Question

»¯¼ò²¢ÇóÖµ£º
£¨1£©£¨2x³-3x²-3£©-£¨-x³+4x²£©£¬ÆäÖÐx=-1£»
£¨2£©ÒÑÖª(a+2)2+|b-

1

2

|=0£¬Çó5a²b-[2a²b-£¨ab²-2a²b£©-4]-2ab²µÄÖµ£»
£¨3£©¼ºÖªa-b=2£¬Çó¶àÏîʽ

1

4

(a-b)2-9(a-b)-

1

2

(a-b)2-5(b-a)掙术
£¨4£©Èô0.5x^|a|y⁴Óë-

2

3

x2y|b-1|ÊÇͬÀàÏÇÒa£¾b£¬Çóa2-ab-2a2+

1

2

ab+

2

3

b2µÄÖµ£®

Answer 1

·ÖÎö£º£¨1£©ÏȽ«Ô­Ê½È¥À¨ºÅ¡¢ºÏ²¢Í¬ÀàÏÔÙ°Ñx=-1´úÈ뻯¼òºóµÄʽ×Ó£¬¼ÆËã¼´¿É£»
£¨2£©¸ù¾ÝÁ½¸ö·Ç¸ºÊýµÄºÍµÈÓÚ0£¬¿É֪ÿһ¸ö·Ç¸ºÊýµÈÓÚ0£¬¿ÉÇó³öa¡¢bµÄÖµ£¬ÔÙ¶ÔËùÇó´úÊýʽ»¯¼ò£¬È»ºóÔÙ°Ña¡¢bµÄÖµ´úÈ뻯¼òºóµÄʽ×Ó£¬¼ÆËã¼´¿É£»
£¨3£©ÏȺϲ¢Í¬ÀàÏÔÙ°Ña-bµÄÖµÕûÌå´úÈ뻯¼òºóµÄʽ×Ó¼ÆËã¼´¿É£»
£¨4£©Ïȸù¾ÝͬÀàÏîµÄ¶¨Ò壬ÒÔ¼°a£¾b£¬¿ÉÇó³öÁ½×éa¡¢bµÄÖµ£¬·Ö±ð´úÈ뻯¼òºóµÄʽ×Ó£¬¼ÆËã¼´¿É£®

½â´ð£º½â£º£¨1£©Ô­Ê½=2x³-3x²-3+x³-4x²=3x³-7x²-3£¬
µ±x=-1ʱ£¬Ô­Ê½=3¡Á£¨-1£©-7¡Á1-3=-13£»

£¨2£©¡ß(a+2)2+|b-

1

2

|=0£¬
¡àa+2=0£¬b-

1

2

=0£¬
¡àa=-2£¬b=

1

2

£¬
ԭʽ=5a²b-2a²b+ab²-2a²b+4-2ab²=a²b-ab²+4£¬
µ±a=-2£¬b=

1

2

£¬Ô­Ê½=4¡Á

1

2

-£¨-2£©¡Á

1

4

+4=6

1

2

£»

£¨3£©Ô­Ê½=-

1

4

£¨a-b£©²-4£¨a-b£©£¬
µ±a-b=2ʱ£¬Ô­Ê½=-

1

4

¡Á4-4¡Á2=-9£»

£¨4£©¡ß0.5x^|a|y⁴Óë-

2

3

x2y|b-1|ÊÇͬÀàÏ
¡à|a|=2£¬|b-1|=4£¬
¡àa=¡À2£¬b=5»ò-3£¬
ÓÖ¡ßa£¾b£¬
¡àa=2£¬b=-3£»a=-2£¬b=-3£¬
ԭʽ=-a²-

1

2

ab+

2

3

b²£¬
µ±a=2£¬b=-3ʱ£¬Ô­Ê½=-4-

1

2

¡Á£¨-6£©+

2

3

¡Á9=5£¬
µ±a=-2£¬b=-3ʱ£¬Ô­Ê½=-4-

1

2

¡Á6+

2

3

¡Á9=-1£®

µãÆÀ£º±¾Ì⿼²éÁËÕûʽµÄ»¯¼òÇóÖµ¡¢·Ç¸ºÊýµÄÐÔÖÊ¡¢Í¬ÀàÏîµÄ¶¨Ò壮ÕûʽµÄ¼Ó¼õÔËËãʵ¼ÊÉϾÍÊÇÈ¥À¨ºÅ¡¢ºÏ²¢Í¬ÀàÏÕâÊǸ÷µØÖп¼µÄ³£¿¼µã£®