要用圆形铁片截出边长为a的正三角形铁片,选用的圆形铁片的半径为 .
【答案】
分析:先根据题意画出图形,再根据等边三角形的性质得出BD=
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BC=
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a,∠OBD=30°,再由三角函数的定义即可求出OB的长.
解答:解:如图所示,
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作OD⊥BC,连接OB,由正三角形的性质可知BD=
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BC=
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a,∠OBD=30°,
∵BD=
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BC=
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a,∠OBD=30°,
∴OB=
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=
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=
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,
∴选用的圆形铁片的半径为
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.
故答案为:
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.
点评:本题考查的是正多边形和圆,解答此类题目的关键是根据题意画出图形,利用数形结合求解.