小题1:(1)解:设该专营店第一季度购进A、B两种型号手机的数量分别为x部和y部. 1分
由题意可知:·························································· 3分
解得:
答:该专营店本次购进A、B两种型号手机的数分别为15部和18部.····················· 4分
小题2:(2)解:设第二季度购进A型号手机a部.········································ 5分
由题意可知:1200a+1000(34-a)≤36000,····················································· 6分
解得:a≤10··························································································· 7分
不等式的最大整数解为10
答:第二季度最多能购A型号手机10部.······················································· 8分