(x+y+3)(x+y-3)
分析:首先由a,b满足
=0,求得a与b的值,然后代入(x
2+y
2)-(axy+b),即可得可以利用分组分解法将其因式分解.
解答:∵a,b满足
=0,
∴a+2=0,b-9=0,
解得:a=-2,b=9,
∴(x
2+y
2)-(axy+b)=(x
2+y
2)-(-2xy+9)=(x
2+y
2+2xy)-9=(x+y)
2-9=(x+y+3)(x+y-3).
故答案为:(x+y+3)(x+y-3).
点评:本题考查了分组分解法分解因式与非负数的性质.此题难度不大,解题的关键是需细心,难点是采用两两分组还是三一分组.