½â£º£¨1£©¸ÖÌú¶¼ÊÇÓÉÌúºÍ̼µÈÎïÖÊ×é³ÉµÄ£¬ÊôÓÚÊôÓÚ»ìºÏÎ¹ÊÌ»ìºÏÎ
£¨2£©ÌúÓëË®ºÍÑõÆø³ä·Ö½Ó´¥Ê±ÈÝÒ×ÉúÐ⣬ÑÎÈÜÒºÄܹ»¼Ó¿ìÌúÉúÐâµÄËÙÂÊ£®¹ÊÌÕôÁóË®£»Ê³ÑÎË®£»Ê³ÑÎʱÌú¶¤µÄ¸¯Ê´¸ü¿ì£®
£¨3£©ÌúÓëÑõÆøºÍË®ÕôÆø¸ô¾øʱ²»ÈÝÒ×ÉúÐ⣮¹ÊÌÌúÓëÑõÆøºÍË®ÕôÆø¸ô¾ø£®
£¨4£©ÌúÐâÓëÏ¡ÑÎËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºFe
2O
3+6HCl¨T2FeCl
3+3H
2O£®
ÌúÓëÏ¡ÑÎËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºFe+2HCl¨TFeCl
2+H
2¡ü£®
³¤Ê±¼ä·´Ó¦ºó£¬ÈÜÒºÖÐÓкÚÉ«¿ÅÁ£³Áµí£¬¸ÃÎïÖÊÊÇ̼£¬°Ñ¸ÃÎïÖÊ´ÓÈÜÒºÖзÖÀë³öÀ´µÄ·½·¨ÊǹýÂË£®¹ÊÌ̼£»¹ýÂË£®
£¨5£©Ñõ»¯ÌúºÍÒ»Ñõ»¯Ì¼·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºFe
2O
3+3CO
2Fe+3CO
2£®
£¨6£©½ðÊô¿óÎïµÄ´¢Á¿ÓÐÏÞ£¬¶øÇÒ²»ÄÜÔÙÉú£¬ËùÒԷϸÖÌúÒª»ØÊÕÀûÓ㮹ÊÌ»ØÊÕÀûÓã®
£¨7£©ÍÔÚ¿ÕÆøÖÐÉú³ÉÍÂ̵Ļ¯Ñ§·½³ÌʽΪ£º2Cu+H
2O+O
2+CO
2¨TCu
2£¨OH£©
2CO
3£®
£¨8£©ÈôÌìƽÈÔ±£³Öƽºâ£¬ËµÃ÷Ï¡ÑÎËáÍêÈ«·´Ó¦£¬ÓÉÓÚÏûºÄµÈÁ¿ÑÎËáʱ£¬·´Ó¦µôµÄÂÁ½ÏÉÙ£¬ËùÒÔÓ¦¸ÃÊÇÂÁ¹ýÁ¿£»ÈôÌìƽʧȥƽºâ£¬Ó¦¸ÃÊÇÏ¡ÑÎËá×ãÁ¿£¬ÌúÓëÏ¡ÑÎËá·´Ó¦Éú³ÉµÄÇâÆøÉÙ£¬Ö¸ÕëÆ«ÏòÌúµÄÒ»±ß£®¹ÊÌÂÁ£»Ìú£®
·ÖÎö£ºÓɶàÖÖÎïÖÊ×é³ÉµÄÎïÖÊÊôÓÚ»ìºÏÎÌúÓëÑõÆøºÍË®³ä·Ö½Ó´¥Ê±ÈÝÒ×ÉúÐ⣻¸ù¾Ý·´Ó¦ÎïºÍÉú³ÉÎï¼°ÆäÖÊÁ¿Êغ㶨ÂÉ¿ÉÒÔÊéд»¯Ñ§·½³Ìʽ£»¹ýÂË¿ÉÒ԰Ѳ»ÈÜÓÚË®µÄÎïÖʳýÈ¥£»¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ¿ÉÒÔÅжϷ´Ó¦½øÐз½ÃæµÄÇé¿ö£®
µãÆÀ£º½â´ð±¾ÌâÒªÕÆÎÕ»¯Ñ§·½³ÌʽµÄÊéд·½·¨ºÍ½ðÊôÉúÐâµÄÌõ¼þµÈ·½ÃæµÄ֪ʶ£¬Ö»ÓÐÕâÑù²ÅÄܶÔÏà¹Ø·½ÃæµÄÎÊÌâ×ö³öÕýÈ·µÄÅжϣ®