СÃ÷½«14.4gº¬ÔÓÖʵĴ¿¼îÑùÆ·£¨Ì¼ËáÄÆÓëÂÈ»¯ÄƵĻìºÏÎÓë90gÏ¡ÑÎËáÏà»ìºÏ£¬Ç¡ºÃÍêÈ«·´Ó¦£¬²âµÃ·´Ó¦Éú³ÉÆøÌåµÄÖÊÁ¿£¨m£©Ó뷴Ӧʱ¼ä£¨t£©µÄÊý¾ÝÈçϱíËùʾ£º

·´Ó¦Ê±¼ät/s

t0

t1

t2

t3

t4

t5

t6      

t 7

ÆøÌåÖÊÁ¿m/g

0

0.88

1.76

2.64

3.52

4.4

X

4.4

(26)                                                                                                                                                                                                                                                                ±íÖÐXµÄֵΪ        £»

(27)                                                                                                                                                                                                                                                                ¼ÆËãÑùÆ·ÖÐNaClµÄÖÊÁ¿£»

(28)                                                                                                                                                                                                                                                                ¼ÆËãÍêÈ«·´Ó¦ºóËùµÃÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊý¡£


(1) 4.4£¨1·Ö£©

(2) Na2CO3 + 2HCl = 2NaCl + H2O + CO2¡ü

106            117         44

y              z          4.4g

    g   £¨1·Ö£©      

ÑùÆ·ÖÐm(NaCl) = 14.4g ¨C 10.6g = 3.8g£¨1·Ö£©

(3)         £¨1·Ö£©

    11.7g + 3.8g = 15.5g£¨1·Ö£©

    £¨2·Ö£©


Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ʵÑé×ÀÉÏÒò¾Æ¾«µÆ´ò·­¶ø×Å»ðʱ£¬×î±ã½ÝµÄÆ˻𷽷¨ÊÇ£¨          £©¡£

A. ÓÃË®³åϨ               B. ÓÃʪĨ²¼¸ÇÃð

C. ÓÃɳÍÁ¸ÇÃð             D. ÓÃÅÝÄ­Ãð»ðÆ÷ÆËÃð

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁб仯¹ý³ÌÖУ¬²»°üº¬»ºÂýÑõ»¯µÄÊÇ£¨     £©

A. ¶¯Ö²ÎïµÄºôÎü   B. ÕáÌǵÄÈܽ⠠  C. ¾ÆºÍ´×µÄÄðÔì    D. ʳÎïµÄ¸¯ÀÃ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁл¯Ñ§·½³ÌʽµÄÊéдÕýÈ·µÄÊÇ¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤¡¤ £¨   £©

A£®2Fe + 6HCl = 2FeCl3 + 3H2¡ü              B£®Zn + AgNO3 = Zn(NO3)2 + Ag

C£®3CO + Fe2O32Fe + 3CO2          D£®CuCl2 + Na2SO4 = CuSO4 + 2NaCl

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


¸ù¾ÝÓÒͼA¡¢B¡¢CÈýÖÖÎïÖʵÄÈܽâ¶ÈÇúÏ߻شð£º

(8)  A¡¢B¡¢CÈýÖÖÎïÖÊÓпÉÄÜΪÆøÌåµÄÊÇ_____________¡£

(9)  t1¡æʱ£¬½«µÈÖÊÁ¿µÄAºÍB·Ö±ð¼ÓÈëÊ¢ÓеÈÖÊÁ¿Ë®µÄÉÕ±­ÖУ¬³ä·Ö½Á°èºó£¬ÆäÖÐÒ»¸öÉÕ±­ÖÐÈÔÓÐÉÙÁ¿¹ÌÌåδÈܽ⣬ÔòδÈܽâµÄ¹ÌÌåÊÇ_____________¡£

(10)                                                                                                                                                                                                                                                                ÒªÔÚ²»¸Ä±äÈÜÖʵÄÖÊÁ¿·ÖÊýµÄÇ°ÌáÏÂʹt2¡æʱBµÄ±¥ºÍÈÜÒº³ÉΪ²»±¥ºÍÈÜÒº£¬¿É²ÉÓõķ½·¨ÊÇ______________¡£

(11)                                                                                                                                                                                                                                                                ÏÖÒªÅäÖÆt3¡æʱAÎïÖʵı¥ºÍÈÜÒº90g£¬ÐèÒªAÎïÖʵÄÖÊÁ¿Îª_________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


 ÏÂÁб仯ÖÐÇ°ÕßÊÇ»¯Ñ§±ä»¯£¬ºóÕßÊÇÎïÀí±ä»¯µÄÊÇ£¨ ¡¡¡¡£©

A. ʳÑÎÈÜÓÚË®£¬»ðÒ©±¬Õ¨              B. þ´øȼÉÕ£¬ÌúÉúÐâ

C. ʳÎ︯°Ü£¬µçµÆ·¢¹â                D. ÆûÓͻӷ¢£¬¾Æ¾«È¼ÉÕ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁжÔÀ¯ÖòȼÉÕ¹ý³ÌÖÐʵÑéÏÖÏóÃèÊö´íÎóµÄÊÇ£¨¡¡¡¡£©

A. »ðÑæ·ÖΪÈý²ã                      B. ÕÖÔÚ»ðÑæÉϵÄÉÕ±­ÄÚ±Ú³öÏÖË®Öé

C. À¯ÖòÖð½¥±ä¶Ì                      D. Éú³ÉÁËÆøÌå¶þÑõ»¯Ì¼

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁеιÜʹÓûò·ÅÖÃͼʾÕýÈ·µÄÊÇ

                           

A£®È¡ÒºÊ±¼·Èë¿ÕÆø                    B£®½«µÎ¹Üºá·ÅÔÚ×ÀÃæ

                        

C£®½«Ï´¾»ºóµÄµÎ¹ÜÇ°Èë½à¾»ÉÕ±­Àï         D£®½«²ÐÁôÊÔÒºµÄµÎ¹Üµ¹³Ö

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º³õÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁйØÓÚ¡°È¼ÉÕºÍÃð»ð¡±µÄÐðÊöÕýÈ·µÄÊÇ  (   )

A£®µµ°¸ÊÒ×Å»ðÓÃÅÝÄ­Ãð»ðÆ÷Ãð»ð

B£®³´²ËʱÓ͹ø×Å»ð£¬Á¢¼´¸ÇÉϹø¸Ç

C£®Ö»Óк¬Ì¼ÔªËصÄÎïÖʲÅÄÜȼÉÕ

D.ֻҪζȴﵽ¿ÉȼÎïµÄ×Å»ðµã£¬¿ÉȼÎï¾ÍÄÜȼÉÕ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