ijÌìÈ»¿óȪˮµÄÖ÷Òª³É·ÝÈçÏ£¬ÇëÈÏÕæÔĶÁºóÌî¿Õ¡£

Ö÷Òª³É·Ö£¨mg/L£©£º

̼ËáÇâ¸ù£¨HCO3-£©£º173¡ª205    ÂÈÀë×Ó£¨Cl-£©£º1.0¡ª8.0  

ÁòËá¸ù£¨SO42-£©£º16.08¡ª19.52   ÄÆÀë×Ó£¨Na+£©£º8¡ª50

þÀë×Ó£º2.5¡ª12.5   PHÖµ£º7.8¡À0.5

£¨1£©Ã¾Àë×Ó»¯Ñ§·ûºÅ¿É±íʾΪ____________£¬

¡°SO42-¡±ÖÐÊý×Ö¡°2¡±µÄº¬ÒåÊÇ                                 ¡£

£¨2£©¸Ã¿óȪˮÏÔ         ÐÔ£¨Ìî¡°Ëᡱ¡¢¡°¼î¡±»ò¡°ÖС±£©¡£

£¨3£©ÈÕ³£Éú»îÖÐÓà         Çø±ðÈíË®ºÍӲˮ£¬¿Éͨ¹ý         ·½·¨½µµÍË®µÄÓ²¶È¡£

Mg2+         Ò»¸öÁòËá¸ùÀë×Ó´øÁ½¸öµ¥Î»µÄ¸ºµçºÉ£¬   ¼î£¬·ÊÔíË®  Öó·Ð 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

25¡¢Ä³ÌìÈ»¿óȪˮµÄÖ÷Òª³É·ÝÈçÏ£¬ÇëÈÏÕæÔĶÁºóÌî¿Õ£®

£¨1£©¡°SO42-¡±ÖÐÊý×Ö¡°2¡±µÄº¬ÒåÊÇ
´ø2¸öµ¥Î»¸ºµçºÉµÄÁòËá¸ùÀë×Ó
£®
£¨2£©¸Ã¿óȪˮÏÔ
¼î
ÐÔ£¨Ìî¡°Ëᡱ¡¢¡°¼î¡±»ò¡°ÖС±£©£®
£¨3£©ÈÕ³£Éú»îÖÐÓÃ
·ÊÔíË®
Çø±ðÈíË®ºÍӲˮ£¬¿Éͨ¹ý
¼ÓÈÈÖó·Ð
·½·¨½µµÍË®µÄÓ²¶È£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

11¡¢Ä³ÌìÈ»¿óȪˮµÄÖ÷Òª³É·ÝÈçÏ£¬ÇëÈÏÕæÔĶÁºóÌî¿Õ£®
Ö÷Òª³É·Ö£¨mg/L£©£º
̼ËáÇâ¸ù£¨HCO3-£©£º173-205    ÂÈÀë×Ó£¨Cl-£©£º1.0-8.0
ÁòËá¸ù£¨SO42-£©£º16.08-19.52   ÄÆÀë×Ó£¨Na+£©£º8-50
þÀë×Ó£º2.5-12.5   PHÖµ£º7.8¡À0.5£¨1£©Ã¾Àë×Ó»¯Ñ§·ûºÅ¿É±íʾΪ
Mg2+
£¬¡°SO42-¡±ÖÐÊý×Ö¡°2¡±µÄº¬ÒåÊÇ
Ò»¸öÁòËá¸ùÀë×Ó´øÁ½¸öµ¥Î»µÄ¸ºµçºÉ
£®
£¨2£©¸Ã¿óȪˮÏÔ
¼î
ÐÔ£¨Ìî¡°Ëᡱ¡¢¡°¼î¡±»ò¡°ÖС±£©£®
£¨3£©ÈÕ³£Éú»îÖÐÓÃ
·ÊÔíË®
Çø±ðÈíË®ºÍӲˮ£¬¿Éͨ¹ý
Öó·Ð
·½·¨½µµÍË®µÄÓ²¶È£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©ÈçͼÊÇת»¯Æû³µÎ²ÆøÖÐÓк¦ÆøÌåµÄ΢¹ÛʾÒâͼ£®
¢Ù·´Ó¦ºóµÄͼʾÖк¬ÓÐ
3
3
ÖÖ·Ö×Ó£»
¢ÚͼÖÐËùʾµÄ»¯Ñ§·½³Ìʽ
2CO+2NO
 ´ß»¯¼Á 
.
 
2CO2+N2
2CO+2NO
 ´ß»¯¼Á 
.
 
