|
(1) |
¹Û²ìͼ1Öª£¬ÈýÔ·ݳöÊÛʱ£¬Ã¿¼þÉÌÆ·µÄÊÛ¼ÛΪ6Ôª£¬¹Û²ìͼ2Öª£¬ÈýÔ·ÝÉú²úÕâÖÖÉÌÆ·µÄ³É±¾ÎªÃ¿¼þ1Ôª£¬ËùÒÔ£¬Ã¿¼þÉÌÆ·ÔÚÈýÔ·ݳöÊÛʱµÄÀûÈóΪ6£1£½5Ôª |
(2) |
¹Û²ìͼ1Öª£¬QÓëtÖ®¼äµÄº¯Êý¹ØϵΪ¶þ´Îº¯Êý£¬Æ䶥µã×ø±êΪ(6£¬4)ÇÒ¹ýµã(3£¬1)£¬ÉèQÓëtÖ®¼äµÄº¯Êý½âÎöʽΪQ£½a(t£6)2£«4£¬ÔòÓÐ1£½a(3£6)2£«4£¬ËùÒÔa£½££¬ËùÒÔQÓëtÖ®¼äµÄº¯Êý½âÎöʽΪQ£½£(t£6)2£«4£¬¼´Q£½£t2£«4t£8£¬ÆäÖÐt£½3£¬4£¬5£¬6£¬7 |
(3) |
¡¡¡¡½â£ºÉèͼ2ÖÐMÓëtµÄº¯Êý½âÎöʽΪM£½kt£«b£¬ÔòÓнâµÃËùÒÔM£½t£«4£¬ÆäÖÐt£½3£¬4£¬5£¬6£¬7£®ËùÒÔW£½M£Q£½t£«4££½t2£t£«12£®Åä·½µÃW£½(t£5)2£«£®ÆäÖÐt£½3£¬4£¬5£¬6£¬7£®µ±t£½5ʱ£¬W×îС£½(Ôª)£®ËùÒÔ£¬30000¼þÉÌÆ·ÔÚÒ»¸öÔÂÄÚÊÛÍ꣬ÖÁÉÙ»ñÀû30000¡Á£½110000Ôª ¡¡¡¡½âÌâÖ¸µ¼£ºÓÉͼ1ÌṩµÄÐÅÏ¢Çó³öMÓëtµÄº¯Êý¹Øϵʽ£¬ÓÉͼ2ÌṩµÄÐÅÏ¢Çó³öQÓëtµÄº¯Êý¹Øϵʽ£®¸ù¾ÝW£½M£QÇó³öWÓëtµÄº¯Êý¹Øϵʽ£¬·ÖÎöWÓëtµÄº¯Êý¹Øϵʽ£¬¿ÉÇó³öÖÁÉÙ»ñÀû¶àÉÙÔª£® |
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º ÌâÐÍ£º
ijÉÌÒµ¹«Ë¾ÎªÖ¸µ¼Ä³ÖÖÓ¦¼¾ÉÌÆ·µÄÉú²úºÍÏúÊÛ£¬¶ÔÈýÔÂÖÁÆßÔ·ݸÃÉÌÆ·µÄÊÛ¼ÛºÍÉú²ú½øÐÐÁ˵÷ÑУ¬½á¹ûÈçÏ£ºÒ»¼þÉÌÆ·µÄÊÛ¼ÛM(Ôª)Óëʱ¼ät(ÔÂ)µÄ¹Øϵ¿ÉÓÃÒ»ÌõÏ߶ÎÉϵĵãÀ´±íʾ(Èçͼ¼×)£¬Ò»¼þÉÌÆ·µÄ³É±¾Q(Ôª)Óëʱ¼ät(ÔÂ)µÄ¹Øϵ¿ÉÓÃÒ»ÌõÅ×ÎïÏßÉϵĵãÀ´±íʾ£¬ÆäÖÐ6Ô·ݳɱ¾×î¸ß(ÈçͼÒÒ)£®
¸ù¾ÝͼÏóÌṩµÄÐÅÏ¢½â´ðÏÂÃæÎÊÌ⣺
