16£®Ð¡Ã÷µÄÂèÂè¾­³£ÎªÐ¡Ã÷Õô¼îÃæÂøÍ·³Ô£¬ÓÐÒ»´ÎСÃ÷×Ðϸ²é¿´ÁË°üװ˵Ã÷£¬·¢ÏÖ´ËÆ·ÅÆÖÐ̼ËáÄƺ¬Á¿´óÓÚ98%£®Ëû´Ó¼ÒÀï´øÑùÆ·À´Ñ§Ð£ÊµÑéÊÒ¼ìÑéÆäÖÐ̼ËáÄƺ¬Á¿ÊÇ·ñÊôʵ£®ÏÖ׼ȷ³ÆÈ¡11gÊÔÑù·ÅÔÚÉÕ±­ÖУ¬ÏòÆäÖеμÓÏ¡ÑÎËáÖÁÇ¡ºÃÍêÈ«·´Ó¦£¨ºöÂÔCO2ÈÜÓÚË®£©£¬¹²ÓÃȥϡÑÎËá50g£¬´ËʱÉÕ±­ÄÚÈÜÒº×ÜÖÊÁ¿Îª56.6g£¨ÔÓÖʲ»ÈÜÓÚË®£¬ÇÒ²»ÓëÏ¡ÑÎËá·´Ó¦£©£®ÊÔ¼ÆË㣺
£¨1£©Éú³ÉCO2ÖÊÁ¿ÊÇ4.4g£®
£¨2£©ÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿ÅжÏÑùÆ·ÖÐ̼ËáÄƺ¬Á¿Óë±êÇ©ÊÇ·ñÏà·û£¿£¨¼ÆËã½á¹û¾«È·µ½0.1%£©
£¨3£©ËùÓÃÏ¡ÑÎËáÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿

·ÖÎö £¨1£©Ì¼ËáÄÆÓëÑÎËá·´Ó¦·Å³öÆøÌå¶þÑõ»¯Ì¼£¬¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ£¬·´Ó¦Ç°ºóÖÊÁ¿²î¼´Îª·Å³öÆøÌå¶þÑõ»¯Ì¼µÄÖÊÁ¿£»
£¨2£©¸ù¾ÝÉú³É¶þÑõ»¯Ì¼ÖÊÁ¿¼ÆËã³öÑùÆ·ÖÐ̼ËáÄÆÖÊÁ¿£¬È»ºóÇó³öÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÓë±êÇ©½øÐбȶԣ¬×ö³öÊÇ·ñÏà·ûµÄÅжϣ»
£¨3£©¸ù¾ÝÉú³É¶þÑõ»¯Ì¼ÖÊÁ¿¼ÆËã³öËùÓÃÏ¡ÑÎËáÖÐÈÜÖʵÄÖÊÁ¿£¬È»ºó¼ÆËã³öËùÓÃÏ¡ÑÎËáÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý¼´¿É£®

½â´ð ½â£º£¨1£©¸ù¾ÝÖØÁ¿Êغ㶨Âɿɵãº11g+50g-56.6g=4.4g£» ¹ÊÌ4.4£»
£¨2£©ÉèÑùÆ·ÖÐ̼ËáÄÆÖÊÁ¿Îªx£¬Ï¡ÑÎËáÖÐËùº¬ÈÜÖÊÖÊÁ¿Îªy
Na2CO3+2HCl=2NaCl+H2O+CO2¡ü
106         73                         44
x             y                         4.4g
$\frac{106}{x}=\frac{73}{y}=\frac{44}{4.4g}$
x=10.6g   y=7.3g
ÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÊÇ£º$\frac{10.6g}{11g}¡Á100%$=96.4%
96.4%£¼98%
²»·û±ê×¼
£¨3£©ËùÓÃÏ¡ÑÎËáµÄÈÜÖʵÄÖÊÁ¿·ÖÊýÊÇ£º$\frac{7.3g}{50g}¡Á100%$=14.6%
´ð£º£¨2£©ÑùÆ·ÖÐ̼ËáÄƵÄÖÊÁ¿·ÖÊýÊÇ96.4%£¬ÑùÆ·ÖÐ̼ËáÄƺ¬Á¿Óë±êÇ©²»Ïà·û£»
£¨3£©ËùÓÃÏ¡ÑÎËáÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýÊÇ14.6%£®

µãÆÀ ÒªÏë½â´ðºÃÕâÀàÌâÄ¿£¬Ê×ÏÈ£¬ÒªÀí½âºÍÊì¼Ç¸ù¾Ý»¯Ñ§·´Ó¦·½³ÌʽµÄ¼ÆËã²½ÖèºÍ¸ñʽ£¬ÒÔ¼°ÓëÖ®Ïà¹ØµÄ֪ʶµÈ£®È»ºó£¬¸ù¾ÝËù¸øµÄÎÊÌâÇé¾°»òͼ±íÐÅÏ¢µÈ£¬½áºÏËùѧµÄÏà¹Ø֪ʶ°´ÕÕÌâÄ¿ÒªÇó½øÐÐÈÏÕæµØÑ¡Ôñ»ò½â´ð¼´¿É£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

