Question

4£®Ä³¹¤³§Éú²úµÄ̼ËáþÑùÆ·Öк¬ÓÐÉÙÁ¿µÄ̼Ëáþ£¬È¡6g¹ÌÌåÑùÆ·ÓÚÉÕ±­ÖÐÖðµÎ¼ÓÈë50gÏ¡ÁòËáÇ¡ºÃÍêÈ«·´Ó¦µÃµ½ÎÞɫ͸Ã÷ÈÜÒººÍÆøÌ壬½«ÆøÌåͨÈë×ãÁ¿³ÎÇåʯ»ÒË®ÐγÉ5g²»ÈÜÎ¼ÙÉèÿ²½·´Ó¦¾ùÍêÈ«£©£®Çë¼ÆË㣺
£¨1£©²úÉúÆøÌåµÄÖÊÁ¿Îª2.2g£»
£¨2£©ÉÏÊöËùµÃµÄÎÞɫ͸Ã÷ÈÜÒºÖУ¬ÈÜÖʵÄÖÊÁ¿·ÖÊýΪ¶àÉÙ£¿£¨Ð´³ö¼ÆËã¹ý³Ì£¬½á¹û±£Áôµ½0.1%£© 
£¨3£©ÈôÑùÆ·ÖÐ̼ËáþµÄÖÊÁ¿·ÖÊý´óÓÚ80%¼´ÎªºÏ¸ñ£¬´ËÑùÆ·ÊôÓÚ²»ºÏ¸ñ£¨Ìî¡°ºÏ¸ñ¡±»ò¡°²»ºÏ¸ñ¡±£©²úÆ·£®

Answer 1

·ÖÎö ¶þÑõ»¯Ì¼ºÍÇâÑõ»¯¸Æ·´Ó¦ÄÜÉú³É̼Ëá¸Æ³ÁµíºÍË®£¬¸ù¾Ý³ÁµíµÄÖÊÁ¿¿ÉÒÔ¼ÆËã¶þÑõ»¯Ì¼µÄÖÊÁ¿£¬¸ù¾Ý¶þÑõ»¯Ì¼µÄÖÊÁ¿¿ÉÒÔ¼ÆËã̼ËáþµÄÖÊÁ¿ºÍÉú³ÉµÄÁòËáþµÄÖÊÁ¿£¬½øÒ»²½¿ÉÒÔ¼ÆËã̼ËáþÑùÆ·ÖÐ̼ËáþµÄÖÊÁ¿·ÖÊý£®

½â´ð ½â£º£¨1£©Éè·´Ó¦Éú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îªx£¬
Ca£¨OH£©₂+CO₂¨TCaCO₃¡ý+H₂O£¬
                   44        100
                   x          5g
$\frac{44}{x}=\frac{100}{5g}$
x=2.2g
ÉèÉú³ÉÁòËáþµÄÖÊÁ¿Îªx£¬Ì¼ËáþµÄÖÊÁ¿Îªy£¬
MgCO₃+H₂SO₄=MgSO₄+H₂O+CO₂¡ü£¬
 84                       120                44
y                           x                   2.2g
$\frac{84}{y}=\frac{120}{x}=\frac{44}{2.2g}$
x=6g
y=4.3g
£¨2£©ËùµÃµÄÎÞɫ͸Ã÷ÈÜÒºÖУ¬ÈÜÖʵÄÖÊÁ¿·ÖÊýΪ$\frac{6g+£¨6g-4.3g£©}{6g+50g-2.2g}¡Á$¡Ö14.3%£»
£¨3£©ÑùÆ·ÖÐ̼ËáþµÄÖÊÁ¿·ÖÊý=$\frac{4.3g}{6g}¡Á$100%¡Ö71.7%£¼80%£¬²»ºÏ¸ñ
´ð°¸£º
£¨1£©2.2£»
£¨2£©ËùµÃµÄÎÞɫ͸Ã÷ÈÜÒºÖУ¬ÈÜÖʵÄÖÊÁ¿·ÖÊýΪ14.3%£»
£¨3£©²»ºÏ¸ñ£®

µãÆÀ ±¾ÌâÖ÷Òª¿¼²éѧÉúÔËÓû¯Ñ§·½³Ìʽ½øÐмÆËãºÍÍƶϵÄÄÜÁ¦£¬¼ÆËãʱҪעÒâ¹æ·¶ÐÔºÍ׼ȷÐÔ£®