(1)Ò»¼þÉÌÆ·ÔÚ3Ô·ݳöÊÛʱµÄÀûÈóÊǶàÉÙÔª?(ÀûÈó£½ÊÛ¼Û£³É±¾)
(2)Çó³öͼ(ÒÒ)ÖбíʾµÄÒ»¼þÉÌÆ·µÄ³É±¾Q(Ôª)Óëʱ¼ät(ÔÂ)Ö®¼äµÄº¯Êý¹Øϵʽ£»
(3)ÄãÄÜÇó³ö3Ô·ÝÖÁ7Ô·ÝÒ»¼þÉÌÆ·µÄÀûÈóW(Ôª)Óëʱ¼ät(ÔÂ)Ö®¼äµÄº¯Êý¹ØϵʽÂð?Èô¸Ã¹«Ë¾ÄÜÔÚÒ»¸öÔÂÄÚÊÛ³ö´ËÖÖÉÌÆ·30000¼þ£¬ÇëÄã¼ÆËã¸Ã¹«Ë¾ÔÚÒ»¸öÔÂÄÚ×îÉÙ»ñÀû¶àÉÙÔª?
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º2010ÄêÖп¼Êýѧ¿¼Ç°10ÈÕÐÅÏ¢Ì⸴ϰÌ⾫ѡ£¨6£©£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º³õÖÐÊýѧ À´Ô´£º2012½ì¾ÅÄ꼶µÚ¶þѧÆÚµÚÒ»½×¶Î¿¼ÊÔÊýѧ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ
ijÉÌÒµ¹«Ë¾ÎªÖ¸µ¼Ä³ÖÖÓ¦¼¾ÉÌÆ·µÄÉú²úºÍÏúÊÛ£¬¶ÔÈýÔÂÖÁÆßÔ·ݸÃÉÌÆ·µÄÊÛ¼ÛºÍÉú²ú½øÐÐÁ˵÷ÑУ¬½á¹ûÈçÏ£ºÒ»¼þÉÌÆ·µÄÊÛ¼ÛM(Ôª)Óëʱ¼ät(ÔÂ)µÄ¹Øϵ¿ÉÓÃÒ»ÌõÏ߶ÎÉϵĵãÀ´±íʾ(Èçͼ¼×)£¬Ò»¼þÉÌÆ·µÄ³É±¾Q(Ôª)Óëʱ¼ät(ÔÂ)µÄ¹Øϵ¿ÉÓÃÒ»ÌõÅ×ÎïÏßÉϵĵãÀ´±íʾ£¬ÆäÖÐ6Ô·ݳɱ¾×î¸ß(ÈçͼÒÒ)£®
¸ù¾ÝͼÏóÌṩµÄÐÅÏ¢½â´ðÏÂÃæÎÊÌ⣺
(1)Ò»¼þÉÌÆ·ÔÚ3Ô·ݳöÊÛʱµÄÀûÈóÊǶàÉÙÔª?(ÀûÈó£½ÊÛ¼Û£³É±¾)
(2)Çó³öͼ(ÒÒ)ÖбíʾµÄÒ»¼þÉÌÆ·µÄ³É±¾Q(Ôª)Óëʱ¼ät(ÔÂ)Ö®¼äµÄº¯Êý¹Øϵʽ£»
(3)ÄãÄÜÇó³ö3Ô·ÝÖÁ7Ô·ÝÒ»¼þÉÌÆ·µÄÀûÈóW(Ôª)Óëʱ¼ät(ÔÂ)Ö®¼äµÄº¯Êý¹ØϵʽÂð?Èô¸Ã¹«Ë¾ÄÜÔÚÒ»¸öÔÂÄÚÊÛ³ö´ËÖÖÉÌÆ·30000¼þ£¬ÇëÄã¼ÆËã¸Ã¹«Ë¾ÔÚÒ»¸öÔÂÄÚ×îÉÙ»ñÀû¶àÉÙÔª?
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com