Question

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Answer 1

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¢Ú$\frac{-8{m}^{4}{n}^{2}}{{a}^{5}b}•\frac{an}{b{m}^{2}}$=-$\frac{4{m}^{2}{n}^{2}}{{a}^{4}{b}^{2}}$£»
¢Û$\frac{4{m}^{2}}{{a}^{2}{b}^{4}}$•$\frac{{n}^{2}{b}^{2}}{{a}^{2}}$=$\frac{4{m}^{2}{n}^{2}}{{a}^{4}{b}^{2}}$
¢Ü$\frac{2m{n}^{2}}{a{b}^{2}}¡Â\frac{{a}^{3}}{m}$=$\frac{2{m}^{2}{n}^{2}}{{a}^{4}{b}^{2}}$£®
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