6£®ÏÂÁÐÎïÖÊË×ÃûÓ뻯ѧʽÏà¶ÔÓ¦µÄÊÇ£¨¡¡¡¡£©
A£®´¿¼î-NaOHB£®¾Æ¾«-C2H6OC£®Ð¡ËÕ´ò-Na2CO3D£®Éúʯ»Ò-Ca£¨OH£©2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

7£®¹Û²ìÈçͼʵÑé»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÉÕ±­ÖÐÈÈË®µÄ×÷ÓÃÊǸøͭƬ¼ÓÈÈ£¬¸ô¾øÑõÆø£®
£¨2£©Í­Æ¬Éϵİ×Á׺ÍË®Öеİ×Á׶Աȣ¬µÃ³öµÄÓйØȼÉÕÌõ¼þµÄ½áÂÛÊÇÓëÑõÆø½Ó´¥£®
£¨3£©´µÃðÉúÈÕÀ¯ÖòÀûÓõÄÃð»ðÔ­ÀíÊÇʹζȽµµ½×Å»ðµãÒÔÏ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

4£®¸ù¾ÝÈçͼµÄÈܽâ¶ÈÇúÏߣ¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®t1¡æʱ£¬AµÄÈܽâ¶È´óÓÚB
B£®t2¡æʱ£¬A¡¢BÁ½ÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊýÒ»¶¨ÏàµÈ
C£®t2¡æʱ£¬½«A¡¢BµÄ±¥ºÍÈÜÒº·Ö±ðÕô·¢µô10gË®£¬Îö³öAµÄÖÊÁ¿´ó
D£®·Ö±ð½«A¡¢BÔÚt1¡æµÄ±¥ºÍÈÜÒºÉýÎÂÖÁt2¡æ£¬Á½ÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý¶¼»áÔö´ó

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

11£®»¯Ñ§ÊÇÒÔʵÑéΪ»ù´¡µÄѧ¿Æ£¬Íê³ÉÏÂÁÐʵÑ飮

£¨1£©Í¼1ʵÑéÄ¿µÄÊÇ£º²â¶¨¿ÕÆøÖÐÑõÆøµÄº¬Á¿£¬ÊµÑé¹ý³ÌÖй۲쵽ÆøÇòÔõÑù±ä»¯£ºÏȱä´óÈ»ºóËõС£»ÊµÑéÖмÓÈë×ãÁ¿°×Á×µÄÄ¿µÄ£º½«×¶ÐÎÆ¿ÄڵĿÕÆøÍêÈ«·´Ó¦
£¨2£©Í¼2µÄ²Ù×÷»áÔì³Éʲôºó¹û£ºËáÒº·É½¦£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ

1£®ÓÃÏÂÁÐÎïÖʽøÐе¼µçÐÔʵÑ飬µÆÅݲ»ÁÁµÄ×éºÏÊÇ£¨¡¡¡¡£©
¢ÙË® ¢ÚʳÑÎË® ¢Û¾Æ¾«ÈÜÒº ¢Ü×ÔÀ´Ë® ¢ÝÏ¡´×Ëá ¢ÞÕáÌǹÌÌ壮
A£®¢Ù¢Û¢ÞB£®¢Ú¢Ü¢ÝC£®½ö¢Û¢ÞD£®½ö¢Ü¢Ý

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

8£®ÏÂÃ漸×é»ìºÏÎïÒ²¿ÉÒÔÓÃÕôÁó·½·¨·ÖÀëµÄÊÇ£¨¡¡¡¡£©
A£®¾Æ¾«ºÍ¾ÆÔã»ìºÏÎïB£®Ï¸É³ºÍʳÑλìºÏÎï
C£®ÕáÌǺÍζ¾«»ìºÏÎïD£®µâ¾Æ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ

16£®Ð´³öÏÂÁз´Ó¦µÄÎÄ×Ö±í´ïʽ£¬²¢ÓÃÏàÓ¦µÄÐòºÅÌî¿Õ£º
£¨1£©ºìÁ×ÔÚ¿ÕÆøÖÐȼÉÕÁ×+ÑõÆø$\stackrel{µãȼ}{¡ú}$ÎåÑõ»¯¶þÁ×£®
£¨2£©ÊµÑéÊÒÓùýÑõ»¯ÇâÖÆÈ¡ÑõÆø¹ýÑõ»¯Çâ$\stackrel{¶þÑõ»¯ÃÌ}{¡ú}$Ë®+ÑõÆø£®
£¨3£©ÁòÔÚÑõÆøÖÐȼÉÕÁò+ÑõÆø$\stackrel{µãȼ}{¡ú}$¶þÑõ»¯Áò£®
£¨4£©ÒÔÉϸ÷·´Ó¦ÖÐÊôÓÚ»¯ºÏ·´Ó¦µÄÊÇ£¨1£©£¨3£©£®£¨ÌîÐòºÅ£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

17£®´ß»¯¼ÁÔÚ»¯Ñ§·´Ó¦À¡¡¡¡£©
A£®Ö»Äܼӿ췴ӦËÙÂÊB£®Ö»ÄܼõÂý·´Ó¦ËÙÂÊ
C£®Ò»¶¨Äܸı䷴ӦËÙÂÊD£®²»Ò»¶¨Ó°Ïì·´Ó¦ËÙÂÊ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