©Èô½«µÚÈý´Î·´Ó¦ºóÈÜÒºÕô·¢µô8.3gË®£¬ÔòËùµÃ²»±¥ºÍÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýΪ18%£»
£¨5£©Èç¹ûÓÃ98%µÄŨÁòËáÅäÖÆ140.0gµÄÉÏÊöËùÓÃÏ¡ÁòËᣬÔòÐèŨÁòËáµÄÖÊÁ¿Îª20g£®

Answer 1

·ÖÎö ¸ù¾Ý±íÖÐÊý¾Ý¿ÉÒÔÅжϳö1¡¢2¡¢3´Î·´Ó¦ÖУ¬Ï¡ÁòËáÍêÈ«·´Ó¦£¬4´Î·´Ó¦ÖÐÏ¡ÁòËá¹ýÁ¿£»
¸ù¾Ý·´Ó¦µÄÁòËáÖÊÁ¿ºÍ¹ÌÌåÖÊÁ¿¿ÉÒÔ¼ÆËã½ðÊôµÄÏà¶ÔÔ­×ÓÖÊÁ¿£¬´Ó¶ø¿ÉÒÔÅжϽðÊôÊÇʲô£»
ÈÜÖÊÖÊÁ¿·ÖÊý=$\frac{ÈÜÖÊÖÊÁ¿}{ÈÜÒºÖÊÁ¿}$¡Á100%£»
ÈÜҺϡÊÍÇ°ºó£¬ÈÜÖÊÖÊÁ¿²»±ä£®

½â´ð ½â£º£¨1£©¸Ã»ìºÏÎïÖÐÍ­µÄÖÊÁ¿·ÖÊýΪ£º$\frac{4.2g}{8g}$¡Á100%=52.5%£¬
¹ÊÌ52.5%£®
£¨2£©Éè½ðÊôÔªËØ·ûºÅÊÇM£¬Ïà¶ÔÔ­×ÓÖÊÁ¿ÊÇy£¬
ÒÔµÚÒ»´ÎʵÑéÊý¾Ý½øÐмÆË㣬
M+H₂SO₄¨TMSO₄+H₂¡ü£¬
y    98
1.2g 35.0g¡Á14.0%
$\frac{y}{1.2g}$=$\frac{98}{35.0g¡Á14.0%}$£¬
y=24£¬
½ðÊôÊÇþ£¬Ã¾ºÍÏ¡ÁòËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºMg+H₂SO₄=MgSO₄+H₂¡ü£®
¹ÊÌMg+H₂SO₄=MgSO₄+H₂¡ü£®
£¨3£©ÉèÉú³ÉµÄÇâÆøÖÊÁ¿Îªx£¬
Mg+H₂SO₄=MgSO₄+H₂¡ü£¬
24             2
2.4g           x
$\frac{24}{2.4g}$=$\frac{2}{x}$£¬
¹ÊÌ$\frac{24}{2.4g}$=$\frac{2}{x}$£®
£¨4£©ÉèÉú³ÉÁòËáпµÄÖÊÁ¿Îªz£¬Éú³ÉÇâÆøµÄÖÊÁ¿Îªn£¬
Mg+H₂SO₄=MgSO₄+H₂¡ü£¬
24        120  2
3.6g       z   n
$\frac{24}{3.6g}$=$\frac{120}{z}$=$\frac{2}{n}$£¬
z=18g£¬n=0.3g£¬
ËùµÃ²»±¥ºÍÈÜÒºÖÊÁ¿Îª£º35.0g¡Á3+3.6g-0.3g-8.3g=100g£¬
ËùµÃ²»±¥ºÍÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýΪ£º$\frac{18g}{100g}$¡Á100%=18%£¬
¹ÊÌ18%£®
£¨5£©ÉèÐèҪŨÁòËáµÄÖÊÁ¿Îªp£¬
¸ù¾ÝÌâÒâÓУºp¡Á98%=140.0g¡Á14.0%£¬
p=20g£¬
¹ÊÌ20g£®

µãÆÀ ÈÜҺŨËõ»òÏ¡ÊÍʱ£¬Ö»ÊǸıäÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý£¬¶øÈÜÒºÖÐÈÜÖÊÖÊÁ¿²»±ä£¬Òª×¢ÒâÀí½â£®