2CO2+N2
£»
¢Û´ÓͼÖÐÄ㻹ÄÜ»ñÈ¡µÄÐÅÏ¢ÊÇ
ÔÚ»¯Ñ§±ä»¯ÖзÖ×Ó¿ÉÒÔÔÙ·Ö£¨»ò»¯Ñ§·´Ó¦Ç°ºóÔªËصÄÖÖÀ಻±ä£¬»ò·Ö×ÓÓÉÔ­×Ó¹¹³É£¬ºÏÀí¾ù¿É
ÔÚ»¯Ñ§±ä»¯ÖзÖ×Ó¿ÉÒÔÔÙ·Ö£¨»ò»¯Ñ§·´Ó¦Ç°ºóÔªËصÄÖÖÀ಻±ä£¬»ò·Ö×ÓÓÉÔ­×Ó¹¹³É£¬ºÏÀí¾ù¿É
£®£¨ÌîÒ»ÖÖ£©
£¨2£©Ä³ÌìÈ»¿óȪˮµÄÖ÷Òª³É·ÝÈçÏÂ±í£¬ÇëÈÏÕæÔĶÁºóÌî¿Õ£®
Ö÷Òª³É·Ö£¨mg/L£©£ºÌ¼ËáÇâ¸ù£¨HCO3-£©£º173-205  ÂÈÀë×Ó£º1.0-8.0  ÁòËá¸ùÀë×Ó£º16.08-19.52   ÄÆÀë×Ó£¨Na+£©£º8-50  Ã¾Àë×ÓMg2+£º2.5-12.5   pHÖµ£º7.8¡À0.5¢ÙÁòËá¸ùÀë×ӵķûºÅΪ
SO42-
SO42-
£¬ÂÈÀë×ӵķûºÅΪ
Cl-
Cl-

¢ÚÈÕ³£Éú»îÖг£ÓÃ
·ÊÔíË®
·ÊÔíË®
Çø±ðÈíË®ºÍӲˮ£®
¢ÛÅ©ÒµºÍÔ°ÁÖ½½¹àÖ²Îïʱ£¬½«´óË®Âþ¹à¸ÄΪÅç¹à¡¢µÎ¹àµÄÄ¿µÄÊÇ
½ÚÔ¼ÓÃË®
½ÚÔ¼ÓÃË®
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

£¨1£©ÈçͼÊÇת»¯Æû³µÎ²ÆøÖÐÓк¦ÆøÌåµÄ΢¹ÛʾÒâͼ£®
¢Ù·´Ó¦ºóµÄͼʾÖк¬ÓÐ______ÖÖ·Ö×Ó£»
¢ÚͼÖÐËùʾµÄ»¯Ñ§·½³Ìʽ______£»
¢Û´ÓͼÖÐÄ㻹ÄÜ»ñÈ¡µÄÐÅÏ¢ÊÇ______£®£¨ÌîÒ»ÖÖ£©
£¨2£©Ä³ÌìÈ»¿óȪˮµÄÖ÷Òª³É·ÝÈçÏÂ±í£¬ÇëÈÏÕæÔĶÁºóÌî¿Õ£®
Ö÷Òª³É·Ö£¨mg/L£©£ºÌ¼ËáÇâ¸ù£¨HCO3-£©£º173-205¡¡ÂÈÀë×Ó£º1.0-8.0¡¡ÁòËá¸ùÀë×Ó£º16.08-19.52¡¡ ÄÆÀë×Ó£¨Na+£©£º8-50¡¡Ã¾Àë×ÓMg2+£º2.5-12.5¡¡ pHÖµ£º7.8¡À0.5
¢ÙÁòËá¸ùÀë×ӵķûºÅΪ______£¬ÂÈÀë×ӵķûºÅΪ______
¢ÚÈÕ³£Éú»îÖг£ÓÃ______Çø±ðÈíË®ºÍӲˮ£®
¢ÛÅ©ÒµºÍÔ°ÁÖ½½¹àÖ²Îïʱ£¬½«´óË®Âþ¹à¸ÄΪÅç¹à¡¢µÎ¹àµÄÄ¿µÄÊÇ______£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º2012Äê¹ã¶«Ê¡Ã·ÖÝÖÐѧÖп¼»¯Ñ§Ä£ÄâÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨1£©ÈçͼÊÇת»¯Æû³µÎ²ÆøÖÐÓк¦ÆøÌåµÄ΢¹ÛʾÒâͼ£®
¢Ù·´Ó¦ºóµÄͼʾÖк¬ÓР   ÖÖ·Ö×Ó£»
¢ÚͼÖÐËùʾµÄ»¯Ñ§·½³Ìʽ    £»
¢Û´ÓͼÖÐÄ㻹ÄÜ»ñÈ¡µÄÐÅÏ¢ÊÇ    £®£¨ÌîÒ»ÖÖ£©
£¨2£©Ä³ÌìÈ»¿óȪˮµÄÖ÷Òª³É·ÝÈçÏÂ±í£¬ÇëÈÏÕæÔĶÁºóÌî¿Õ£®
Ö÷Òª³É·Ö£¨mg/L£©£ºÌ¼ËáÇâ¸ù£¨HCO3-£©£º173-205  ÂÈÀë×Ó£º1.0-8.0  ÁòËá¸ùÀë×Ó£º16.08-19.52   ÄÆÀë×Ó£¨Na+£©£º8-50  Ã¾Àë×ÓMg2+£º2.5-12.5   pHÖµ£º7.8±0.5
¢ÙÁòËá¸ùÀë×ӵķûºÅΪ    £¬ÂÈÀë×ӵķûºÅΪ   
¢ÚÈÕ³£Éú»îÖг£Óà   Çø±ðÈíË®ºÍӲˮ£®
¢ÛÅ©ÒµºÍÔ°ÁÖ½½¹àÖ²Îïʱ£¬½«´óË®Âþ¹à¸ÄΪÅç¹à¡¢µÎ¹àµÄÄ¿µÄÊÇ    £®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